CBSE Class 10 Maths Revision Notes Chapter 3 Pair of Linear Equations in Two Variables 2026–27

Pair of Linear Equations in Two Variables explains how two linear equations can be solved together to find common values of x and y.
For CBSE Class 10 Maths, this chapter covers graphical, substitution, elimination and cross multiplication methods.

Pair of Linear Equations in Two Variables deals with two equations that contain the same two variables. These equations help students solve real-life problems related to cost, age, distance, speed and quantity.

Use these CBSE Class 10 Maths Revision Notes Chapter 3 to revise the chapter in a clear order. Start with the meaning of a linear equation, then revise solution types, graphical method, substitution method, elimination method and cross multiplication method.

Key Takeaways

  • Linear equation: An equation where the highest power of each variable is 1.
  • General form: ax + by + c = 0, where a and b are not both zero.
  • Solution: A pair (x, y) that satisfies both equations.
  • Nature of lines: Intersecting lines give one solution, parallel lines give no solution and coincident lines give infinitely many solutions.

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CBSE Class 10 Maths Chapter 3 Pair of Linear Equations at a Glance

Chapter 3 connects equations with graphs and algebraic methods. The same pair of equations can be solved through graphs, substitution, elimination or cross multiplication.

Concept Meaning Quick Example
Linear equation Equation with degree 1 2x + y = 4
Solution Values of x and y that satisfy the equation (0, 4) satisfies 2x + y = 4
Pair of linear equations Two linear equations in x and y a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0
Consistent pair Pair with at least one solution Intersecting or coincident lines
Inconsistent pair Pair with no solution Parallel lines
Dependent pair Pair with infinitely many solutions Coincident lines

CBSE Class 10 Maths Chapter 3 revision notes showing intersecting linear equations and their solution point.

Linear Equation in Two Variables Class 10

A linear equation in two variables contains two variables with power 1. In Class 10 Maths Chapter 3 Notes, the variables are usually x and y.

The general form is:

ax + by + c = 0

Here:

  • a, b and c are real numbers.
  • a and b cannot be zero at the same time.
  • x and y are variables.

Copyable format:

ax + by + c = 0

a and b cannot be zero simultaneously.

Example:

2x + y - 4 = 0

This is a linear equation in two variables because the powers of x and y are 1.

Solution of a Linear Equation in Two Variables

A solution of a linear equation in two variables is an ordered pair (x, y) that makes the equation true. One linear equation in two variables can have infinitely many solutions.

Example:

2x + y = 4

Check (0, 4):

2(0) + 4 = 4

4 = 4

So, (0, 4) is a solution.

Check (1, 2):

2(1) + 2 = 4

4 = 4

So, (1, 2) is also a solution.

Copyable format:

If 2x + y = 4, then (0, 4) is a solution.

If 2x + y = 4, then (1, 2) is also a solution.

Pair of Linear Equations in Two Variables Class 10

A pair of linear equations in two variables means two equations in x and y considered together. The common solution satisfies both equations.

General form:

a1x + b1y + c1 = 0

a2x + b2y + c2 = 0

Here:

  • a1, b1, c1, a2, b2 and c2 are real numbers.
  • a1 and b1 are not both zero.
  • a2 and b2 are not both zero.

Example:

2x + y - 6 = 0

4x - 2y - 4 = 0

The solution of this pair is the point that satisfies both equations.

Graphical Method of Solution for Pair of Linear Equations

The graphical method of solution shows each linear equation as a straight line. The point where the two lines meet gives the solution.

Steps:

  • Write both equations in a form that helps find points.
  • Choose values of x and calculate values of y.
  • Plot two points for each equation.
  • Draw both straight lines.
  • Read the point of intersection.

Example:

2x + y - 6 = 0

4x - 2y - 4 = 0

The two lines intersect at (2, 2).

So, the solution is:

x = 2

y = 2

Copyable format:

Solution = point of intersection of the two lines

If the lines intersect at (2, 2), then x = 2 and y = 2.

Nature of Lines and Solution Conditions

The nature of two straight lines decides the number of solutions. This is a key part of CBSE Notes Class 10 Maths Chapter 3.

Nature of Lines Condition Number of Solutions Type of Pair
Intersecting lines a1/a2 ≠ b1/b2 One solution Consistent
Coincident lines a1/a2 = b1/b2 = c1/c2 Infinitely many solutions Dependent and consistent
Parallel lines a1/a2 = b1/b2 ≠ c1/c2 No solution Inconsistent

Copyable format:

If a1/a2 ≠ b1/b2, then the pair has a unique solution.

If a1/a2 = b1/b2 = c1/c2, then the pair has infinitely many solutions.

If a1/a2 = b1/b2 ≠ c1/c2, then the pair has no solution.

Consistent, Inconsistent and Dependent Pair of Linear Equations

A pair of linear equations is consistent when it has at least one solution. Intersecting and coincident lines are consistent.

A pair is inconsistent when it has no solution. Parallel lines are inconsistent.

A pair is dependent when both equations represent the same line. A dependent pair has infinitely many solutions.

Pair Type Meaning Graph
Consistent pair Has one or more solutions Intersecting or coincident lines
Inconsistent pair Has no solution Parallel lines
Dependent pair Has infinitely many solutions Coincident lines

Substitution Method for Pair of Linear Equations

The substitution method is useful when one equation can easily give one variable in terms of the other. The value is then substituted in the second equation.

Example:

7x - 15y = 2

x + 2y = 3

From the second equation:

x + 2y = 3

x = 3 - 2y

Substitute this value in the first equation:

7(3 - 2y) - 15y = 2

21 - 14y - 15y = 2

21 - 29y = 2

-29y = -19

y = 19/29

Now substitute y in:

x = 3 - 2y

x = 3 - 2(19/29)

x = 3 - 38/29

x = 87/29 - 38/29

x = 49/29

Answer:

x = 49/29

y = 19/29

Copyable format:

x = 49/29, y = 19/29

Elimination Method for Pair of Linear Equations

The elimination method removes one variable by making its coefficients equal. This method works well when coefficients can be matched easily.

Example:

2x + 3y = 8

4x + 6y = 7

Multiply the first equation by 2:

4x + 6y = 16

Second equation:

4x + 6y = 7

Subtract:

(4x - 4x) + (6y - 6y) = 16 - 7

0 = 9

This is a false statement.

Answer:

The pair has no solution.

So, the equations are inconsistent.

Copyable format:

0 = 9 is false.

Therefore, the pair has no solution.

Cross Multiplication Method for Linear Equations in Two Variables

The cross multiplication method gives direct formulas for x and y. It is useful when the pair is in standard form.

For:

a1x + b1y + c1 = 0

a2x + b2y + c2 = 0

The formulas are:

x = (b1c2 - b2c1)/(a1b2 - a2b1)

y = (c1a2 - c2a1)/(a1b2 - a2b1)

Condition:

a1b2 - a2b1 ≠ 0

Copyable format:

x = (b1c2 - b2c1)/(a1b2 - a2b1)

y = (c1a2 - c2a1)/(a1b2 - a2b1)

a1b2 - a2b1 ≠ 0

Another common form:

x/(b1c2 - b2c1) = y/(c1a2 - c2a1) = 1/(a1b2 - a2b1)

Equations Reducible to a Pair of Linear Equations

Some equations do not look linear at first. They can become linear after using substitution.

Example:

2/x + 3/y = 4

5/x - 4/y = 9

Let:

1/x = u

1/y = v

Then the equations become:

2u + 3v = 4

5u - 4v = 9

Now this is a pair of linear equations in u and v. After finding u and v, substitute back to get x and y.

Copyable format:

1/x = u

1/y = v

2/x + 3/y = 4 becomes 2u + 3v = 4

5/x - 4/y = 9 becomes 5u - 4v = 9

Formula Table for Class 10 Maths Chapter 3 Notes

Use this table for quick revision before solving questions from Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables.

Concept Copyable Formula
Linear equation in two variables ax + by + c = 0
Pair of linear equations a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0
Unique solution a1/a2 ≠ b1/b2
Infinitely many solutions a1/a2 = b1/b2 = c1/c2
No solution a1/a2 = b1/b2 ≠ c1/c2
Cross multiplication for x x = (b1c2 - b2c1)/(a1b2 - a2b1)
Cross multiplication for y y = (c1a2 - c2a1)/(a1b2 - a2b1)
Reducible equation substitution 1/x = u, 1/y = v

Solved Examples from Chapter 3 Pair of Linear Equations

Solved examples help students choose the correct method. Use substitution when one variable is easy to isolate, elimination when coefficients can be matched and cross multiplication for direct formula-based solving.

Example 1: Check a Solution of a Linear Equation

Check whether (0, 4) is a solution of:

2x + y = 4

Substitute x = 0 and y = 4:

2(0) + 4 = 4

4 = 4

Answer:

(0, 4) is a solution of 2x + y = 4.

Example 2: Find the Nature of a Pair of Equations

Check whether the pair has one solution, no solution or infinitely many solutions:

2x - 3y = 8

4x - 6y = 9

Write in standard form:

2x - 3y - 8 = 0

4x - 6y - 9 = 0

Compare:

a1 = 2, b1 = -3, c1 = -8

a2 = 4, b2 = -6, c2 = -9

Ratios:

a1/a2 = 2/4 = 1/2

b1/b2 = -3/-6 = 1/2

c1/c2 = -8/-9 = 8/9

So:

a1/a2 = b1/b2 ≠ c1/c2

Answer:

The lines are parallel.

The pair has no solution.

The pair is inconsistent.

Example 3: Solve by Elimination Method

Solve:

x + 2y = 8

2x - 3y = 2

Multiply the first equation by 2:

2x + 4y = 16

Second equation:

2x - 3y = 2

Subtract:

(2x - 2x) + (4y - (-3y)) = 16 - 2

7y = 14

y = 2

Substitute y = 2 in:

x + 2y = 8

x + 2(2) = 8

x + 4 = 8

x = 4

Answer:

x = 4

y = 2

Solution = (4, 2)

Chapter 3 Pair of Linear Equations Summary

This chapter teaches how two linear equations in the same two variables can be solved together. The solution depends on whether the lines intersect, are parallel or coincide.

  • A linear equation in two variables has the form ax + by + c = 0.
  • A solution is an ordered pair (x, y) that satisfies the equation.
  • A pair of linear equations can represent intersecting, parallel or coincident lines.
  • Intersecting lines have one solution.
  • Parallel lines have no solution.
  • Coincident lines have infinitely many solutions.
  • Substitution method replaces one variable using the other.
  • Elimination method removes one variable by matching coefficients.
  • Cross multiplication method gives direct formulas for x and y.
  • Some equations can be reduced to linear equations by substitution.

Useful Important Questions Class 10 Maths Links

Resource Link
CBSE Class 10 Maths Syllabus CBSE Class 10 Maths Syllabus
CBSE Class 10 Maths Revision Notes CBSE Class 10 Maths Revision Notes
CBSE Extra Questions for Class 10 Maths CBSE Extra Questions for Class 10 Maths
CBSE Sample Papers for Class 10 Maths CBSE Sample Papers for Class 10 Maths
CBSE Class 10 Maths Formula CBSE Class 10 Maths Formula
NCERT Solutions for Class 10 Maths NCERT Solutions for Class 10 Maths

FAQs (Frequently Asked Questions)

The key concepts are linear equation in two variables, pair of linear equations, graphical method, substitution method, elimination method and cross multiplication method. Students also revise consistent, inconsistent and dependent pairs using coefficient ratios.

Compare the ratios a1/a2, b1/b2 and c1/c2. If a1/a2 ≠ b1/b2, the pair has one solution. If a1/a2 = b1/b2 = c1/c2, it has infinitely many solutions. If a1/a2 = b1/b2 ≠ c1/c2, it has no solution.

The graphical method shows the solution as the point where two lines meet. It helps students understand why intersecting lines have one solution, parallel lines have no solution and coincident lines have infinitely many solutions.

The elimination method is easier when the coefficients of one variable can be made equal quickly. It removes one variable and gives a simple equation in the other variable.

Example:

2x + 3y = 8

4x + 6y = 16

Here, multiplying the first equation by 2 makes coefficients easy to compare.

Common mistakes include writing equations outside standard form, using the wrong coefficient ratios, changing signs during elimination and forgetting that coincident lines have infinitely many solutions. Students also need to check whether a word problem asks for values, nature of solution or graphical representation.