CBSE Class 12 Physics Revision Notes Chapter 2: Electrostatic Potential and Capacitance
Electrostatic potential is the work done per unit positive charge in bringing it from infinity to a point in an electric field. For CBSE Class 12 Physics, the chapter connects potential, conductors, dielectrics, capacitance and electrical energy storage.
Electrostatic Potential and Capacitance explains how work and energy are associated with stationary electric charges. It introduces potential due to point charges, dipoles and systems of charges. It also explains how capacitors store charge and energy.
Use these CBSE Class 12 Physics Revision Notes Chapter 2 for the 2026–27 session. Revise definitions first, followed by formulas, conductor properties, dielectrics, capacitor combinations and stored energy.
Key Takeaways
- Electrostatic potential: Work done per unit positive test charge in bringing it from infinity to a point.
- Equipotential surface: The potential remains constant, so no work is done along the surface.
- Capacitance: C = Q/V, and its SI unit is farad.
- Stored energy: U = ½CV² = ½QV = Q²/2C.
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Electrostatic Potential and Potential Difference Class 12 Physics Notes
Electrostatic force is a conservative force. Therefore, work done between two points depends on the initial and final positions, not the path followed.
Electrostatic Potential Energy
Electrostatic potential energy is the energy stored when a charge is moved against an electrostatic force.
The change in potential energy is equal to the work done by an external force:
ΔU = UP − UR = WRP
Only the difference in potential energy has physical significance. Its zero can be selected at any convenient point, usually infinity.
Electrostatic Potential
Electrostatic potential at a point is the work done by an external force in bringing a unit positive test charge from infinity to that point.
V = W/q
Here:
- V is electrostatic potential.
- W is the external work done.
- q is the test charge.
Electrostatic potential is a scalar quantity. Its SI unit is volt.
1 V = 1 J/C
Potential Difference and Work Done
Potential difference between points A and B is the work done per unit positive charge in moving it from A to B.
VB − VA = WAB/q
The work done in moving charge q through a potential difference is:
WAB = q(VB − VA)
Potential difference is physically significant. The actual potential depends on the selected zero-potential reference.
Potential Due to Different Charge Configurations in Chapter 2 Notes
Potential follows the superposition principle. The total potential equals the algebraic sum of potentials due to individual charges.
Potential Due to a Point Charge
For a point charge Q, potential at a distance r is:
V = 1/(4πε₀) × Q/r
or
V = kQ/r
where:
k = 1/(4πε₀)
Important points:
- V is positive for a positive charge.
- V is negative for a negative charge.
- V varies as 1/r.
- Potential at infinity is taken as zero.
The electric field of a point charge varies as 1/r², while its potential varies as 1/r.
Potential Due to an Electric Dipole
An electric dipole consists of charges +q and −q separated by distance 2a.
Its dipole moment is:
p = q(2a)
The direction of p is from the negative charge to the positive charge.
At a distant point:
V = 1/(4πε₀) × p cos θ/r²
This expression applies when r is much greater than a.
On the dipole axis:
θ = 0° or 180°
V = ±1/(4πε₀) × p/r²
On the equatorial plane:
θ = 90°
V = 0
The dipole potential depends on both distance r and angle θ. It decreases as 1/r² at large distances.
Potential Due to a System of Charges
For charges q₁, q₂, q₃, …, qₙ, the potential at point P is:
V = 1/(4πε₀) × (q₁/r₁ + q₂/r₂ + q₃/r₃ + … + qₙ/rₙ)
Potential is added algebraically because it is a scalar quantity. The signs of all charges must be included.
Potential Due to a Uniformly Charged Spherical Shell
Let a spherical shell of radius R carry total charge Q.
Outside the shell, where r ≥ R:
V = 1/(4πε₀) × Q/r
The shell behaves as if its entire charge were concentrated at its centre.
On the surface:
V = 1/(4πε₀) × Q/R
Inside the shell, where r < R:
V = 1/(4πε₀) × Q/R
The potential remains constant throughout the interior. However, the electric field inside the shell is zero.
| Position | Electric Potential | Electric Field |
| Outside the shell | kQ/r | kQ/r² |
| On the surface | kQ/R | kQ/R² |
| Inside the shell | kQ/R | 0 |
Equipotential Surfaces and Electric Field Potential Relation Notes
An equipotential surface has the same potential at every point. Moving a charge along such a surface requires no work.
Properties of Equipotential Surfaces
- Potential remains constant at every point.
- Work done in moving a charge along the surface is zero.
- Electric field is always perpendicular to the surface.
- Two equipotential surfaces cannot intersect.
- Closely spaced surfaces represent a stronger electric field.
- Widely spaced surfaces represent a weaker electric field.
For a point charge, equipotential surfaces are concentric spheres centred on the charge.
For a uniform electric field, equipotential surfaces are parallel planes perpendicular to the field.
Relation Between Electric Field and Potential
Electric field points in the direction of the steepest decrease in potential.
For a small displacement dl along the field:
E = −dV/dl
In one dimension:
Ex = −dV/dx
The negative sign shows that potential decreases in the direction of the electric field.
For a uniform electric field:
VB − VA = −E·d
If displacement d is along the electric field:
VB − VA = −Ed
Electrostatic Potential Energy Class 12 Physics Chapter 2 Notes
Potential energy represents the work required to assemble a charge configuration.
Potential Energy of a System of Charges
For two point charges q₁ and q₂ separated by distance r₁₂:
U = 1/(4πε₀) × q₁q₂/r₁₂
For three charges:
U = 1/(4πε₀) × (q₁q₂/r₁₂ + q₂q₃/r₂₃ + q₃q₁/r₃₁)
For a system of several charges, include the interaction energy of every distinct pair once.
- U is positive for like charges.
- U is negative for unlike charges.
- The reference value is generally taken as zero when all charges are infinitely separated.
Potential Energy in an External Field
If a charge q is placed at a point where the external potential is V(r), its potential energy is:
U = qV(r)
The potential V(r) must be due to external charges. It must not include the potential created by charge q itself.
Potential Energy of an Electric Dipole
For an electric dipole of moment p placed in a uniform electric field E:
U = −p·E
U = −pE cos θ
| Orientation | Angle | Potential Energy | Nature |
| Parallel to field | 0° | −pE | Stable equilibrium |
| Perpendicular to field | 90° | 0 | Neither maximum nor minimum |
| Opposite to field | 180° | +pE | Unstable equilibrium |
The dipole has minimum energy when aligned with the electric field.
Electrostatics of Conductors Revision Notes
A conductor contains free charges. These charges rearrange until electrostatic equilibrium is reached.
Properties of Conductors in Electrostatic Equilibrium
- Electric field inside a conductor is zero.
E = 0 - Potential is constant throughout the conductor.
Every point inside and on its surface has the same potential. - Excess charge remains on the surface.
No excess charge remains inside the conducting material. - Electric field is normal to the surface.
A tangential component would move free charges and disturb equilibrium. - Field just outside a charged conductor is:
E = σ/ε₀
Here, σ is the surface charge density. - Charge density is greater at sharper points.
Charges accumulate more strongly where the radius of curvature is small.
Electrostatic Shielding
A cavity inside a conductor remains protected from external electrostatic fields when no charge is present inside it.
The electric field inside such a cavity is zero. This effect is called electrostatic shielding.
A closed conducting enclosure can therefore protect sensitive equipment from external electric fields.
Dielectrics and Polarisation Class 12 Physics Notes
A dielectric is an insulating material that does not contain free charge carriers. Its molecules become polarised in an external electric field.
Polar and Non-polar Molecules
| Type | Meaning | Behaviour Without an External Field |
| Polar molecule | Centres of positive and negative charges do not coincide | Has a permanent dipole moment |
| Non-polar molecule | Centres of positive and negative charges coincide | Has no permanent dipole moment |
In an external field, polar molecules tend to align with the field. Non-polar molecules develop an induced dipole moment.
Polarisation and Dielectric Constant
Polarisation P is the dipole moment per unit volume of a dielectric.
When a dielectric is placed in an electric field, an opposing field develops inside it. This reduces the net electric field.
The dielectric constant is:
K = E₀/E
It can also be written as:
K = C/C₀
Therefore:
C = KC₀
Here:
- C₀ is capacitance without the dielectric.
- C is capacitance with the dielectric.
- K is the dielectric constant.
Capacitors and Capacitance Class 12 Chapter 2 Notes
A capacitor consists of two conductors separated by an insulator. The conductors carry equal and opposite charges +Q and −Q.
Capacitance and Its SI Unit
Capacitance is the ratio of charge on either conductor to the potential difference between them.
C = Q/V
Capacitance depends on:
- Shape of the conductors
- Size of the conductors
- Separation between the conductors
- Nature of the medium between them
It does not depend directly on Q or V.
The SI unit of capacitance is farad.
1 F = 1 C/V
Common smaller units are:
- 1 μF = 10⁻⁶ F
- 1 nF = 10⁻⁹ F
- 1 pF = 10⁻¹² F
Parallel-Plate Capacitor
A parallel plate capacitor has two large conducting plates of area A separated by distance d.
For plates carrying surface charge densities +σ and −σ:
E = σ/ε₀
Since:
σ = Q/A
Therefore:
E = Q/(ε₀A)
The potential difference is:
V = Ed
V = Qd/(ε₀A)
Using C = Q/V:
C = ε₀A/d
This expression assumes that the separation is much smaller than the dimensions of the plates. Edge effects are then neglected.
Effect of a Dielectric on Capacitance
When a dielectric of constant K completely fills the space between the plates:
C = Kε₀A/d
Therefore:
C = KC₀
A dielectric increases capacitance by reducing the effective electric field and potential difference for the same charge.
Combination of Capacitors in Class 12 Physics Revision Notes
Capacitors can be connected in series or parallel to obtain a required equivalent capacitance.
Capacitors in Series
In a series combination:
- Each capacitor carries the same charge.
- The total potential difference equals the sum of individual potential differences.
- Equivalent capacitance is less than the smallest individual capacitance.
V = V₁ + V₂ + V₃ + …
Since V = Q/C:
1/Ceq = 1/C₁ + 1/C₂ + 1/C₃ + …
For two capacitors:
Ceq = C₁C₂/(C₁ + C₂)
For n identical capacitors of capacitance C:
Ceq = C/n
Capacitors in Parallel
In a parallel combination:
- Potential difference is the same across every capacitor.
- Total charge equals the sum of individual charges.
- Equivalent capacitance is greater than every individual capacitance.
Q = Q₁ + Q₂ + Q₃ + …
Since Q = CV:
Ceq = C₁ + C₂ + C₃ + …
For n identical capacitors:
Ceq = nC
Series and Parallel Comparison
| Property | Series Combination | Parallel Combination |
| Charge | Same on each capacitor | Divides among capacitors |
| Potential difference | Divides among capacitors | Same across each capacitor |
| Equivalent capacitance | Reciprocal sum | Direct sum |
| Relative value | Less than smallest capacitance | Greater than largest capacitance |
Energy Stored in a Capacitor Chapter 2 Notes
Charging a capacitor requires work. This work becomes electrostatic potential energy stored in the electric field.
Work Done in Charging a Capacitor
At an intermediate charge q:
V = q/C
The small work required to add charge dq is:
dW = Vdq
dW = qdq/C
Integrating from 0 to Q:
U = Q²/2C
Using Q = CV:
U = ½QV
U = ½CV²
Thus:
U = ½CV² = ½QV = Q²/2C
Energy Density of an Electric Field
For a parallel plate capacitor:
U = ½CV²
Using C = ε₀A/d and V = Ed:
U = ½ε₀E²(Ad)
Here, Ad is the volume between the plates.
Therefore, energy per unit volume is:
u = ½ε₀E²
In a dielectric medium:
u = ½εE²
Battery-Connected and Battery-Disconnected Cases
A dielectric changes the capacitor differently depending on whether the battery remains connected.
| Quantity | Battery Connected | Battery Disconnected |
| Potential difference V | Constant | Decreases to V/K |
| Charge Q | Increases to KQ | Constant |
| Capacitance C | Increases to KC | Increases to KC |
| Electric field E | Constant | Decreases to E/K |
| Stored energy U | Increases to KU | Decreases to U/K |
For the connected case, the battery supplies additional charge.
For the disconnected case, no additional charge can enter or leave the capacitor.
Electrostatic Potential and Capacitance Formula Notes
| Concept | Formula | Key Variables |
| Electrostatic potential | V = W/q | W = work, q = charge |
| Potential difference | VB − VA = WAB/q | WAB = external work |
| Potential due to point charge | V = 1/(4πε₀) × Q/r | Q = source charge |
| Potential due to dipole | V = 1/(4πε₀) × p cos θ/r² | p = dipole moment |
| Potential due to many charges | V = 1/(4πε₀) × Σ(qᵢ/rᵢ) | Scalar addition |
| Field-potential relation | E = −dV/dl | Along field direction |
| Two-charge potential energy | U = 1/(4πε₀) × q₁q₂/r₁₂ | r₁₂ = separation |
| Charge in external potential | U = qV | V is external potential |
| Dipole in uniform field | U = −pE cos θ | θ = angle with E |
| Capacitance | C = Q/V | Unit: farad |
| Parallel plate capacitor | C = ε₀A/d | A = plate area |
| Capacitor with dielectric | C = Kε₀A/d | K = dielectric constant |
| Capacitors in series | 1/Ceq = Σ(1/Cᵢ) | Same charge |
| Capacitors in parallel | Ceq = ΣCᵢ | Same voltage |
| Energy stored | U = ½CV² | Also ½QV |
| Energy stored | U = Q²/2C | Constant-charge form |
| Energy density | u = ½ε₀E² | Vacuum |
Important Terms in Class 12 Physics Chapter 2
| Concept | Definition | Key Term |
| Electrostatic potential | Work done per unit positive charge from infinity | Scalar quantity |
| Potential difference | Work done per unit charge between two points | Volt |
| Equipotential surface | Surface having the same potential throughout | Zero work |
| Capacitance | Charge stored per unit potential difference | Farad |
| Dielectric | Insulator polarised by an electric field | Dielectric constant |
| Polarisation | Dipole moment per unit volume | P |
| Electrostatic shielding | Protection of a cavity from external electric fields | Conductor |
| Energy density | Energy stored per unit volume of an electric field | ½ε₀E² |
Revise Class 12 Physics Chapter 2 Notes in 30 Minutes
A 30-minute revision can be divided into three parts:
- First 10 minutes: Potential, potential difference and charge configurations
- Next 10 minutes: Equipotential surfaces, conductors and dielectrics
- Final 10 minutes: Capacitor combinations, stored energy and formulas
Keep the sign of charges, the selected zero of potential and the battery connection in mind while solving numericals.
Useful Links for Class 12 Physics
| Section | Useful Links |
| Syllabus | CBSE Class 12 Physics Syllabus |
| Revision Notes | CBSE Class 12 Physics Revision Notes |
| Physics Notes | CBSE Class 12 Physics Revision Notes Chapter 1 |
| NCERT Solutions | NCERT Solutions for Class 12 Physics |
| Sample Papers | CBSE Sample Papers for Class 12 Physics |
| Important Questions | Important Questions Class 12 Physics |
| NCERT Books | NCERT Books for Class 12 Physics |
| Class 12 Support | CBSE Class 12 Syllabus |
FAQs (Frequently Asked Questions)
Electric field depends on the rate of change of potential. A region can have constant non-zero potential and still have zero electric field. This happens inside a charged spherical shell and throughout a conductor in electrostatic equilibrium.
The point is equally distant from +q and −q. Their potentials have equal magnitudes and opposite signs, so their algebraic sum is zero. The electric field there is not necessarily zero.
A dielectric becomes polarised and creates an opposing electric field. This reduces the potential difference for the same charge. Since C = Q/V, the capacitance increases.
The charge remains constant because the battery is disconnected. Capacitance increases to KC, so U = Q²/2C decreases to U/K. The remaining energy is associated with the mechanical work involved in pulling the dielectric inward.
No, two equipotential surfaces cannot intersect. An intersection would give two different potential values at the same point. It would also imply two possible electric-field directions at that point.
