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Three angles of a quadilateral are respectively 100 degree , 98 degree, 92 degree. find the fouth angle.

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Always in a quadrilateral, the sum of all the angles is 360.

here, 3 angles are already given, so the forth angle can be calculated as

100+98+92+4th angle=360

=>4th angle=360-100-98-92

=70

4th angle=70

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The sum of the 4 angles of a quadrilateral is 360.

Let the unknown angle x then,

x+98+92+100=360

x=70

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the sum of four angles in a quadrilateral is 360 degrees

let the fourth angle be

therefore 100degree+98degree+92degree+ = 360 degree

the fourth angle ie = 70 degree

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<1 = 100^{o}

<2 =98^{o}

<3 =92^{o}

<4 =?

the sum of the angles ina quadrilaterl is 360o

according to the angle sum property of a quadrilateral,

<1+<2+<3+<4=360

100+98+92+<4=360

290+<4=360

<4=360-290

<4=70

.^{.}. the fourth angle of the quadrilateral is 70^{o}.

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According to angle sum property of a quadrilateral the sum of all the angles of a quadrilateral is 360^{}.

A+B+C+D=360

let the fourth angle be x

100+98+92+x=360

290+x=360

x=360-290

x=70.....................Ans

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Sum of all angles = 360

sum of the given 3 angles = 100+98+92 = 290

4^{th} angle = 360 - 290 = 70^{0}

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The sum of 4 angles of the quad. is 360 degree . So, 360 - [100+98+92] is equal to 360-[ 290] is 70.

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Sum of the Angles of a quadrilateral = 360

100+98+92+x=360

290+x=360

x=360 - 290

x=70

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by angle sum property,

100+98+92+fourth angle=360,

fourth angle=360-100-98-92,

=70 degrees.

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in a quad. ,the sum of angles of a quad. is always 360 degree.in this question 3 angles r given and one to find .

so acc. to ques. 100+98+92+4th angle=360 deg.

290+4th angle=360 deg..

4th angle=360-290

4th angle =70

so 4th angle is 70 degree..

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Let the fourth angle be x.

As the sum of the total angles of the quadilateral is 360

so 100+ 98+ 92+ x = 360

so 100+ 98 +92 =290

so 360 - 290=x

so x = 70

The fourth angle is of 70 measure

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The sum of angles(4) of a quadrilateral is = 360 degrees.

if unknown angle is x .

100+98+92+x = 360

290+x= 360

x = 360-290=70 degrees

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100^{0}+98^{0}+92^{0}+x=360 [Angle sum property of a quadrilateral]

290^{0}+x=360^{0}

x=70^{0}

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The sum of the 4 angles of a quadrilateral is 360 degree.

Let the unknown angle 'x'then,

x + 98 degree + 92 degree + 100 degree = 360 degree

x=70 degree

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1+ 2+ 3+ 4=360degrees.

1=2=3=given.

So,let the unknown angle be x.

Then,

100+98+92+x=360

x = 70 degrees

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Sum of all the angles of quadrilateral=360

Let x=fourth angle

Now,

100+98+92+x=360

x=360-290

x=70

So, the 4^{th} angle is 70.

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The sum of the angles in a quadrilateral is 360^{o}

100^{o}+98^{o}+92^{o}+x^{o}= 360^{o}

290^{o}+x^{o} = 360^{o} x^{o} = 360^{o}- 290^{o}

^{ }x^{o} = 70^{o}

The fourth angle in the given quadrilateral is 70^{o}.

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Sum of the angles in a quadrilateral=360 degrees

given: 100,98,92 degrees

let the fourth angle be x

100+98+92+x=360

290+x=360

x=360-290

x=70 degrees

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sum of the angles of a quadrilateral=360

100+98+92+x=360

290+x=360

x=360-290

x=70

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let angle a = 100 degree

let angle b = 98 degree

let angle c = 92 degree

let angle d = x

sum of all angles of a quadrilateral = 360 degree

angle (a+b+c+d) = 360 degree

100 +98+92+x = 360 degree

290 + x = 360 degree

x = 360 - 290

x = 70 degree

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let angle a = 100 degree

let angle b = 98 degree

let angle c = 92 degree

let angle d = x

sum of all angles of a quadrilateral = 360 degree

angle (a+b+c+d) = 360 degree

100 +98+92+x = 360 degree

290 + x = 360 degree

x = 360 - 290

x = 70 degree

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360-(100 +98 +92)= the fourth angle

360-290= 70 degree

4th angle= 70 degree

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sum of angles of a quadrilateral is 360 degrees.

therefore,4th angle=360-(100+98+92)

70degrees

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Let the angle to be find be x

Sum of the four angles of a quadilateral=360

100+98+92+x =360

290+x =360

x=360-290

=70

The fourth angle is 70 degree.

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Sum of the angles of a quadrilateral is 360 degree

Let the 4th angle be x

so, 100+98+92+x=360

290+x=360

x=70

So,the 4th angle would measure 70 degree

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sum of all angle of quadrilateral is 360.

98+100+92+a=360

290+a=360

a=360- 290

a=70

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1 angle=100

2 angle=98

3 angle=92

4 angle=360-sum of 3 angles

=360-290=70

3 angle=70

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sum of all 4 angles=360 degrees

1 = 100 degree

2=98 degree

3=92 degree

4= x

sum of all four angles=360 degrees

100 degree+98 degree+92 degree+x=360 degree

290 degree+x=360 degree

x = 360-290 degrees

x=70 degrees

the 4th will be 70 dedgrees

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sum of angles of a quadrilateral=360

100+98+92+angle4=360

angle4+ 290=360

angle4=360-290=70

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sum of angles of a quadilateral=360 degrees

100+98+92+fourth angle=360

fourth angle=70 degrees

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We know that sum of angles of a quadrilateral is equal to 360^{.}........(1)

1^{st} angle=100^{.}

2^{nd} angle=98^{.}

3^{rd }angle=92^{.}

4^{th} angle=x(say)

now using equation 1 we get

100^{.}+98^{.}+92^{.}+x=360^{.}

^{ }290^{.}+x=360^{.}

x=360^{.}-290^{.}

or x=70^{.}

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we know sum of angles = 360^{0}

let fouth angle = x

thus, 100 + 98 + 92 + x = 360 (by the question)

or 290 + x = 360

or x = 360 - 290

or x = 70^{0}

therefore the fourth angle of quadrilateral would be 70^{0}.

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According to the angle sum property of quadrilaterals the sum of anngles of a quadrilateral is 360^{0.}

Here 3 side are give , so we can find the 4^{th} side.

let the 4^{th }side be x,

100+98+92+x=360^{0.}

or x =360-(100+98+92)

= 360-290

= 70^{0}

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let the angle of the quadilateral be A,B,C & D

given that,

DAB=100, ABC=98, BCD=92

let the angle ADC be x

in quadilateral

A+B+C+D=360

therefore,

100+98+92+x=360

290+x=360

x=360-290

x=70

therefore the value of the forth angle ADC

(i.e) ADC=70

first angle=100 degree

second angle=98 degree

third angle=92 degree

sum of all the angles=360 degree

let,the fourth angle be x degree

therefore, the equation is

100+98+92+x=360

290+x=360

x=360-290

x=70

therfore, the fourth angle=70 degree

Sum of four angles of a quadrilateral = 360^{0}

Angle 1 = 100^{0}

Angle 2 = 98^{0}

Angle 3 = 92^{0}

Angle 4 = ?

Angle 4 = 360 - 1+2+3

^{ }Angle 4 = 360 - 290

Angle 4 = 70^{0}

Let the 4th angle=x^{0}

We know that sum of 4 sides of quadilateral is360^{0}

therefore 100^{0}+98^{0}+92^{0}+x=360^{0}

290^{0}+x^{0}=360^{0}

x^{0}=360^{0}-290^{0}=70^{0}

Sum of the interior angles of a quadrilateral is 360 degrees.

Let the 4th angle of the quadrilateral be X.

Therefore,

100+98+92+X=360 degrees.

290+X=360 degrees

X=360-290

= 70 degrees.

Ans: The measure of the 4th angle of the quadrilateral is 70 degrees.

let the third angle be x

so

x+98+92+100=360 (because sum of all the angles in a quadilateral is 360)

x+290=360

x=360-290

x=70

Let fourth angle =x

Now, By angle su property of quadrilateral

100+98+92+x = 360

290 + x =360

x=70

GIVEN:- A=100

B=98

C=92

D=?

NOW IN A QUARDILATERAL A+B+C+D=360

100+98+92+D=360

290+D=360

D=360-290=70

Sum of the angles of quadrilateral = 360

100 + 98 + 92 + x = 360

x = 70

Since the sum of the angles of the quardilateral is 360*, the fourth angle must be 360-290=70*

sum of 4 angles in a quadrilateral=360 degree

so, 100+98+92+x=360 degree

or 290+x=360

or x=360-290=70 degree

sum of angles in a quad is 360^{0.}

let the four s be A,B,C,D

A+B+C+D=360^{0}

100^{0}+98^{0}+92^{0}+D=360^{0}

100^{0}+190^{0}+D=360^{0}

290^{0}+D=360^{0}

D=360^{0}-290^{0}

D=70^{0}

According to angle sum property of a quadrilateral the sum of all the angles of a quadrilateral is 360^{}.

A+B+C+D=360

let the fourth angle be x

100+98+92+x=360

290+x=360

x=360-290

x=70.....................Ans

sum of the measures of all the angles are 360^{0}

hence the measure of the 4^{th} angle is 70

Let the 4th angle be X.

By angle sum property of a quadilateral

92+98+100+X=360

290+X=360

X=360-290

X=70

Hence the 4th angle measures 70 degree.

1+2+3+x=360 Total of the angles of a quadrilateral is 360

100+98+92+x=360

290+x=360

x=360-290

=70

we have

100,98,92 and sum of all angle of a quadilateral is 360.let the forth angle be x

100+98+92+x=360

290+x=360

x=70

the sum of the angles of the quadrilateral is 360

100+ 98+ 92 + <A=360

<A= 360-290

<A=70