Another Peek Beyond the Point explains how decimals behave when students multiply, divide, compare, and use them in real-life calculations. The chapter shows why decimal placement matters in money, distance, area, speed, measurement, and calendar-based questions.
Important Questions Class 7 Maths Part 2 Chapter 4 help students practise Another Peek Beyond the Point through solved examples and exam-style questions. This chapter continues decimal learning from earlier chapters, but now students work with decimal multiplication, decimal division, decimal quotients, decimal divisors, and non-ending decimals.
The chapter uses everyday situations such as buying pens, measuring ribbon, calculating cloth length, finding petrol mileage, stacking coins, and understanding leap years. A single decimal point error can change rupees, kilometres, metres, weights, or time, so students must learn each step carefully.
Key Takeaways
| Topic |
What Students Should Remember |
| Decimal recap |
Decimals extend the Indian place value system |
| Decimal multiplication |
Multiply like whole numbers, then place the decimal |
| Division by 10, 100, 1000 |
Move the decimal point left |
| Decimal quotient |
Long division can continue after the ones place |
| Decimal divisor |
Convert the divisor into a whole number first |
| Non-ending decimals |
Some divisions repeat and do not end |
| Word problems |
Read the unit before choosing the operation |
| Leap year rules |
Decimal multiplication explains calendar correction |
Class 7 Maths Part 2 Chapter 4 Important Questions on Decimal Recap
Class 7 Maths Part 2 Chapter 4 important questions begin with decimal place value. Students should revise tenths, hundredths, thousandths, and decimal shifting before solving multiplication and division questions.
Important Questions Class 7 Maths Part 2 Chapter 4: Very Short Answers
Q1. What is the name of Class 7 Maths Part 2 Chapter 4in the uploaded book content?
Class 7 Maths Part 2 Chapter 4 is based on Another Peek Beyond the Point.
The chapter focuses on decimal multiplication, decimal division, long division, decimal divisors, and decimal applications.
Q2. What does 27.53 mean in place value?
27.53 means 2 tens, 7 ones, 5 tenths, and 3 hundredths.
So, 27.53 = 20 + 7 + 0.5 + 0.03.
Q3. Write 254/1000 as a decimal.
254/1000 = 0.254.
The digit 2 is in the tenths place, 5 is in the hundredths place, and 4 is in the thousandths place.
Q4. Write 847/10000 as a decimal.
847/10000 = 0.0847.
The denominator has four zeroes, so the decimal has four places.
Q5. What happens when we divide a number by 10?
The decimal point moves one place to the left.
For example, 123 ÷ 10 = 12.3.
Q6. What happens when we divide a number by 1000?
The decimal point moves three places to the left.
For example, 678 ÷ 1000 = 0.678.
Decimal Multiplication Class 7 Questions
Decimal multiplication class 7 questions test whether students can place the decimal point correctly. The chapter explains this through money, distance, cloth, area, coins, and measurement examples.
Multiplying Decimals Class 7 Solved Questions
Q1. Arshad buys 5 pens. One pen costs ₹9.5. How much should he pay?
Arshad should pay ₹47.5.
9.5 × 5 = 47.5.
This is the same as adding ₹9.5 five times.
Q2. A car travels 12.5 km per litre. How far will it travel with 7.5 litres?
The car will travel 93.75 km.
12.5 × 7.5 = 93.75.
First calculate 125 × 75 = 9375. Since there are two decimal places, the product is 93.75.
Q3. Ajay’s school is 827 m from home. He walks to school and back for 6 days. How much does he walk in a week?
Ajay walks 9.924 km in a week.
827 m = 0.827 km.
One day’s walking = 0.827 × 2 = 1.654 km.
Six days’ walking = 1.654 × 6 = 9.924 km.
Q4. Find the area of a rectangle with length 13.3 cm and breadth 5.7 cm.
The area is 75.81 sq cm.
Area = length × breadth.
13.3 × 5.7 = 75.81.
Q5. If 596 × 248 = 147808, find 5.96 × 24.8.
5.96 × 24.8 = 147.808.
The numbers have 2 decimal places and 1 decimal place. So, the product has 3 decimal places.
Decimal Multiplication Rules and Practice
Multiplying decimals class 7 questions become easier when students separate calculation from decimal placement. First multiply like whole numbers, then count decimal places.
Step-by-Step Decimal Multiplication Questions
Q1. Find 5.8 × 1.24.
5.8 × 1.24 = 7.192.
First multiply 58 × 124 = 7192.
The numbers 5.8 and 1.24 have 3 decimal places in all, so the answer is 7.192.
Q2. Find 27.34 × 6.
27.34 × 6 = 164.04.
2734 × 6 = 16404.
Since 27.34 has two decimal places, the product is 164.04.
Q3. Find 4.23 × 3.7.
4.23 × 3.7 = 15.651.
423 × 37 = 15651.
There are three decimal places in all, so the answer is 15.651.
Q4. Find 0.432 × 0.23.
0.432 × 0.23 = 0.09936.
432 × 23 = 9936.
There are five decimal places in all, so the answer is 0.09936.
Q5. Thejus needs 1.65 m cloth for one shirt. How much cloth is needed for 3 shirts?
Thejus needs 4.95 m cloth.
1.65 × 3 = 4.95.
Decimal Multiplication Word Problems Class 7
Decimal multiplication word problems class 7 questions usually involve money, length, height, weight, distance, or area. Students should always check the unit before writing the final answer.
Word Problems with Explained Answers
Q1. Meenu bought 4 notebooks and 3 erasers. Each notebook costs ₹15.50 and each eraser costs ₹2.75. How much did she spend?
Meenu spent ₹70.25.
Cost of notebooks = 4 × 15.50 = ₹62.00.
Cost of erasers = 3 × 2.75 = ₹8.25.
Total cost = 62.00 + 8.25 = ₹70.25.
Q2. The thickness of one rupee coin is 1.45 mm. Find the height of 36 coins stacked together in centimetres.
The height is 5.22 cm.
Height in mm = 1.45 × 36 = 52.2 mm.
Since 10 mm = 1 cm, 52.2 mm = 5.22 cm.
Q3. The price of 1 kg oranges is ₹56.50. Find the cost of 2.250 kg oranges.
The cost is ₹127.125.
56.50 × 2.250 = 127.125.
We can write 56.50 as 56.5 and 2.250 as 2.25.
Q4. Dwarakanath buys notebooks at ₹23.6 each and sells each at ₹30. He sells 50 notebooks. Find his profit.
His profit is ₹320.
Profit on one notebook = 30 - 23.6 = ₹6.4.
Profit on 50 notebooks = 6.4 × 50 = ₹320.
Q5. Given 18 × 12 = 216, find 0.18 × 0.12.
0.18 × 0.12 = 0.0216.
The two numbers have four decimal places in all. So, 216 becomes 0.0216.
Decimal Division Class 7 Questions
Decimal division class 7 questions focus on sharing, cutting, grouping, and finding one-unit value. This chapter includes division by 10, 100, 1000, whole numbers, and decimal divisors.
Division by 10, 100 and 1000
Q1. Anuja has 3.9 m ribbon and cuts it into 10 equal pieces. Find each piece.
Each piece is 0.39 m.
3.9 ÷ 10 = 0.39.
The decimal point moves one place to the left.
Q2. What is 3.9 ÷ 100?
3.9 ÷ 100 = 0.039.
The decimal point moves two places to the left.
Q3. Find 18.7 ÷ 10, 18.7 ÷ 100, and 18.7 ÷ 1000.
18.7 ÷ 10 = 1.87.
18.7 ÷ 100 = 0.187.
18.7 ÷ 1000 = 0.0187.
Q4. What is 21.1 ÷ 100?
21.1 ÷ 100 = 0.211.
Move the decimal point two places to the left.
Q5. What is 0.0058 ÷ 10?
0.0058 ÷ 10 = 0.00058.
A zero is added when there are not enough digits on the left.
Decimal Quotient Class 7 Long Division Questions
Decimal quotient class 7 questions show that long division can continue beyond the ones place. Students regroup ones into tenths, tenths into hundredths, and hundredths into thousandths.
Long Division Decimals Class 7 Questions
Q1. Find 29 ÷ 2.
29 ÷ 2 = 14.5.
Each person gets 14 m first. The remaining 1 m becomes 10 tenths. Half of 10 tenths is 5 tenths, so the answer is 14.5.
Q2. Find 29 ÷ 4.
29 ÷ 4 = 7.25.
29/4 can be changed into 725/100. So, the decimal quotient is 7.25.
Q3. Find 1325 ÷ 4.
1325 ÷ 4 = 331.25.
After dividing the whole number part, the remaining 1 one becomes 10 tenths. Then 2 tenths remain and become 20 hundredths.
Q4. Find 237 ÷ 8.
237 ÷ 8 = 29.625.
The quotient continues after the decimal point because some ones remain after whole-number division.
Q5. A shopkeeper packs 9.5 kg sugar equally in 4 bags. Find the weight of each bag.
Each bag weighs 2.375 kg.
9.5 ÷ 4 = 2.375.
Decimal Divisor Class 7 Questions
Decimal divisor class 7 questions are important because students often get confused when the divisor has a decimal point. Convert the divisor into a whole number by multiplying both numbers by the same power of 10.
Division by Decimal Divisors
Q1. Ravi travels 126 km in 2.5 hours. Find his average speed.
Ravi’s average speed is 50.4 km per hour.
Average speed = 126 ÷ 2.5.
Multiply both numbers by 10: 1260 ÷ 25 = 50.4.
Q2. Find 4.68 ÷ 1.3.
4.68 ÷ 1.3 = 3.6.
Multiply both numbers by 10.
46.8 ÷ 13 = 3.6.
Q3. Find 4.68 ÷ 0.13.
4.68 ÷ 0.13 = 36.
Multiply both numbers by 100.
468 ÷ 13 = 36.
Q4. Find 2.46 ÷ 1.5.
2.46 ÷ 1.5 = 1.64.
Multiply both numbers by 10.
24.6 ÷ 15 = 1.64.
Q5. Find 2.46 ÷ 0.15.
2.46 ÷ 0.15 = 16.4.
Multiply both numbers by 100.
246 ÷ 15 = 16.4.
How to Choose Multiplication or Division in Decimal Word Problems
Students often make mistakes because they choose the operation too quickly. The words in the question usually show whether the problem needs multiplication or division.
Use multiplication when one unit value is repeated many times. For example, “one pen costs ₹9.5, find the cost of 5 pens” needs multiplication.
Use division when a total quantity is shared, cut, grouped, or used to find one-unit value. For example, “3.9 m ribbon is cut into 10 equal pieces” needs division.
When a divisor has a decimal point, first convert it into a whole number. This keeps the long division cleaner.
Class 7 Decimals Questions and Answers from Real-Life Situations
Class 7 decimals questions and answers from this chapter use measurement, price comparison, regular polygons, juice sharing, petrol use, and flour distribution. These questions test both operation choice and unit conversion.
Application-Based Decimal Questions
Q1. A 4 m wooden block is cut into 5 equal pieces. Find the length of each piece.
Each piece is 0.8 m.
4 ÷ 5 = 0.8.
Q2. The perimeter of a regular polygon with 12 sides is 208.8 cm. Find each side.
Each side is 17.4 cm.
208.8 ÷ 12 = 17.4.
Q3. 3 litres of watermelon juice is shared equally among 8 friends. How much does each get in millilitres?
Each friend gets 375 ml.
3 litres = 3000 ml.
3000 ÷ 8 = 375 ml.
Q4. A car covers 234.45 km using 12.6 litres of petrol. Find the distance travelled per litre.
The car travels 18.607142... km per litre.
234.45 ÷ 12.6 gives a non-ending decimal. Students may round the answer based on the question’s instruction.
Q5. 13.5 kg flour is distributed equally among 15 students. How much flour does each student receive?
Each student receives 0.9 kg flour.
13.5 ÷ 15 = 0.9.
Leap Year Decimal Questions Class 7
Leap year decimal questions make this chapter different from a regular decimals chapter. The book uses 365.2422 days to explain why calendars need leap-year corrections.
Leap Year Questions with Answers
Q1. Why is a calendar year not exactly equal to Earth’s revolution time?
A calendar year has 365 days, but Earth takes about 365.2422 days to go around the Sun.
The extra 0.2422 day builds up over many years.
Q2. How many extra days build up after 100 years if we use only 365 days per year?
24.22 extra days build up after 100 years.
0.2422 × 100 = 24.22 days.
Q3. Why do we add one day every 4 years?
We add one day every 4 years because 0.2422 day is close to one-fourth of a day.
After 4 years, the extra time is close to 1 day.
Q4. Why is every 100th year usually not a leap year?
Every 100th year is usually not a leap year because adding one day every 4 years overcompensates.
In 100 years, this system gives 36,525 calendar days, while Earth needs about 36,524.22 days.
Q5. Why is every 400th year a leap year?
Every 400th year is a leap year to reduce the long-term calendar error.
This correction makes the calendar closer to Earth’s actual revolution time.
Class 7 Maths Part 2 Chapter 4 Extra Questions
Class 7 Maths Part 2 Chapter 4 extra questions help students practise mixed decimal operations. These questions follow the decimal multiplication and division ideas from the chapter.
Ganita Prakash Class 7 Part 2 Chapter 4 Questions
Q1. Find 15.6 × 1.2 using 156 × 12 = 1872.
15.6 × 1.2 = 18.72.
There are two decimal places in all.
Q2. Find 187.2 ÷ 1.2.
187.2 ÷ 1.2 = 156.
Multiply both numbers by 10.
1872 ÷ 12 = 156.
Q3. Find 18.72 ÷ 15.6.
18.72 ÷ 15.6 = 1.2.
Multiply both numbers by 100.
1872 ÷ 1560 = 1.2.
Q4. Find 0.156 × 0.12.
0.156 × 0.12 = 0.01872.
156 × 12 = 1872.
There are five decimal places in all.
Q5. Find 25 ÷ 1000.
25 ÷ 1000 = 0.025.
The decimal point moves three places to the left.
Q6. Find 25 ÷ 0.10.
25 ÷ 0.10 = 250.
Dividing by 0.10 is the same as multiplying by 10.
Q7. Find 24.86 ÷ 1.2.
24.86 ÷ 1.2 = 20.7166...
This quotient does not end quickly. Students should follow the rounding instruction if given.
Q8. Find 5.728 ÷ 1.52.
5.728 ÷ 1.52 = 3.768421...
This is another decimal quotient where division may continue.
Another Peek Beyond the Point Class 7 Worksheet Questions
This worksheet-style section helps students revise the chapter after reading the solved questions. Try solving these first, then check the answers.
Practice Set
Q1. Find 6 × 0.4.
Answer: 2.4.
Q2. Find 7 × 0.3.
Answer: 2.1.
Q3. Find 9 × 0.05.
Answer: 0.45.
Q4. Find 23.02 × 100.
Answer: 2302.
Q5. Find 0.306 × 1000.
Answer: 306.
Q6. Find 13.2 ÷ 4.
Answer: 3.3.
Q7. Find 1.32 ÷ 4.
Answer: 0.33.
Q8. Find 0.132 ÷ 4.
Answer: 0.033.
Q9. Find 12.6 ÷ 8.
Answer: 1.575.
Q10. Find 0.0126 ÷ 8.
Answer: 0.001575.
Decimals Class 7 MCQ for Quick Revision
MCQs help students check decimal rules quickly. These questions test decimal placement, division rules, and operation choice.
MCQs with Answers
Q1. What is 6 × 0.4?
(a) 0.24
(b) 2.4
(c) 24
(d) 0.024
Answer: (b) 2.4.
6 × 4 tenths = 24 tenths = 2.4.
Q2. What is 18.7 ÷ 100?
(a) 187
(b) 1.87
(c) 0.187
(d) 0.0187
Answer: (c) 0.187.
Dividing by 100 moves the decimal point two places left.
Q3. What is the first step in 4.68 ÷ 1.3?
(a) Add the decimals
(b) Multiply both numbers by 10
(c) Multiply both numbers by 1000
(d) Remove only the dividend decimal
Answer: (b) Multiply both numbers by 10.
This changes 1.3 into 13.
Q4. Which quotient may not end?
(a) 29 ÷ 2
(b) 29 ÷ 4
(c) 10 ÷ 3
(d) 1325 ÷ 4
Answer: (c) 10 ÷ 3.
The quotient 3.333... repeats.
Q5. If 596 × 248 = 147808, what is 5.96 × 24.8?
(a) 14.7808
(b) 147.808
(c) 1478.08
(d) 1.47808
Answer: (b) 147.808.
The factors have three decimal places in all.
Most Important Exam Questions from Class 7 Maths Part 2 Chapter 4
These questions cover the highest-value ideas from the chapter. Students should practise them after learning decimal multiplication and division rules.
High-Value Questions with Explained Answers
Q1. How do you place the decimal point while multiplying decimals?
Count the total number of digits after the decimal point in both factors.
Multiply the numbers without decimal points first. Then place the decimal point in the product so it has the same total decimal places.
Q2. Why does 0.25 × 0.8 give a product smaller than both numbers?
Both 0.25 and 0.8 are between 0 and 1.
Multiplying by a number between 0 and 1 gives part of the other number. So, 0.25 × 0.8 = 0.2.
Q3. Why can 128 ÷ 0.4 be greater than 128?
Dividing by 0.4 means finding how many groups of 0.4 fit into 128.
Since 0.4 is less than 1, many such groups fit into 128. So, 128 ÷ 0.4 = 320.
Q4. Why do some decimal divisions never end?
Some decimal divisions never end because the remainder keeps repeating.
For example, 10 ÷ 3 gives 3.333... because the remainder repeats at every step.
Q5. What is special about 1 ÷ 7?
1 ÷ 7 gives 0.142857142857...
The block 142857 repeats. The book also shows how this repeating block has a cyclic pattern when multiplied by numbers from 1 to 6.
CBSE Class 7 Maths Important Links