Important Questions Class 7 Maths Chapter 2 Arithmetic Expressions

Arithmetic expressions are number statements made using operations like addition, subtraction, multiplication, and division.
For example, 30 + 5 × 4 has a different value from (30 + 5) × 4 because brackets change the order of calculation.

Arithmetic Expressions is one of the first Class 7 Maths chapters where students learn to read numbers like a mathematical sentence. The chapter trains students to form expressions from daily situations, compare values without long calculation, identify terms, remove brackets, and use the distributive property for faster solving. Important Questions Class 7 Maths Chapter 2 helps students practise these exact skills for CBSE 2026 school exams. The questions in this chapter often test small changes in signs, brackets, and terms, so careful step-by-step working matters more than memorising rules.

Key Takeaways

  • Arithmetic Expressions: Class 7 students learn to form and evaluate number expressions using +, –, ×, and ÷.
  • Terms: Expressions become easier when subtraction changes into addition of inverse numbers.
  • Brackets: A minus sign before brackets changes the signs of all terms inside.
  • Distributive Property: Multiplication across brackets helps simplify products like 97 × 25.

Important Questions Class 7 Maths Chapter 2 Structure 2026

Concept Formula Or Rule Key Variables
Removing Brackets a – (b + c) = a – b – c a, b, c are terms
Difference Inside Brackets a – (b – c) = a – b + c Sign of c changes
Distributive Property a × (b + c) = a × b + a × c a multiplies each term

Class 7 Maths Chapter 2 Important Questions On Simple Expressions

A simple expression shows a calculation before its final value appears. In CBSE 2026 tests, these questions check whether students can convert words into expressions and evaluate them correctly.

1. What is an arithmetic expression?

An arithmetic expression is a number statement with operations like +, –, ×, and ÷.

For example, 13 + 2 is an arithmetic expression.

  1. It contains two numbers, 13 and 2.
  2. It uses the addition operation.
  3. Its value is 15.

Final Answer: 13 + 2 is an arithmetic expression with value 15.

2. Write an expression for five days of lunch at ₹25 per day.

The expression is 5 × 25.

Given Data:

  1. Number of school days = 5
  2. Lunch cost per day = ₹25

Calculation:

5 × 25 = 125

Final Answer: The expression is 5 × 25, and the total amount is ₹125.

3. Fill in the blank: 13 + 4 = ____ + 6.

The missing number is 11.

Step 1: Find the left side.

13 + 4 = 17

Step 2: The right side must also equal 17.

____ + 6 = 17

Step 3: Subtract 6 from 17.

17 – 6 = 11

Final Answer: 13 + 4 = 11 + 6

4. Fill in the blank: 22 + ____ = 6 × 5.

The missing number is 8.

Step 1: First evaluate the right side.

6 × 5 = 30

Step 2: Now solve the left side.

22 + ____ = 30

Step 3: Find the missing value.

30 – 22 = 8

Final Answer: 22 + 8 = 6 × 5

5. Arrange these expressions in increasing order: 67 – 19, 67 – 20, 35 + 25, 5 × 11, 120 ÷ 3.

The increasing order starts with the smallest value.

67 – 19 = 48
67 – 20 = 47
35 + 25 = 60
5 × 11 = 55
120 ÷ 3 = 40

Order:

120 ÷ 3 < 67 – 20 < 67 – 19 < 5 × 11 < 35 + 25

Final Answer: 120 ÷ 3, 67 – 20, 67 – 19, 5 × 11, 35 + 25

Class 7 Maths Chapter 2 Arithmetic Expressions With Comparing Expressions

Comparison questions reward reasoning more than long calculation. These Comparing Arithmetic Expressions Class 7 Questions often use nearby numbers to test whether students can notice small changes.

6. Compare 245 + 289 and 246 + 285.

245 + 289 is greater.

  1. In the second expression, the first number increases by 1.
  2. The second number decreases by 4.
  3. Overall, the second expression becomes 3 less.

Calculation check:

245 + 289 = 534
246 + 285 = 531

Final Answer: 245 + 289 > 246 + 285

7. Compare 273 – 145 and 272 – 144.

Both expressions are equal.

  1. The first expression starts 1 higher.
  2. It also subtracts 1 more.
  3. Both changes balance each other.

Calculation check:

273 – 145 = 128
272 – 144 = 128

Final Answer: 273 – 145 = 272 – 144

8. Compare 364 + 587 and 363 + 589.

363 + 589 is greater.

  1. The first number decreases by 1.
  2. The second number increases by 2.
  3. The total increases by 1.

Calculation check:

364 + 587 = 951
363 + 589 = 952

Final Answer: 364 + 587 < 363 + 589

9. Compare 213 – 77 and 214 – 76.

213 – 77 is less.

  1. The second expression starts 1 higher.
  2. It also subtracts 1 less.
  3. Its value becomes 2 greater.

Calculation check:

213 – 77 = 136
214 – 76 = 138

Final Answer: 213 – 77 < 214 – 76

Class 7 Maths Arithmetic Expressions Questions With Answers On Terms

Terms show how an expression breaks into smaller parts. These Terms In Arithmetic Expressions Class 7 Questions help students avoid common mistakes with subtraction signs.

10. Identify the terms in 13 – 2 + 6.

The terms are 13, –2, and 6.

Step 1: Rewrite subtraction as addition of the inverse.

13 – 2 + 6 = 13 + (–2) + 6

Step 2: The parts separated by plus signs are terms.

Final Answer: The terms are 13, –2, and 6.

11. Identify the terms in 39 – 2 × 6 + 11.

The terms are 39, –2 × 6, and 11.

Step 1: Rewrite the expression.

39 – 2 × 6 + 11 = 39 + (–2 × 6) + 11

Step 2: Multiplication stays inside one term.

Step 3: The plus signs separate the terms.

Final Answer: The terms are 39, –2 × 6, and 11.

12. Evaluate 28 – 7 + 8 by writing its terms.

The value is 29.

Step 1: Write the expression as terms.

28 – 7 + 8 = 28 + (–7) + 8

Step 2: Add the terms.

28 + (–7) + 8 = 21 + 8

Step 3: Find the value.

21 + 8 = 29

Final Answer: 28 – 7 + 8 = 29

13. Evaluate 48 – 10 × 2 + 16 ÷ 2.

The value is 36.

Step 1: Identify the terms.

48 + (–10 × 2) + (16 ÷ 2)

Step 2: Evaluate each term.

–10 × 2 = –20
16 ÷ 2 = 8

Step 3: Add the terms.

48 – 20 + 8 = 36

Final Answer: 48 – 10 × 2 + 16 ÷ 2 = 36

14. Evaluate 6 × 3 – 4 × 8 × 5.

The value is –142.

Step 1: Identify the terms.

(6 × 3) + (–4 × 8 × 5)

Step 2: Evaluate each term.

6 × 3 = 18
4 × 8 × 5 = 160

Step 3: Add with signs.

18 – 160 = –142

Final Answer: 6 × 3 – 4 × 8 × 5 = –142

Brackets In Arithmetic Expressions Class 7 Questions With Step-By-Step Solutions

Brackets decide which part of an expression must be evaluated first. In Ganita Prakash Class 7 Chapter 2 Arithmetic Expressions, this prevents mistakes like reading 30 + 5 × 4 as (30 + 5) × 4.

15. Why is 30 + 5 × 4 equal to 50?

30 + 5 × 4 is equal to 50 because 5 × 4 forms one term.

Step 1: Evaluate the multiplication term first.

5 × 4 = 20

Step 2: Add it to 30.

30 + 20 = 50

Final Answer: 30 + 5 × 4 = 50

16. Evaluate 30 + (5 × 4).

The value is 50.

Step 1: Solve the bracket first.

5 × 4 = 20

Step 2: Add 30.

30 + 20 = 50

Final Answer: 30 + (5 × 4) = 50

17. Evaluate (30 + 5) × 4.

The value is 140.

Step 1: Solve the bracket first.

30 + 5 = 35

Step 2: Multiply by 4.

35 × 4 = 140

Final Answer: (30 + 5) × 4 = 140

18. Why are 30 + (5 × 4) and (30 + 5) × 4 different?

They are different because the brackets group different operations.

In 30 + (5 × 4), multiply first.

30 + 20 = 50

In (30 + 5) × 4, add first.

35 × 4 = 140

Final Answer: 30 + (5 × 4) ≠ (30 + 5) × 4

Removing Brackets Class 7 Questions For CBSE 2026 Practice

A minus sign before brackets changes the signs inside the brackets. These Arithmetic Expressions Class 7 Extra Questions are important for school tests.

19. Remove the brackets: 200 – (40 + 3).

The expression without brackets is 200 – 40 – 3.

  1. The bracket has 40 + 3.
  2. A minus sign comes before the bracket.
  3. Both signs inside change.

Expression:

200 – (40 + 3) = 200 – 40 – 3

Calculation:

200 – 40 – 3 = 157

Final Answer: 200 – (40 + 3) = 157

20. Remove the brackets: 100 – (15 + 56).

The expression without brackets is 100 – 15 – 56.

  1. The bracket contains 15 + 56.
  2. The minus sign changes both signs.
  3. Then subtract both amounts.

Calculation:

100 – (15 + 56) = 100 – 15 – 56
= 85 – 56
= 29

Final Answer: 100 – (15 + 56) = 29

21. Remove the brackets: 500 – (250 – 100).

The expression without brackets is 500 – 250 + 100.

  1. The bracket contains 250 – 100.
  2. A minus sign comes before the bracket.
  3. The sign of 250 becomes negative.
  4. The sign of –100 becomes positive.

Calculation:

500 – (250 – 100) = 500 – 250 + 100
= 250 + 100
= 350

Final Answer: 500 – (250 – 100) = 350

22. Remove the brackets: 14 – (12 + 10).

The expression without brackets is 14 – 12 – 10.

  1. The bracket has two positive terms.
  2. The minus sign changes both signs.
  3. Now subtract both values.

Calculation:

14 – (12 + 10) = 14 – 12 – 10
= 2 – 10
= –8

Final Answer: 14 – (12 + 10) = –8

23. Remove the brackets: 14 – (12 – 10).

The expression without brackets is 14 – 12 + 10.

  1. The sign before 12 changes to minus.
  2. The sign before 10 changes to plus.
  3. Add and subtract in order.

Calculation:

14 – (12 – 10) = 14 – 12 + 10
= 2 + 10
= 12

Final Answer: 14 – (12 – 10) = 12

Distributive Property Class 7 Questions With Solved Examples

The distributive property helps students multiply faster by splitting numbers. These questions also support Class 7 Maths Chapter 2 Solutions and revision before tests.

24. Expand 2 × (43 + 24) using distributive property.

The expanded form is 2 × 43 + 2 × 24.

Step 1: Multiply 2 with each term inside brackets.

2 × (43 + 24) = 2 × 43 + 2 × 24

Step 2: Calculate both products.

2 × 43 = 86
2 × 24 = 48

Step 3: Add the results.

86 + 48 = 134

Final Answer: 2 × (43 + 24) = 134

25. Expand (4 + 3) × 5.

The expanded form is 4 × 5 + 3 × 5.

Step 1: Multiply each term by 5.

(4 + 3) × 5 = 4 × 5 + 3 × 5

Step 2: Calculate both products.

4 × 5 = 20
3 × 5 = 15

Step 3: Add both values.

20 + 15 = 35

Final Answer: (4 + 3) × 5 = 35

26. Use distributive property to find 97 × 25.

The value is 2425.

Step 1: Write 97 as 100 – 3.

97 × 25 = (100 – 3) × 25

Step 2: Apply distributive property.

(100 – 3) × 25 = 100 × 25 – 3 × 25

Step 3: Calculate.

100 × 25 = 2500
3 × 25 = 75

Step 4: Subtract.

2500 – 75 = 2425

Final Answer: 97 × 25 = 2425

27. Use distributive property to find 104 × 15.

The value is 1560.

Step 1: Write 104 as 100 + 4.

104 × 15 = (100 + 4) × 15

Step 2: Apply distributive property.

(100 + 4) × 15 = 100 × 15 + 4 × 15

Step 3: Calculate.

1500 + 60 = 1560

Final Answer: 104 × 15 = 1560

28. Compare 23 × (17 – 9) and 23 × 17 + 23 × 9.

23 × (17 – 9) is less.

Step 1: Expand the left expression.

23 × (17 – 9) = 23 × 17 – 23 × 9

Step 2: Compare with the right expression.

23 × 17 + 23 × 9

Subtraction gives a smaller value than addition.

Final Answer: 23 × (17 – 9) < 23 × 17 + 23 × 9

Class 7 Maths Chapter 2 Extra Questions For School Exam Practice

Mixed practice helps students handle 1-mark, 2-mark, 3-mark, and 5-mark questions. This set works like an Arithmetic Expressions Worksheet Class 7 for CBSE 2026 revision.

29. Write an expression for four adults and three children travelling by metro.

The expression is 4 × 40 + 3 × 20.

Given Data:

  1. Adult ticket = ₹40
  2. Child ticket = ₹20
  3. Adults = 4
  4. Children = 3

Formula Used:

Total cost = Number of adults × Adult fare + Number of children × Child fare

Calculation:

4 × 40 + 3 × 20 = 160 + 60
= 220

Final Answer: The total cost is ₹220.

30. Binu earns ₹20,000 monthly and spends ₹12,000 monthly. Find her yearly saving.

Binu saves ₹96,000 in one year.

Given Data:

  1. Monthly income = ₹20,000
  2. Monthly expenses = ₹5,000 + ₹5,000 + ₹2,000
  3. Number of months = 12

Formula Used:

Yearly saving = 12 × Income – 12 × Expenses

Calculation:

12 × 20,000 – 12 × (5,000 + 5,000 + 2,000)
= 2,40,000 – 1,44,000
= 96,000

Final Answer: Binu saves ₹96,000 in one year.

31. A snail climbs 3 cm in the day and slips 2 cm at night. When will it reach a 10 cm post?

The snail reaches the top on the 8th day.

Given Data:

  1. Day climb = 3 cm
  2. Night slip = 2 cm
  3. Post height = 10 cm

Reasoning:

  1. In one full day-night cycle, the snail gains 1 cm.
  2. After 7 full cycles, it reaches 7 cm.
  3. On the 8th day, it climbs 3 cm.

Calculation:

7 × (3 – 2) + 3 = 7 + 3
= 10 cm

Final Answer: The snail reaches the top on the 8th day.

32. Identify expressions equal to 83 – 37 – 12.

The equal expressions are 84 – 38 – 12 and –37 + 83 – 12.

  1. 84 – 38 – 12 keeps the same difference as 83 – 37 – 12.
  2. –37 + 83 – 12 has the same terms in a different order.
  3. Changing the order of addition terms does not change the value.

Final Answer: 84 – 38 – 12 and –37 + 83 – 12

33. Choose a number and create five expressions with the same value.

Let the chosen number be 24.

12 + 12 = 24
30 – 6 = 24
4 × 6 = 24
48 ÷ 2 = 24
20 + 4 = 24

Final Answer: Five expressions with value 24 are shown above.

NCERT Class 7 Maths Chapter 2 Questions For Quick Revision

NCERT-style questions check whether students can explain their steps, not only write final answers. These Class 7 Maths Chapter 2 Questions And Answers support daily revision after school.

34. Why does subtraction become addition of the inverse?

Subtraction becomes addition of the inverse because both give the same change in value.

Example:

18 – 10 = 8
18 + (–10) = 8

  1. Subtracting 10 reduces the number by 10.
  2. Adding –10 also reduces the number by 10.
  3. Both expressions have the same value.

Final Answer: a – b = a + (–b)

35. Does changing the order of addition terms change the value?

Changing the order of addition terms does not change the value.

Example:

14 + 10 + (–5) = 19
(–5) + 10 + 14 = 19

  1. Addition allows terms to change order.
  2. This is the commutative property of addition.
  3. The final sum stays the same.

Final Answer: Addition terms can change order without changing the value.

36. Why is 5 × 4 + 3 not equal to 5 × (4 + 3)?

They are unequal because brackets change the grouped operation.

First expression:

5 × 4 + 3 = 20 + 3 = 23

Second expression:

5 × (4 + 3) = 5 × 7 = 35

Final Answer: 5 × 4 + 3 ≠ 5 × (4 + 3)

Arithmetic Expressions Class 7 Solutions For 3-Mark And 5-Mark Questions

Long-answer questions usually combine expression writing, bracket use, and calculation. These Class 7 Maths Arithmetic Expressions Questions improve step-by-step answer writing.

37. A vendor sells 15 apples at ₹12 each and 10 oranges at ₹8 each. He spends ₹50 on transport. Find his net earning.

The vendor’s net earning is ₹210.

Given Data:

  1. Apples = 15
  2. Price per apple = ₹12
  3. Oranges = 10
  4. Price per orange = ₹8
  5. Transport cost = ₹50

Formula Used:

Net earning = Apple earning + Orange earning – Transport cost

Calculation:

15 × 12 + 10 × 8 – 50
= 180 + 80 – 50
= 210

Final Answer: The vendor’s net earning is ₹210.

38. Write a story for the expression 4 × 9 + 2 × 6 and find its value.

One story is about buying notebooks and pens.

Story:

A student buys 4 notebooks at ₹9 each and 2 pens at ₹6 each.

Calculation:

4 × 9 + 2 × 6
= 36 + 12
= 48

Final Answer: The total cost is ₹48.

39. Add brackets to make 34 – 9 + 12 = 13.

The correct expression is 34 – (9 + 12) = 13.

Step 1: The required value is 13.

Step 2: Add 9 and 12 first.

9 + 12 = 21

Step 3: Subtract from 34.

34 – 21 = 13

Final Answer: 34 – (9 + 12) = 13

40. Find the value of 1 – 2 + 3 – 4 + 5 – 6 + 7 – 8 + 9 – 10.

The value is –5.

Step 1: Group positive terms.

1 + 3 + 5 + 7 + 9 = 25

Step 2: Group negative terms.

–2 – 4 – 6 – 8 – 10 = –30

Step 3: Add both groups.

25 + (–30) = –5

Final Answer: The value is –5.

Class 7 Maths Important Links

Resource Link
Important Questions Class 7 Maths Important Questions Class 7 Maths
CBSE Important Questions Class 7 CBSE Important Questions Class 7
CBSE Class 7 Maths Revision Notes CBSE Class 7 Maths Revision Notes
CBSE Class 7 Maths Chapter 1 Notes CBSE Class 7 Maths Chapter 1 Notes
CBSE Class 7 Syllabus CBSE Class 7 Syllabus
CBSE Sample Papers for Class 7 CBSE Sample Papers for Class 7

Q.1

What is the value of the following expression?0.10.01+0.010.1

1.10.10

2.10.01

3.1.10

4.1.01

Marks:1

Ans Option1
Explanation

0.10.01+0.010.1=10+110=10+0.1=10.1

Q.2 What is the value of 10.05 × 1.05?

1. 10.5125

2. 10.5525

3. 10.5515

4. 10.5425

Marks:1

Ans Option2
Explanation

1005 × 105 = 105525

Since 10.05 has 2 digits and 1.05 has 2 digits after the decimal point, therefore, the product must have 4 digits after decimal point.

10.05 × 1.05 = 10.5525

Q.3 Bob has given half of the whole cake to his sister Maria. Maria further divided it into three parts, ate only one part and kept the rest two parts in the fridge for later. What part of the whole cake has she kept in the fridge?

23

13

16

32

Marks:1

Ans Option2
Explanation

Share=12The part which Maria ate=12÷3Remaining part=12−16=3−16=26=13

Q.4

4+35−27

Marks:1
Ans

L.C.M of 1, 5, 7 = 35

∴  4+35−27=140+21−1035 =15135

Q.5  What is the expanded form of 205.149?

Marks:1

2×1000+0×100+5×10+1×110+4×1100+9×11000 2×100+0×10+5×1+1×1+4×110+9×1100 1×100+4×10+9×1+2×110+0×1100+5×11000  2×100+0×10+5×1+1×110+4×1100+9×11000

Ans Option4
Explanation

Hundreds
(100)		 Tens
(10)		 Ones
(1)		 Tenths

110

 Hundredths

1100

 Thousandths

11000
2 0 5 1 4 9

The expanded form of 205.149 is:2×100+0×10+5×1+1×110+4×1100+9×11000

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FAQs (Frequently Asked Questions)

To solve arithmetic expressions Class 7, first solve brackets, then evaluate multiplication or division terms, and finally add the terms. For example, 30 + 5 × 4 = 30 + 20 = 50.

To remove brackets in Class 7 Maths, check the sign before the bracket. If there is a minus sign, change the signs inside, as in 14 – (12 – 10) = 14 – 12 + 10.

Terms in arithmetic expressions Class 7 are the parts separated by plus signs after rewriting subtraction. For example, 39 – 2 × 6 + 11 has terms 39, –2 × 6, and 11.

To compare arithmetic expressions Class 7, compare how each number changes instead of solving fully. For example, 273 – 145 = 272 – 144 because the first expression starts 1 higher and subtracts 1 more.

Important questions in arithmetic expressions Class 7 include writing expressions, finding values, comparing expressions, identifying terms, removing brackets, and applying distributive property. These are the main CBSE 2026 question types from Chapter 2.