Q:

A:

Three lakh fifty three thousand five hundred fifty two

Q:

A:

1005

Q:

A:

The HCF of two prime numbers is 1.

Q:

A:

No, because the sum of two obtuse angles is more than 180° and this is not possible in the triangle.

Q:

Write the following situation as integer with appropriate sign.

a bank withdrawal of 500

A:

-500

Q:

A:

Q:

A:

Q:

30, 54, 61, 83, 47, 93, 26, 78, 64, 55

80, 56, 43, 67, 94, 73, 48, 39, 84, 63

54, 61, 92, 43, 24, 84, 72, 36, 57, 90

77, 69, 42, 56, 74, 81, 46, 34, 29, 40

Prepare a table with tally marks.

A:

Q:

In a Mathematics test, marks obtained by the 40 students are as follows, arrange them in a table by using the tally marks.

8 1 3 7 6 5 5 4 4 2 4 9 5 3 7 1 6 5 2 7 7 3 8 4 2 8 9 5 8 6 7 4 5 6 9 6 4 4 6 6 |

Also find:

(a) How many students obtained maximum marks.

(b) How many students obtained minimum marks.

(c) How many students obtained marks more than 4.

A:

Marks Obtained | Tally Marks | Number of Students |

1 | || | 2 |

2 | ||| | 3 |

3 | ||| | 3 |

4 | || | 7 |

5 | | | 6 |

6 | || | 7 |

7 | 5 | |

8 | |||| | 4 |

9 | ||| | 3 |

a) 3 students secured maximum marks (frequency of 9 is 3).

b) 2 students secured minimum marks (frequency of 1 is 2).

c) 25 students secured more than 4 marks (Total frequency of 5,6,7,8,9 marks = 6+7+5+4+3= 25).

Q:

Days | Monday | Tuesday | Wednesday | Thursday | Friday |

Number of Books Sold | 60 | 55 | 50 | 45 | 30 |

A:

Q:

(a) 65

(b) 77

A:

(a) 65 = 50+10+5 = L+X+V = LXV

(b) 77 = 50+10+10+7= L+X+X+VII = LXXVII

(b) 77 = 50+10+10+7= L+X+X+VII = LXXVII

Q:

A:

7 X 109

= 7 X (100 + 9)

=7 X 100 + 7 X 9

= 700 + 63

= 763

Q:

A:

1 64

2 32

4 16

8 8

The possible factors are 1, 2, 4, 8, 16, 32 and 64

Q:

(i) AC = AB + ____

(ii) BC = BD – ____.

A:

(i) BC

(ii) CD

Q:

A:

No, as the sum of two right–angles will be 180 ° and the third angle cannot be zero.

Q:

Draw a number line and represent the following number:

(a) + 8

(b) –10

A:

Q:

A:

Q:

a) Two ones and five-tenths

b) Three hundred and three-tenths

A:

Q:

30, 54, 61, 83, 47, 93, 26, 78, 64, 55

80, 56, 43, 67, 94, 73, 48, 39, 84, 63

54, 61, 92, 43, 24, 84, 72, 36, 57, 90

77, 69, 42, 56, 74, 81, 46, 34, 29, 40

Prepare a table with tally marks.

A:

Q:

A:

Each copy has 15 pages.

Hence 13,560 copies = 15 13,560 pages

Therefore,

Everyday 2,03,400 pages are printed.

Q:

A:

(25 X 4) X 7896 X (50 X 2)

=100 X 7896 X 100

=78960000

Q:

A:

Given no 438750

DIVISIBILITY BY

2 Yes, since units place is even.

4 No, since the number formed by last 2 digits is 50 which is not divisible by 4.

5 Yes, since units place is 0.

Q:

a) Name two pairs of opposite sides.

b) Name four pairs of adjacent sides.

c) Name two pairs of opposite angles.

A:

a) PO and MN; PM and ON.

b) OP and PM; PM and MN; MN and NO; NO and OP.

c) P and N; M and O.

Q:

A:

(i) 6 sides, Hexagon (ii) 8 sides, Octagon

Q:

(-3) + (-7) ____ (-7) - (-3)

A:

(-3) + (-7) = -10

(-7) - (-3) = -7 + 3 = -4

-10 < -4

Therefore, (-3) + (-7) < (-7) - (-3)

Q:

A:

Q:

a) 13.8

b) 13.08

c) 13.008

A:

Q:

In a Mathematics test, marks obtained by the 40 students are as follows, arrange them in a table by using the tally marks.

8 1 3 7 6 5 5 4 4 2 4 9 5 3 7 1 6 5 2 7 7 3 8 4 2 8 9 5 8 6 7 4 5 6 9 6 4 4 6 6 |

Also find:

(a) How many students obtained maximum marks.

(b) How many students obtained minimum marks.

(c) How many students obtained marks more than 4.

A:

Marks Obtained | Tally Marks | Number of Students |

1 | || | 2 |

2 | ||| | 3 |

3 | ||| | 3 |

4 | || | 7 |

5 | | | 6 |

6 | || | 7 |

7 | 5 | |

8 | |||| | 4 |

9 | ||| | 3 |

a) 3 students secured maximum marks (frequency of 9 is 3).

b) 2 students secured minimum marks (frequency of 1 is 2).

c) 25 students secured more than 4 marks (Total frequency of 5,6,7,8,9 marks = 6+7+5+4+3= 25).

Q:

A:

Q:

A:

First we find the L.C.M of 20, 40, and 75

2 | 20, 40, 75 |

2 | 10, 20, 75 |

2 | 5, 10 75 |

5 | 5, 5 75 |

5 | 1 1, 15 |

3 | 1, 1, 3 |

1, 1, 1 |

LCM = 2 2 2 5 5 3 = 600

Least 5 digit number = 10000

__ 16 __ 600) 10000

__600__

4000

__3600__

400

Since remainder is 400 it needs 200 more, to be fully divisible by 600.

Required no = 10000 + (200 + 9)[We need the number that leaves remainer 9]

= 10209

Q:

(i) Line segment, (ii) Line, (iii) Intersecting lines, (iv) Parallel lines.

A:

(i) Line Segment: A line segment corresponds to the shortest distance between two points. The line segment joining points A and B is denoted by .

(ii) Line: A line is obtained when a line segment is extended on both sides indefinitely.

(iii) Intersecting lines: Two distinct lines meeting at a point are called intersecting lines.

(iv) Parallel lines: Two lines in a plane are said to be parallel if they do not meet.

(ii) Line: A line is obtained when a line segment is extended on both sides indefinitely.

(iii) Intersecting lines: Two distinct lines meeting at a point are called intersecting lines.

(iv) Parallel lines: Two lines in a plane are said to be parallel if they do not meet.

Q:

(i) The sum of two integers is – 20. If one integer is 20, find the other integer.

(ii) The sum of two integers is 147. If one integer is – 59, find the other integer.

A:

(i) Sum of two integers = – 20

One integer = 20

Second integer = – 20 – 20

= – 40

(ii) Sum of two integers = 147

One integer = – 59

Second integer = 147 – (– 59)

= 147 + 59

= 206

Q:

A:

Q:

Is this rope sufficient to tie a cloth line between two hooks which are 6 m apart?

A:

Q:

Days | Monday | Tuesday | Wednesday | Thursday | Friday |

Number of Books Sold | 60 | 55 | 50 | 45 | 30 |

A:

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