NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals (EX 2.7) Exercise 2.7

The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, for Class 7 Mathematics are available for students to practice Decimal Division for examinations. The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, are one of the most effective learning materials for exam preparation. The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, are made up of seven probing questions, all of which have simple answers.

The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, can be used by students to address practical problems on Decimal Division using Whole Numbers and Decimal Numbers. With the review of complex Arithmetic topics described in the summary, students may easily grasp the full chapter.

By using the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, students can comprehend the full idea of Fractions and Decimals. Students can quickly master the concepts of dividing Whole Numbers by Decimals and Dividing Decimals by Decimals with consistent and persistent practice with every question. With the help of NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, students can easily study and excel in examinations.

Students will command the step-by-step method for Decimal Division by using the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7. The majority of the questions in Class 7 Maths Exercise 2.7 are produced by subject-matter experts. This is why students should use the Class 7 Maths Chapter 2 Exercise 2.7 Solutions to learn and study.

Extramarks offers the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7 (in line with the CBSE curriculum) for all courses to provide students with a competitive advantage throughout their preparation. The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, can be the most useful resource for boosting exam preparation for those who want to achieve better than expected. For the best results, students should refer to solutions like the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7 to answer all of the questions from the exercises.

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals (EX 2.7) Exercise 2.7 

Mathematics might be challenging, but when well prepared, it can also be a very well-scored subject. Extramarks’ NCERT Solutions for Class 7 Mathematics would be extremely beneficial to those who are suffering with any particular Mathematical topic or question. The NCERT Class 7 Mathematics solutions can be relied upon as they have been correctly developed and organised by subject specialists with years of experience. The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, are designed to provide students with a step-by-step approach for handling challenging Mathematics problems and to assist them in finding answers to their concerns. Students can use the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, to review the entire curriculum and improve their scores.

NCERT Maths Solution Class 7 Chapter 2 Exercise 2.7 – A Closer Look.

Decimals and fractions serve as the foundation for learning the principles of representing certain Mathematical information with the greatest accuracy feasible. Simply explained, a fraction is a component of something larger, but a decimal is the smallest portion of something mostly uncountable.

Although these images are frequently seen in daily lives, they are not paid much attention to. When Data such as Money, Fluid Amount, Weight, and so on are not complete, they can be represented using Fractions and Decimals. Students can master this chapter by studying with the help of NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7.

This chapter’s major insights for students are as follows:

  • They can be used interchangeably.
  • To convert a Decimal to a Fraction, use the Division Operator.
  • To convert a Fraction to a Decimal, use multiplication.
  • Further calculations will reveal some additional important elements of employing Decimals and Fractions. They are mentioned below:
  • Writing many sorts of Fractions, Including Proper, Improper, and Mixed Fractions.
  • Understanding Decimal Numbers (after the decimal).
  • Fractional Reciprocity.
  • Addition, Multiplication, Subtraction, and Division are Examples of Fraction and Decimal Operations.
  • Operations with Fractional Reciprocals

As a result, reading through the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, will help students obtain insight into such ideas. In addition, to help students comprehend NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, experts have used plain language throughout the explanations. As a result, students can build a good grasp of the subject and ace even the most difficult test questions. Students can also download these study resources on their devices for future use. It will be beneficial to them in the following ways:

  • They can modify the formulae and shortcut tactics regularly.
  • They can use the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7 to cross-check the answers.
  • They can also learn a different, more easy method for tackling certain numerical problems. Students cannot solve every question in one session. The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7 contains the answers to all of the sums in Class 7 Maths Chapter 2 Exercise 2.7.

NCERT Maths Solution Class 7 Chapter 2 Exercise 2.7 – A Closer Look.

The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, are available on Extramarks’ website in PDF format for offline access. Students may either practice online or download these files to practice various sorts of questions relating to this chapter and earn the highest possible scores in their exams. In previous sessions, students learned Fraction Addition and Subtraction as well as Decimal Addition and Subtraction. Students will cover Fraction Multiplication and Division as well as Decimal Multiplication and Division in this subject. The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, have been produced by subject specialists to assist students with their test preparations.

Fractions and Decimals are covered in the NCERT Class 7 Maths Chapter 2 Exercise 2.7. In previous lessons, students learned about Fractions and Decimals, as well as the Operations of Addition and Subtraction on them. They are now looking at the Operations of Multiplication and Division on Fractions and Decimals.

Similarly, Multiplication of a Fraction by a Whole Number, Division of a Whole Number by a Fraction, Division of a Fraction by a Whole Number, Multiplication of Decimals by 10,100, 100, and so on. Other themes include Decimal Multiplication by a Whole Number, Decimal Multiplication by a Decimal, Decimal Division by 10, 100, 1000, and so on, and Decimal Division by the Whole Number.

Here is a Brief Overview of All These Questions Covered in This Chapter.

Class 7 Maths Chapter 2 Exercise 2.7 – Question 1

Students are given eight brief questions in the first part, and they must use the Division Operator to determine the number. The first term here is a Decimal, and the second term is a full number. Students must understand how to utilise the Division Operator. In the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, Extramarks has offered step-by-step solutions to assist students in building a thorough grasp of the concepts and formulas. Students can use the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, to get a better understanding of these ideas and improve their exam preparation.

NCERT Class 7 Maths Exercise 2.7 – Question 2

The second question is quite similar to the first. They are given seven brief numerical problems to solve using the Division Operator. The only difference between this and the previous question is that the full number here is 10. Students can answer this question using a simple approach found in the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7. When it divides a number with a Decimal by a multiple of 10, it moves the Decimal Place. Students must move that many places to the left of the number containing a Decimal, based on the number of Zeroes in the Divisor.

As previously said, students will discover a Decimal Number in a variety of formats: single or double digits before or after the Decimal. They must use extreme caution while dividing, since even a minor shift in Decimal can result in a false response. As a result, students must ensure that they go through the splitting procedure thoroughly. Students frequently get confused when putting a Decimal point in a number, which is why experts created a step-by-step explanation to help them understand the procedure. The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.7, are very useful when it comes to solving questions.

Class 7 Maths Chapter 2 Exercise 2.7 – Question 3

Question 3 requires the Division Operator to employ a Divisor of 100. The only difference between this and the previous question is that students must divide the provided Decimal figures by 100. They are given six short numerical values, each of which contains one or two digits after or before the Decimals.

When working with Decimal Numbers, the most crucial factor to consider is the Decimal Position. It will be easier to approach a question and progress after they have correctly recognised it. The NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7, will point them in the proper direction for dealing with these hard issues.

As stated in the preceding question, students must shift the Decimal based on the number of zeroes present. If the number is 100, they must move the Decimal two places to the left. However, there is a crucial tip that they should keep in mind. If there is just one digit before the Decimal and students need to move the Decimal two places to the left, put a ‘0’ (zero) before the Decimal. For example, 4.36 must be divided by 100. In this case, the answer is 0.0436.

Class 7 NCERT Maths Solution Chapter 2 Exercise 2.7 – Question 4

In Question 4, students must use the identical approach of shifting the Decimal as in the previous two problems, except that the Divisor is 1000. That means they must move the Decimal three spaces to the left of its current location. Students can use the NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7, to acquire better knowledge and clarity on these concepts. These are conventional answers developed by experts. They are well aware of the grey area where students frequently make mistakes, and they have specifically emphasised such sections. Students will be aware of this in advance, allowing them to avoid making the same mistake in their actual exams.

Students should also use caution when using zero in Decimals. It makes no difference whether students put a zero before or after the Decimal. Placing one or more zeros after the Decimal also does not affect the meaning. Any other zero would result in a different number. For a more in-depth explanation, students must refer to the NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7.

Class 7 Maths Chapter 2 Exercise 2.7 – Question 5

This is the most crucial question in this exercise because it deals solely with Decimal numbers. Both the Dividend and the Divisor are in Decimal here. Only a thorough comprehension of the topic will enable students to gain a good grasp of it.

Both before and after the Decimal, the numbers have one or two digits. During tests, students sometimes struggle with dealing with numbers in Decimal form. As a result, educators recommend that students convert them into Fractions whenever feasible to simplify the calculation.

In addition, the NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7 solutions state that they can convert the division operator to multiplication to make calculations easier. To learn this strategy, students must check the Extramarks study resources before the exam.

NCERT Class 7 Maths Exercise 2.7 – Question 6

This is the final exercise question, and it is a word problem. Students must decide the type of Mathematical operation necessary in this case. They must also comprehend who is to be split by whom.

Students must check out the NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7, for more in-depth insights on word problems. They must comprehend the primary need for using the division procedure. A car that travels 43.2 kilometres on 2.4 litres of gasoline will go less distance with less fuel. Students can solve this using the unitary technique, which requires them to compute the distance for one litre of gasoline before moving on to larger amounts.

Students must access NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7, from the Extramarks website to boost their test preparation. It is also possible to obtain the NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7, using that technique if someone already has the Extramarks application downloaded on their phone. The best aspect of the NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7, is that it can be used both offline and online.

Class 7 Maths NCERT Solutions Chapter 2 Exercise 2.7 – Other Exercises

A quick rundown of all the previous exercises in this chapter has been mentioned below:-

Exercise 2.1

This first exercise is centred on fractions and has eight questions, including numerical and word problems. Students must do the following:

  • To a whole number, add a Fraction.
  • Sort the Fractions in Ascending order.
  • Analyse and demonstrate the characteristics of a magic square.
  • A few word problems based on Fractions using the unitary technique.

To be able to answer the questions, They must be familiar with the unitary technique. For a detailed explanation, see the NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7.

Exercise 2.2

For a thorough explanation of the exercise, students can go through the solutions for exercise 2.2 like the NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7. It will enable students to complete tests more quickly and without making silly mistakes.

Exercise 2.3

The exercise involves Fractions, with some questions focusing on Multiplication. Students can find the explanations for the same in NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7. It will improve their exam preparation and allow them to solve the questions faster during the exams.

Exercise 2.4

This exercise contains four questions, and students will most likely learn about:

  • Calculating the Reciprocal of a Fraction
  • Fractions are divided by a full number and another fraction.

They should be aware that division can be converted into Multiplication for easier computation. Students can learn this approach from the NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7.

Exercise 2.5

This exercise has questions on Decimals and their conversion into single units. There are also a few word problems to assist students to get a thorough grasp of the subject. Students will answer nine questions from this exercise

Students must take reference from NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7 for a more in-depth understanding of Decimals. Experts have naturally explained the topics so that students do not miss out on any important information.

Exercise 2.6

This exercise has five questions focused on Decimal Multiplication. Students can refer to the NCERT Solutions for a thorough understanding of this exercise.

NCERT Solutions for Class 7

When it comes to preparing for the CBSE Class 7 examination and achieving an outstanding result, the NCERT Solutions for Class 7 are important. These solutions were developed by skilled educators and specialists in the area, and they provide authentic and dependable sources of NCERT Solutions for Class 7. The NCERT Solutions for Class 7 give students an advantage in terms of better and faster problem solving as well as easier comprehension of the important ideas and theories covered in the CBSE-mandated Class 7 syllabus.

The solutions available on the Extramarks’ website conform to the CBSE board’s regulations and standards and are up-to-date with the most recent editions of textbooks and syllabuses. NCERT Class 7 Solutions can help students overcome any challenges related to the various subjects presented and can also be used for quick recaps before examinations. The NCERT Class 7 solutions are simple to download and include step-by-step explanations of all of the questions and ideas taught in the CBSE board-prescribed textbooks for Class 7.

The Advantages of NCERT Solutions for Class 7

  • The solutions have been prepared and collated by some of the subject’s professional lecturers and professors, so there is no requirement to questionthe answers’ reliability.
  • The solutions are presented in clear and straightforward language, with easily understandable charts and diagrams, so that students can fully comprehend the subject.
  • The solutions are created to achieve excellent exam scores.
  • The answers are precise and error-free, which increases dependability.

Students will benefit from using the NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7 to improve their theoretical and practical understanding. Every question from Class 7 Maths Chapter 2 Exercise 2.7 is addressed in the NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7, which is easily accessible in PDF format. Along with the solutions, there are hints and pointers. These hints would help in answering the questions. The NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7 are available on Extramarks in PDF format.

Q.1

Find: ( i ) 0.4÷2 ( ii ) 0.35÷5 ( iii ) 2.48÷4 ( iv ) 65.4÷6 ( v ) 651.2÷4 ( vi ) 14.49÷7 ( vii ) 3.96÷4 ( viii )0.80÷5 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaaieqacaWFgbGaa8xAaiaa=5gacaWFKbGa a8NoaaqaamaabmaabaGaa8xAaaGaayjkaiaawMcaaiaa=bcacaWFWa Gaa8Nlaiaa=rdacaWF3dGaa8Nmaiaa=bkacaWFGcGaa8hOaiaa=bka caWFGcGaaCzcamaabmaabaGaa8xAaiaa=LgaaiaawIcacaGLPaaaca WFGaGaa8hmaiaa=5cacaWFZaGaa8xnaiaa=DpacaWF1aGaa8hOaiaa xMaadaqadaqaaiaa=LgacaWFPbGaa8xAaaGaayjkaiaawMcaaiaa=b cacaWFYaGaa8Nlaiaa=rdacaWF4aGaa839aiaa=rdacaWLjaWaaeWa aeaacaWFPbGaa8NDaaGaayjkaiaawMcaaiaa=bcacaWF2aGaa8xnai aa=5cacaWF0aGaa839aiaa=zdaaeaadaqadaqaaiaa=zhaaiaawIca caGLPaaacaWFGaGaa8Nnaiaa=vdacaWFXaGaa8Nlaiaa=jdacaWF3d Gaa8hnaiaaxMaadaqadaqaaiaa=zhacaWFPbaacaGLOaGaayzkaaGa a8hiaiaa=fdacaWF0aGaa8Nlaiaa=rdacaWF5aGaa839aiaa=Ddaca WFGcGaa8hOamaabmaabaGaa8NDaiaa=LgacaWFPbaacaGLOaGaayzk aaGaa8hiaiaa=ndacaWFUaGaa8xoaiaa=zdacaWF3dGaa8hnaiaaxM aadaqadaqaaiaa=zhacaWFPbGaa8xAaiaa=LgaaiaawIcacaGLPaaa caWFWaGaa8Nlaiaa=HdacaWFWaGaa839aiaa=vdaaaaa@97B8@

Ans.

( i ) 0.4÷2 = 0.2 ( ii ) 0.35÷5 = 0.07 ( iii ) 2.48÷4= 0.62 ( iv ) 65.4÷6= 10.9 ( v ) 651.2÷4= 162.8 ( vi ) 14.49÷7 = 2.07 ( vii ) 3.96÷4= 0.99 ( viii )0.80÷5= 0.16 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaadaqadaqaaiaabMgaaiaawIcacaGLPaaa caqGGaGaaGimaiaac6cacaqG0aGaey49aGRaaeOmaiaacckacqGH9a qpdaqjEaqaaiaaicdacaGGUaGaaGOmaaaaaeaacaGGGcWaaeWaaeaa caqGPbGaaeyAaaGaayjkaiaawMcaaiaabccacaaIWaGaaiOlaiaabo dacaqG1aGaey49aGRaaeynaiaacckacqGH9aqpdaqjEaqaaiaaicda caGGUaGaaGimaiaaiEdaaaaabaWaaeWaaeaacaqGPbGaaeyAaiaabM gaaiaawIcacaGLPaaacaqGGaGaaeOmaiaac6cacaqG0aGaaeioaiab gEpa4kaabsdacaqG9aGaaeiiamaaL4babaGaaeimaiaab6cacaqG2a GaaeOmaaaaaeaadaqadaqaaiaabMgacaqG2baacaGLOaGaayzkaaGa aeiiaiaabAdacaqG1aGaaiOlaiaabsdacqGH3daUcaqG2aGaaeypai aabccadaqjEaqaaiaabgdacaqGWaGaaeOlaiaabMdaaaaabaWaaeWa aeaacaqG2baacaGLOaGaayzkaaGaaeiiaiaabAdacaqG1aGaaeymai aac6cacaqGYaGaey49aGRaaeinaiaab2dacaqGGaWaauIhaeaacaqG XaGaaeOnaiaabkdacaqGUaGaaeioaaaaaeaadaqadaqaaiaabAhaca qGPbaacaGLOaGaayzkaaGaaeiiaiaabgdacaqG0aGaaiOlaiaabsda caqG5aGaey49aGRaae4naiaacckacqGH9aqpdaqjEaqaaiaaikdaca GGUaGaaGimaiaaiEdaaaaabaGaaiiOamaabmaabaGaaeODaiaabMga caqGPbaacaGLOaGaayzkaaGaaeiiaiaabodacaGGUaGaaeyoaiaabA dacqGH3daUcaqG0aGaaeypaiaabccadaqjEaqaaiaabcdacaqGUaGa aeyoaiaabMdaaaaabaWaaeWaaeaacaqG2bGaaeyAaiaabMgacaqGPb aacaGLOaGaayzkaaGaaGimaiaac6cacaqG4aGaaGimaiabgEpa4kaa bwdacaqG9aGaaeiiamaaL4babaGaaeimaiaab6cacaqGXaGaaeOnaa aaaaaa@B6C7@

Q.2

Find: ( i ) 4.8÷10 ( ii ) 52.5÷10 ( iii ) 0.7÷10 ( iv ) 33.1÷10 ( v ) 272.23÷10 ( vi ) 0.56÷10 ( vii )3.97÷10 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaaieqacaWFgbGaa8xAaiaa=5gacaWFKbGa a8NoaaqaamaabmaabaGaa8xAaaGaayjkaiaawMcaaiaa=bcacaWF0a Gaa8Nlaiaa=HdacaWF3dGaa8xmaiaa=bdacaWFGcGaa8hOaiaa=bka caWFGcWaaeWaaeaacaWFPbGaa8xAaaGaayjkaiaawMcaaiaa=bcaca WF1aGaa8Nmaiaa=5cacaWF1aGaa839aiaa=fdacaWFWaGaa8hOaiaa =bkacaWFGcGaa8hOaiaa=bkadaqadaqaaiaa=LgacaWFPbGaa8xAaa GaayjkaiaawMcaaiaa=bcacaWFWaGaa8Nlaiaa=DdacaWF3dGaa8xm aiaa=bdacaWLjaGaa8hOamaabmaabaGaa8xAaiaa=zhaaiaawIcaca GLPaaacaWFGaGaa83maiaa=ndacaWFUaGaa8xmaiaa=DpacaWFXaGa a8hmaaqaamaabmaabaGaa8NDaaGaayjkaiaawMcaaiaa=bcacaWFYa Gaa83naiaa=jdacaWFUaGaa8Nmaiaa=ndacaWF3dGaa8xmaiaa=bda caWFGcGaa8hOaiaa=bkadaqadaqaaiaa=zhacaWFPbaacaGLOaGaay zkaaGaa8hiaiaa=bdacaWFUaGaa8xnaiaa=zdacaWF3dGaa8xmaiaa =bdacaWFGcGaa8hOaiaa=bkacaWFGcWaaeWaaeaacaWF2bGaa8xAai aa=LgaaiaawIcacaGLPaaacaWFZaGaa8Nlaiaa=LdacaWF3aGaa839 aiaa=fdacaWFWaaaaaa@9888@

Ans.

( i ) 4.8÷10= 0.48 ( ii ) 52.5÷10 = 5.25 ( iii ) 0.7÷10= 0.07 ( iv ) 33.1÷10= 3.31 ( v ) 272.23÷10= 27.223 ( vi ) 0.56÷10= 0.056 ( vii )3.97÷10= 0.397 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaadaqadaqaaiaabMgaaiaawIcacaGLPaaa caqGGaGaaeinaiaac6cacaqG4aGaey49aGRaaeymaiaaicdacqGH9a qpdaqjEaqaaiaaicdacaGGUaGaaGinaiaaiIdaaaaabaGaaiiOamaa bmaabaGaaeyAaiaabMgaaiaawIcacaGLPaaacaqGGaGaaeynaiaabk dacaGGUaGaaeynaiabgEpa4kaabgdacaaIWaGaaiiOaiabg2da9maa L4babaGaaGynaiaac6cacaaIYaGaaGynaaaaaeaacaGGGcWaaeWaae aacaqGPbGaaeyAaiaabMgaaiaawIcacaGLPaaacaqGGaGaaGimaiaa c6cacaqG3aGaey49aGRaaeymaiaaicdacqGH9aqpdaqjEaqaaiaaic dacaGGUaGaaGimaiaaiEdaaaaabaWaaeWaaeaacaqGPbGaaeODaaGa ayjkaiaawMcaaiaabccacaqGZaGaae4maiaac6cacaqGXaGaey49aG RaaeymaiaaicdacqGH9aqpdaqjEaqaaiaaiodacaGGUaGaaG4maiaa igdaaaaabaWaaeWaaeaacaqG2baacaGLOaGaayzkaaGaaeiiaiaabk dacaqG3aGaaeOmaiaac6cacaqGYaGaae4maiabgEpa4kaabgdacaaI WaGaeyypa0ZaauIhaeaacaaIYaGaaG4naiaac6cacaaIYaGaaGOmai aaiodaaaaabaGaaiiOamaabmaabaGaaeODaiaabMgaaiaawIcacaGL PaaacaqGGaGaaGimaiaac6cacaqG1aGaaeOnaiabgEpa4kaabgdaca aIWaGaeyypa0ZaauIhaeaacaaIWaGaaiOlaiaaicdacaaI1aGaaGOn aaaaaeaacaGGGcWaaeWaaeaacaqG2bGaaeyAaiaabMgaaiaawIcaca GLPaaacaqGZaGaaiOlaiaabMdacaqG3aGaey49aGRaaeymaiaaicda cqGH9aqpdaqjEaqaaiaaicdacaGGUaGaaG4maiaaiMdacaaI3aaaaa aaaa@ACB1@

Q.3

Find: ( i ) 2.7÷100 ( ii ) 0.3÷100 ( iii ) 0.78÷100 ( iv ) 432.6÷100 ( v ) 23.6÷10 0 (vi) 98.53÷100 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaaieqacaWFgbGaa8xAaiaa=5gacaWFKbGa a8NoaaqaamaabmaabaGaa8xAaaGaayjkaiaawMcaaiaa=bcacaWFYa Gaa8Nlaiaa=DdacaWF3dGaa8xmaiaa=bdacaWFWaGaa8hOaiaa=bka caWFGcGaa8hOaiaaxMaadaqadaqaaiaa=LgacaWFPbaacaGLOaGaay zkaaGaa8hiaiaa=bdacaWFUaGaa83maiaa=DpacaWFXaGaa8hmaiaa =bdacaWFGcGaa8hOaiaa=bkacaWFGcGaaCzcaiaaxMaacaWFGcWaae WaaeaacaWFPbGaa8xAaiaa=LgaaiaawIcacaGLPaaacaWFGaGaa8hm aiaa=5cacaWF3aGaa8hoaiaa=DpacaWFXaGaa8hmaiaa=bdaaeaada qadaqaaiaa=LgacaWF2baacaGLOaGaayzkaaGaa8hiaiaa=rdacaWF ZaGaa8Nmaiaa=5cacaWF2aGaa839aiaa=fdacaWFWaGaa8hmaiaa=b kacaWFGcGaaCzcaiaa=bkadaqadaqaaiaa=zhaaiaawIcacaGLPaaa caWFGaGaa8Nmaiaa=ndacaWFUaGaa8Nnaiaa=DpacaWFXaGaa8hmai aa=bkacaWFWaGaaCzcaiaaxMaacaWFOaGaa8NDaiaa=LgacaWFPaGa aGjbVlaa=LdacaWF4aGaa8Nlaiaa=vdacaWFZaGaa839aiaa=fdaca WFWaGaa8hmaaaaaa@9213@

Ans.

( i ) 2.7÷100= 0.027 ( ii ) 0.3÷100 = 0.003 ( iii ) 0.78÷100= 0.0078 ( iv ) 432.6÷100 = 4.326 ( v ) 23.6÷10 0= 0.236 (vi) 98.53÷100= 0.9853 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaadaqadaqaaiaabMgaaiaawIcacaGLPaaa caqGGaGaaeOmaiaac6cacaqG3aGaey49aGRaaeymaiaabcdacaaIWa Gaeyypa0ZaauIhaeaacaaIWaGaaiOlaiaaicdacaaIYaGaaG4naaaa aeaadaqadaqaaiaabMgacaqGPbaacaGLOaGaayzkaaGaaeiiaiaaic dacaGGUaGaaG4maiabgEpa4kaabgdacaqGWaGaaGimaiaacckacqGH 9aqpdaqjEaqaaiaaicdacaGGUaGaaGimaiaaicdacaaIZaGaaiiOaa aaaeaacaGGGcWaaeWaaeaacaqGPbGaaeyAaiaabMgaaiaawIcacaGL PaaacaqGGaGaaGimaiaac6cacaqG3aGaaeioaiabgEpa4kaabgdaca aIWaGaaGimaiabg2da9maaL4babaGaaGimaiaac6cacaaIWaGaaGim aiaaiEdacaaI4aaaaaqaamaabmaabaGaaeyAaiaabAhaaiaawIcaca GLPaaacaqGGaGaaGinaiaaiodacaaIYaGaaiOlaiaaiAdacqGH3daU caqGXaGaaeimaiaaicdacaGGGcGaeyypa0ZaauIhaeaacaaI0aGaai OlaiaaiodacaaIYaGaaGOnaaaaaeaadaqadaqaaiaabAhaaiaawIca caGLPaaacaqGGaGaaGOmaiaaiodacaGGUaGaaGOnaiabgEpa4kaabg dacaaIWaGaaiiOaiaaicdacqGH9aqpdaqjEaqaaiaaicdacaGGUaGa aGOmaiaaiodacaaI2aaaaaqaaiaacIcacaWG2bGaamyAaiaacMcaca aMe8UaaGyoaiaaiIdacaGGUaGaaGynaiaaiodacqGH3daUcaqGXaGa aeimaiaaicdacqGH9aqpdaqjEaqaaiaaicdacaGGUaGaaGyoaiaaiI dacaaI1aGaaG4maaaaaaaa@A5E3@

Q.4

Find: ( i ) 7.9÷1000 ( ii ) 26.3÷1000 ( iii ) 38.53÷1000 ( iv ) 128.9÷1000 ( v ) 0.5÷1000 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaaieqacaWFgbGaa8xAaiaa=5gacaWFKbGa a8NoaaqaamaabmaabaGaa8xAaaGaayjkaiaawMcaaiaa=bcacaWF3a Gaa8Nlaiaa=LdacaWF3dGaa8xmaiaa=bdacaWFWaGaa8hmaiaa=bka caWFGcGaa8hOaiaa=bkacaWLjaWaaeWaaeaacaWFPbGaa8xAaaGaay jkaiaawMcaaiaa=bcacaWFYaGaa8Nnaiaa=5cacaWFZaGaa839aiaa =fdacaWFWaGaa8hmaiaa=bdacaWFGcGaa8hOaiaa=bkacaWFGcGaaC zcaiaaxMaacaWFGcWaaeWaaeaacaWFPbGaa8xAaiaa=LgaaiaawIca caGLPaaacaWFGaGaa83maiaa=HdacaWFUaGaa8xnaiaa=ndacaWF3d Gaa8xmaiaa=bdacaWFWaGaa8hmaaqaamaabmaabaGaa8xAaiaa=zha aiaawIcacaGLPaaacaWFGaGaa8xmaiaa=jdacaWF4aGaa8Nlaiaa=L dacaWF3dGaa8xmaiaa=bdacaWFWaGaa8hmaiaa=bkacaWFGcGaaCzc aiaa=bkadaqadaqaaiaa=zhaaiaawIcacaGLPaaacaWFGaGaa8hmai aa=5cacaWF1aGaa839aiaa=fdacaWFWaGaa8hmaiaa=bdacaWLjaGa aCzcaaaaaa@8951@

Ans.

( i ) 7.9÷1000= 0.0079 ( ii ) 26.3÷1000 = 0.0263 ( iii ) 38.53÷1000= 0.03853 ( iv ) 128.9÷1000 = 0.1289 ( v ) 0.5÷1000= 0.0005 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaadaqadaqaaiaabMgaaiaawIcacaGLPaaa caqGGaGaaG4naiaac6cacaaI5aGaey49aGRaaeymaiaabcdacaaIWa GaaGimaiabg2da9maaL4babaGaaGimaiaac6cacaaIWaGaaGimaiaa iEdacaaI5aaaaaqaamaabmaabaGaaeyAaiaabMgaaiaawIcacaGLPa aacaqGGaGaaGOmaiaaiAdacaGGUaGaaG4maiabgEpa4kaabgdacaqG WaGaaeimaiaaicdacaGGGcGaeyypa0ZaauIhaeaacaaIWaGaaiOlai aaicdacaaIYaGaaGOnaiaaiodaaaaabaGaaiiOamaabmaabaGaaeyA aiaabMgacaqGPbaacaGLOaGaayzkaaGaaeiiaiaaiodacaaI4aGaai OlaiaabwdacaqGZaGaey49aGRaaeymaiaaicdacaaIWaGaaGimaiab g2da9maaL4babaGaaGimaiaac6cacaaIWaGaaG4maiaaiIdacaaI1a GaaG4maaaaaeaadaqadaqaaiaabMgacaqG2baacaGLOaGaayzkaaGa aeiiaiaaigdacaaIYaGaaGioaiaac6cacaaI5aGaey49aGRaaeymai aabcdacaqGWaGaaGimaiaacckacqGH9aqpdaqjEaqaaiaaicdacaGG UaGaaGymaiaaikdacaaI4aGaaGyoaaaaaeaadaqadaqaaiaabAhaai aawIcacaGLPaaacaqGGaGaaGimaiaac6cacaaI1aGaey49aGRaaeym aiaabcdacaaIWaGaaGimaiabg2da9maaL4babaGaaGimaiaac6caca aIWaGaaGimaiaaicdacaaI1aaaaaaaaa@991D@

Q.5

Find: ( i ) 7÷3.5 ( ii ) 36÷0.2 ( iii ) 3.25÷0.5 ( iv ) 30.94÷0.7 ( v ) 0.5÷0.25 ( vi ) 7.75÷0.25 ( vii ) 76.5÷0.15 ( viii )37.8÷14 (ix) 2.73÷1.3 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaaieqacaWFgbGaa8xAaiaa=5gacaWFKbGa a8NoaaqaamaabmaabaGaa8xAaaGaayjkaiaawMcaaiaa=bcacaWF3a Gaa839aiaa=ndacaWFUaGaa8xnaiaa=bkacaWFGcGaa8hOaiaa=bka caWFGcGaaCzcamaabmaabaGaa8xAaiaa=LgaaiaawIcacaGLPaaaca WFGaGaa83maiaa=zdacaWF3dGaa8hmaiaa=5cacaWFYaGaa8hOaiaa xMaadaqadaqaaiaa=LgacaWFPbGaa8xAaaGaayjkaiaawMcaaiaa=b cacaWFZaGaa8Nlaiaa=jdacaWF1aGaa839aiaa=bdacaWFUaGaa8xn aiaaxMaadaqadaqaaiaa=LgacaWF2baacaGLOaGaayzkaaGaa8hiai aa=ndacaWFWaGaa8Nlaiaa=LdacaWF0aGaa839aiaa=bdacaWFUaGa a83naaqaamaabmaabaGaa8NDaaGaayjkaiaawMcaaiaa=bcacaWFWa Gaa8Nlaiaa=vdacaWF3dGaa8hmaiaa=5cacaWFYaGaa8xnaiaaxMaa caWLjaGaaCzcamaabmaabaGaa8NDaiaa=LgaaiaawIcacaGLPaaaca WFGaGaa83naiaa=5cacaWF3aGaa8xnaiaa=DpacaWFWaGaa8Nlaiaa =jdacaWF1aGaa8hOaiaa=bkadaqadaqaaiaa=zhacaWFPbGaa8xAaa GaayjkaiaawMcaaiaa=bcacaWF3aGaa8Nnaiaa=5cacaWF1aGaa839 aiaa=bdacaWFUaGaa8xmaiaa=vdaaeaadaqadaqaaiaa=zhacaWFPb Gaa8xAaiaa=LgaaiaawIcacaGLPaaacaWFZaGaa83naiaa=5cacaWF 4aGaa839aiaa=fdacaWF0aGaaCzcaiaaxMaacaWLjaGaa8hkaiaa=L gacaWF4bGaa8xkaiaa=bcacaWFYaGaa8Nlaiaa=DdacaWFZaGaa839 aiaa=fdacaWFUaGaa83maaaaaa@ACC2@

Ans.

( i ) 7÷3.5= 2 ( ii ) 36÷0.2= 180 ( iii ) 3.25÷0.5= 6.5 ( iv ) 30.94÷0.7= 44.2 ( v ) 0.5÷0.25=2 ( vi ) 7.75÷0.25= 31 ( vii ) 76.5÷0.15= 510 ( viii )37.8÷14= 2.7 (ix) 2.73÷1.3= 2.1 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaadaqadaqaaiaabMgaaiaawIcacaGLPaaa caqGGaGaae4naiabgEpa4kaabodacaqGUaGaaeynaiaab2dacaqGGa WaauIhaeaacaqGYaaaaaqaamaabmaabaGaaeyAaiaabMgaaiaawIca caGLPaaacaqGGaGaae4maiaabAdacqGH3daUcaqGWaGaaeOlaiaabk dacaqG9aWaauIhaeaacaqGXaGaaeioaiaabcdaaaaabaWaaeWaaeaa caqGPbGaaeyAaiaabMgaaiaawIcacaGLPaaacaqGGaGaaG4maiaac6 cacaaIYaGaaGynaiabgEpa4kaaicdacaGGUaGaaeynaiaab2dacaqG GaWaauIhaeaacaqG2aGaaeOlaiaabwdaaaaabaWaaeWaaeaacaqGPb GaaeODaaGaayjkaiaawMcaaiaabccacaaIZaGaaGimaiaac6cacaaI 5aGaaGinaiabgEpa4kaabcdacaqGUaGaae4naiaab2dadaqjEaqaai aabsdacaqG0aGaaeOlaiaabkdaaaaabaWaaeWaaeaacaqG2baacaGL OaGaayzkaaGaaeiiaiaaicdacaGGUaGaaGynaiabgEpa4kaabcdaca qGUaGaaeOmaiaabwdacaqG9aGaaeOmaaqaamaabmaabaGaaeODaiaa bMgaaiaawIcacaGLPaaacaqGGaGaaG4naiaac6cacaaI3aGaaGynai abgEpa4kaabcdacaqGUaGaaeOmaiaabwdacaqG9aWaauIhaeaacaqG ZaGaaeymaaaaaeaacaGGGcWaaeWaaeaacaqG2bGaaeyAaiaabMgaai aawIcacaGLPaaacaqGGaGaaG4naiaaiAdacaGGUaGaaGynaiabgEpa 4kaabcdacaqGUaGaaeymaiaabwdacaqG9aGaaeiiamaaL4babaGaae ynaiaabgdacaqGWaaaaaqaamaabmaabaGaaeODaiaabMgacaqGPbGa aeyAaaGaayjkaiaawMcaaiaaiodacaaI3aGaaiOlaiaaiIdacqGH3d aUcaqGXaGaaeinaiaab2dadaqjEaqaaiaabkdacaqGUaGaae4naaaa aeaacaqGOaGaaeyAaiaabIhacaqGPaGaaeiiaiaabkdacaqGUaGaae 4naiaabodacqGH3daUcaaIXaGaaiOlaiaaiodacqGH9aqpdaqjEaqa aiaaikdacaGGUaGaaGymaaaaaaaa@BE8C@

Q.6

A vehicle covers a distance of 43.2 km in 2.4 litres of petrol.How much distance will it cover in one litre of petrol?

Ans.

Distance coverd by a vehicle in 2.4 litres = 43.2 kmSo, the distance vehicle will cover in 1 litre of petrol= 43.22.4km=18 km

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FAQs (Frequently Asked Questions)

Most students find Mathematics to be a difficult subject. If students face any problems, they must be tackled using references such as NCERT Solutions. NCERT Solutions for Class 7 Mathematics is divided into 15 chapters. They are as follows

  1. Integers
  2. Fractions and Decimals
  3. Data Handling
  4. Simple Equations
  5. Lines and Angles
  6. The Triangles and its Properties
  7. Congruence of Triangles
  8. Comparing Quantities
  9. Rational Numbers
  10. Practical Geometry
  11. Perimeter and Area
  12. Algebraic Expressions
  13. Exponents and Powers
  14. Symmetry
  15. Visualising Solid Shapes

 

Following one integrated material for reference is critical. Using textbooks to study for the exam is not an appropriate method. As a result, the NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7 are reliable resources. It is streamlined or a condensed version of a chapter or book.

Extramarks’ NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7 are highly useful in understanding the various questions in Class 7 Maths Exercise 2.7. To verify that their final solution is right, scholars can use the NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7 to double-check their procedure and method or to correct any errors. Using the NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7, students can recognise and fix their misconceptions and silly mistakes. These solutions are available for download via the Extramarks website and mobile application.

The NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7 consists of 7 questions and their answers. These solutions are thorough and accurate for the exams. Every problem is resolved using the appropriate procedure or technique. The NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.7 technique might help students score higher marks in their exams.