Types of Quadrilaterals
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Q1
In a parallelogram ABCD. The bisector of ∠A and ∠B meet at O. Measurement of ∠AOB is...
Marks:1Answer:
90^{o}.
Explanation:
We know that adjacent angles are supplementary in a parallelogram.
Therefore, A + B = 180^{o} ...(1)
Ondividing both sides by '2' we get
OAB + ABO = 90^{o} ...(2)
In triangle AOB,
OAB + ABO + AOB = 180^{o}
i.e., AOB = 90^{o}. 
Q2
In the given figure, ABCD is a parallelogram. Then the angle measures x, y and z are
Marks:1Answer:
130^{o}, 20^{o} and 30^{o}.
Explanation:
ABCD is gram.ABC + CBE = 180^{}
ABC = 180^{ } 50^{ }= 130^{}
ABC = ADC = x = 130^{}
DAC + CAB = CBE
z = CAB = 50^{}  DAC = 50^{ } 20^{ }= 30^{}
CAB + ABC + ACB = 180^{}
30^{ }+ 130^{ + } ACB = 180^{}
ACB = 180^{} 160^{ }= 20^{}
y = 20^{}
x =^{ }130^{}, y^{ }=^{ }20^{}, z = 30^{}

Q3
Which of the following statement is false in the following statements?
Marks:1Answer:
The adjacent angles in a parallelogram are complementary.
Explanation:
We know that “The adjacent angles in a parallelogram are supplementary”.

Q4
The value of the variable x and y in the given kite are respectively
Marks:1Answer:
5 and 9.
Explanation:
As ABCD is a kite,
BC = AD
2y + 4 = 3Y – 5
y = 9
Again, 2x + 5 = y + 6 (AB = AD)
x = 5
Therefore, x = 5 and y = 9.

Q5
In given figure, if ∠ADE = ∠ABC, then quadrilateral BCED is a
Marks:1Answer:
trapezium.
Explanation:
If ADE = ABC, then DE  BC
So, quadrilateral BCED is a trapezium.