CBSE [ Delhi ]_X_Mathematics_2006_Set I
To Access the full content, Please Purchase

Q1
Find the sum of all the two digit natural numbers divisible by 4. Marks:3Answer:

Q2
The 6th term of an Arithmetic Progression (AP) is 10 and the 10^{th} term is 26. Determine the 15^{th} term of the AP. Marks:3Answer:

Q3
A household article is available for Rs. 2,500 cash or Rs. 520 cash down payment followed by four equal monthly instalments. If the rate of interest charged under the instalment plan is 25% per annum, find the amount of each instalment. Marks:3Answer:
Now out of Syllabus 
Q4
A man borrows Rs. 36,410 from a finance company and has to repay it in three equal annual installments. Find the amount of each installment if the rate of interest is 10% per annum compounded annually. Marks:3Answer:
Now out of Syllabus 
Q5
Solve for x: 12abx^{2}  (9a^{2}  8b^{2})x  6ab = 0 Marks:3Answer:

Q6
If (x  2) (x + 3) is the HCF of the polynomials P(x) = (x^{2}  3x +2) (2x^{2} + 7x + a) and
Q(x) = (x^{2} + 4x + 3) (3x^{2}  7x + b).
Find the values of a and b.Marks:3Answer:
Now Out of syllabus 
Q7
Solve for x and y:
47x + 31y = 63
31x + 47y = 15Marks:3Answer:

Q8
In Figure 3, AB =AC ,Prove that BE = EC Marks:3Answer:
Since tangent from an external point to a circle are equal in length. Therefore AD = AF BD = BE CE = CF Now
AB = AC (given)ABAD = ACAD AB – AD = AC –AF BD = CF BE = CE proved 
Q9
A twodigit number is such that the product of its digits is 35. When 18 is added to the number, the digits interchange their places. Find the number. Marks:3Answer:
Let the unit place digit = x Tens Place digit = y Number = 10y + x On interchanging the digits, the new number = 10x + y y = 35/x According to the question 18 + x + 10y = 10x + y 18 = 9x9y x  y = 2 x – 35/x = 2 
Q10
In Figure 1, ACB = 90° , CD AB, prove that CD^{2} = BD.AD. Marks:3Answer:
In Triangle ACB and Triangle ADC Angle A = angle A ( Same angle) Angle C = angle D ( Both 90 degree) By AA Triangle ACB similar to triangle ADC Similarly Triangle ACB is similar to BDC So triangle ADC is similar to BDC AD/CD = AC/CB = CD/BD AD/CD = CD/BD CD^{2} = BD.AD