 # Oxygen and its Compounds

## There is no content available!

To Access the full content, Please Purchase

• Q1

The oxidation state of sulphur in S8, H2S and S2F2 respectively are

Marks:1

0, -2 and +1

##### Explanation:

The oxidation state of any element in uncombined state is zero. Thus, the oxidation state of sulphur in S8 is zero.

Oxidation number of S in H2S:
Let oxidation number of S is x
(2 × 1) + x = 0
x = -2
Thus, the oxidation state of sulphur in H2S is -2.

Oxidation number of S in S2F2:
Let oxidation number of S is x
(2 × x) + ( 2 -1) = 0
x = 1
Thus, the oxidation state of sulphur in S2F2 is +1.

• Q2

The number of P-O-P bonds (linkages) in cyclic metaphosphoric acid are

Marks:1

three.

##### Explanation: Cyclic metaphosphoric acid (HPO3)3  has three P-O-P bonds.

• Q3

Nitrogen forms five oxides.The oxidation state of nitrogen in these oxides ranges from

Marks:1

+1 to +5.

##### Explanation:

The oxides of nitrogen are N2O(+1 oxidation state), NO(+2 oxidation state) , N2O3(+3 oxidation state) , N2O4 (+4 oxidation state) and N2O5(+5 oxidation state) .

• Q4

In nitrate ion, the number of bond pairs and lone pairs of electron respectively on N atom are

Marks:1

4, 0.

##### Explanation: The number of bond pairs = 4
Number of lone pairs = 0.