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While covering a distance of of 30 km.Ajeet takes 2 hrs more than amit.If Ajeet doubles his speed , he would take  1 hr less than Amit.Find their speeds of walking.

Posted- 2403 days ago

ajeet's speed- xkm\hr

amit's speed-ykm\hr

Now solve these then you will get the answer,

30/x=30\y  + 2           (distance=time*speed)

30/y=  30\2x  + 1      (distance=time*speed)

LET THE SPEED AT WHICH AJEET WALKS BE      X km/hr

LET LET THE SPEED AT WHICH AMIT WALKS BE     Ykm/hr

AJEET                                                                                        AMIT

SPEED:X                            km/hr                                             Y

DIST:30                                km                                                30

TIME:30/X                               HR                                               30/Y

NEW SPEED:2X                        km/hr                                              Y

DIST:30                                km                                                 30

NEW TIME:30/2X                     HR                                               30/Y

30/X=30/Y+2

30/2X=30/Y-1

let ajeet's speed be 'x' km/h

let amit's speed be 'y' km/h

Ajeet takes 2 hrs more than amit.

30/x - 30/y =2

1/x - 1/y = 1/15

15y - 15x= xy                                      .........(1)

If Ajeet doubles his speed , he would take  1 hr less than Amit.

30/y - 30/2x = 1

60x - 30y = 2xy

30x - 15y = xy                                     .........(2)

adding the equations (1) & (2)

15y - 15x= xy

30x- 15y= xy

15x=xy

y=15

substituting the value of y in eqn. (1)

15y - 15x= xy

225 - 15x = 15x

225=30x

x=7.5

therefore the speed of ajeet is 7.5 km/h and that of amit is 15 km/h.