CBSE Class 10 Maths Revision Notes Chapter 6 Triangles 2026–27
Triangles Class 10 explains similarity, proportional sides, equal angles and key theorems used in geometry. For CBSE Class 10 Maths, this chapter covers similar figures, triangle similarity, area ratios and Pythagoras Theorem.
Triangles in Class 10 builds on the idea of congruence studied earlier. In this chapter, students learn about figures that have the same shape but may not have the same size.
Use these CBSE Class 10 Maths Revision Notes Chapter 6 to revise the chapter step by step. Start with similar figures, then move to similarity of triangles, Basic Proportionality Theorem, similarity criteria, area theorem and Pythagoras Theorem.
Key Takeaways
- Similar figures: Figures with the same shape but not necessarily the same size.
- Similar triangles: Triangles with equal corresponding angles and proportional corresponding sides.
- Basic Proportionality Theorem: A line parallel to one side of a triangle divides the other two sides in the same ratio.
- Pythagoras Theorem: In a right triangle, hypotenuse² = base² + perpendicular².
Finding it difficult to remember triangle similarity criteria and theorem ratios?
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CBSE Class 10 Maths Chapter 6 Triangles at a Glance
Class 10 Maths Chapter 6 Triangles focuses on similar triangles and their use in proving important geometry results. The chapter also connects proportional sides with area ratios and right triangles.
| Concept | Meaning | Quick Formula or Condition |
| Similar figures | Same shape, size may differ | Corresponding angles equal, sides proportional |
| Similar triangles | Triangles with same shape | ΔABC ~ ΔDEF |
| Basic Proportionality Theorem | Parallel line divides two sides in same ratio | AD/DB = AE/EC |
| Area theorem | Area ratio equals square of side ratio | ar(ABC)/ar(PQR) = AB²/PQ² |
| Pythagoras Theorem | Relation in a right triangle | hypotenuse² = base² + perpendicular² |
Similar Figures in Triangles Class 10
Similar figures have the same shape but may have different sizes. All congruent figures are similar, but similar figures need not be congruent.
Examples:
- All circles are similar.
- All squares are similar.
- All equilateral triangles are similar.
- A small photograph and its enlarged copy are similar.
Two polygons are similar when:
- their corresponding angles are equal
- their corresponding sides are in the same ratio
Copyable format:
Corresponding angles are equal.
Corresponding sides are proportional.
Similarity of Triangles
The similarity of triangles is based on equal corresponding angles and proportional corresponding sides. If both conditions are met, the triangles have the same shape.
For triangles ABC and DEF:
ΔABC ~ ΔDEF
This means:
∠A = ∠D
∠B = ∠E
∠C = ∠F
And:
AB/DE = BC/EF = AC/DF
Copyable format:
ΔABC ~ ΔDEF
AB/DE = BC/EF = AC/DF
The order of letters is important. In ΔABC ~ ΔDEF, A corresponds to D, B corresponds to E and C corresponds to F.
Basic Proportionality Theorem
The Basic Proportionality Theorem is also known as Thales theorem. It connects parallel lines with equal ratios in a triangle.
Statement:
If a line is drawn parallel to one side of a triangle and intersects the other two sides at distinct points, then the other two sides are divided in the same ratio.
In ΔABC, if DE || BC, where D lies on AB and E lies on AC, then:
AD/DB = AE/EC
Copyable format:
If DE || BC, then AD/DB = AE/EC.
This theorem is used when a parallel line is already given in the question.
Converse of Basic Proportionality Theorem
The converse of Basic Proportionality Theorem works in the reverse direction. It helps prove that a line is parallel to the third side of a triangle.
Statement:
If a line divides any two sides of a triangle in the same ratio, then the line is parallel to the third side.
In ΔABC, if D lies on AB and E lies on AC, and:
AD/DB = AE/EC
Then:
DE || BC
Copyable format:
If AD/DB = AE/EC, then DE || BC.
Use this theorem when the ratio is given and parallel lines need to be proved.
Criteria for Similarity of Triangles
The criteria for similarity of triangles help students prove two triangles similar without checking all angles and all sides. The main criteria are AA, AAA, SSS and SAS.
| Criterion | Full Form | Condition |
| AA similarity criterion | Angle-Angle | Two angles of one triangle equal two angles of another triangle |
| AAA similarity criterion | Angle-Angle-Angle | All corresponding angles are equal |
| SSS similarity criterion | Side-Side-Side | Corresponding sides are in the same ratio |
| SAS similarity criterion | Side-Angle-Side | Two corresponding sides are proportional and included angles are equal |
AA and AAA Similarity Criteria
Two triangles are similar if two angles of one triangle are equal to two angles of another triangle. The third pair of angles becomes equal by the angle sum property.
If:
∠A = ∠D
∠B = ∠E
Then:
ΔABC ~ ΔDEF
Copyable format:
If ∠A = ∠D and ∠B = ∠E, then ΔABC ~ ΔDEF.
The AAA similarity criterion says that if all three corresponding angles are equal, the triangles are similar.
Copyable format:
If ∠A = ∠D, ∠B = ∠E and ∠C = ∠F, then ΔABC ~ ΔDEF.
SSS Similarity Criterion
The SSS similarity criterion is used when all corresponding sides of two triangles are in the same ratio. In this case, the corresponding angles are also equal.
If:
AB/DE = BC/EF = AC/DF
Then:
ΔABC ~ ΔDEF
Copyable format:
If AB/DE = BC/EF = AC/DF, then ΔABC ~ ΔDEF.
Use this criterion when the question gives all three sides or side ratios.
SAS Similarity Criterion
The SAS similarity criterion is used when two sides of one triangle are proportional to two sides of another triangle, and the included angles are equal.
If:
AB/DE = AC/DF
And:
∠A = ∠D
Then:
ΔABC ~ ΔDEF
Copyable format:
If AB/DE = AC/DF and ∠A = ∠D, then ΔABC ~ ΔDEF.
Use this criterion when two side ratios and the angle between them are given.
Areas of Similar Triangles
The areas of similar triangles are related to the squares of their corresponding sides. This theorem is important for questions that combine similarity and area.
Statement:
The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
If:
ΔABC ~ ΔPQR
Then:
ar(ABC)/ar(PQR) = AB²/PQ² = BC²/QR² = AC²/PR²
Copyable format:
If ΔABC ~ ΔPQR, then
ar(ABC)/ar(PQR) = AB²/PQ² = BC²/QR² = AC²/PR²
This means side ratio is squared when comparing areas.
Pythagoras Theorem
Pythagoras Theorem applies to a right-angled triangle. It relates the hypotenuse, base and perpendicular.
Statement:
In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Copyable format:
Hypotenuse² = Base² + Perpendicular²
For right ΔABC, right-angled at B:
AC² = AB² + BC²
Here:
- AC is the hypotenuse.
- AB and BC are the other two sides.
Converse of Pythagoras Theorem
The converse of Pythagoras Theorem helps check whether a triangle is right-angled. It works when the side lengths are known.
Statement:
If the square of one side of a triangle is equal to the sum of the squares of the other two sides, then the angle opposite the first side is a right angle.
Copyable format:
If AC² = AB² + BC², then ∠B = 90°.
Example:
For a triangle with sides 3 cm, 4 cm and 5 cm:
5² = 3² + 4²
25 = 9 + 16
25 = 25
So, the triangle is right-angled.
Formula and Theorem Table for Class 10 Triangles
This table can be used with Class 10 Mathematics Revision Notes Chapter 6 for quick theorem recall before solving geometry questions.
| Concept | Copyable Result |
| Similar triangles | ΔABC ~ ΔDEF |
| Corresponding side ratio | AB/DE = BC/EF = AC/DF |
| Basic Proportionality Theorem | If DE |
| Converse of BPT | If AD/DB = AE/EC, then DE |
| AA similarity criterion | If two angles are equal, triangles are similar |
| SSS similarity criterion | If all corresponding sides are proportional, triangles are similar |
| SAS similarity criterion | If two sides are proportional and included angles are equal, triangles are similar |
| Areas of similar triangles | ar(ABC)/ar(PQR) = AB²/PQ² |
| Pythagoras Theorem | Hypotenuse² = Base² + Perpendicular² |
| Converse of Pythagoras Theorem | If c² = a² + b², the triangle is right-angled |
Solved Examples from Chapter 6 Triangles
Solved examples help students identify which theorem to use. First check whether the question gives parallel lines, angle equality, side ratios, area ratios or a right triangle.
Example 1: Use Basic Proportionality Theorem
In ΔABC, DE || BC. D lies on AB and E lies on AC.
Then, by Basic Proportionality Theorem:
AD/DB = AE/EC
If:
AD = 3 cm
DB = 2 cm
AE = 6 cm
Find EC.
Use:
AD/DB = AE/EC
3/2 = 6/EC
3EC = 12
EC = 4 cm
Answer:
EC = 4 cm
Example 2: Prove Two Triangles Similar by AA Criterion
In triangles ABC and DEF:
∠A = ∠D
∠B = ∠E
Since two angles of one triangle are equal to two angles of another triangle:
ΔABC ~ ΔDEF
Answer:
The triangles are similar by AA similarity criterion.
Example 3: Use Areas of Similar Triangles
If ΔABC ~ ΔPQR and:
AB/PQ = 3/2
Then:
ar(ABC)/ar(PQR) = AB²/PQ²
ar(ABC)/ar(PQR) = 3²/2²
ar(ABC)/ar(PQR) = 9/4
Answer:
The ratio of areas is 9:4.
Example 4: Use Pythagoras Theorem
In right ΔABC, right-angled at B:
AB = 6 cm
BC = 8 cm
Find AC.
Use:
AC² = AB² + BC²
AC² = 6² + 8²
AC² = 36 + 64
AC² = 100
AC = 10 cm
Answer:
AC = 10 cm
Chapter 6 Triangles Summary
These Class 10 Maths Chapter 6 Notes help students revise similar figures, triangle similarity, theorem ratios, area relation and Pythagoras Theorem in one flow.
- Similar figures have the same shape but not necessarily the same size.
- All congruent figures are similar, but all similar figures need not be congruent.
- Two triangles are similar when their corresponding angles are equal and corresponding sides are proportional.
- If DE || BC, then:
- AD/DB = AE/EC
- If AD/DB = AE/EC, then:
- DE || BC
- AA, AAA, SSS and SAS are used to prove similarity of triangles.
- For similar triangles:
- ar(ABC)/ar(PQR) = AB²/PQ² = BC²/QR² = AC²/PR²
- In a right triangle:
- Hypotenuse² = Base² + Perpendicular²
- The converse of Pythagoras Theorem helps identify a right-angled triangle.
How to Choose the Right Similarity Criterion
Students often lose marks because they know the criteria but choose the wrong one in a proof. Use the given information in the question to decide the criterion.
| Given in the Question | Use This Criterion | What to Check |
| Two angles of each triangle are equal | AA similarity criterion | Match the corresponding angles in the correct order |
| Three angles are equal | AAA similarity criterion | Confirm all corresponding angles are equal |
| Three pairs of corresponding sides are proportional | SSS similarity criterion | Check AB/DE = BC/EF = AC/DF |
| Two pairs of sides are proportional and the included angle is equal | SAS similarity criterion | The equal angle must lie between the proportional sides |
| A line is parallel to one side of a triangle | Basic Proportionality Theorem | Use AD/DB = AE/EC |
| Two sides are divided in the same ratio | Converse of Basic Proportionality Theorem | Prove the line is parallel to the third side |
Quick rule:
- Use AA when angles are given.
- Use SSS when all three side ratios are given.
- Use SAS when two side ratios and the included angle are given.
- Use BPT when a parallel line is given.
- Use converse of BPT when a parallel line needs to be proved.
Proof Flow for Important Theorems in Triangles
Proof-based questions in Chapter 6 usually follow a fixed pattern. This table helps students revise how to start and complete each theorem proof.
| Theorem | What is Given | What to Prove | Main Proof Flow |
| Basic Proportionality Theorem | In ΔABC, DE | BC | |
| Converse of Basic Proportionality Theorem | AD/DB = AE/EC | DE | |
| Areas of Similar Triangles | ΔABC ~ ΔPQR | ar(ABC)/ar(PQR) = AB²/PQ² | Draw altitudes from corresponding vertices. Use area formula 1/2 × base × height. Prove the small right triangles are similar to get the altitude ratio. |
| Pythagoras Theorem | ΔABC is right-angled at B | AC² = AB² + BC² | Draw BD ⊥ AC. Prove ΔADB ~ ΔABC and ΔBDC ~ ΔABC. Use side ratios to get AB² = AD × AC and BC² = DC × AC. Add both results. |
| Converse of Pythagoras Theorem | AC² = AB² + BC² | ∠B = 90° | Construct a right triangle with sides equal to AB and BC. Use Pythagoras to show the hypotenuse equals AC. Then prove both triangles congruent by SSS. |
Useful Important Questions Class 10 Maths Links
| Resource | Link |
| CBSE Class 10 Maths Syllabus | CBSE Class 10 Maths Syllabus |
| CBSE Class 10 Maths Revision Notes | CBSE Class 10 Maths Revision Notes |
| CBSE Extra Questions for Class 10 Maths | CBSE Extra Questions for Class 10 Maths |
| CBSE Sample Papers for Class 10 Maths | CBSE Sample Papers for Class 10 Maths |
| CBSE Class 10 Maths Formula | CBSE Class 10 Maths Formula |
| NCERT Solutions for Class 10 Maths | NCERT Solutions for Class 10 Maths |
FAQs (Frequently Asked Questions)
The most important topics are similar figures, similarity of triangles, Basic Proportionality Theorem, converse of Basic Proportionality Theorem, AA similarity criterion, SSS similarity criterion, SAS similarity criterion, areas of similar triangles and Pythagoras Theorem.
Students can check angle equality or side ratios. If two angles are equal, use AA similarity criterion. If all corresponding sides are proportional, use SSS similarity criterion. If two side ratios and the included angle match, use SAS similarity criterion.
The Basic Proportionality Theorem says that if a line is drawn parallel to one side of a triangle and intersects the other two sides, then those two sides are divided in the same ratio.
Copyable format:
If DE || BC, then AD/DB = AE/EC.
If two triangles are similar, the ratio of their areas is equal to the square of the ratio of their corresponding sides.
Copyable format:
ar(ABC)/ar(PQR) = AB²/PQ² = BC²/QR² = AC²/PR²
Pythagoras Theorem is used in right-angled triangles to find a missing side. The formula is hypotenuse² = base² + perpendicular². Its converse is used to check whether a triangle is right-angled.
