CBSE Class 11 Physics Revision Notes Chapter 3: Motion in a Plane
Motion in a Plane explains how position, velocity and acceleration are represented when an object moves in two dimensions. The chapter uses vectors to study projectile motion, relative velocity and uniform circular motion.
Motion along a straight line can be represented using positive and negative signs. However, motion in a plane may occur in several directions, so both magnitude and direction become important.
These CBSE Class 11 Physics Revision Notes Chapter 3 cover vector operations, components, projectile motion and circular motion. The Class 11 Physics Chapter 3 notes also explain how one two-dimensional problem can be divided into separate horizontal and vertical motions.
Key Takeaways
- Vectors have magnitude and direction and follow vector-addition laws.
- Vector components simplify motion by separating it along perpendicular axes.
- Projectile motion combines constant horizontal velocity with vertical acceleration.
- Centripetal acceleration acts towards the centre during circular motion.
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Access Class 11 Physics Chapter 3 Motion in a Plane Notes in 30 Minutes
The chapter on Motion in a Plane Class 11 begins with vector algebra and then applies it to two-dimensional motion.
| Revision Area | Main Concepts |
| Vector basics | Scalars, vectors and unit vectors |
| Vector calculations | Addition, subtraction and resolution |
| Plane motion | Position, velocity and acceleration components |
| Relative motion | Velocity of one object relative to another |
| Projectile motion | Trajectory, height, range and flight time |
| Circular motion | Angular speed and centripetal acceleration |
Summary of Class 11 Physics Motion in a Plane
Motion in one dimension allows only two directions. In two dimensions, an object may change its position along both the x-axis and y-axis.
The chapter therefore introduces:
- Scalars and vectors
- Vector addition and subtraction
- Resolution of vectors
- Motion in two dimensions
- 2D relative velocity
- Projectile motion
- Uniform circular motion
The same equations of motion used in a straight line can be applied independently to horizontal and vertical components.
Scalars and Vectors
Physical quantities are classified as scalars or vectors based on whether direction is required.
Scalar Quantities
A scalar quantity has magnitude only.
It is completely described by a numerical value and unit.
Examples include:
- Mass
- Time
- Distance
- Speed
- Temperature
- Energy
- Work
Scalars follow the rules of ordinary algebra.
Vector Quantities
A vector quantity has magnitude and direction.
It must also follow the triangle or parallelogram law of addition.
Examples include:
- Displacement
- Velocity
- Acceleration
- Force
- Momentum
Difference Between Scalars and Vectors
| Basis | Scalar Quantity | Vector Quantity |
| Description | Magnitude only | Magnitude and direction |
| Addition | Ordinary algebra | Vector-addition laws |
| Direction | Not required | Required |
| Example | Speed | Velocity |
| Representation | Number and unit | Arrow or vector notation |
Representation of a Vector
A vector is represented by a directed line segment.
- Its length represents magnitude.
- Its arrowhead shows direction.
- Its starting point is called the tail.
- Its ending point is called the head.
The magnitude of vector A is written as:
|A| = A
The magnitude itself is a scalar.
Position and Displacement Vectors
The position vector locates a particle relative to an origin.
For a particle at coordinates (x, y):
r = xî + yĵ
If the particle moves from r to r′, its displacement is:
Δr = r′ - r
The position and displacement vectors differ in their starting points.
| Position Vector | Displacement Vector |
| Starts from the origin | Starts from the initial position |
| Locates the particle | Shows change in position |
| Depends on chosen origin | Depends on initial and final points |
| Written as r | Written as Δr |
The displacement vector does not depend on the actual path followed.
Unit Vectors
Unit vectors have magnitude 1 and indicate direction.
The standard unit vectors are:
- î along the x-axis
- ĵ along the y-axis
- k̂ along the z-axis
Their magnitudes are:
|î| = |ĵ| = |k̂| = 1
A unit vector has no physical unit.
The unit vector along A is:
 = A/|A|
Parallel Vectors
Two vectors are parallel when they act along parallel lines.
If:
B = λA
then B is parallel to A.
When λ is positive, both vectors have the same direction. When λ is negative, their directions are opposite.
Equal Vectors
Two vectors are equal when they have:
- Equal magnitudes
- The same direction
Their positions in the plane may be different.
Negative Vector
The vector -A has the same magnitude as A but points in the opposite direction.
Therefore:
|-A| = |A|
Zero Vector
A vector having zero magnitude is called a zero or null vector.
A + (-A) = 0
Its direction cannot be defined.
A displacement becomes a zero vector when the particle returns to its initial position.
Vector Addition and Subtraction
Vectors must be combined by considering both magnitude and direction.
Multiplication of a Vector by a Scalar
Multiplying vector A by a positive scalar λ changes its magnitude but not its direction.
|λA| = λ|A|
If λ is negative, the direction reverses.
Examples:
- 2A has twice the magnitude of A.
- -2A has twice the magnitude in the opposite direction.
- 0A gives the zero vector.
Triangle Law of Vector Addition
The triangle law uses the head-to-tail method.
To add A and B:
- Draw A.
- Place the tail of B at the head of A.
- Join the tail of A to the head of B.
- The joining vector gives the resultant.
Therefore:
R = A + B
The two vectors and their resultant form a triangle.
Parallelogram Law of Vector Addition
For the parallelogram law:
- Draw A and B from a common origin.
- Complete a parallelogram using them as adjacent sides.
- Draw the diagonal from the common origin.
- The diagonal represents the resultant.
Both graphical methods produce the same vector.
Properties of Vector Addition
Vector addition is commutative:
A + B = B + A
It is also associative:
(A + B) + C = A + (B + C)
Vector Subtraction
Vector addition and subtraction are closely related.
Subtracting B from A means adding the negative of B:
A - B = A + (-B)
The direction of B is reversed before addition.
Resultant of Two Vectors
If A and B make an angle θ, the magnitude of the resultant is:
R = √(A² + B² + 2AB cos θ)
The direction α of the resultant relative to A is:
tan α = B sin θ/(A + B cos θ)
Special cases are:
| Angle Between A and B | Resultant |
| 0° | A + B |
| 90° | √(A² + B²) |
| 180° |
Resolution of Vectors
The resolution of vectors means dividing a vector into components along selected directions.
Rectangular components are usually taken along the x-axis and y-axis.
Rectangular Vector Components
Suppose vector A makes an angle θ with the positive x-axis.
Its components are:
Ax = A cos θ
Ay = A sin θ
Therefore:
A = Axî + Ayĵ
The x and y quantities are scalar components, while Axî and Ayĵ are component vectors.
Signs of Vector Components
The signs depend on the quadrant.
| Quadrant | Ax | Ay |
| First | Positive | Positive |
| Second | Negative | Positive |
| Third | Negative | Negative |
| Fourth | Positive | Negative |
Finding Magnitude from Components
If Ax and Ay are known:
A = √(Ax² + Ay²)
This follows from the Pythagorean theorem.
Finding Direction from Components
The direction is given by:
tan θ = Ay/Ax
Therefore:
θ = tan⁻¹(Ay/Ax)
The quadrant must be checked before fixing the direction.
Analytical Method of Vector Addition
Suppose:
A = Axî + Ayĵ
B = Bxî + Byĵ
Then:
R = A + B
R = (Ax + Bx)î + (Ay + By)ĵ
Therefore:
Rx = Ax + Bx
Ry = Ay + By
The magnitude of the resultant is:
R = √(Rx² + Ry²)
Its direction is:
tan θ = Ry/Rx
This analytical method is more accurate than drawing vectors to scale.
Motion in a Plane
In motion in two dimensions, position, velocity and acceleration have components along both axes.
The x and y motions can be studied separately.
Position Vector in Two Dimensions
For a particle at coordinates (x, y):
r = xî + yĵ
Here, x and y may change with time.
Displacement in a Plane
If the position changes from r to r′:
Δr = r′ - r
In component form:
Δr = Δxî + Δyĵ
where:
Δx = x′ - x
Δy = y′ - y
Average Velocity
Average velocity is:
vavg = Δr/Δt
In component form:
vavg = (Δx/Δt)î + (Δy/Δt)ĵ
Its direction is the same as the displacement vector.
Instantaneous Velocity
Instantaneous velocity is:
v = dr/dt
In component form:
v = vxî + vyĵ
where:
vx = dx/dt
vy = dy/dt
Its magnitude is:
v = √(vx² + vy²)
The direction is:
tan θ = vy/vx
The instantaneous velocity is tangent to the particle’s path.
Acceleration in a Plane
Average acceleration is:
aavg = Δv/Δt
Instantaneous acceleration is:
a = dv/dt
In component form:
a = axî + ayĵ
where:
ax = dvx/dt
ay = dvy/dt
Velocity and acceleration may point in different directions.
Motion with Constant Acceleration
For constant acceleration:
v = v₀ + at
In component form:
vx = v₀x + axt
vy = v₀y + ayt
The position becomes:
r = r₀ + v₀t + ½at²
In component form:
x = x₀ + v₀xt + ½axt²
y = y₀ + v₀yt + ½ayt²
These equations form the basis of projectile motion.
2D Relative Velocity
2D relative velocity describes the velocity of one moving object as observed from another moving object.
If A and B have velocities vA and vB:
Velocity of A relative to B:
vAB = vA - vB
Velocity of B relative to A:
vBA = vB - vA
Therefore:
vAB = -vBA
Relative Velocity in Different Directions
Since velocity is a vector, subtraction must be done through components.
If:
vA = vAxî + vAyĵ
vB = vBxî + vByĵ
Then:
vAB = (vAx - vBx)î + (vAy - vBy)ĵ
The relative speed is:
|vAB| = √[(vAx - vBx)² + (vAy - vBy)²]
Rain-Man Problems
Suppose rain falls vertically with velocity vr and wind gives it a horizontal velocity vw.
The apparent velocity of rain is the vector sum of these components.
Its direction satisfies:
tan θ = Horizontal component/Vertical component
The umbrella must be tilted opposite to the apparent direction of rain.
Boat-River Problems
A boat’s velocity relative to the ground is:
vBG = vBW + vWG
where:
- vBG is boat velocity relative to ground.
- vBW is boat velocity relative to water.
- vWG is water velocity relative to ground.
The resultant depends on both the boat’s velocity and river current.
Projectile Motion
A projectile is an object projected into the air and then allowed to move under gravity.
Examples include:
- A thrown ball
- A kicked football
- A stone projected at an angle
- Water leaving a pipe
The standard projectile motion formulas assume negligible air resistance.
Horizontal and Vertical Components
Suppose the projectile is launched with speed u at angle θ.
Horizontal component:
ux = u cos θ
Vertical component:
uy = u sin θ
Acceleration components are:
ax = 0
ay = -g
The horizontal and vertical motions are independent.
Position at Time t
Taking the launch point as the origin:
x = u cos θ × t
y = u sin θ × t - ½gt²
The horizontal position changes uniformly.
The vertical position changes under constant acceleration.
Velocity at Time t
Horizontal velocity:
vx = u cos θ
Vertical velocity:
vy = u sin θ - gt
The horizontal velocity remains constant.
The vertical velocity changes because of gravity.
The speed is:
v = √(vx² + vy²)
Equation of Trajectory
From the horizontal equation:
t = x/(u cos θ)
Substituting into the vertical equation:
y = x tan θ - gx²/(2u² cos²θ)
This is the equation of trajectory.
Since it contains an x² term, the path is parabolic.
Time to Reach Maximum Height
At maximum height:
vy = 0
Therefore:
0 = u sin θ - gtₘ
Hence:
tₘ = u sin θ/g
Time of Flight
For a projectile returning to the same level:
T = 2u sin θ/g
The time of flight depends on the vertical component of initial velocity.
Maximum Height of Projectile
At the highest point, vertical velocity becomes zero.
The maximum height of projectile is:
H = u² sin²θ/2g
Horizontal Range of Projectile
The range is the total horizontal distance travelled.
R = Horizontal velocity × Time of flight
R = u cos θ × 2u sin θ/g
Therefore:
R = u² sin 2θ/g
Maximum Range
Range is maximum when:
sin 2θ = 1
Therefore:
2θ = 90°
θ = 45°
The maximum range is:
Rmax = u²/g
Complementary Angles
Two angles θ and (90° - θ) produce the same range.
This happens because:
sin 2θ = sin[2(90° - θ)]
However, their maximum heights and flight times are different.
Horizontal Projectile
A projectile launched horizontally has:
ux = u
uy = 0
Its horizontal position is:
x = ut
Its vertical displacement is:
y = ½gt²
The time of fall depends only on the vertical height.
Important Points About Projectile Motion
During projectile motion:
| Quantity | Behaviour |
| Horizontal acceleration | Zero |
| Horizontal velocity | Constant |
| Vertical acceleration | Constant and downward |
| Vertical velocity | Changes |
| Acceleration at maximum height | Equal to g downward |
| Vertical velocity at maximum height | Zero |
| Path | Parabolic |
| Total velocity | Changes in magnitude and direction |
The standard range and flight-time formulas apply when the launch and landing levels are equal.
Uniform Circular Motion
An object performs uniform circular motion when it moves along a circular path with constant speed.
Its velocity changes continuously because its direction changes.
Direction of Linear Velocity
The linear velocity of the particle is tangent to the circular path.
At every point, the radius and velocity are perpendicular.
Angular Displacement
Angular displacement is the angle through which the radius vector turns.
For arc length s and radius R:
θ = s/R
Its SI unit is radian.
Angular Velocity
Angular velocity is the rate of change of angular displacement.
ω = Δθ/Δt
For uniform circular motion, angular velocity remains constant.
Its SI unit is rad s⁻¹.
Relation Between Linear and Angular Velocity
Since:
s = Rθ
Dividing by time:
v = Rω
Thus, linear speed depends on radius and angular velocity.
Centripetal Acceleration
The inward acceleration in circular motion is called centripetal acceleration.
It always points towards the centre.
Its magnitude is:
ac = v²/R
Using v = Rω:
ac = Rω²
Although speed remains constant, the change in direction produces acceleration.
Time Period and Frequency
Time period T is the time taken for one revolution.
Frequency ν is the number of revolutions completed per second.
ν = 1/T
For one revolution:
ω = 2π/T
Also:
ω = 2πν
Linear speed is:
v = 2πR/T
or:
v = 2πRν
Uniform and Non-Uniform Circular Motion
| Basis | Uniform Circular Motion | Non-Uniform Circular Motion |
| Speed | Constant | Changes |
| Velocity | Changes in direction | Changes in magnitude and direction |
| Centripetal acceleration | Present | Present |
| Tangential acceleration | Zero | Present |
| Angular speed | Constant | Variable |
Motion in a Plane Formula Summary
Vector Formulae
| Concept | Formula |
| Position vector | r = xî + yĵ |
| Displacement vector | Δr = r′ - r |
| Vector components | Ax = A cos θ, Ay = A sin θ |
| Vector magnitude | A = √(Ax² + Ay²) |
| Vector direction | tan θ = Ay/Ax |
| Resultant components | Rx = Ax + Bx, Ry = Ay + By |
| Resultant magnitude | R = √(Rx² + Ry²) |
Motion in a Plane Formulae
| Concept | Formula |
| Average velocity | vavg = Δr/Δt |
| Instantaneous velocity | v = dr/dt |
| Acceleration | a = dv/dt |
| Constant-acceleration velocity | v = v₀ + at |
| Constant-acceleration position | r = r₀ + v₀t + ½at² |
| Relative velocity | vAB = vA - vB |
Projectile Motion Formulae
| Concept | Formula |
| Horizontal velocity | ux = u cos θ |
| Vertical velocity | uy = u sin θ |
| Horizontal position | x = u cos θ × t |
| Vertical position | y = u sin θ × t - ½gt² |
| Equation of trajectory | y = x tan θ - gx²/(2u² cos²θ) |
| Time to maximum height | tₘ = u sin θ/g |
| Time of flight | T = 2u sin θ/g |
| Maximum height | H = u² sin²θ/2g |
| Horizontal range | R = u² sin 2θ/g |
| Maximum range | Rmax = u²/g |
Circular Motion Formulae
| Concept | Formula |
| Angular displacement | θ = s/R |
| Angular velocity | ω = Δθ/Δt |
| Linear speed | v = Rω |
| Frequency | ν = 1/T |
| Angular speed using period | ω = 2π/T |
| Centripetal acceleration | ac = v²/R |
| Centripetal acceleration using ω | ac = Rω² |
Important Topics in Class 11 Physics Chapter 3
Students should revise the following areas carefully:
- Difference between scalars and vectors
- Position and displacement vectors
- Unit vectors
- Triangle and parallelogram laws
- Resolution of vectors
- Analytical vector addition
- Position, velocity and acceleration components
- Relative velocity in a plane
- Projectile-motion formulas
- Equation of trajectory
- Time of flight and maximum height
- Horizontal range
- Uniform circular motion
- Linear and angular velocity
- Centripetal acceleration
Tips for Learning Motion in a Plane Class 11
Understand Components Before Projectiles
Projectile motion becomes easier after learning how a vector splits along the x-axis and y-axis.
Draw the Coordinate Axes
Choose positive x and y directions before assigning signs to components.
Treat Both Directions Separately
In projectile motion, horizontal acceleration is zero while vertical acceleration is -g.
Check the Formula Conditions
The standard range and flight-time equations assume that the projectile lands at its launch level.
Track Vector Signs
A negative component indicates direction. The magnitude of a vector remains non-negative.
Use Diagrams for Relative Motion
Rain-man and boat-river problems become clearer after drawing all velocity vectors.
Connect Circular Motion with Direction
In circular motion, speed may remain constant while velocity changes because its direction changes.
Basic Questions from Motion in a Plane
Why does a projectile follow a parabolic path?
The horizontal position varies linearly with time, while the vertical position contains a time-squared term. Eliminating time produces an equation containing x², which represents a parabola.
Why is acceleration non-zero at maximum height?
Only the vertical velocity becomes zero at maximum height. Gravity continues to act downward, so acceleration remains equal to g.
How are vectors added using the parallelogram law?
The two vectors are drawn from a common origin as adjacent sides of a parallelogram. The diagonal from the common origin represents the resultant.
Why does centripetal acceleration point inward?
Velocity changes direction towards the centre as the particle follows the circular path. The resulting acceleration therefore acts radially inward.
How is relative velocity calculated in a plane?
Subtract the observer’s velocity vector from the object’s velocity vector. The subtraction should be performed separately along the x and y axes.
Useful Links for Class 11 Physics
| Section | Useful Links |
| Syllabus | CBSE Class 11 Physics Syllabus |
| Revision Notes | CBSE Class 11 Physics Revision Notes |
| Physics Notes | CBSE Class 11 Physics Revision Notes Chapter 1 |
| NCERT Solutions | NCERT Solutions for Class 11 Physics |
| Sample Papers | CBSE Sample Papers for Class 11 Physics |
| Important Questions | Important Questions Class 11 Physics |
| NCERT Books | NCERT Books for Class 11 Physics |
| Class 11 Support | CBSE Class 11 Syllabus |
FAQs (Frequently Asked Questions)
A scalar has magnitude only, while a vector has both magnitude and direction. Scalars follow ordinary algebra, while vectors follow vector-addition laws.
It separates the initial velocity into horizontal and vertical components. Each component can then be studied using one-dimensional equations.
Horizontal velocity and gravitational acceleration remain constant when air resistance is neglected. Vertical velocity, total speed and direction change during flight.
Range is proportional to sin 2θ. Its maximum value is 1 when 2θ = 90°, giving θ = 45°.
Acceleration can result from a change in direction. In uniform circular motion, speed remains constant while velocity changes direction continuously.