Substitution

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  • Q1

    If p = 1, q= 2 and r = 3, then the value of
    2p2q – 6pq + pq2r is

    Marks:1
    Answer:

    4.

    Explanation:
    Putting p = 1, q = 2 and r = 3 in 2p2q – 6pq + pq2r, we get
    2p2q – 6pq + pq2r = 2(1)2(2) – 6(1)(2) + (1)(2)2(3)
                                  = 4 – 12 + 12
                                  = 4.
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  • Q2

    If a = 0, b= 2 and c = 1, then the value of
    2a2b – 3bc2 + 4b2 is

    Marks:1
    Answer:

    10.

    Explanation:
    Putting a = 0, b = 2 and c = 1 in 2a2b – 3bc2 + 4b2, we get
              2(0)2(2) – 3(2)(1)2 + 4(2)2
              = 0 – 6 + 16 = 10.   
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  • Q3

    If a = 3, b = 2 and k = 7, What is the value of 5a3 - 2b2 - k - 5?

    Marks:1
    Answer:

    115

    Explanation:

    5a3 – 2b2 – k – 5
    Putting the values of a , b and k in the given expression, we get
    = 5 × 3 × 3 × 3 – 2 × 2 × 2 – 7 – 5
    = 135 – 8 – 12
    = 135 – 20
    = 115

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  • Q4

    If x = 1 and y = 2, then the value of x2y + x2y2 – xy2 is

    Marks:1
    Answer:

    2

    Explanation:

    Putting x = 1 and y = 2 in x2y + x2y2 – xy2, we get

    (1)2(2) + (1)2(2)2 – (1)(2)2

    = 2 + 4 – 4

    = 2

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  • Q5

    If the value of t = 4, then the value of 5t + 4 is

    Marks:1
    Answer:

    24.

    Explanation:
    The value of 5t + 4 is given by: 5(4) + 4 = 20 + 4 = 24, as t = 4.
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