 # CBSE [All India]_X_Mathematics_2011_Set II

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• Q1

The roots of the equation
x2 – 3x –m(m+3)=0, where m is a constant, are

(A)
m,  m+3
(B)    –m,  m+3
(C)            m, - (m+3)
(D)    –m, - (m+3)

Marks:1

(B)    –m, m+3 • Q2

If the common difference of an A.P. is 3, then a20 – a15 is
(A) 5
(B) 3
(C) 15
(D) 20

Marks:1

(C) 15 • Q3

In Figure, O is the centre of a circle, PQ is a chord and PT is the tangent at P. If POQ=70°, then TPQ is equal to (A) 55°
(B) 70°
(C) 45°
(D) 35°

Marks:1

(D) 35° • Q4

In figure, AB and AC are tangents to the circle with centre O such that BAC =40°. Then BOC is equal to (A)
40°
(B)
50°
(C) 140°
(D)
150°

Marks:1

(C) 140° • Q5

The perimeter (in cm) of a square circumscribing a circle of radius a cm is

(A) 8a
(B) 4a
(C) 2a
(D) 16a

Marks:1

(A) 8a • Q6

A tower stands vertically on the ground. From a point on the ground which is 25 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 45°. Then the height (in meters) of the tower is

(A)
25 2

(B)
25 3

(C)
25

(D)
12.5

Marks:1

(C)    25  • Q7

If P(a/2, 4) is the mid-point of the line - segment joining the points A(-6, 5) and B(- 2, 3), then the value of a is

(A)
– 8

(B)
3

(C)
– 4

(D)
4

Marks:1

(A)    – 8 • Q8

If A and B are the points (- 6, 7) and (- 1, - 5) respectively, then the distance 2AB is equal to

(A)   13

(B)   26

(C) 169

(D) 238

Marks:1

(B) 26 • Q9

The surface area of a solid hemisphere of radius r cm (in cm2) is

(A) 2
pr2

(B) 3
pr2

(C) 4
pr2

(D) (2/3)
pr2

Marks:1

(B) 3pr2 • Q10

A card is drawn from a well-shuffled deck of 52 playing cards. The probability that the card is not a red king, is

(A) 1/13

(B) 12/13

(C) 1/26

(D) 25/26

Marks:1 