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Equations of Plane in Different Forms
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Q1Marks:1
Answer:
Explanation:

Q2
The foot of perpendicular from (a, b, c) on the line x = y = z is the point (r, r, r) where
Marks:1Answer:
3r = a + b + c.
Explanation:

Q3
The equation of the plane which passes through the points (2, 3, –4) and (1, –1, 3) and parallel to xaxis is
Marks:1Answer:
7y + 4z – 5 = 0.
Explanation:
Equation of the plane parallel to xaxis is
by + cz + d = 0Since it passes through the points (2, 3, 4) and (1, 1, 3)
3b  4c + d = 0 and b + 3c + d = 0

Q4
The equation of the plane passing through (1, 0, 0), (0, 1, 0)
and (0, 0, 1) isMarks:1Answer:
x + y + z = 1.
Explanation:
Since plane passes through (1, 0, 0), (0, 1, 0) and (0, 0, 1), therefore,
it makes equal intercepts on x, y and zaxes, i.e.,1.
Hence its equation is x/1 +y/1 +z/1 = 1 or x+y+z=1

Q5
The intercept form of the plane x+3y4z=12 is
Marks:1Answer:
Explanation: