 CBSE [All India]-Set-2-2012

To Access the full content, Please Purchase

• Q1

What are the directions of electric and magnetic field vectors relative to each other and relative to the direction of propagation of electromagnetic waves?

Marks:1 • Q2

Two wires of equal length, one of copper and the other of manganin have the same resistance. Which wire is thicker?

Marks:1

We know that, Thus, manganin is thicker.

• Q3

A bar magnet is moved in the direction indicated by the arrow between two coils PQ and CD. Predict the directions of induced current in each coil. Marks:1

The direction of induced current will be clockwise in both the coils. In first coil, the direction of induced current is from P to Q and in the second coil the direction is from C to D.

• Q4

For the same value of angle of incidence, the angles of refraction in three media A, B  and C are 15°, 25° and 35° respectively. In which medium would the velocity of light be minimum?

Marks:1 Therefore, velocity of light is minimum in medium ‘A’.

• Q5

A proton and an electron have same kinetic energy. Which one has a greater de-Broglie wavelength and why?

Marks:1 • Q6

Mention the two characteristic properties of the material suitable for making core of transformer?

Marks:1

Two characteristic properties of the material suitable for making core of transformer are:
(i) It should have low coercivity and low retentivity.
(ii) It should have a smaller hysteresis loop.

• Q7

A charge ‘q’ is placed at the centre of a cube of side l. What is the electric flux passing through each face of the cube?

Marks:1 • Q8

In a single-slit diffraction experiment, the width of the slit is made double the original width. How does this affect the size and intensity of the central diffraction band?

Marks:1

On doubling the width of the slit, the size of the    central maximum will become half and the intensity becomes four times.

• Q9

An electric dipole is held in a uniform electric field.
(i) Show that the net force acting on it is zero.
(ii) The dipole is aligned parallel to the field. Find the work done in rotating it through an angle of 180°.

Marks:2

(i) (ii)
W = change in potential energy
= Ufinal – Uinitial
= (–pE cos180°) – (–pE cos0°)
= 2pE