NCERT Solutions for Class 11 Physics Chapter 2: Motion in a Straight Line

NCERT Solutions for Class 11 Physics Chapter 2 Motion in a Straight Line are designed to help students understand the fundamentals of motion using simple concepts, clear definitions, and standard equations. This chapter lays the groundwork for kinematics and is essential for solving numericals in higher Physics chapters.

These solutions strictly follow the latest NCERT textbook and are written in a clear, exam-oriented, and student-friendly manner, making them ideal for school exams, CBSE board preparation, and competitive exams like JEE & NEET.

NCERT Solutions for Class 11 Physics Chapter 2: Motion in a Straight Line

NCERT Solutions for Class 11 Physics Chapter 2: Motion in a Straight Line


NCERT Solutions for Class 11 Physics Chapter 2 – Exercise Questions


NCERT Solutions – Chapter 2: Motion in a Straight Line

Q.1) In which of the following examples of motion, can the body be considered approximately a point object?

  1. a railway carriage moving without jerks between two stations
  2. a monkey sitting on top of a man cycling smoothly on a circular track
  3. a spinning cricket ball that turns sharply on hitting the ground
  4. a tumbling beaker that has slipped off the edge of a table

Answer:

  1. The railway carriage can be considered a point object because its size is negligible compared to the distance between stations.
  2. The monkey can be considered a point object as its size is very small compared to the size of the circular track.
  3. The spinning cricket ball cannot be considered a point object because its size is comparable to the distance it turns after hitting the ground.
  4. The tumbling beaker cannot be considered a point object as its size is comparable to the height of the table.

Q.2) The position-time (x–t) graphs for two children A and B are shown. Choose the correct options:

  1. (A/B) lives closer to school than (B/A)
  2. (A/B) starts from school earlier than (B/A)
  3. (A/B) walks faster than (B/A)
  4. A and B reach home at the (same/different) time
  5. (A/B) overtakes (B/A) on the road (once/twice)

Answer:

  1. A lives closer to school than B.
  2. A starts earlier than B.
  3. B walks faster than A.
  4. A and B reach home at the same time.
  5. B overtakes A once.

Q.3) A drunkard walks 5 steps forward and 3 steps backward repeatedly. Each step is 1 m and takes 1 s. Find the time taken to fall into a pit 13 m away.

Answer:

Distance covered in one cycle = 5 − 3 = 2 m
Time taken in one cycle = 5 + 3 = 8 s

Distance covered in 4 cycles = 8 m in 32 s.
In the next 5 s, the drunkard moves 5 m forward and reaches 13 m.

Total time taken = 32 + 5 = 37 seconds


Q.4) State whether the following statements are true or false with reasons:

  1. With zero speed at an instant, a body may have non-zero acceleration.
  2. With zero speed, a body may have non-zero velocity.
  3. With constant speed, a body may have zero acceleration.
  4. With positive acceleration, a body must be speeding up.

Answer:

  1. True. At the highest point of motion, speed becomes zero but acceleration exists.
  2. False. Speed is the magnitude of velocity and cannot be zero if velocity exists.
  3. True. Constant velocity implies zero acceleration.
  4. True (conditionally). If velocity and acceleration are in the same direction.

Q.5) Which graphs cannot represent one-dimensional motion of a particle?

Answer:

  • (a) A particle cannot have two positions at the same instant of time.
  • (b) A particle cannot have two velocities at the same instant in one dimension.
  • (c) Speed cannot be negative.
  • (d) Total path length cannot decrease with time.

Q.6) Does the given x–t graph show straight-line motion for t ≥ 0?

Answer:

No. The graph does not represent a straight-line path. It can represent motion with
constant acceleration.


Q.7) A police van fires a bullet at a thief’s car. Find the speed with which the bullet hits the car.

Answer:

Speed of police van = 30 km/h = 8.33 m/s
Muzzle speed of bullet = 150 m/s
Speed of thief’s car = 192 km/h = 53.33 m/s

Effective speed of bullet = 150 + 8.33 = 158.33 m/s
Relative speed w.r.t thief’s car = 158.33 − 53.33 = 105 m/s

Note: Q&A containing MathML/LaTeX may not render inside PDF.

Frequently Asked Questions (FAQs)

Q1. Is Chapter 2 of Class 11 Physics important for exams?

Yes, this chapter is very important as it introduces kinematics and forms the base for solving numerical problems in later chapters.


Q2. Are equations of motion important for competitive exams?

Yes, equations of motion are frequently used in JEE and NEET numerical problems.


Q3. What is the most scoring part of this chapter?

Numericals based on equations of motion, graphs, and motion under gravity are highly scoring.


Q4. Are these NCERT Solutions enough for board exams?

Yes, these solutions cover all NCERT exercise questions and are sufficient for CBSE school exams.


Q5. Can I download these NCERT Solutions as a PDF?

Yes, the chapter-wise PDF is available for easy offline access and revision.