CBSE Sample Papers For Class 11 Physics Mock Paper 1

CBSE Sample Paper for Class 11 Physics Mock Paper 1 with Solutions

The branch of science that mainly deals with the nature, properties and interactions of matter and energy is termed as Physics. It is a subject in which one cannot beat around the bush while writing or developing answers. Having a proper understanding about theoretical and practical knowledge of the concepts is very important in Physics. It is a well known fact that there are a lot of formulas, theories and concepts which can be hard to memorize and recall at the time of exam if one does not follow a structural way to study.For a basic knowledge about the concepts, students should go through NCERT books for Class 11 Physics. Once through with these, students can visit the website of Extramarks to access CBSE Sample Papers For Class 11 Physics Mock Paper 1.It not only helps students to test their ability, memory as well as grasping power and also helps them identify the areas they need to work on more specifically.

CBSE Class 11 Physics Sample Paper Mock Paper 1

CBSE Sample Papers For Class 11 Physics Mock Paper 1 with solutions are very significant for students of Class 11 who are appearing for the CBSE examinations. Within a few clicks one can download these CBSE Sample Papers For Class 11 Physics Mock Paper 1 from the website or app of Extramarks and can boost up the preparation. Apart from these, students can find CBSE previous year question papers on Extramarks as well. These sources are very beneficial for students to secure good marks in the exams.

CBSE Class 11 Physics Sample Paper Mock Paper 1 with Solutions

Solving a Sample paper is useful  in many ways. While solving CBSE Sample Papers For Class 11 Physics Mock Paper 1 that are prepared by the subject experts at Extramarks with prudence, a student can understand the actual level of his or her exam preparation. The solutions to these CBSE Sample Papers For Class 11 Physics Mock Paper 1 are also available at Extramarks. The availability of solutions to mock papers saves a lot of time for the students. They can evaluate and mark their answers aptly with answers..

All you Need to Know About the CBSE Class 11 Physics Examination Syllabus

Knowing the syllabus of any subject is crucial before commencing preparation of the same. The Central Board of Secondary Education

(CBSE) prepared the curriculum for every Class from class 1 to class 12. This curriculum is revised and edited every year. Students can access the latest syllabus for any subject via Extramarks CBSE syllabus. As far as the syllabus of Class 11 Physics is concerned, there are a total of 10 units divided into 25 chapters further. First unit deals with the topic of the Physical world and Measurements. Kinematics is discussed in the second unit. Third unit comprises a very important topic I.e. Laws of Motion. Unit 4 deals with Work, power and Energy. Motion is the basic theme of Unit 5. Gravitation is the Central idea of unit 6. Matter, Thermodynamics, Kinetic Theory etc. are dealt with under unit 7 to 9. The last unit I.e. unit 10 deals with Oscillation and waves. CBSE Sample Papers For Class 11 Physics Mock Paper 1 on Extramarks cover these topics as per their importance and recurrence in the examinations.

Portions for practicals include:

The practical Paper for Physics consists of 30 marks. The division of these 30 marks is discussed here:

  • 2 experiments from each unit are to be performed. This portion carries 16 marks in all as there are 4 units and 2 experiments from each unit makes the total count of questions 8.
  • Practical record is of 6 marks.
  • Investigatory projects carry minimal weightage I.e.3 marks.
  • Viva of 5 marks is conducted too.

Question Paper Pattern

The Central Board of Secondary Education releases the pattern of question papers every year, as per the advancements and requirements. Class 11 question paper of Physics subject is divided into four type of questions. Part 1 deals with very short answers.  These are approximately 20 in count and carry 1 mark each. These include fill in the blanks, mcqs, assertion reason based questions or even one liners.

The 2nd part is divided into 7 questions of 2 marks each. These are categorised as Short answers type 1.

The 3rd part deals with Short answers of type 2. The number of questions is the same as type 1, which is 7 questions. But these questions are allotted 3 marks each.

The last section deals with 3 long answer type questions. These are descriptive in nature and carry 5 marks for each correct answer.

This makes the total count of marks equal to 70.

Thus students should prepare for the exam according to the latest pattern. For this, they may refer to CBSE Sample Papers on Extramarks. On clicking the same, they will be able to access CBSE Sample Papers For Class 11 Physics Mock Paper 1. The advantage of using these CBSE Sample Papers For Class 11 Physics Mock Paper 1 for preparation is that these CBSE Sample Papers For Class 11 Physics Mock Paper 1 are based on the blueprint of paper pattern given by CBSE.

5 Best Ways to Use these Sample Mock Papers to Make it More Beneficial

Having resources available, the skill to aptly use them to derive maximum utilization and satisfaction is necessary. Extramarks provides CBSE Sample Papers For Class 11 Physics Mock Paper 1 for Class 11 students preparing for final exams or competitive exams. Below are given 5 best ways in which these CBSE Sample Papers For Class 11 Physics Mock Paper 1 should be used to get maximum benefits:

1.While attempting CBSE Sample Papers For Class 11 Physics Mock Paper 1, one should keep a timer equivalent to the exam duration. This helps build time management skills in students, and students are able to attempt the final exam within the given time frame.

  1. These CBSE Sample Papers For Class 11 Physics Mock Paper 1 should be attempted with honesty and candor. Do not cheat while writing answers to CBSE Sample Papers For Class 11 Physics Mock Paper 1. This will give students a  clear picture about their performance and knowledge, and also the topics they need to focus more on.

3.Students should try to present answers in a neat and well structured format while solving CBSE Sample Papers For Class 11 Physics Mock Paper 1. This develops the habit of writing clear and concise answers in the final exam too.

4.Writing vague answers might lead to deduction in marks. Thus students should make sure to include key points in their answers. This reflects their understanding of conceptual knowledge.

  1. Practicing through Extramarks CBSE Sample Papers For Class 11 Physics Mock Paper 1 helps students build up confidence. Though the actual questions in the final exam may differ, solving CBSE Sample Papers For Class 11 Physics Mock Paper 1 familiarises students with the format of final question paper as these CBSE Sample Papers For Class 11 Physics Mock Paper 1 follow the pattern of exam as released by CBSE.


Extramarks CBSE Sample Papers For Class 11 Physics Mock Paper 1 are quite useful for students to prepare and practice for their examinations. Solving these CBSE Sample Papers For Class 11 Physics Mock Paper 1 on a regular basis develops a flow and confidence in students. It also helps increase the grades in the subject. Thus by using the resources available at Extramarks, students can prepare for the exams in a subtle way and can get good marks in the exams.

Q1. The dimension of energy is ________ which is also the dimension of ____________.


MLT, force

MLT-1, pressure

MLT-2, power

ML2T-2, work

Ans: ML2T-2, work

Q2. A ball is dropped downwards, after 1 second another ball is dropped downwards from the same point. The distance between them after 3 seconds will be


20 m

25 m

50 m

98 m

Ans: 25 m

Q3. A body A moves with a uniform acceleration ‘a’ and zero initial velocity. Another body B starting from the same point moves in the same direction with a constant velocity v. The two bodies will meet after a time






Ans: 2v/a

Q4. The range of a particle when launched at an angle of 15o with the horizontal is 1.5 km. The range of the projectile when launched at an angle of 45o to the horizontal is


1.5 km

2 km

2.5 km

3 km

Ans: 3 km

Q5. A wooden block of mass M is placed on a smooth inclined plane of inclination 60° with the horizontal. The force exerted by the plane on the wooden block has a magnitude






Ans: 0.5Mg

Q6. A ball is dropped from a height of 1m. If coefficient of restitution between the surface and the ball is 0.6, the ball rebounds to a height of


1 m

0.6 m

0.4 m

0.36 m

Ans: 0.36 m

Q7. A meter stick is balanced of a knife edge at its centre. When two coins, each of mass 5 g are put one on top of the other at the 12.0 cm mark the stick is found to be balanced at 45.0 cm. What is the mass of metre stick?


55 g  45 g  50 g  66 g

Ans: 66 g

Q8. Two satellites of mass 4m and m respectively, orbit the earth in circular orbits of radii r and 4r. The ratio of their orbital speeds is






Ans: 2:1

Q9. If one mole of a monatomic gas (γ= 5/3) is mixed with one mole of a diatomic gas (γ = 7/5), the value of γ for the mixture is






Ans: 1.50

Q10. A manometer connected to a closed tap reads 450000 Pa. When the tap is opened, the reading of manometer falls to 400000 Pa. Then the velocity of flow of water is


7 ms-1

8 ms-1

9 ms-1

10 ms-1

Ans: 10 ms-1

Q11. An elastic material with Young’s modulus ‘Y’ is subjected to a tensile stress ‘S’, elastic energy stored per unit volume of the material is






Ans: S2/2Y

Q12. A point source emits waves in all directions in a non-absorbing medium. The ratio of the amplitudes of waves at two points distant 9 and 25 m from the source is






Ans: 25:9

Q13. The most appropriate material for cooking pot is the one having


high specific heat and low conductivity

high specific heat and high conductivity

low specific heat and high conductivity

low specific heat and high conductivity

Ans: low specific heat and high conductivity

Q14. For an ideal gas of pressure P and volume V,


adiabatic curve is always less steeper than isothermal curve.

adiabatic curve is always steeper than isothermal curve.

adiabatic curve has same steep as isothermal curve.

adiabatic curve always coincides with isothermal curve.

Ans: adiabatic curve is always steeper than isothermal curve.

Q15. A particle has displacement y given by y = 3 sin (5πt + ∅) where y is in metre and t is in seconds. The frequency and period of motion is


0.4 Hz, 2.5 s

2.5 Hz, 0.4 s

2.5 Hz, 2.5 s

0.4 Hz, 0.4 s


2.5 Hz, 0.4 s

Q16. The ratio of speed of A and B from the graph is


1 : 1

1 : 2

1 : 3

1 : 4

Ans: 1 : 3

Q17. A steel wire of 10 m in length is stretched through 5 mm. If Young’s modulus of steel is 2×1011 N/m2, what is the energy density of wire?


2.5×104 J/m2  1.5×103 J/m2  4.5×103 J/m2  4×103 J/m2

Ans: 2.5×104 J/m2

Q18. Let k be the force constant of a spring. The work done in increasing its length from l1 to l2 will be


k (l1 – l2)

k(l1 + l2)/2

k (l1+ l22)

k (l1– l22)/2

Ans: k (l1– l22)/2

Q19. Calculate the escape velocity from the moon. It is given that mass of the moon = 7.4 X 1022 kg and radius of the moon is 1740 km.

Ans: The escape velocity is given by

Q20. A metre stick is balanced on a knife edge at its centre. When two coins, each of mass 5 g are put one on top of the other at the 12.0 cm mark, the stick is found to be balanced at 45.0 cm. What is the mass of the metre stick?


Let, mass of the meter stick= mHere, mass of each coin, m=5 gAs the coins are placed 12 cm away from the end P, the centre of mass gets displaced by 5 cm from point R towards the end P.The centre of mass is positioned at the seperation of 45 cm from point P.For the equilibrium state about the 45 cm mark, we have:10×g(4512)=mg(5045)m=10×335=66gMass of the metre stick, m’ =66 g.

Q21. It is required to prepare a steel meter scale, such that the millimeter intervals are to be accurate within 0.0005mm at a certain temperature. Determine the maximum temperature variation allowable during the rulings of millimeter marks.


A refrigerator is to maintain eatables kept at 90C. If room temperature is 360C, calculate the coefficient of performance.



for steel = 1.322 x  10-5 0C-1



Here T1 = 360C = 36 + 273 = 309 k

 T2 = 90C = 9 + 273 = 282 k

Coefficient of performance

 = T2 / (T1 – T2)

= 282 / (309 – 282)

= 282/ 27

= 10.4

Q22. The ceiling of a long hall is 25 m high. What is the maximum horizontal distance that a ball thrown with a speed of 40 ms-1 can go without hitting the ceiling of the hall?


Given,speedofball,u = 40 ms -1 Maximumheight,h = 25m Letθbetheangleofprojectionwiththehorizontal. Forprojectilemotion, Maximumheight,H =  u 2 sin 2 θ 2g 25 m =  40 ms -1 2 sin 2 θ 2×9 .8 ms -2 sin 2 θ = 0.30625 sinθ = 0.5534 θ = sin -1 0.5534  = 33.60° Horizontalrange,R =  u 2 sin2θ g R =  40 ms -1 2 ×sin2×33.6° 9 .8 ms -2  = 150.5m

Q23. A SONAR system fixed in a submarine operates at a frequency 40.0 kHz. An enemy submarine moves towards the SONAR with a speed of 360 km h–1. What is the frequency of sound reflected by the submarine? Take the speed of sound in water to be 1450 m s–1.


Here,operating frequency of the SONAR, ν=40 kHz Speed of theenemy submarine, v e =360  kmh -1 = 100  ms -1 Speed of sound in thewater,v= 1450 ms -1 Asthe source is at rest and the observer(enemysubmarine) is moving toward it, Apparent frequency ( ν ) received and reflected bythe submarine is givenas: ν=( v+ v e v )ν=( 1450+100 1450 )×40=42.76kHz The frequency ( ν ) received by the enemy submarineis given as: ν=( v v+ v s )ν Here, v s =100 ms 1 ν=( 1450 1450+100 )×42.76=45.93kHz MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKfMBHbqedmvETj2BSbqefm0B1jxALjhiov2DaebbnrfifHhDYfgasaacH8MrFz0xbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=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@E122@

Q24. Read the following two statements below carefully and state, with reasons, if it is true or false.</>

(a) The Young’s modulus of rubber is greater than that of steel;

(b) The stretching of a coil is determined by its shear modulus.


(a) Thegivenstatementisfalse,becausefor a given  stressthereismorestrain in rubber than steel. Young’s modulusisgivenbytherelation: Y= Stress Strain For a constantvalueofstress:Y 1 Strain TheYoung’smodulusof rubber is less ascomparedto itisfor steel. (b) Shear modulus is given by the ratio of the applied stress to  the change in the shape of a body. The stretching of a coil changes  its shape without any change in the length of the wire used in the  coil. Therefore, shear modulus of elasticity is involved in it.

Q25. At what temperature is the root mean square speed of an atom in an argon gas cylinder equal to the rms speed of a helium gas atom at – 20°C? (Atomic mass of Ar = 39.9 u, of He = 4.0 u).


Here,Temperature of helium atom, T He =20°C =253 K Atomic mass of theargongas, M Ar =39.9 u Atomic mass of theheliumgas, M He =4.0 u Letrms speed of argongas= ( v rms ) Ar    Let rms speed of heliumgas= ( v rms ) He   Rms speed of theargon gasis given as: ( v rms ) Ar = 3R T Ar M Ar  ( i ) Where,R=Universal gas constant T Ar =Temperature of argon gas Rms speed of thehelium gasis given as: ( v rms ) He = 3R T He M He ( ii ) Asperthequestion: ( v rms ) Ar = ( v rms ) He 3R T Ar M Ar = 3R T He M He T Ar M Ar = T He M He T Ar = T He M He × M Ar = 253 4 ×39.9 =2523.675=2.52×1 0 3 K Temperature of the argon gasatom=2.52×1 0 3  K 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Q26. Which of the following is the most precise device for measuring length :
(a) a vernier calipers with 20 divisions on the sliding scale
(b) a screw gauge of pitch 1mm and 100 divisions on the circular scale
(c) an optical instrument that can measure length to within a wavelength of light?


(a)Leastcountofthegivenverniercallipers Valueofonemainscaledivision Totalnumberofdivisionsontheslidingscale 1mm 20  = 0.05mm = 0.005cm (b)Leastcountofscrewgauge Pitchofscrewgauge Totalno.ofdivisionsoncircularscale 1 100  mm = 0.01 mm = 0.001cm (c)Here,wavelengthoflight,λ 10 -5  cm = 0.00001cm Themostprecisedeviceisthatwhoseleastcountisminimum. Anopticalinstrumentisthemostprecisedevice.

Q27. A 14.5 kg mass, fastened to the end of a steel wire of unstretched length 1.0 m, is whirled in a vertical circle with an angular velocity of 2 rev s-1 at the bottom of the circle. The cross-sectional area of the wire is 0.065 cm2. Calculate the elongation of the wire when the mass is at the lowest point of its path.


Here,mass, m = 14.5 kg Length of steel wire, l = 1.0 m Angular velocity, ω = 2 revs -1 Area of Cross-sectionof the wire, a = 0 .065 cm 2  = 0 .065 ×10 -4 m 2 When the mass is at the lowest point of its path: Letelongation of the wire = ΔL  Total force exertedon themass,when it is placed at  the lowestposition of the vertical circleisgivenas: F = mg + mlω 2 F =14.5 kg × 9 .8 ms 2  +14.5 kg ×1 m× ( 2 revs -1 ) 2 F = 200.1 N TherelationforYoung’s modulus isgivenas, Y = Stress Strain  =  F A Δl l = Fl AΔl Δl =  Fl AY (i) Young’s modulusforSteel = 2 × 10 11 Pa Applyingequation(i),weobtain: Δl =  200.1 N ×1 m 0 .065×10 -4 ×2×10 11  Pa Δl = 1 .539× 10 –4 m Elongation of the wire = 1 .539 × 10 –4

Q28. There is an air bubble of radius 1.0 mm in a liquid of surface tension 0.075N/m and density 103kg/m3. The bubble is at a depth of 10.0 cm below the free surface. By what amount is the pressure inside the bubble greater than the atmospheric pressure?


A person weighing 60 kg takes in 2000 kcal diet in a day. If this energy were to be used in heating the person without any losses, what would be his rise in temperature? Given specific heat of human body is 0.83 cal g-1 0C-1 .   


Here  r = 1.0mm = 10-3m;S = 0.075 N/m


Q29. Two bodies of masses 5kg and 3kg moving in the same direction along the same straight line with velocities 5m/s and 3m/s respectively suffers one dimensional elastic collision. Find the velocities of two bodies after the collision.


A sphere of mass 2 kg is attached to a string 4 m long and is whirled in a horizontal circle. The string can withstand a maximum tension of 32 N. Calculate maximum velocity of revolution that can be given to the stone without breaking the string.





T= 32N; m = 2kg; r = 4m

The tension in the string provides the necessary centripetal acceleration.
So, T = m r



​=  T / mr

= 32N / (2kg x 4m)


​= 2 rad /s

So, the velocity of revolution, v =


​ x r

= 2 rad/s x 4m

= 8 m/s.


Q30. A block of mass 2 kg hanged with a rope is going upward with an acceleration of 4m/s2, calculate tension.


The equation of motion of block is given by

F   = T – mg

Ma = T – mg

T= mg + ma

= m (g + a)

= 2 (9.8 + 2)

T= 2 x 11.8 = 23.6N

Q31. Two masses m1 and m2 are separated by distance r. Find the moment of inertia of this arrangement about an axis passing through the centre of mass and perpendicular to the line joining them.


A solid sphere rolls up an inclined plane of angle of inclination 300.At the bottom of the inclined plane the centre of mass of the sphere has speed of 5 m/sec.Find how far up the sphere will go?

Ans: If centre of mass is origin,





Let a be the deacceleration of the sphere

Q32. Two wires A and B of lengths 2m and 1.4m respectively have radii of 0.45 × 10-2 m & 0.5 × 10–2 m. Weights of 7 kg and 12 kg are attached to the wires as per the arrangement shown below.

Q33. The velocity of a small ball of mass 10 g and density 7.8g/cc becomes constant when dropped in a container filled with glycerine. If the density of glycerine is 1.3g/cc ,find the viscous force acting on the ball?


Water is flowing in a river. If the velocity of a layer at a distance 10cm from the bottom is 20cm/sec ,find the velocity of layer at a height of 40cm from the bottom?


Here mass of the ball is 10g


We know,

Q34. The cylindrical tube of a spray pump has a cross section of 8.0cm2 ,one of which has 40 fine holes each of diameter 1.0mm. If the liquid flows inside the tube at the rate of 1.5m per minute, what is the speed of ejection of the liquid through the holes?


Area of cross section of tube, a1= 8.0cm2 = 8.0X10-4m2

No of holes = 40
Diameter of each hole D = 1mm = 10-3m

Q35. A stationary source emits a sound towards a wall moving towards it with a velocity u. Speed of sound in air is v. Find the fractional change in wavelength of the sound sent and the sound reflected which is observed at source.



Wavelength sent = λ. Let actual frequency = f

Here wall is moving towards source. So frequency observed at wall

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