CBSE Important Questions Class 7 Maths Chapter 5 Parallel and Intersecting Lines

CBSE Important Questions Class 7 Maths Chapter 5 – Parallel and Intersecting Lines

Class 7 Maths Chapter 5 Parallel and Intersecting Lines is a chapter of the new NCERT (National Council of Educational Research and Training) textbook Ganita Prakash. It explains what happens when two lines meet at a point (intersecting lines), when they never meet (parallel lines), and what angles are formed when a third line, called a transversal, crosses them. Students learn about acute, right and obtuse angles, angles on a straight line, and co-interior and corresponding angles.

These CBSE important questions for Class 7 Maths Chapter 5 are figure-based multiple choice questions on identifying an acute angle, finding an unknown angle on a straight line, recognising parallel lines, and using the angle rules for parallel lines cut by a transversal. Every question has a clear step-by-step answer in simple English, so students can practise on their own, parents can check the working, and teachers can use them in class. A free printable PDF of these important questions is also available on this page.

CBSE Important Questions Class 7 Maths Chapter 5 Parallel and Intersecting Lines

CBSE Important Questions Class 7 Maths Chapter 5 Parallel and Intersecting Lines

Q1. Refer to the given figure. Different angles are shown with angular arcs. Which one of them is an acute angle?
(a) ∠POQ
(b) ∠ROQ
(c) ∠POS
(d) ∠ROS

Rays OP, OQ, OR, OS and OT from point O

Answer: (a) ∠POQ
An acute angle is less than 90°. ∠POQ, between ray OP and ray OQ, is smaller than a right angle, so it is acute. ∠ROQ and ∠ROS are right angles (90°), and ∠POS is bigger than a right angle. So the acute angle is ∠POQ.

Q2. In the given figure, if XOY is a straight line, then the value of ∠XOA is
(a) 45°
(b) 65°
(c) 75°
(d) 115°

Straight line XOY with angle XOA = (x + 20) degrees and angle AOY = (2x + 25) degrees

Answer: (b) 65°
Angles on a straight line add up to 180°. So (x + 20) + (2x + 25) = 180
3x + 45 = 180, so 3x = 135 and x = 45
∠XOA = x + 20 = 45 + 20 = 65°
Check: ∠AOY = 2(45) + 25 = 115°, and 65° + 115° = 180° ✓

Q3. In the given figure, lines m and n, which do not intersect on extending infinitely, are
(a) parallel lines
(b) intersecting lines
(c) null
(d) transversal

Line l crossing lines m and n

Answer: (a) parallel lines
Lines that never meet, however far they are extended, are called parallel lines. Lines m and n keep the same distance apart everywhere, so they are parallel. Line l, which crosses both of them, is the transversal.

Q4. In the given figure, if i is parallel to m, then x is
(a) 100°
(b) 110°
(c) 120°
(d) 130°

Parallel lines i and m cut by transversal t, with angles 70 degrees and x

Answer: (b) 110°
The angles 70° and x lie between the two parallel lines on the same side of the transversal t. Such co-interior angles add up to 180°. So 70° + x = 180°, which gives x = 110°.

Related Study Material on Extramarks

Q.1 In the given figure, find the values of x, y, and z.

Marks:3
Ans

The given figure is:

From figure,
z = 90° (vertically opposite angles)
Now,
x, z, 30° lie on a straight line
By Linear Pair Axiom,
x + z + 30—¦ = 180°
x + 90° + 30° = 180°
x + 120° = 180—¦
x = 60°
And,
y = 30° (vertically opposite angles)
Hence, x = 60°, y = 30°, z=90°

Q.2 In the figure given below, PQ, RS, and UT are parallel lines.

If  measure of ∠c=57  and ∠a =∠c3, find the values of ∠a, ∠b and ∠d.

Marks:2
Ans

Given that : ∠c=57 and  ∠a = ∠c3∴∠a = 573= 19Since PQ UT,∠a + ∠b = ∠c alternate interior angles⇒19+ ∠b = 57⇒∠b = 57−19=38Also, PQ RS Given∠a + ∠d = 180 co−interior angles19+ ∠d = 180∠d = 180– 19= 161

Q.3 (i) Find the angle, which is equal to its complement.
(ii) Find the angle, which is equal to its supplement.

Marks:2
Ans

(i) Let x be the required angle.
Then x+x = 90° ⇒ 2x= 90° ⇒ x= 45°
Therefore, the angle which is equal to its complement is 45°.

(ii) Let x be the required angle.
Then x+x = 180° ⇒ 2x= 90° ⇒ x= 90°
Therefore, the angle which is equal to its supplement is 90°.

Q.4 In the given figure, lines l and m are parallel. What is the value of x?

Marks:1
1. 30°

2. 60°

3. 90°

4. 120°

Ans

3. 90°

Explanation

In the given figure draw a line, which is parallel to l and m as shown below.

∠1=60° (Alternate  angles)∠2=30° (Alternate  angles)∴x=∠1+∠2=60°+30°=90°

Q.5 What is the value of x, if l || m?

Marks:1
1.36°

2. 30°

3. 45°

4. 90°

Ans

1. 36°

Explanation

Since, l–m∴  2x+3x=180° (co-interior angles)⇒5x=180°⇒x=180°5=36°Hence, the required value of  x  is  36°.

Please register to view this section