Class 6 Maths Chapter 6 Perimeter and Area is part of the new NCERT textbook Ganita Prakash. It teaches students how to find the distance around a shape (its perimeter) and the space a shape covers (its area). Students learn the perimeter of rectangles, squares, triangles and regular polygons, how to find area by counting unit squares, the area of rectangles and squares, and how the area of a triangle is half the area of a rectangle drawn around it.
These CBSE important questions for Class 6 Maths Chapter 6 cover multiple choice questions, area on a grid, comparing perimeter and area, and real-life word problems such as running around a park, fencing a garden, tiling a floor and framing a photograph. Every question has a clear step-by-step answer in simple English, so students can practise on their own, parents can check the working, and teachers can use them for class tests. A free printable PDF of these important questions is also available on this page.
CBSE Important Questions Class 6 Maths Chapter 6 – Perimeter and Area



Find out the length of the boundary (i.e., the perimeter) of each of the other arrangements below.

(a) Which rectangle has the greatest perimeter?
(b) Which rectangle has the least perimeter?
(c) If you take a rectangle of area 32 sq cm, what will your answers be? Given any area, is it possible to predict the shape of the rectangle with the greatest perimeter as well as the least perimeter? Give examples and reasons for your answer

(a) Mark ‘A’ at the point where Akshi will be after she runs 250 m.
[Hint: In the tangram pieces, by placing the shapes over each other, we can find out that Shapes A and B have the same area, and Shapes C and E have the same area. You would have also figured out that Shape D can be exactly covered using Shapes C and E, which means Shape D has twice the area of Shape C or Shape E, etc.]

Q1. What is the perimeter of a rectangle whose length is 12 cm and breadth is 8 cm?
(a) 20 cm
(b) 40 cm
(c) 96 cm
(d) 48 cm
Answer: (b) 40 cm
Perimeter of a rectangle = 2 × (length + breadth)
= 2 × (12 cm + 8 cm) = 2 × 20 cm = 40 cm
Q2. The side of a square is 9 m. What is its area?
(a) 36 sq m
(b) 18 sq m
(c) 81 sq m
(d) 81 m
Answer: (c) 81 sq m
Area of a square = side × side = 9 m × 9 m = 81 sq m.
Area is always written in square units, so option (d) 81 m is not correct.
Q3. Each side of an equilateral triangle is 7 cm. What is its perimeter?
(a) 14 cm
(b) 21 cm
(c) 49 cm
(d) 28 cm
Answer: (b) 21 cm
An equilateral triangle has three equal sides.
Perimeter = 3 × side = 3 × 7 cm = 21 cm
Q4. The perimeter of a square park is 64 m. What is the length of each side?
(a) 8 m
(b) 32 m
(c) 16 m
(d) 256 m
Answer: (c) 16 m
Perimeter of a square = 4 × side
So, side = perimeter ÷ 4 = 64 m ÷ 4 = 16 m
Q5. Find the area of the shape drawn on the grid. Each small square is 1 square unit.
(a) 10 square units
(b) 11 square units
(c) 12 square units
(d) 13 square units

Answer: (b) 11 square units
Count the full squares: the body of the house has 3 × 3 = 9 squares, and there is 1 more square in the roof. So there are 10 full squares.
The roof also has 2 half squares (the triangles). 2 half squares = 1 full square.
Area = 10 + 1 = 11 square units
Q6. Look at rectangles A (6 cm × 4 cm) and B (8 cm × 3 cm). Which statement is true?
(a) They have the same area and the same perimeter
(b) They have the same area but different perimeters
(c) They have different areas but the same perimeter
(d) They have different areas and different perimeters

Answer: (b) They have the same area but different perimeters
Area of A = 6 × 4 = 24 sq cm; Area of B = 8 × 3 = 24 sq cm. The areas are equal.
Perimeter of A = 2 × (6 + 4) = 20 cm; Perimeter of B = 2 × (8 + 3) = 22 cm. The perimeters are different.
So shapes with the same area can have different perimeters.
Q7. Triangle PQR is drawn on a grid of unit squares. What is its area?
(a) 24 square units
(b) 12 square units
(c) 10 square units
(d) 20 square units

Answer: (b) 12 square units
The dotted lines complete a rectangle of 6 units × 4 units around the triangle.
Area of the rectangle = 6 × 4 = 24 square units.
The diagonal PR cuts the rectangle into two equal triangles, so the area of triangle PQR = 24 ÷ 2 = 12 square units.
Q8. A regular hexagon has each side 5 cm long. What is its perimeter?
(a) 25 cm
(b) 30 cm
(c) 35 cm
(d) 20 cm
Answer: (b) 30 cm
A regular hexagon has 6 equal sides.
Perimeter = 6 × side = 6 × 5 cm = 30 cm
Q9. Meera takes 3 rounds of a rectangular park that is 80 m long and 45 m wide. How much distance does she cover?

Answer: Meera covers 750 m.
Distance covered in 1 round = perimeter of the park
= 2 × (80 m + 45 m) = 2 × 125 m = 250 m
Distance covered in 3 rounds = 3 × 250 m = 750 m
Q10. A square garden has a side of 25 m. Find the cost of fencing it all around at the rate of ₹40 per metre.
Answer: The cost of fencing is ₹4,000.
Length of fence needed = perimeter of the garden = 4 × 25 m = 100 m
Cost of fencing = 100 × ₹40 = ₹4,000
Q11. The area of a rectangle is 96 sq cm and its length is 12 cm. Find its breadth and perimeter.
Answer: Breadth = 8 cm; Perimeter = 40 cm
Area = length × breadth ⇒ 96 = 12 × breadth
Breadth = 96 ÷ 12 = 8 cm
Perimeter = 2 × (12 cm + 8 cm) = 2 × 20 cm = 40 cm
Q12. A room floor is 6 m long and 4 m wide. It is to be covered with square tiles of side 50 cm. How many tiles are needed? If each tile costs ₹45, find the total cost of the tiles.
Answer: 96 tiles are needed and the total cost is ₹4,320.
Side of each tile = 50 cm = 0.5 m
Tiles along the length = 6 m ÷ 0.5 m = 12; tiles along the width = 4 m ÷ 0.5 m = 8
Number of tiles = 12 × 8 = 96
(Check: area of floor = 6 × 4 = 24 sq m; area of one tile = 0.5 × 0.5 = 0.25 sq m; 24 ÷ 0.25 = 96)
Total cost = 96 × ₹45 = ₹4,320

Q13. A wire 36 cm long is bent to form a square. The same wire is then straightened and bent to form a rectangle of length 12 cm. Which shape encloses more area, and by how much?
Answer: The square encloses more area, by 9 sq cm.
The perimeter of both shapes is equal to the length of the wire, 36 cm.
Square: side = 36 ÷ 4 = 9 cm; area = 9 × 9 = 81 sq cm
Rectangle: 2 × (12 + breadth) = 36 ⇒ 12 + breadth = 18 ⇒ breadth = 6 cm; area = 12 × 6 = 72 sq cm
Difference = 81 − 72 = 9 sq cm

Q14. Draw all the rectangles with whole-number sides (in cm) that have a perimeter of 20 cm. Which of them has the greatest area?
Answer: The 5 cm × 5 cm square has the greatest area (25 sq cm).
Perimeter = 2 × (length + breadth) = 20 cm, so length + breadth = 10 cm.
Possible sides: 9 × 1, 8 × 2, 7 × 3, 6 × 4 and 5 × 5
Their areas: 9, 16, 21, 24 and 25 sq cm
All five have the same perimeter, but the area grows as the sides become closer to each other. The square has the greatest area.

Q15. A photograph 20 cm long and 15 cm wide is pasted on a card, leaving a border of 2 cm all around it. Find (i) the length and width of the card, (ii) the area of the border.
Answer: (i) 24 cm × 19 cm (ii) 156 sq cm
(i) The border adds 2 cm on each side. Length of card = 20 + 2 + 2 = 24 cm; width of card = 15 + 2 + 2 = 19 cm
(ii) Area of card = 24 × 19 = 456 sq cm; area of photograph = 20 × 15 = 300 sq cm
Area of border = 456 − 300 = 156 sq cm

Related Study Material on Extramarks
- CBSE Important Questions Class 6 Maths Chapter 1
- CBSE Important Questions Class 6 Maths Chapter 2
- CBSE Important Questions Class 6 Maths Chapter 3
- CBSE Important Questions Class 6 Maths Chapter 4
- CBSE Important Questions Class 6 Maths Chapter 5
- CBSE Important Questions Class 6 Maths Chapter 7
- CBSE Important Questions Class 6 Maths Chapter 8
- CBSE Important Questions Class 6 Maths Chapter 9
- CBSE Important Questions Class 6 Maths Chapter 10











