Surface Area and Volume of 3D Solids
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Q1
What is the surface area of a cuboidshaped box whose length, breadth and height are 16 cm, 8 cm, and 6 cm respectively?
Marks:1Answer:
544 cm^{2}
Explanation:
Total surface area of the box = 2(16 8 + 8 6 + 6 16) = 544 cm^{2}

Q2
The length of cold storage is double its breadth. If its height is 3 m and the area of its four walls is 108 m^{2}, then its length and breadth are:
Marks:1Answer:
12 m and 6 m respectively
Explanation:

Q3
If each edge of a cube is 40 cm long, then its surface area (in inches) is (Use 2.5 cm = 1 inch)
Marks:1Answer:
1536 inches^{2}
Explanation:

Q4
The sum of the length, breadth and depth of a cuboid is 19 cm and its diagonal is 5√5 cm. Its surface area (in cm^{2}) is
Marks:1Answer:
236 cm^{2}
Explanation:
Let x cm, y cm and z cm be the length, breadth and depth of a cuboid respectively.
Therefore,
x + y + z = 19
x^{2} + y^{2} + z^{2} = (5√5)^{2}
= 125.
Surface area of the cuboid
= 2(xy + yz + zx)
= (x + y + z )^{2 } (x^{2} + y^{2} + z^{2})
= 361 – 125
= 236 cm^{2} 
Q5
The total surface area of a cube whose side is 0.5 cm is
Marks:1Answer:
(3/2) cm^{2}
Explanation:
Surface area of a cube of side 0.5 cm
= 6 x (0.5)^{2}
= 6 x 0.25
= 1.50
= (3/2) cm^{2}