CBSE Class 9 Maths Revision Notes Chapter 10

Class 9 Mathematics Revision Notes for Circles of Chapter 10

Extramarks’ Class 9 Mathematics Chapter 10 Notes help students with a detailed understanding of the chapter. These notes are designed as per the latest CBSE curriculum by subject-matter experts. Moreover, students can score  better marks in their exams by carefully examining the CBSE Class 9 Chapter 10 Mathematics Notes

Class 9 Mathematics Revision Notes for Circles of Chapter 10

Access Class 9 Mathematics Chapter 10 – Circles 



A circle can be defined as the locus of points at a certain distance from a fixed point.


  • A straight line that connects any two points on a circle is known as a chord.
  • It is represented by the letters AB. 
  • The longest chord that passes through the centre of the circle is termed the diameter. 
  • The diameter is twice the radius and is referred to as a CD. 
  • A line that divides a circle in half is termed a secant. PQR is a secant of a circle.


It refers to the length of a full circle and is defined as the border curve (or perimeter) of the circle.


  • Any section or a part of the circumference is referred to as an arc.
  • A circle is divided into two equal pieces by diameter.
  • A semicircle is larger than a minor arc.
  • A semicircle is smaller than a major arc.
  • ABC⌢ is a major arc, whereas ADC⌢ is a minor arc.


  • The area between an arc and the two radii connecting the arc’s centre and endpoints is called a sector.
  • A section of a circle a chord has cut off is known as a segment.

Concentric Circles:

Circles with the same centre are concentric circles.

Theorem 1:

Theorem 1: 

A straight line drawn from the centre of a circle that is not a diameter to bisect a chord is always at a right angle to the chord.

  • Given Data: Here, AB is a chord of a circle with the centre O. The midpoint of AB is M. OM is joined. 
  • To Prove: ∠AMO = ∠BMO = 90°
  • Construction: Join AO and BO 
  • Proof: In ΔAOM and ΔBOM 
Statement Reason
AO = BO radii
AM = BM Data
OM = OM Common
∴∠AMO = ∠BMO Statement (4)
But ∠AMO + ∠BMO= 180° Linear pair
∠AMO = ∠BMO= 90° Statements 5 and 6

Angle Properties (Angle, Cyclic Quadrilaterals and Arcs):

  • ∠APB on the circumference is suspended by a straight line AB.
  • On the remaining part of the circumference, ∠APB can be said to be subtended by arc AMB.
  • Arc AMB subtends ∠AOB at the centre and ∠APB on the circumference.
  • ∠AQB and ∠APB are in the same segment. 

Cyclic Quadrilaterals:

The quadrilateral is called a cyclic quadrilateral if the vertices of a quadrilateral lie on a circle. The vertices are called concyclic points. 


The exterior angle of a cyclic quadrilateral is equivalent to the opposite interior angle. 

Given: ABCD is a cyclic quadrilateral. BC is extended to E.

To Prove: ∠DCE = ∠A


Statement Reason
∠A + ∠BCD=180ο Opposite ∠s of a cyclic quadrilateral
∠BCD + ∠DCE=180ο Linear pair
∴ ∠BCD + ∠DCE=∠A + ∠BCD Statements (1) and (2)
∴ ∠DCE = ∠A Statement (2)

Alternate Segment Property 

Theorem 10:   

The angle in the alternate segment is equal to the angle between a tangent and a chord through the point of contact. 

  • Given Data: 

A straight line SAT touches a given circle with centre O at A. AC is a chord through the point of contact A. 

Angles in the alternate segments to ∠CAT and ∠CAS are denoted by ∠ADC and ∠AEC, respectively.

  • To prove: ∠CAT=∠ADC and ∠CAS=∠AEC 
  • Construction: Draw AOB as diameter and join BC and OC. 
  • Proof:
Statement Reason
∠OAC= ∠OCA= x Since OA=OC and supposition
∠CAT+ ∠x= 90° Since tangent-radius property
∠AOC + ∠x+ ∠y= 180° Sum of angles of a triangle
∠AOC= 180°- 2∠x Statement 3
∠AOC= 2∠ADC ∠ at the centre = 2∠ on the circle
∠CAT= 90° – x Statement 2
2∠CAT= 180°- 2x Statement 6
2∠CAT= 2∠ADC Statements 4,5,7
∠CAT= ∠ADC Statement 8
∠CAS+∠CAT= 180° Linear pair
∠ADC= ∠AEC= 180° Opposite angles of a cyclic quadratic
∠CAS+∠CAT= ∠ADC+∠AEC Statements 10 and 11

Therefore, ∠CAS=∠AEC (Statement 9 and 12)

Test for Concyclic Points:

(a) Conversely, one test for the concyclic points is ‘Angles in the same segment of a circle are equal’.  

It states that: 

The four points are concyclic if two equal angles are on the same side of a line and are subtended by it.

If ∠P=∠Q and the points P, and Q are on the same side of AB, then all the points A, B, P and Q are concyclic.

(b) Another test for concyclic points is the converse of ‘opposite angles of a cyclic quadrilateral are supplementary’.

It states that: 

The vertices of a quadrilateral are concyclic if the opposing angles are supplementary. 

For instance, if ∠A+∠C=180∘ then A, B, C and D are concyclic points.

FAQs (Frequently Asked Questions)

1. What is a cyclic quadrilateral? Explain the theorem associated with it.

When all the quadrilateral vertices lie on a circle, they are called cyclic quadrilaterals.

According to the theorem, any pair of opposite angles in a cyclic quadrilateral will be 180°.

2. What happens to the angles subtended from the common chord?

The angles subtended from the common chord that lie on the same segment are always equal.