Oxygen and its Compounds

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  • Q1

    The oxidation state of sulphur in S8, H2S and S2F2 respectively are

    Marks:1
    Answer:

    0, -2 and +1

    Explanation:

    The oxidation state of any element in uncombined state is zero. Thus, the oxidation state of sulphur in S8 is zero.

    Oxidation number of S in H2S:
    Let oxidation number of S is x
    (2 × 1) + x = 0
    x = -2
    Thus, the oxidation state of sulphur in H2S is -2.

    Oxidation number of S in S2F2:
    Let oxidation number of S is x
    (2 × x) + ( 2 -1) = 0
    x = 1
    Thus, the oxidation state of sulphur in S2F2 is +1.

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  • Q2

    The number of P-O-P bonds (linkages) in cyclic metaphosphoric acid are

    Marks:1
    Answer:

    three.

    Explanation:

    Cyclic metaphosphoric acid (HPO3)3  has three P-O-P bonds.

     

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  • Q3

    Nitrogen forms five oxides.The oxidation state of nitrogen in these oxides ranges from

    Marks:1
    Answer:

    +1 to +5.

    Explanation:

    The oxides of nitrogen are N2O(+1 oxidation state), NO(+2 oxidation state) , N2O3(+3 oxidation state) , N2O4 (+4 oxidation state) and N2O5(+5 oxidation state) .

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  • Q4

    In nitrate ion, the number of bond pairs and lone pairs of electron respectively on N atom are

    Marks:1
    Answer:

    4, 0.

    Explanation:
     
    The number of bond pairs = 4
    Number of lone pairs = 0.
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  • Q5

    Name two forms of black phosphorus and how are they different from each other?

    Marks:2
    Answer:

    The two forms of phosphorus are α-black phosphorus and β- black phosphorus. The former can be sublimed in air while the latter can not be burned in air even up to 673 K.

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