CBSE Class 11 Maths Revision Notes Chapter 1 Sets

Sets are well-defined collections of objects, numbers or elements used to organise information in mathematics. For CBSE Class 11 Maths 2026–27, this chapter covers set notation, representation of sets, types of sets, subsets, Venn diagrams and set operations.

Sets is the first chapter in Class 11 Mathematics, but the idea is not new. You already use sets in daily life when you talk about a group of students, a list of subjects, a team of players or a collection of books.

In Maths, a set is a collection with one important rule: it must be clearly defined. This means you should be able to say whether an object belongs to the collection or not.

For example, “vowels in the English alphabet” is a set because the members are fixed: a, e, i, o and u. But “best students in a class” is not a set because different people may choose different students.

Use these CBSE Class 11 Maths Revision Notes Chapter 1 to understand how sets are written, represented and used in operations such as union, intersection, difference and complement.

These Class 11 Maths Chapter 1 Notes also work as CBSE Class 11 Maths Notes Chapter 1 for quick revision of Sets.

Key Takeaways

  • Set: A set is a well-defined collection of objects.
  • Representation: Sets are represented in roster form and set-builder form.
  • Subset: A set A is a subset of B if every element of A is also an element of B.
  • Set operations: Union, intersection, difference and complement are the main operations on sets.

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Access Class 11 Maths Chapter 1 Sets Notes in 30 Minutes

These notes are arranged for 30-minute revision, so you can revise the chapter in the same order you study it in class.

Start with the meaning of a set. Then understand how sets are written in roster form and set-builder form. After that, revise types of sets, subsets, Venn diagrams and operations such as union, intersection, difference and complement.

By the end of this chapter, you should be able to look at a collection, decide whether it is a set, represent it correctly and solve basic set operation questions.

These Class 11 Maths Sets Notes and Sets Class 11 Notes cover all important terms, formulas and examples in one place.

Topic What You Revise
Introduction to sets Meaning and examples of sets
Set notation Symbols used in sets
Representation of sets Roster form and set-builder form
Types of sets Empty, finite, infinite, equal and equivalent sets
Subsets Subset, proper subset and power set
Universal set Basic set used in a given context
Venn diagrams Diagram-based representation of set relations
Set operations Union, intersection, difference and complement
Laws of sets Important algebraic laws and De Morgan’s laws
Cardinality Number of elements in a set

CBSE Class 11 Maths Chapter 1 revision notes infographic showing a Venn diagram for Sets.

Why Do Students Study Sets in Class 11 Maths?

Sets give you the basic language for many Class 11 and Class 12 Maths topics.

You will use the idea of sets in:

Topic How Sets Help
Relations and Functions To define domain, codomain and range
Probability To describe outcomes and events
Sequences To group numbers with a pattern
Coordinate Geometry To describe points satisfying conditions
Higher Maths To understand logic, algebra and calculus

So, Sets is not just a separate chapter. It helps you understand how Maths organises information.

These Class 11 Mathematics Revision Notes Chapter 1 help you connect Sets with relations, functions, probability and other higher Maths topics.

Introduction to Sets

The concept of sets is a basic part of modern mathematics.

Sets are used to define relations and functions. They are also used in geometry, probability, sequences, algebra, computer science and other fields.

The theory of sets was developed by German mathematician Georg Cantor while working on problems related to trigonometric series.

What is a Set in Mathematics?

A set is a well-defined collection of objects.

The word “well-defined” is important. It means there should be no confusion about whether something belongs to the set or not.

Example:

A = {1, 2, 3, 4, 5}

This is a set because every element is clearly listed.

Another example:

V = {a, e, i, o, u}

This is the set of vowels in the English alphabet.

Now compare these two collections:

Collection Is It a Set? Why?
Students in Class 11A Yes The members can be clearly identified
Intelligent students in Class 11A No “Intelligent” can mean different things to different people
Natural numbers less than 10 Yes The numbers are fixed
Beautiful flowers No Beauty is based on opinion

So, in Class 11 Sets, always check one thing first: Can we clearly decide the members?

Set Notation

Once a set is defined, Maths needs symbols to write it quickly. This is where set notation is used.

Sets are usually denoted by capital letters such as A, B, C, X, Y and Z.

Elements are usually denoted by small letters such as a, b, c, x, y and z.

Symbol Meaning Example
Belongs to 2 ∈ A
Does not belong to 7 ∉ A
{ } Set brackets A = {1, 2, 3}
n(A) Number of elements in A If A = {1, 2, 3}, n(A) = 3
φ or { } Empty set A = φ

Example:

If A = {2, 4, 6, 8}, then:

2 ∈ A
5 ∉ A
n(A) = 4

Common Sets Used in Class 11 Maths Chapter 1

Symbol Meaning
N Set of natural numbers
Z Set of integers
Q Set of rational numbers
R Set of real numbers
Z+ Set of positive integers
Q+ Set of positive rational numbers
R+ Set of positive real numbers

Examples:

N = {1, 2, 3, 4, 5, ...}

Z = {..., -3, -2, -1, 0, 1, 2, 3, ...}

Representation of Sets

After learning what a set is, the next step is to learn how to write it.

Sets can be represented in two main forms:

Form Meaning
Roster form Listing all elements inside braces
Set-builder form Describing elements through a common property

Roster Form or Tabular Form

In roster form, all elements of a set are listed inside braces and separated by commas.

Example:

A = {2, 4, 6, 8}

This is the set of even natural numbers less than 10.

Rules of Roster Form

Rule Example
Elements are written inside { } A = {1, 2, 3}
Elements are separated by commas B = {a, e, i, o, u}
Order does not matter {1, 2, 3} = {3, 2, 1}
Repeated elements are written once {S, C, H, O, O, L} = {S, C, H, O, L}

Set-Builder Form

Roster form works well when the set has fewer elements. But when a set is large or follows a rule, set-builder form is easier.

In set-builder form, a set is described using the common property of its elements.

Example:

A = {x : x is an even natural number less than 10}

This means A contains all x such that x is an even natural number less than 10.

So,

A = {2, 4, 6, 8}

Roster Form vs Set-Builder Form

Basis Roster Form Set-Builder Form
Meaning Elements are listed Property of elements is described
Example {2, 4, 6, 8} {x : x is an even natural number less than 10}
Use Useful for finite sets Useful for large or infinite sets
Style Direct listing Rule-based representation

Examples of Representation of Sets

Description Roster Form Set-Builder Form
Vowels in English alphabet {a, e, i, o, u} {x : x is a vowel in English alphabet}
Natural numbers less than 6 {1, 2, 3, 4, 5} {x : x ∈ N and x < 6}
Even natural numbers less than 10 {2, 4, 6, 8} {x : x is an even natural number less than 10}
Prime factors of 30 {2, 3, 5} {x : x is a prime factor of 30}

Empty Set

Sometimes, a rule does not give any element. That is when we get an empty set.

An empty set is a set that has no element.

It is also called a null set or void set.

It is denoted by φ or { }.

Examples:

A = {x : x is a natural number between 1 and 2}

There is no natural number between 1 and 2.

So, A = φ.

Another example:

B = {x : x is an even prime number greater than 2}

Since 2 is the only even prime number, B = φ.

Finite and Infinite Sets

A finite set has a definite number of elements.

An infinite set does not have a finite number of elements.

Type Meaning Example
Finite set Has definite number of elements A = {1, 2, 3, 4}
Infinite set Has unlimited elements N = {1, 2, 3, 4, ...}

Examples:

Set of days in a week = finite set
Set of natural numbers = infinite set
Set of letters in English alphabet = finite set
Set of points on a line = infinite set

Equal Sets

Two sets A and B are equal if they have exactly the same elements.

Order does not matter.

Repeated elements do not change a set.

Example:

A = {1, 2, 3}
B = {3, 2, 1}

So, A = B.

Another example:

A = {S, C, H, O, O, L}
B = {S, C, H, O, L}

So, A = B because repeated elements are counted only once.

Equivalent Sets

Two sets are equivalent if they have the same number of elements.

They may or may not contain the same elements.

Example:

A = {a, b, c}
B = {1, 2, 3}

Here, n(A) = 3 and n(B) = 3.

So, A and B are equivalent, but not equal.

Basis Equal Sets Equivalent Sets
Meaning Same elements Same number of elements
Elements Must be identical Can be different
Example {1, 2, 3} and {3, 2, 1} {a, b, c} and {1, 2, 3}

Subsets

Once you understand sets, the next idea is to compare one set with another.

A set A is a subset of set B if every element of A is also an element of B.

It is written as:

A ⊂ B

Example:

A = {1, 2}
B = {1, 2, 3, 4}

Since every element of A is in B, A ⊂ B.

Important Points on Subsets

Point Meaning
Every set is a subset of itself A ⊂ A
Empty set is a subset of every set φ ⊂ A
If A ⊂ B and B ⊂ A A = B
If A ⊂ B and A ≠ B A is a proper subset of B

Proper Subset

A set A is a proper subset of B if every element of A belongs to B, but A and B are not equal.

Example:

A = {1, 2}
B = {1, 2, 3}

Here, A is a proper subset of B.

Power Set

The power set of a set A is the set of all subsets of A.

It is denoted by P(A).

Example:

If A = {1, 2}, then its subsets are:

φ, {1}, {2}, {1, 2}

So,

P(A) = {φ, {1}, {2}, {1, 2}}

If a set has n elements, then the number of elements in its power set is:

2^n

Example:

If A has 3 elements, then P(A) has 2^3 = 8 elements.

Universal Set

A universal set is the basic set that contains all the elements under discussion.

It is denoted by U.

Example:

If we are studying natural numbers, then U may be the set of natural numbers.

If we are studying vowels, then U may be the set of all letters in the English alphabet.

Subsets of Real Numbers

The set of real numbers has important subsets.

Set Meaning
N Natural numbers
Z Integers
Q Rational numbers
R Real numbers
T Irrational numbers

Relations among these sets:

N ⊂ Z ⊂ Q ⊂ R

Also,

T ⊂ R

Irrational numbers are real numbers that are not rational.

Intervals as Subsets of R

Intervals are used to represent subsets of real numbers.

Let a and b be real numbers and a < b.

Interval Set-Builder Form Meaning
(a, b) {x : a < x < b} Open interval
[a, b] {x : a ≤ x ≤ b} Closed interval
[a, b) {x : a ≤ x < b} Closed at a, open at b
(a, b] {x : a < x ≤ b} Open at a, closed at b

Example:

{x : x ∈ R, -5 < x ≤ 7} = (-5, 7]

The length of an interval is:

b - a

Venn Diagrams

Set operations become easier when we can see them visually. Venn diagrams help with this.

Venn diagrams are used to show relationships between sets.

They usually contain:

Shape Represents
Rectangle Universal set
Circle Set or subset
Overlap area Common elements
Area outside circle but inside rectangle Elements not in the set

Venn diagrams are useful for understanding union, intersection, difference and complement of sets.

Operations on Sets

Just like numbers have operations such as addition and subtraction, sets also have operations.

Think of two groups in your class.

Set A = students who play cricket
Set B = students who play football

Now:

  • A ∪ B means students who play cricket or football or both.
  • A ∩ B means students who play both cricket and football.
  • A - B means students who play cricket but not football.
  • A' means students who do not belong to set A, within the universal set.

This makes set operations easier to understand before using formulas.

Operation Symbol Meaning
Union Elements in A or B or both
Intersection Common elements of A and B
Difference - Elements in A but not in B
Complement A' Elements in U but not in A

Union of Sets

The union of two sets A and B is the set of all elements that belong to A or B or both.

It is written as:

A ∪ B

Example:

A = {1, 2, 3}
B = {3, 4, 5}

A ∪ B = {1, 2, 3, 4, 5}

Common elements are written only once.

Intersection of Sets

The intersection of two sets A and B is the set of all elements common to both A and B.

It is written as:

A ∩ B

Example:

A = {1, 2, 3}
B = {3, 4, 5}

A ∩ B = {3}

Disjoint Sets

Two sets are disjoint if they have no common element.

If A and B are disjoint, then:

A ∩ B = φ

Example:

A = {1, 3, 5}
B = {2, 4, 6}

A ∩ B = φ

So, A and B are disjoint sets.

Difference of Sets

The difference of A and B is the set of elements that belong to A but not to B.

It is written as:

A - B

Example:

A = {1, 2, 3, 4}
B = {3, 4, 5}

A - B = {1, 2}

B - A = {5}

So, A - B and B - A are generally not equal.

Complement of a Set

The complement of set A is the set of all elements in the universal set U that are not in A.

It is written as:

A'

Example:

U = {1, 2, 3, 4, 5, 6}
A = {2, 4, 6}

A' = {1, 3, 5}

Important Laws of Sets

Law Formula
Idempotent Law A ∪ A = A, A ∩ A = A
Identity Law A ∪ φ = A, A ∩ U = A
Domination Law A ∪ U = U, A ∩ φ = φ
Commutative Law A ∪ B = B ∪ A, A ∩ B = B ∩ A
Associative Law (A ∪ B) ∪ C = A ∪ (B ∪ C)
Distributive Law A ∪ (B ∩ C) = (A ∪ B) ∩ (A ∪ C)
Complement Law A ∪ A' = U, A ∩ A' = φ
Double Complement Law (A')' = A

De Morgan’s Laws

De Morgan’s laws are used to simplify expressions involving complements.

Law Formula
First Law (A ∪ B)' = A' ∩ B'
Second Law (A ∩ B)' = A' ∪ B'

These laws are useful in set proofs and Venn diagram questions.

Cardinality of Sets

Cardinality means the number of elements in a set.

It is written as n(A).

Example:

A = {2, 4, 6, 8}

n(A) = 4

Important Formulas for Sets

Formula for Two Sets

n(A ∪ B) = n(A) + n(B) - n(A ∩ B)

If A and B are disjoint:

n(A ∪ B) = n(A) + n(B)

Formula for Three Sets

n(A ∪ B ∪ C) = n(A) + n(B) + n(C) - n(A ∩ B) - n(B ∩ C) - n(A ∩ C) + n(A ∩ B ∩ C)

Number of Subsets

If a set A has n elements, then:

Number of subsets = 2^n

Number of proper subsets = 2^n - 1

Solved Examples on Sets

Example 1: Write in Roster Form

Write A = {x : x is a natural number and x < 6} in roster form.

Solution:

Natural numbers less than 6 are 1, 2, 3, 4 and 5.

So,

A = {1, 2, 3, 4, 5}

Example 2: Write in Set-Builder Form

Write {2, 4, 6, 8} in set-builder form.

Solution:

The elements are even natural numbers less than 10.

So,

A = {x : x is an even natural number less than 10}

Example 3: Find Union and Intersection

Let A = {1, 2, 3, 4} and B = {3, 4, 5, 6}.

Find A ∪ B and A ∩ B.

Solution:

A ∪ B = {1, 2, 3, 4, 5, 6}

A ∩ B = {3, 4}

Example 4: Find the Complement

Let U = {1, 2, 3, 4, 5, 6, 7, 8} and A = {2, 4, 6, 8}.

Find A'.

Solution:

A' contains elements of U that are not in A.

A' = {1, 3, 5, 7}

Example 5: Word Problem on Sets

In a town of 840 people, 450 read Hindi, 300 read English and 200 read both. Find the number of people who read neither.

Solution:

Let H be the set of people who read Hindi.
Let E be the set of people who read English.

n(H) = 450
n(E) = 300
n(H ∩ E) = 200

n(H ∪ E) = n(H) + n(E) - n(H ∩ E)

n(H ∪ E) = 450 + 300 - 200 = 550

People who read neither = Total people - n(H ∪ E)

= 840 - 550

= 290

So, 290 people read neither Hindi nor English.

Quick Highlights of Class 11 Maths Chapter 1 Notes

Topic Quick Revision Point
Set Well-defined collection of objects
Element Member of a set
Roster form Listing elements inside braces
Set-builder form Describing elements by a property
Empty set Set with no element
Finite set Set with definite number of elements
Infinite set Set with unlimited elements
Equal sets Sets with same elements
Equivalent sets Sets with same number of elements
Subset Every element of one set belongs to another
Power set Set of all subsets
Universal set Basic set under discussion
Union Elements in A or B or both
Intersection Common elements
Difference Elements in A but not B
Complement Elements outside A but inside U

Important Terms from CBSE Class 11 Maths Revision Notes Chapter 1

The important terms below revise set notation, representation of sets, roster form, set-builder form, empty set, finite set, infinite set, equal sets, equivalent sets, subsets, power set, universal set, Venn diagrams, union of sets, intersection of sets, difference of sets, complement of a set, De Morgan’s laws and cardinality of sets in one place.

Term Meaning
Set Well-defined collection of objects
Element Object or member of a set
Roster form Representation by listing all elements
Set-builder form Representation by using a common property
Empty set Set with no element
Null set Another name for empty set
Finite set Set with definite number of elements
Infinite set Set with unlimited elements
Equal sets Sets with exactly the same elements
Equivalent sets Sets with same cardinality
Subset Set whose every element belongs to another set
Proper subset Subset that is not equal to the original set
Power set Set of all subsets
Universal set Set containing all elements under discussion
Venn diagram Diagram showing set relations
Union Set of elements in A or B or both
Intersection Set of common elements
Difference Set of elements in one set but not the other
Complement Elements not in the set but present in universal set
Cardinality Number of elements in a set

Useful Links for Class 11 Maths

Section Useful Links
Syllabus CBSE Class 11 Maths Syllabus
Revision Notes CBSE Class 11 Maths Revision Notes
Maths Notes CBSE Class 11 Maths Revision Notes Chapter 2
NCERT Solutions NCERT Solutions Class 11 Maths
Sample Papers CBSE Sample Papers for Class 11 Maths
Important Questions Important Questions Class 11 Maths
NCERT Books NCERT Books for Class 11 Maths

Q.1 Draw appropriate Venn diagram for each of the following:

a) A’ ∩ B’.
b) A’.

Ans

a) A’ ∩ B’ = (A ∪ B)’

b) A’

Q.2 In a survey of 200 students of a school it was found that 120 study mathematics, 90 study physics and 70 study chemistry, 40 study mathematics and physics, 30 study physics and chemistry, 50 study chemistry and mathematics and 20 study none of these subjects. Find the number of students who study all three subjects.

Ans

n(U) = 200
n(M) = 120, n (P) = 90
n(C) =70
n(M ∩ P) = 40 , (P ∩ C) = 30
n(C ∩ M) = 50, n(M ∪ P ∪ C)’ = 20
Now n(M ∪ P ∪ C)’ = n(U) – n(M ∪ P ∪ C)
20 = 200 – n (M ∪ P ∪ C)
Therefore, n(M ∪ P ∪ C) = 200 – 20 = 180
n(M ∪ P ∪ C) = n(M) + n(P) + n(C) – n(M ∩ P) – n(P ∩ C) – n(C ∩ M) + n(M ∩ P ∩ C)
180 = 120 + 90 + 70 – 40 – 30 – 50 + n(M ∩ P ∩ C)
⇒ n(M ∩ P ∩ C) = 180 – 120 – 90 – 70 + 40 + 30 + 50
⇒ n(M ∩ P ∩ C) = 20.

Q.3 If S and T are two sets such that S has 21 elements. T has 32 elements and S ∩ T has 11 elements. How many elements does S ∪ T has?

Ans

n(S) = 21
n(T) = 32
n(S ∩ T) = 11
n(S ∪ T) = n(S) + n (T) – n(S ∩ T)
= 21 + 32 – 11
= 53 – 11
= 42
Therefore, n(S ∪ T) = 42

Q.4 Fill in the blanks to make the following statements true.

1) A ∪ A’ = ____
2) Φ
A’ = _____
3) R – Q = _____, where R is the set of real numbers and Q is the set of rational numbers.
4) A ∩ A’ = ______

5) U A = _____
6) A
A = _____

Ans

1) A ∪ A’ = U (Universal set)
2) Φ ∪ A’ = A’
3) R – Q = set of irrational numbers where R is the set of real numbers and Q is the set of rational numbers.
4) A ∩ A’ = Φ
5) U’ ∩ A = Φ
6) A ∩ A = A

Q.5 Taking U = {x : x is natural number} write the complements of the following sets:

1. A = {x : x is an even natural number}
2. B = {x : 2x + 5 = 9}
3. C = {x : x 7}
4. D = {x : x is a prime number}

Ans

1. A’ = {x : x is an odd natural number}
2. B’ = {x : x ∈ N, x ≠ 2}
3. C’ = {x : x ∈ N and x < 7}
4. D’ = {x : x is a composite number}

Q.6 Let U = {1, 2, 3, 4, 5, 6}, A = {2, 3} and B = {3, 4, 5}. Show that (A ∪ B)’ = A’ ∩ B’.

Ans

A ∪ B = {2, 3, 4, 5}
∴ (A ∪ B)’ = {1, 6}
Also A’ = {1, 4, 5, 6}
B ‘ {1, 2, 6}
∴ A’ ∩ B’ = {1, 6}
Hence (A ∪ B)’ = A’ ∩ B’

Q.7 If A = {3, 5, 7, 9, 11}, B = {7, 9, 11, 13} and C = {11, 13, 15}, find

(i) (A ∩ B) (B C)
(ii) A (B C)
(iii) Are (i) and (ii) equal?

Ans

(i) A ∩ B = {7, 9, 11}
B C = {11, 13}
(A B) ∩ (B C) = {11}

(ii) B C = {7, 9, 11, 13, 15}
A (B C) = {7, 9, 11}

(iii) No, both are not equal.

Q.8 State True or False justify your answers

(i) {2,3,4,5} and{3,6} are disjoint sets
(ii) {a,e,i,o,u} and {x : x is a vowel} are disjoint sets
(iii) {2,6,10} and {3,7,11} are disjoint sets

Ans

(i) False, as 3 is common to both the sets.
(ii) False, both are equal sets.
(iii) True, as they have no element in common.

Q.9 In a town of 840 persons, 450 persons read Hindi, 300 read English and 200 read both. Find the number of persons who read neither.

Ans

n(U) = 840
n(H) = 450
n(E ) = 300
n(H ∩ E) = 200
Required number is
n(H ∪ E)c = 840 – n( H ∪ E)
= 840 – {n(H) + n(E) – n(H ∩ E)}
= 840 – {450 + 300 – 200}
= 840 – 550
= 290

Q.10 If U = {1, 2, 3, 4, 5, 6, 7, 8, 9}, A = {1, 2, 3, 4} and B = {2, 4, 6, 8}, find (A ∪ B)c.

Ans

Given A = {1, 2, 3, 4}, B = {2, 4, 6, 8}
A ∪ B = {1, 2, 3, 4, 6, 8}(A ∪ B)c = {5, 7, 9}

Q.11 State whether A = B or not.

(a) If A = {2, 4, 6, 8, 10} and B = {x : x is positive even integer and x ≤ 10}.
(b) A = {7, 3} and B = {x : x is a solution of x2 + 5x + 6 = 0}.

Ans

a) A = { 2, 4, 6, 8, 10} B = { x : x is positive even integer and x ≤ 10}
or A = {2, 4, 6, 8, 10} and B = {2, 4, 6, 8, 10}
Therefore A = B

b) A = {7, 3}
x2 + 5x + 6 = 0
⇒ x(x + 2) + 3(x + 2) = 0
⇒ (x + 2)(x + 3) = 0
⇒ x = –2 x = –3
Therefore, B = {–2, –3}.
Thus, A ≠ B

Q.12 Consider the sets Φ, A = {1, 3, 9} and B = {1, 5, 9, 11}. Fill in with Φ, ⊂ or ⊄.

1) Φ _____ B
2) A _____ B

Ans

1) Φ B as Φ is a subset of every set.
2) A B as 3 ∈ A but 3 ∉ B.

Q.13 a) Write the set {1, 4, 9, …,100} in set builder form.
b) Write the Set E = {x: x is a letter of the word ‘MATHEMATICS’}

Ans

a) A = {x: x = y2, y is a natural number less than or equal to 10}
OR
A = {x: x = y2, y ∈ N and 1 ≤ y ≤ 10}

b) {M,A,T,H,E,I,C,S}

Q.14 Which type of set is the set of odd natural numbers divisible by 2?

Ans

Null set, as there is no odd natural number which is divisible by 2.

Q.15 If A = {1, 2, 3, 4} and B = {3, 4, 5, 6}, find

a) A ∪ B
b) A ∩ B

Ans

a) A ∪ B = {1, 2, 3, 4, 5, 6}
b) A ∩ B = {3, 4}

Q.16 If A = {1, 2, 3}, B = {3, 4, 5}, find A – B and B – A. Is A – B = B – A?

Ans

Set of elements of A that are not in B: A – B = {1, 2}
Set of elements of B that are not in A: B – A = {4, 5}
Thus , A – B ≠ B – A

Q.17 Write the set {3, 6, 9, 12, …} in set builder form.

Ans

A = {3x : x ∈ N}

Q.18 Define disjoint sets.

Ans

Two sets A and B are said to be disjoint if A ∩ B = Φ.
E.g. {a, b, c, d} and {e, f, g, h} are disjoint sets.

Q.19 If A = {x : x is a prime number ∀ x ∈ N}, then find Ac.

Ans

Ac = {x : x is not a prime number ∀ x ∈ N}

Q.20 If A = {1, 2, 3}, then find P(A).

Ans

P(A) = {Φ, {1}, {2}, {3}, {1, 2}, {2, 3}, {3, 1}, {1, 2, 3}}

Q.21 If A = {a, b, c}, B = {b, e, f}, find A – B.

AnsA – B = {a, c}

Q.22 Define the difference of sets.

Ans

The difference of sets A and B, denoted by A-B, is the set of all those elements of A which do not belongs to B, i.e.,
A – B = {x : x ∈ A and x ∉ B}

Q.23 If A = {x : x ∈ N and x < 100} and B = {y : y ∈ N and y is a multiple of 2 less than 100}, find A ∪ B.

Ans

A ∪ B = A = {x : x ∈ N and x < 100}

Q.24 Write the set A = {x : x ∈ N and x2 < 25} in roster form.

Ans

{1, 2, 3, 4}

Q.25 Find the pair of equal sets from the following sets:
A = {0}, B = {x : x > 10 and x < 4}, C = {x : x – 3 = 0} and D = {x : x is a positive root of equation x2 – 2x – 3}

Ans

Here A = {0}, B = Φ, C = {3}, D = {3}
Thus C = D

Q.26 Define finite and infinite sets.

Ans

Finite Set: A set which is empty or contains finite number of elements is known as a finite set.
Infinite Set: A set that contains infinite number of elements is known as an infinite set.

Q.27 Write the following intervals in set builder form:

(i) (–7, 0)
(ii) [–2, 3)

Ans

(i) (–7, 0) = {x : x ∈ R and –7 < x < 0}.
(ii) [-2, 3) = {x : x ∈ R and –2 ≤ x < 3}.

Q.28 Define symmetric difference of two sets.

Ans

Let A and B be two sets, then symmetric difference denoted as A Δ B, is defined as follows:
A Δ B = (A – B) ∪ (B – A) = {x : x ∉ A ∩ B}
The Venn diagram is shown below:

Q.29 If A,B and C are any three sets, then prove that A ∩ (BΔC) = (A ∩ B) Δ (A ∩ C).

Ans

Here,
A ∩ (BΔC) = A ∩ [(B – C) ∪ (C – B)]
= [A ∩ (B – C)] ∪ [A ∩ (C – B)]
= [(A ∩ B) – (A ∩ C)] ∪ [(A ∩ C) – (A ∩ B)]
= (A ∩ B) Δ (A ∩ C)

Q.30 Fill in the blanks to make each of the following a true statement:

(i) A ∪ A’ = _____.
(ii) A ∩ A’ = _____.

Ans

(i) A ∪ A’ = U (Universal set)
(ii) A ∩ A’ = Φ (No element is common in both the sets)

Q.31

If AB=ϕ, then find n(AB).

Ans

We know, n(A ∪ B) = n(A) + n(B) – n(A ∩ B)
If A ∩ B = Φ, then n(A ∩ B) = 0.
This implies that,
n(A ∪ B) = n(A) + n(B) – 0
or, n(A ∪ B) = n(A) + n(B)

Q.32 In a school, there are 20 teachers who teach Mathematics or Physics. Of these, 12 teach Mathematics and 4 teach both Physics and Mathematics. How many teach Physics?

Ans

Let M denote the set of mathematics teacher and P denote the set of physics teacher.
Given that, n(M ∪ P) = 20
n(M ∩ P) = 4
n(M) = 12
We wish to determine n(P)
We have,
n(M P) = n(M) + n(P) – n(M ∩ P)
we obtain
20 = 12 + n (P) – 4
⇒ 8 + n(P) = 20
Thus, n(P) = 12

Hence, 12 teachers teach physics.

Q.33 In a class of 35 students, 24 like to play cricket and 16 like to play football. Also, each student likes to play at least one of the two games. How many students like to play both cricket and football?

Ans

Let X be the set of students who like to play cricketand Y be the set of students who like to play football.Then XY is the set of students who like to playat least one game.and XY is the set of students who like to play both games.Given, n(X)=24, n(Y)=16, n(XY)=35, n(XY)=?Using the formula,n(XY)=n(X)+n(Y)n(XY)we get35=24+16n(XY)n(XY)=4035n(XY)=5Thus, 5 students like to play both games.

Q.34 In a group of 70 Students, 37 like coffee, 52 like tea and each student likes at least one of the two drinks. How many students like both coffee and tea?

Ans

Let X be the set of students who like to take coffeeand Y be the set of students who like to take tea.Then XUY is the set of students who like at leastone of the two drinks andXY is the set of students who like both coffee and tea.Given, n(X)=37 n(Y)=52n(XY)=70, n(XY)=?Using the formula,n(XY)=n(X)+n(Y)n(XY)we get,70=37+52n(XY)n(XY)=8970n(XY)=19Thus, 19 students like both coffee and tea.

Q.35 Mr. X has five friends. He wishes to arrange a dinner party on some occasion. In how many ways he can invite his friends on dinner party by inviting at least one of them.

Ans

Let a, b, c, d, e be the friends of Mr. X
A = {a,b,c,d,e}
The number of all possible subsets of set A = 25 = 32
[The no. of subset of a set having n elements is 2n]
This includes a null set that indicates not inviting any friend.
The number of ways in which he can invite his friends = 25 = 32
Hence, the number of ways in which he can invite at least one of his friends = 25 – 1
= 32 – 1
= 31

Q.36 In a school, there are 20 teachers who teach Mathematics or Physics. Of these, 12 teach Mathematics and 4 teach both Physics and Mathematics. How many teach Physics only?

Ans

Let M denote the set of mathematics teacher and P denote the set of physics teacher.
Given that,

n(M U P)=20n(MP)=4,n(M)=12We wish to determine n(P)We have,n(MP)=n(M)+n(P)n(MP)

We obtain
20 = 12 + n (P) – 4
⇒ 8 + n(P) = 20
Thus, n(P) = 12
⇒ The number of teachers teach physics = 12

Since the number of teachers teach both physics and mathematics = 4
∴ Number of teachers teach physics only = 12 – 4
= 8

Q.37 In a survey of 400 students in a school, 100 were listed as taking apple juice, 150 as taking orange juice and 75 were listed as taking both apple as well as orange juice. Find how many students were taking neither apple juice nor orange juice.

Ans

Let U denote the set of surveyed students and A denote the set of students taking apple juice and B denote the set of students taking orange juice.
Then n(U) = 400
n(A) = 100
n(B) = 150 and

n(AB)=75Using the formula,n(AB)=n(A)+n(B)n(AB)we getn(AB)=100+15075n(AB)=175Also, n(AB)=n(U)n(AB)n(AB)r=400175n(AB)=225Hence, 225 students were taking neither apple juice nor orange juice.

Q.38 A market research group conducted a survey of 2000 consumers and reported that 1350 consumers like beverage A and 750 consumers like beverage B, what is the least number that must have liked both beverages?

Ans

Let A be the set of consumers who like beverage Aand B be the set of consumers who like beverage B.Then, AUB is the set of consumers who like least one of the two drink andAB is the set of consumers who like both beverages.Given,n(A)=1350n(B)=750For n(AB) to be least, n(AB) is maximum.So, maximum values of n(AB) is 2000n(AB)n(A)+n(B)n(AB)20001350+750n(AB)20002100n(AB)n(AB)21002000n(AB)100The least number of consumers who like both beverages is 100.

Q.39 There are 200 individuals with a skin disorder, 120 had been exposed to the chemical C1, 50 to chemical C2 and 30 to both the chemicals C1 and C2. Find the number of individuals exposed to

(i) Chemical C1 but not chemical C2
(ii) Chemical C2 but not chemical C1

Ans

Let U denote the universal set consisting of individuals suffering from the skin disorder.
A denote the set of individuals exposed to chemical C1.
B denote the set of individuals exposed to chemical C2.
Here, n(U) = 200,
n(A) = 120, n(B) = 50 and

n(AB)=30(i) we have,n(AB)=n(A)n(AB)n(AB)=12030n(AB)=90Hence, the number of individuals exposed to chemicalC1 but not to chemical C2 is 90.(ii) we have,n(BA)=n(B)n(AB)n(BA)=5030n(BA)=20Hence, the number of individuals exposed to chemicalC2 but not to chemical C1 is 20.

Q.40 In a survey of 60 people, it was found that 25 people read newspaper H, 26 read newspaper T, 26 read newspaper I, 9 read both H and I, 11 read both H and T, 8 read both T and I, 3 read all three newspapers. Find the number of people who read at least one of the newspapers.

Ans

Let H denote the people who read newspaper H.I denote the people who read newspaper I.T denote the people who read newspaperT.n(H)=25n(I)=26n(T)=26n(HI)=9n(HT)=11n(TI)=8n(HIT)=3Since n(HTI) denote the number of people who read at least one ofthe newspapers, we haven(HTI)=n(H)+n(T)+n(I)n(HI)n(HT)n(TI)+n(HTI) =25+26+269118+3 =7728+3 =8028 =52Hence, the number of people who read at least one of the newspapers is 52.

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FAQs (Frequently Asked Questions)

A set is a well-defined collection of objects, numbers or elements. For example, A = {1, 2, 3, 4} is a set because its members are clearly identified.

The two methods of representing a set are roster form and set-builder form. Roster form lists all elements inside braces, while set-builder form describes elements using a common property.

Roster form directly lists the elements of a set, such as {2, 4, 6}. Set-builder form describes the same set using a rule, such as {x : x is an even natural number less than 8}.

An empty set is a set that has no element. It is also called a null set or void set. It is denoted by φ or { }.

Union means all elements that belong to A or B or both. Intersection means only the elements common to both A and B. Union is written as A ∪ B, while intersection is written as A ∩ B.