 # CBSE [ All India ]_X_Mathematics_2009_Set II

To Access the full content, Please Purchase

• Q1

Find the [ HCF x LCM ] for the numbers 105 and 120.

Marks:1

Since,
HCF LCM = Product of numbers

= 105 120

= 12600 HCF LCM = 12600

• Q2

Find the number of solutions of the following pair of linear equations :
x + 2y – 8 = 0
2x + 4y = 16

Marks:1 • Q3

If 4/5, a, 2 are three consecutive terms of an A.P., then find the value of a.

Marks:1 • Q4

Two coins are tossed simultaneously. Find the probability of getting exactly one head.

Marks:1 • Q5

In figure, ABC is circumscribing a circle. Find the length of BC. Marks:1

From the given figure, we have

BP =  BR = 3 cm

CQ = AC - AQ = (11 - 4) cm = 7 cm [ AQ = QR]

Now, BC = BP + PC = (3 + 7) cm = 10 cm [ PC = CQ].

• Q6

If the diameter of a semicircular protractor is 14 cm, then find its perimeter.

Marks:1 • Q7

If 1 is a zero of the polynomial p(x) = ax2 – 3 (a – 1) x –1, then find the value of a.

Marks:1

If 1 is the zero of the polynomial, then
p(1) = 0 p(1) = a(1)2 – 3 (a – 1) 1 –1 = 0 a – 3a + 3 –1 = 0 –2a = –2 a = 1

• Q8 Marks:1 • Q9 Marks:1   