## There is no content available!

To Access the full content, Please Purchase

• Q1

In a parallelogram ABCD. The bisector of A and B meet at O. Measurement of AOB is...

Marks:1

90o.

##### Explanation:

We know that adjacent angles are supplementary in a parallelogram.
Therefore, A + B = 180o ...(1)
Ondividing both sides by '2' we get
OAB + ABO = 90o ...(2)
In triangle AOB,
OAB + ABO + AOB = 180o
i.e., AOB = 90o.

• Q2

In the given figure, ABCD is a parallelogram. Then the angle measures x, y and z are

Marks:1

130o, 20o and 30o.

##### Explanation:

ABCD is gram.

ABC + CBE = 180

ABC = 180 - 50 = 130

ABC = ADC = x = 130

DAC + CAB = CBE

z = CAB = 50 - DAC = 50 - 20 = 30

CAB + ABC + ACB = 180

30 + 130 + ACB = 180

ACB = 180- 160 = 20

y = 20

x = 130, y = 20, z = 30

• Q3

Which of the following statement is false in the following statements?

Marks:1

The adjacent angles in a parallelogram are complementary.

##### Explanation:

We know that “The adjacent angles in a parallelogram are supplementary”.

• Q4

The value of the variable x and y in the given kite are respectively

Marks:1

5 and 9.

##### Explanation:

As ABCD is a kite,

2y + 4 = 3Y – 5

y = 9

Again, 2x + 5 = y + 6           (AB = AD)

x = 5

Therefore, x = 5 and y = 9.

• Q5

In given figure, if ∠ADE = ∠ABC, then quadrilateral BCED is a

Marks:1