Important Questions Class 6 Maths Chapter 1
Class 6 Maths Chapter 1 Important Questions – Knowing Our Numbers
Maths is an important subject we study in school. In Class 6, students will learn the basics of the subject, which will be needed in higher classes. The first chapter is about learning numbers. Maths deals with numbers, and students must identify numbers.
In this chapter, students will study larger numbers like thousands, lakhs, etc. They will learn how to express these numbers with the help of commas. The chapter also includes addition and subtraction of larger numbers, how to find the largest among given numbers, etc. This is an easy chapter, but students must practice questions to build their concepts.
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Also, get access to CBSE Class 6 Maths Important Questions for other chapters too:
CBSE Important Questions for Class 6 Maths |
||
Sr No | Chapter No | Chapter Name |
1 | Chapter 1 | Knowing Our Numbers |
2 | Chapter 2 | Whole Numbers |
3 | Chapter 3 | Playing with Numbers |
4 | Chapter 4 | Basic Geometrical Ideas |
5 | Chapter 5 | Understanding Elementary Shapes |
6 | Chapter 6 | Integers |
7 | Chapter 7 | Fractions |
8 | Chapter 8 | Decimals |
9 | Chapter 9 | Data Handling |
10 | Chapter 10 | Mensuration |
11 | Chapter 11 | Algebra |
12 | Chapter 12 | Ratio and Proportion |
13 | Chapter 13 | Symmetry |
14 | Chapter 14 | Practical Geometry |
Knowing Our Numbers Class 6 Extra Questions with Solutions
Our experts have made the question series to help students. They have collected the questions from textbook exercises, CBSE sample papers, CBSE past years’ question papers, NCERT Exemplars, and important reference books. They have also solved the questions so that students can follow the answers. Experienced professionals have further checked the solutions to ensure the best quality of the content. Thus, the Important Questions Class 6 Maths Chapter 1 will help students score better in exams. The important questions are-
Question 1.
Fill in the blanks:
(i) One lakh = ………….. ten thousand.
(ii) 1 million = ………… hundred thousand.
(iii) 1 crore = ………… ten lakh.
(iv) 1 crore = ………… million.
(v) 1 million = ………… lakh.
Answer 1.
(i) 1 lakh = ten ten thousand.
(ii) 1 million = ten hundred thousand.
(iii) 1 crore = ten ten lakh
(iv) 1 crore = ten million
(v) 1 million = ten lakh
Question 2.
Fill in the blanks:
(i) 1 metre = ____millimetres.
(ii) 1 centimetre = ____ millimetres.
(iii) 1 kilometre = ____ millimetres.
Answer 2.
(i) 1000,
(ii) 10,
(iii) 10, 00, 000
Question 3.
Fill in the blanks:
(i) 1 gram = ___ milligrams.
(ii) 1 litre = ___ millilitres.
(iii) 1 kilogram = ___ milligrams.
Answer 3.
(i) 1000,
(ii) 1000,
(iii) 10,00,000
Question 4.
Place the commas correctly and write the numerals :
(i) Seventy-three lakh seventy-five thousand three hundred seven.
(ii) Nine crore five lakh forty-one.
(iii) Seven crore fifty-two lakh twenty-one thousand three hundred two.
(iv) Fifty-eight million four hundred twenty- three thousand two hundred two.
(v) Twenty-three lakh thirty thousand ten.
Answer 4.
(i) 73,75,307
(ii) 9,05,00,041
(iii) 7,52,21,302
(iv) 5,84,23,202
(v) 23,30,010.
Question 5.
Insert commas in the numbers suitably and write their names according to the Indian System of Numeration:
(i) 87595762
(ii) 8546283
(iii) 99900046
(iv) 98432701
Answer 5.
(i) 8,75,95,762 (Eight crore seventy-five lakh ninety-five thousand seven hundred sixty- two)
(ii) 85,46,283 (Eighty-five lakh forty-six thousand two hundred eighty-three)
(iii) 9,99,00,046 (Nine crore ninety-nine lakh forty-six)
(iv) 9,84,32,701 (Nine crores eighty-four lakh thirty-two thousand seven hundred one)
Question 6.
Insert commas in the numbers suitably and write their names according to the International System of Numeration:
(i) 78921092
(ii) 7452283
(iii) 99985102
(iv) 48049831
Answer 6.
(i) 78,921,092 (Seventy-eight million nine hundred twenty-one thousand ninety-two)
(ii) 7,452,283 (Seven million four hundred fifty- two thousand two hundred eighty-three)
(iii) 99,985,102 (Ninety-nine million nine hundred eighty-five thousand one hundred two)
(iv) 48,049,831 (Forty-eight million forty-nine thousand eight hundred thirty-one)
Question 7.
A number in which the Sum of all of its factors is equal to twice the number is called a ___ number.
Answer 7.
Perfect
Question 8.
The numbers which have more than just two factors are called ___ numbers.
Answer 8.
Composite
Question 9.
Two is the only ___ number which is even.
Answer 9.
Prime
Question 10.
Two numbers having only one as a common factor are called ___ numbers.
Answer 10.
Co-prime
Question 11.
The Lowest Common Multiple ( LCM) of two or more given numbers is always the lowest of their common ___.
Answer 11.
Multiple
Question 12.
The Highest Common Factor (HCF) of two or more than two given numbers is also known as the highest of their common ___.
Answer 12.
Factors
Question 13.
The product of the place values of the two 2’s in 428721 is
(i) 4
(ii) 40000
(iii) 400000
(iv) 40000000
Answer 13.
(iii): Place the values of 2’s in 428721 are 20000 and 20
∴ The required product = 20000 × 2 = 400000
Question 14.
Number 3 × 10000 + 7 × 1000 + 9 × 100 + 0 × 10 + 4 is the same as
(i) 3794
(ii) 37940
(iii) 37904
(iv) 379409
Answer 14.
(ii) : 3 × 10000 + 7 × 1000 + 9 × 100 + 0 × 10 + 4
= 30000 + 7000 + 900 + 4 = 37904
Question 15.
If one is added to the greatest 7-digit number, then it will be equal to
(i) 10 thousand
(ii) 1 lakh
(iii) 10 lakh
(iv) One crore
Answer 15.
(iv) : The greatest 7-digit number = 99,99,999
Now, 99,99,999 + 1 = 1,00,00,000
Question 16.
The greatest number in which on rounding off to the nearest thousands gives 5000, is
(i) 5001
(ii) 5559
(iii) 5999
(iv) 5499
Answer 16.
(iv) : (1) Rounding off 5001 to nearest thousands = 5000
(2) Rounding off 5559 to nearest thousands = 6000
(3) Rounding off 5999 to nearest thousands = 6000
(4) Rounding off 5499 to nearest thousands = 5000
And 5499 > 5001
Question 17.
Keeping the place of six in the number 6350947 same, the smallest number which can be obtained by rearranging other digits is
(i) 6975430
(ii) 6043579
(iii) 6034579
(iv) 6034759
Answer 17.
(iii) : Tire new number formed = 6034579
Question 18.
The smallest four-digit number having three different digits is
(i) 1102
(ii) 1012
(iii) 1020
(iv) 1002
Answer 18.
(iv): The smallest 4-digit number with three different digits is 1002.
Question 19.
The number of all the whole numbers between 38 and 68 is
(i) 31
(ii) 30
(iii) 29
(iv) 28
Answer 19.
(iii): There are 29 whole numbers between 38 and 68.
Question 20.
The product of the successor and the predecessor of 999 is
(i) 999000
(ii) 998000
(iii) 989000
(iv) 1998
Answer 20.
(ii) : Successor of the number 999 = 999 + 1 = 1000
Predecessor of the number 999 = 999 – 1 = 998
Hence, their product = 998 1000 = 998000
Question 21.
Write in expanded form :
(i) 74836
(ii) 574021
(iii) 8907010
Answer 21.
(i) 74836 is equal to = 7 × 10000 + 4 × 1000 + 8 × 100 + 3 × 10 + 6 × 1
(ii) 574021 is equal to = 5 × 100000 + 7 × 10000 + 4 x 1000 + 0 × 100 + 2 × 10 + 1 × 1
(iii) 8907010 is equal to = 8 × 1000000 + 9 × 100000 + 0 × 10000 + 7 × 1000 + 0 × 100 + 1 × 10 + 0 × 1
Question 22.
A book exhibition was held for 4 days in a school. The number of the tickets sold on the counter on the first, second, third, and the final day was – 1094, 1812, 2050, and 2751. Find the total number of tickets that sold on all four days.
Answer 22.
Number of the tickets sold on the first day = 1094
Number of the tickets sold on the second day = 1812
Number of the tickets sold on the third day = 2050
Number of the tickets sold on the final day = 2751
∴Total number of the tickets sold on all of these four days = 1094 + 1812 + 2050 + 2751 = 7,707.
Question 23.
Shekhar is a famous cricket player. He has so far scored a total of 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?
Answer 23.
Shekhar has so far scored a total of 6980 runs
He wishes to complete a total of 10,000 runs.
Therefore total number of the runs needed by him are = 10,000 – 6980 = 3020 runs
Question 24.
Which of the following given statements is not true?
(i) Both the addition and multiplication are associative for whole numbers.
(ii) Zero is the identity for the multiplication of whole numbers.
(iii) Addition and multiplication are commutative for whole numbers.
(iv) Multiplication is distributive over addition for whole numbers.
Answer 24.
(ii): Zero is the identity for the addition of whole numbers.
Question 25.
Which of the following given statements is not true?
(i) 0 + 0 = 0
(ii) 0 – 0 = 0
(iii) 0 × 0 = 0
(iv) 0 – 0 = 0
Answer 25.
(iv) : 0 + 0 is not defined.
Question 26.
The predecessor of 1 lakh is
(i) 99000
(ii) 99999
(iii) 999999
(iv) 100001
Answer 26.
(ii) : 1 lakh = 100000
∴ Predecessor of 100000 = 100000 – 1 = 99999
Question 27.
The successor of 1 million is
(i) Two million
(ii) 1000001
(iii) 100001
(iv) 10001
Answer 27.
(ii) : 1 million = 1000000
∴ Successor of 1000000 = 1000000 + 1 = 1000001
Question 28.
The number of all the even numbers between 58 and 80 is
(i) 10
(ii) 11
(iii) 12
(iv) 13
Answer 28.
(i) : Even numbers between the numbers 58 and 80 are 60, 62, 64, 66, 68, 70, 72, 74, 76, 78.
So, these are ten even numbers between 58 and 80.
Question 29.
The Sum of the number of primes numbers between 16 to 80 and between 90 to 100 is
(i) 20
(ii) 18
(iii) 17
(iv) 16
Answer 29.
(iii) : Prime numbers between 16 to 80 are – 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73 and 79.
So, there are total 16 prime numbers between 16 to 80.
Also, 97 is the only one prime number between 90 to 100.
So, there is only one prime number between 90 to 100.
∴ Required sum = 16 + 1 = 17
Question 30.
Which of the following given statements is not true?
(i) The HCF of the two distinct prime numbers is 1
(ii) The HCF of two coprime numbers is 1
(iii) The HCF of two consecutive even numbers is 2
(iv) The HCF of an even number and an odd number is always even
Answer 30.
(iv): The HCF of an even and an odd number is always said to be an odd number.
Question 31.
In an election, the successful candidate was registered 5,77,500 votes, and his nearest rival had secured 3,48,700 votes. By what total margin did the successful candidate win the election?
Answer 31.
Number of the votes secured by the successful candidate = 5,77,500
Number of the votes secured by his nearest rival = 3,48,700
Therefore, margin of the votes is necessary to win the election = 5,77,500 – 3,48,700 = 2,28,800
Question 32.
Kirti bookstore sold books worth a total of ₹2,85,891 in the 1st week of June and books worth a total of ₹4,00,768 in the second week of the month. How much was the total sale for the two weeks together? And in which week was the total sale greater and by how much?
Answer 32.
Books sold in the first week of the month June are worth ₹2,85,891
Books sold in the second week of the month are worth ₹4,00,768
Therefore, the total sale of the books in the two weeks together is
= ₹2,85,891 + ₹4,00,768 = ₹6,86,659
In the 2nd week of the month, the sale of total books was greater.
Therefore, the difference in the sale of books
= ₹4,00,768 – ₹2,85,891 = ₹1,14,877
So, in the second week of June, the total sale of books was more than ₹1,14,877.
Question 33.
Find the difference below between the highest and the lowest numbers that is written using the digits 6, 2, 7, 4, and 3, each only once.
Answer 33.
Given digits = 6, 2, 7, 4, 3
Greatest number is = 76432
Least number is = 23467
Therefore, difference = 76432 – 23467 = 52,965
Question 34.
A machine, on average, manufactures 2,825 screws a day. How many screws did it produce in January 2006?
Answer 34.
The number of screws that are manufactured in a day = 2,825.
Number of screws that are manufactured in month of January = 31 x 2825 = 87,575
Question 35.
The total distance between the school and the house of a student is 1 km and 875 m. Every day she walks both the ways. Find the total distance she covered in six days.
Answer 35.
Distance between the school and her house = 1 km 875 m = (1000 + 875) m = 1875 metre.
Total Distance travelled by the student from school to home and from home to school is = 2 x 1875 = 3750 m
Distance travelled by the student in six days is = 3750 m x 6 – 22500 m = 22 km 500 m.
Therefore, the total distance covered in 6 days = 22 km 500 m.
Question 36.
A merchant had ₹78,592 with her. She placed an order to purchase 40 radio sets at ₹1200 each. How much total money will remain with her after the purchase?
Answer 36.
Amount of money present with the merchant = ₹78,592
Total Number of the radio sets = 40
Price of one of the radio set = ₹1200
Therefore, the cost of 40 radio sets = ₹1200 x 40 = ₹48,000
Remaining money left with the merchant = ₹78,592 – ₹48000 = ₹30,592
Hence, the amount of ₹30,592 will remain with her after purchasing the following radio sets.
Question 37.
A vessel has four litres and 500 ml of curd. How many total glasses, each of 25 mL capacity, can be filled?
Answer 37.
Quantity of the curd in a vessel = 4 l 500 mL = (4 x 1000 + 500) mL = 4500 mL.
Capacity of 1 glass = 25 mL
Therefore the number of glasses = 4500/25
= 180
Question 38.
A student has multiplied the number 7236 by 65 instead of multiplying by 56. Calculate by how much was his answer greater than the right answer?
Answer 38.
The student had multiplied the number 7236 by 65 instead of multiplying by 56.
The difference between the two above multiplications is = (65 – 56) x 7236 = 9 x 7236 = 65124
(We don’t have to do both the multiplication)
Hence, the answer that is greater than the correct answer is 65,124.
Question 39.
Estimate each of the following given numbers using the general rule:
(i) 730 + 998
(ii) 796 – 314
(iii) 12,904 + 2,888
(iv) 28,292 – 21,496
Answer 39.
(i) 730 + 998
Rounding off 730 nearest to hundreds = 700
Rounding off 998 nearest to hundreds = 1,000
∴ 730 + 998 = 700 + 1000 = 1700
(ii) 796 – 314
Rounding off 796 nearest to hundreds = 800
Rounding off 314 nearest to hundreds = 300
∴ 796 – 314 = 800 – 300 = 500
(iii) 12,904 + 2,888
Rounding off 12,904 nearest to thousands = 13000
Rounding off 2888 nearest to thousands = 3000
∴ 12,904 + 2,888 = 13000 + 3000 = 16000
(iv) 28,292 – 21,496
Rounding off 28,292 nearest to thousands = 28,000
Rounding off 21,496 nearest to thousands = 21,000
∴ 28,292 – 21,496 = 28,000 – 21,000 = 7,000
Question 40.
Estimate the following given products using the general rule:
(i) 578 x 161
(ii)5281 x 3491
(iii) 1291 x 592
(iv) 9250 x 29
Answer 40.
(i) 578 x 161 = 600 x 200 = 1,20,000
(ii) 5281 x 3491 = 5000 x 3000 = 1,50,00,000
(iii) 1291 x 592 = 1300 x 600 = 7,80,000
(iv) 9250 x 29 = 9000 x 30 = 2,70,000
Question 41.
Which of the following is not true?
(i) (7 + 8) + 9 = 7 + (8 + 9)
(ii) (7 × 8) × 9 = 7 × (8 × 9)
(iii) 7 + 8 × 9 = (7 + 8) × (7 + 9)
(iv) 7 × (8 + 9) = (7 × 8) + (7 × 9)
Answer 41.
(iii) : 7 + 8 × 9 = 7 + 72 = 79,
(7 + 8) × (7 + 9) = 15 × 16 = 240
and 79 ≠ 240
Question 42.
The length of the river ‘Narmada’ is 1290 km. Its length in metres is – _____.
Answer 42.
1290000
As, 1290 km = (1290 × 1000) m = 1290000 m
Question 43.
The total distance between Srinagar and Leh is 422 km. The same distance in metres is – _____.
Answer 43.
422000
As, 422 km= (422 × 1000) m = 422000 m
Question 44.
Writing numbers from the greatest to the smallest is called an arrangement in ___ order.
Answer 44.
Descending
Question 45.
By reversing the order of the digits of the greatest number made by the five different non-zero digits, we get the new number which is the number of _____ five digits.
Answer 45.
Smallest
By reversing the order of the digits of the greatest number made by the five different non-zero digits, the new number present is the smallest number of these digits.
Question 46.
By adding 1 to the greatest ___ digit number, we get the number ten lakh.
Answer 46.
6
As, greatest six-digit number = 999999
By adding one to 999999, we get 1000000.
Question 47.
The number five crore twenty-three lakh seventy-eight thousand four hundred one can also be written, using the commas, in the Indian System of Numeration as.
Answer 47.
5, 23, 78, 401
Question 48.
In the Roman Numeration, the symbol X can be subtracted from – ___, M and C only.
Answer 48.
L
Question 49.
The number 66 in Roman numerals is.
Answer 49.
LXVI : 66 = LXVI
Question 50.
The total population of Pune was 2,538,473 in 2001. Rounded off to the nearest thousands, the population was ___.
Answer 50.
2,538,000
Question 51.
The smallest whole number is ___.
Answer 51.
0 : 0 is the smallest whole number.
Question 52.
The successor of number 106159 is ___.
Answer 52.
106160
As, Successor of 106159 is 106159 + 1, i.e., 106160
Question 53.
400 is the predecessor of the number ___.
Answer 53.
401
As, 400 is the predecessor of 400 + 1, i.e., 401
Question 54.
___ is the successor of the largest three digit number.
Answer 54.
1000
As, Largest three digit number = 999
And the successor of 999 is 999 + 1, i.e., 1000
Question 55.
If the number 7254*98 is to be divisible by the number 22, then the digit at * is
(i) 1
(ii) 2
(iii) 6
(iv) 0
Answer 55.
(iii) : 7254 * 98 is divisible by the number 22 only if it is divisible by both 2 and 11.
Given that the number is even. Therefore it is divisible by the number 2.
7254 * 98 is divisible by 11, only if
(7 + 5 + * + 8) – (2 + 4 + 9) or (20 + *) – 15 or 5 + * is also divisible by 11.
∴ The digit at * place should be filled by 6.
Question 56.
The largest number which will always divide the Sum of any pair of consecutive odd numbers is
(i) 2
(ii) 4
(iii) 6
(iv) 8
Answer 56.
(ii)The Sum of any pair of the consecutive odd numbers results in the form of a multiple of 4.
∴ The required largest number is 4.
Question 57.
A number is divisible by five and six. It may not be divisible by
(i) 10
(ii) 15
(iii) 30
(iv) 60
Answer 57.
(iv): The Least Common Multiple also known as LCM of 5 and 6 is 30.
And also 30 is divisible by the numbers 10, 15 and 30 but not by the number 60.
Question 58.
The greatest number which will always divide the product of the predecessor and successor of an odd natural number other than 1, is
(i) 6
(ii) 4
(iii) 16
(iv) 8
Answer 58.
(ii): As the odd natural numbers other than 1 are – 3, 5, 7, 9 and so on.
Now, we know that the predecessor and successor of 3 are – 2 and 4 respectively, and their product is two × four = 8
Similarly, we know that the predecessor and the successor of 5 are – 4 and 6, respectively, and their product is four × 6 = 24.
Thus, the above shows that the greatest number which always divides the product of the predecessor and the successor of an odd natural number other than 1 is 4.
Question 59.
A person had only ₹ 1000000 with him. He purchased a coloured-T.V. for ₹ 16580, a motorcycle for ₹ 45890 and a flat for ₹ 870000. How much money was left with him?
Answer 59.
The total amount a person had was = ₹ 1000000
The total amount he spent on a colour T.V. was = ₹ 16580
The amount he spent on a motorcycle was = ₹ 45890
The amount he spent on a flat was = ₹ 870000
∴ Total amount he spent is = ₹ (16580 + 45890 + 870000) = ₹ 932470
Thus, the total amount left with him = ₹ 1000000 – ₹ 932470 = ₹ 67530
Question 60.
Out of 180000 tablets of Vitamin A, a total of 18734 are distributed among the students in the district. Find the total number of remaining vitamin tablets.
Answer 60.
Total tablets of Vitamin A are = 180000
Total number of tablets distributed among the students in the district = 18734
∴ The number of total remaining vitamin tablets = 180000 – 18734 = 161266
Question 61.
Chinmay only had ₹ 610000. He gave a total of ₹ 87500 to Jyoti, ₹ 126380 to Javed and ₹ 350000 to John. How much money was left with him?
Answer 61.
Chinmay had a total amount = of ₹ 610000
The total amount he gave to Jyoti = ₹ 87500
The total amount he gave to Javed = ₹ 126380
The total amount he gave to John = ₹ 350009
Total amount given by Chinmay is = ₹ (87500 + 126380 + 350000) = ₹ 563880
Thus, the amount left with him
= ₹ 610000 – ₹ 563880 = ₹ 46120
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Practise is very important, and it helps students in several ways. Our experts have made the question series to help students in practise. Thus, the questions will help students in several ways, and they will be worthy of their time. The benefits of solving the Important Questions Class 6 Maths Chapter 1 are as follows-
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Q.1 Which of the following is the representation of number 74 according to roman numerals?
(a). LXXIV
(b). XXXXXXXIV
(c). MLXVI
(d). DCCXLV
Marks:1
Ans(a). LXXIV
L=50
X=10
V=5
IV=4
LXX= 70
LXXIV=74
Q.2 What is the greatest 7 digit number formed by using the digits 4 , 9 , 1 and 6? Note that each digit should be used at least once.
(a). 99,99,641
(b). 9,641
(c). 99,66,441
(d). 11,11,469
Marks:1
Ans
(a). 99,99,641
Given digits:
9 > 6 > 4 > 1
The greatest 7 digit number using the digits 4, 9, 1 and 6 is 99,99,641.
Q.3 Which one of the following is the estimated product of 47 and 215?
(a) 11,000
(b) 10,000
(c) 10,150
(d) 10,500
Marks:1
Ans
(b) 10,000
Rounding off 215 to the nearest hundreds, we get 200.
Rounding off 47 to nearest tens, we get 50.
Estimated product
= 200 × 50
=10,000
Thus, 10,000 is the estimated product of 47 and 215.
Q.4 Write 645340001 using comma in International System of Numeration.
Marks:1
Ans
645,340,001
Q.5 a) How many thousands make a million?
b) How many lakhs make a crore?
Marks:2
Ans
a) 1000 thousands make 1 million. (? 1 million = 1,000,000 = 1000 thousands)
b) 100 lakhs make a crore. (? 1 crore = 1,00,00,000 = 100 lakhs)
CBSE Important Questions for Class 6 Maths
FAQs (Frequently Asked Questions)
1. Is Class 6 Maths Chapter 1 easy?
The first chapter of Class 6 Maths provides a few basic ideas related to numbers. They will learn how to express bigger numbers, such as in thousands, lakhs, crores, etc. They will also learn how to use commas to write larger number, add or subtract large numbers, etc. This is an easy chapter because most students have ideas regarding lakhs, crores, or other units of numbers. Thus, students won’t have problems understanding the subject matter if they follow the textbook closely. Students can take help from the Important Questions Class 6 Maths Chapter 1 prepared by the experts of Extramarks, and they will find a wide variety of questions to solve.
2. How can the question series help students?
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