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Three angles of a quadilateral are respectively 100 degree , 98 degree, 92 degree. find the fouth angle.

Posted- 1993 days ago

Sum of the Angles of a quadrilateral = 360

100+98+92+x=360

x=70 degree

Always in a quadrilateral, the sum of all the angles is 360.

here, 3 angles are already given, so the forth angle can be calculated as

100+98+92+4th angle=360

=>4th angle=360-100-98-92

=70

4th angle=70

100+92+98+x=360

x=360-100-190

x=70

The sum of the 4 angles of a quadrilateral is 360.

Let the unknown angle x then,

x+98+92+100=360

x=70

the sum of four angles in a quadrilateral is 360 degrees

let the fourth angle be

therefore 100degree+98degree+92degree+ = 360 degree

the fourth angle  ie   = 70 degree

100+92+98+x=360

290+x=360

x=360-290(law of transposition)

x=70 degree

Sum of the Angles of a quadrilateral = 360 100+98+92+x=360 x=70 degree

100+92+98+x=360

290+x=360

x=360-290

x=70

<1 = 100o

<2 =98o

<3 =92o

<4 =?

the sum of the angles ina quadrilaterl is 360o

according to the angle sum property of a quadrilateral,

<1+<2+<3+<4=360

100+98+92+<4=360

290+<4=360

<4=360-290

<4=70

... the fourth angle of the quadrilateral is 70o.

According to angle sum property of a quadrilateral the sum of all the angles of a quadrilateral is 360.

A+B+C+D=360

let the fourth angle be x

100+98+92+x=360

290+x=360

x=360-290

x=70.....................Ans

Sum of all angles = 360

sum of the given 3 angles = 100+98+92 = 290

4th angle = 360 - 290 = 700

Hi

Fourth angle = 70

The sum of 4 angles of the quad. is 360 degree . So, 360 - [100+98+92] is equal to 360-[ 290] is 70.

Sum of the Angles of a quadrilateral = 360

100+98+92+x=360

290+x=360

x=360 - 290

x=70

by angle sum property,

100+98+92+fourth angle=360,

fourth angle=360-100-98-92,

=70 degrees.

70 degree

in a quad. ,the sum of angles of a quad. is always  360 degree.in this question 3 angles r given and one to find .

so acc. to ques. 100+98+92+4th angle=360 deg.

290+4th angle=360 deg..

4th angle=360-290

4th angle =70

so 4th angle is 70 degree..

Let the fourth angle be x.

As the sum of the total angles of the quadilateral is 360

so 100+ 98+ 92+ x = 360

so 100+ 98 +92 =290

so 360 - 290=x

so x = 70

The fourth angle is of 70 measure

The sum of angles(4) of a quadrilateral is = 360 degrees.

if unknown angle is x .

100+98+92+x = 360

290+x= 360

x = 360-290=70 degrees

1000+980+920+x=360         [Angle sum property of a quadrilateral]

2900+x=3600

x=700

The sum of the 4 angles of a quadrilateral is 360 degree.

Let the unknown angle 'x'then,

x + 98 degree + 92 degree + 100 degree = 360 degree

x=70 degree

70 degree.

1+ 2+ 3+ 4=360degrees.

1=2=3=given.

So,let the unknown angle be x.

Then,

100+98+92+x=360

x = 70 degrees

Sum of all the angles of quadrilateral=360

Let x=fourth angle

Now,

100+98+92+x=360

x=360-290

x=70

So, the 4th angle is 70.

The sum of the angles in a quadrilateral is 360o

100o+98o+92o+xo= 360o

290o+xo = 360o        xo = 360o- 290o

xo = 70o

The fourth angle in the given quadrilateral is 70o.

Sum of the angles in a quadrilateral=360 degrees

given: 100,98,92 degrees

let the fourth angle be x

100+98+92+x=360

290+x=360

x=360-290

x=70 degrees

sum of the angles of a quadrilateral=360

100+98+92+x=360

290+x=360

x=360-290

x=70

let angle a = 100 degree

let angle b = 98 degree

let angle c = 92 degree

let angle d = x

sum of all angles of a quadrilateral = 360 degree

angle (a+b+c+d) = 360 degree

100 +98+92+x = 360 degree

290 + x = 360 degree

x = 360 - 290

x = 70 degree

let angle a = 100 degree

let angle b = 98 degree

let angle c = 92 degree

let angle d = x

sum of all angles of a quadrilateral = 360 degree

angle (a+b+c+d) = 360 degree

100 +98+92+x = 360 degree

290 + x = 360 degree

x = 360 - 290

x = 70 degree

70 degrees.

360-(100 +98 +92)= the fourth angle

360-290= 70 degree

4th angle= 70 degree

Total angle=360 degrees.

Fourth angle=360-100-98-92=70 degrees

sum of angles of a quadrilateral is 360 degrees.

therefore,4th angle=360-(100+98+92)

70degrees

Let the angle to be find be x

Sum of the four angles of a quadilateral=360

100+98+92+x          =360

290+x      =360

x=360-290

=70

The fourth angle is 70 degree.

Sum of the angles of a quadrilateral is 360 degree

Let the 4th angle be x

so, 100+98+92+x=360

290+x=360

x=70

So,the 4th angle would measure 70 degree

sum of all angle of quadrilateral is 360.

98+100+92+a=360

290+a=360

a=360- 290

a=70

1 angle=100

2 angle=98

3 angle=92

4 angle=360-sum of 3 angles

=360-290=70

3 angle=70

sum of all 4 angles=360 degrees

= 100 degree

2=98 degree

3=92 degree

4= x

sum of all four angles=360 degrees

100 degree+98 degree+92 degree+x=360 degree

290 degree+x=360 degree

x = 360-290 degrees

x=70 degrees

the 4th  will be 70 dedgrees

100+98+92+x=360

x=70

70degrees

sum of angles of a quadrilateral=360

100+98+92+angle4=360

angle4+ 290=360

angle4=360-290=70

sum of angles of a quadilateral=360 degrees

100+98+92+fourth angle=360

fourth angle=70 degrees

100+98+92+x=360 (angle sum property of quadrilateral)

290+x=360

x=360-290

x=70

100+98+92+x=360 x=360-290=70 70

We know that sum of angles of a quadrilateral is equal to 360.........(1)

1st angle=100.

2nd angle=98.

3rd angle=92.

4th angle=x(say)

now using equation 1 we get

100.+98.+92.+x=360.

290.+x=360.

x=360.-290.

or x=70.

we know sum of angles = 3600

let fouth angle = x

thus, 100 + 98 + 92 + x = 360 (by the question)

or 290 + x = 360

or x = 360 - 290

or x = 700

therefore the fourth angle of quadrilateral would be 700.

92+x=180;

x=180-92

x=88 degrees.

According to the angle sum property of quadrilaterals the sum of anngles of a quadrilateral is 3600.

Here 3 side are give , so we can find the 4th side.

let the 4th side be x,

100+98+92+x=3600.

or x =360-(100+98+92)

= 360-290

= 700

let the angle of the quadilateral be A,B,C & D

given that,

DAB=100, ABC=98, BCD=92

let the angle ADC be x

A+B+C+D=360

therefore,

100+98+92+x=360

290+x=360

x=360-290

x=70

therefore the value of the forth angle ADC

70 degrees

first angle=100 degree

second angle=98 degree

third angle=92 degree

sum of all the angles=360 degree

let,the fourth angle be x degree

therefore, the equation is

100+98+92+x=360

290+x=360

x=360-290

x=70

therfore, the fourth angle=70 degree

Sum of four angles of a quadrilateral = 3600

Angle 1 = 1000

Angle 2 = 980

Angle 3 = 920

Angle 4 = ?

Angle 4 = 360 - 1+2+3

Angle 4 = 360 - 290

Angle 4 = 700

Let the 4th angle=x0

We know that sum of 4 sides of quadilateral is3600

therefore 1000+980+920+x=3600

2900+x0=3600

x0=3600-2900=700

100+98+92+x=360

290+x=360

x=360-290

x=70

Sum of the interior angles of a quadrilateral is 360 degrees.

Let the 4th angle of the quadrilateral be X.

Therefore,

100+98+92+X=360 degrees.

290+X=360 degrees

X=360-290

= 70 degrees.

Ans: The measure of the 4th angle of the quadrilateral is 70 degrees.

X=70 degree

If all are interior then the forth angle is 70.

let the third angle be x

so

x+98+92+100=360 (because sum of all the angles in a quadilateral is 360)

x+290=360

x=360-290

x=70

Let fourth angle =x

Now, By angle su property of quadrilateral

100+98+92+x = 360

290 + x =360

x=70

GIVEN:-  A=100

B=98

C=92

D=?

NOW IN A QUARDILATERAL A+B+C+D=360

100+98+92+D=360

290+D=360

D=360-290=70

Sum of the angles of quadrilateral = 360

100 + 98 + 92 + x = 360

x = 70

Since the sum of the angles of the quardilateral is 360*, the fourth angle must be 360-290=70*

sum of 4 angles in a quadrilateral=360 degree

so, 100+98+92+x=360 degree

or 290+x=360

or x=360-290=70 degree

sum of angles in a quad is 3600.

let the four s be A,B,C,D

A+B+C+D=3600

1000+980+920+D=3600

1000+1900+D=3600

2900+D=3600

D=3600-2900

D=700

According to angle sum property of a quadrilateral the sum of all the angles of a quadrilateral is 360.

A+B+C+D=360

let the fourth angle be x

100+98+92+x=360

290+x=360

x=360-290

x=70.....................Ans

sum of the measures of all the angles are 3600

hence the measure of the 4th angle is 70

70 digrees

Let the 4th angle be X.

By angle sum property of a quadilateral

92+98+100+X=360

290+X=360

X=360-290

X=70

Hence the 4th angle measures 70 degree.

70 degree.

70 degree

100+98+92+x=360 x=70

1+2+3+x=360 Total of the angles of a quadrilateral is 360

100+98+92+x=360

290+x=360

x=360-290

=70

we have

100,98,92 and sum of all angle of a quadilateral is 360.let the forth angle be x

100+98+92+x=360

290+x=360

x=70

the sum of the angles of the quadrilateral is 360

100+ 98+ 92 + <A=360

<A= 360-290

<A=70

70 degrees