Trigonometric Equations

There is no content available!

To Access the full content, Please Purchase

  • Q1

    The value of y for which the equation sin4x + cos4x + sin2x + y = 0 may be valid, if

    Marks:1
    Answer:

    - 3/2 y 1/2.

    Explanation:

    sin4x + cos4x + sin2x + y = 0

    (sin2x)2 + (cos2x)2 + 2 sin2x cos2x – 2sin2x cos2x + sin2x + y= 0

    sin22x – 2sin2x – 2 – 2y = 0

     

    View Answer
  • Q2

    General solution of satisfying the equation is

    Marks:1
    Answer:

    = n or = n /3.

    Explanation:

    View Answer
  • Q3

    Marks:1
    Answer:

    Explanation:

    View Answer
  • Q4

    Marks:1
    Answer:

    Explanation:

    View Answer
  • Q5

    Solution of the equation 4sin4x + cos4x = 1 is

    Marks:1
    Answer:

    x = 2ncos–1(3/5).

    Explanation:

    We have 4 sin4x + cos4x = 1

    4(1 – cos2x)2 + cos4x = 1

    5 cos4x – 8 cos2x + 3 = 0

    (cos2x – 1) (5cos2x – 3) = 0

    if 5cos2x = 3, cos2x = 3/5

    cos x = + (3/5)

    Therefore,

    x= 2ncos -1(3/5)

     

    View Answer