Class 9 Mathematics Revision Notes for Circles of Chapter 10
Extramarks’ Class 9 Mathematics Chapter 10 Notes help students with a detailed understanding of the chapter. These notes are designed as per the latest CBSE curriculum by subject-matter experts. Moreover, students can score better marks in their exams by carefully examining the CBSE Class 9 Chapter 10 Mathematics Notes.
Class 9 Mathematics Revision Notes for Circles of Chapter 10
Access Class 9 Mathematics Chapter 10 – Circles
Introduction
Circle:
A circle can be defined as the locus of points at a certain distance from a fixed point.
Chord:
- A straight line that connects any two points on a circle is known as a chord.
- It is represented by the letters AB.
- The longest chord that passes through the centre of the circle is termed the diameter.
- The diameter is twice the radius and is referred to as a CD.
- A line that divides a circle in half is termed a secant. PQR is a secant of a circle.
Circumference:
It refers to the length of a full circle and is defined as the border curve (or perimeter) of the circle.
Arc:
- Any section or a part of the circumference is referred to as an arc.
- A circle is divided into two equal pieces by diameter.
- A semicircle is larger than a minor arc.
- A semicircle is smaller than a major arc.
- ABC⌢ is a major arc, whereas ADC⌢ is a minor arc.
Sector:
- The area between an arc and the two radii connecting the arc’s centre and endpoints is called a sector.
- A section of a circle a chord has cut off is known as a segment.
Concentric Circles:
Circles with the same centre are concentric circles.
Theorem 1:
Theorem 1:
A straight line drawn from the centre of a circle that is not a diameter to bisect a chord is always at a right angle to the chord.
- Given Data: Here, AB is a chord of a circle with the centre O. The midpoint of AB is M. OM is joined.
- To Prove: ∠AMO = ∠BMO = 90°
- Construction: Join AO and BO
- Proof: In ΔAOM and ΔBOM
Statement |
Reason |
AO = BO |
radii |
AM = BM |
Data |
OM = OM |
Common |
ΔAOM ≅ΔBOM |
S.S.S |
∴∠AMO = ∠BMO |
Statement (4) |
But ∠AMO + ∠BMO= 180° |
Linear pair |
∠AMO = ∠BMO= 90° |
Statements 5 and 6 |
Angle Properties (Angle, Cyclic Quadrilaterals and Arcs):
- ∠APB on the circumference is suspended by a straight line AB.
- On the remaining part of the circumference, ∠APB can be said to be subtended by arc AMB.
- Arc AMB subtends ∠AOB at the centre and ∠APB on the circumference.
- ∠AQB and ∠APB are in the same segment.
Cyclic Quadrilaterals:
The quadrilateral is called a cyclic quadrilateral if the vertices of a quadrilateral lie on a circle. The vertices are called concyclic points.
Corollary:
The exterior angle of a cyclic quadrilateral is equivalent to the opposite interior angle.
Given: ABCD is a cyclic quadrilateral. BC is extended to E.
To Prove: ∠DCE = ∠A
Proof:
Statement |
Reason |
∠A + ∠BCD=180ο |
Opposite ∠s of a cyclic quadrilateral |
∠BCD + ∠DCE=180ο |
Linear pair |
∴ ∠BCD + ∠DCE=∠A + ∠BCD |
Statements (1) and (2) |
∴ ∠DCE = ∠A |
Statement (2) |
Alternate Segment Property
Theorem 10:
The angle in the alternate segment is equal to the angle between a tangent and a chord through the point of contact.
A straight line SAT touches a given circle with centre O at A. AC is a chord through the point of contact A.
Angles in the alternate segments to ∠CAT and ∠CAS are denoted by ∠ADC and ∠AEC, respectively.
- To prove: ∠CAT=∠ADC and ∠CAS=∠AEC
- Construction: Draw AOB as diameter and join BC and OC.
- Proof:
Statement |
Reason |
∠OAC= ∠OCA= x |
Since OA=OC and supposition |
∠CAT+ ∠x= 90° |
Since tangent-radius property |
∠AOC + ∠x+ ∠y= 180° |
Sum of angles of a triangle |
∠AOC= 180°- 2∠x |
Statement 3 |
∠AOC= 2∠ADC |
∠ at the centre = 2∠ on the circle |
∠CAT= 90° – x |
Statement 2 |
2∠CAT= 180°- 2x |
Statement 6 |
2∠CAT= 2∠ADC |
Statements 4,5,7 |
∠CAT= ∠ADC |
Statement 8 |
∠CAS+∠CAT= 180° |
Linear pair |
∠ADC= ∠AEC= 180° |
Opposite angles of a cyclic quadratic |
∠CAS+∠CAT= ∠ADC+∠AEC |
Statements 10 and 11 |
Therefore, ∠CAS=∠AEC (Statement 9 and 12)
Test for Concyclic Points:
(a) Conversely, one test for the concyclic points is ‘Angles in the same segment of a circle are equal’.
It states that:
The four points are concyclic if two equal angles are on the same side of a line and are subtended by it.
If ∠P=∠Q and the points P, and Q are on the same side of AB, then all the points A, B, P and Q are concyclic.
(b) Another test for concyclic points is the converse of ‘opposite angles of a cyclic quadrilateral are supplementary’.
It states that:
The vertices of a quadrilateral are concyclic if the opposing angles are supplementary.
For instance, if ∠A+∠C=180∘ then A, B, C and D are concyclic points.