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 The experts have collected the questions from different sources. They have taken help from the textbook exercises, CBSE sample papers, NCERT Exemplars and important reference books. Apart from this, they have included several questions from CBSE question papers for past years so that students may know about possible questions in exams. Thus, the students can search for questions in different sources, but they will find them in the Class 7 Mathematics Chapter 9 Important Questions.
 The experts have solved the questions too. Thus, students can follow the answers prepared by the experts if they need help solving the questions. They can also check their answers with the answers given by experts. Experienced professionals have further reviewed the solutions to ensure the best quality of the content. Thus, the Mathematics Class 7 Chapter 9 Important Questions will help students to clear their ideas and boost interest in the subject matter.
 Practice is very important for students because it helps them in many ways. Students often need more than textbook exercises because they find a limited number of questions in the textbook. The experts have collected the questions from different sources and included them in the question series. So students can solve different types of problems regularly. Regular practice will help them to clear their doubts and build their concepts. So, it will help them to generate interest in the subject and increase their confidence for the exams. Thus, the Chapter 9 Class 7 Mathematics Important Questions will help them to score higher marks in the exams.
Mathematics Chapter 9 – Rational Numbers Class 7 Questions
Mathematics is a very important subject that students study in school. We need Mathematics in every aspect of our lives to solve reallife problems. Students have learnt about different types of numbers in past classes. In this chapter, they will learn about rational numbers.
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ToggleChapter 9 of Class 7 Mathematics discusses rational numbers. Any number that can be expressed by a fraction with a denominator and numerator is rational. The term came from ratio, and these numbers can be expressed as the ratio of two integers. Students must practice questions from this chapter to score better marks in exams.
Extramarks is a leading company that provides all the important study materials related to CBSE and NCERT. Our experts have made the Important Questions Class 7 Mathematics Chapter 9 to help students in practice. They have collected the questions from different sources such as the CBSE sample papers, NCERT Exemplars, CBSE question papers of past years, important reference books and textbook exercises. They have also solved the questions to clear the doubts of students.
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Important Questions Class 7 Mathematics Chapter 9 with Solutions
The experts of Extramarks have prepared the question series by taking help from various sources. They have collated the questions from NCERT textbook, CBSE question papers of past years, CBSE sample papers and important reference books. They have solved the questions, and experienced professionals have further checked the answers to ensure the best quality for students. Thus, the Important Questions Class 7 Mathematics Chapter 9 will help students generate interest in the subject matter and boost confidence for the exams. The important questions are given below
Question 1. List any five rational numbers between:
(a) 1 and 0
Answer:
The five rational numbers present between the numbers 1 and 0 are as follows,
1< (2/3) < (3/4) < (4/5) < (5/6) < (6/7) < 0
(b) 2 and 1
Answer:
The five rational numbers present between the numbers 2 and 1 are,
2 < (8/7) < (less than) (9/8) < (10/9) < (11/10) < (12/11) < 1
(c) 4/5 and 2/3
Answer:
The five rational numbers present between the numbers 4/5 and 2/3 are,
4/5 < (less than) (13/12) < (14/13) < (15/14) < (16/15) < (17/16) < 2/3
(d) 1/2 and 2/3
Answer:
The five rational numbers present between 1/2 and 2/3 are,
1/2 < (less than) (1/6) < (0) < (1/3) < (1/2) < (20/36) < 2/3
Question 2. Write any four more rational numbers in each of these following patterns:
(a) 3/5, 6/10, 9/15, 12/20, …..
Answer:
In the above given question, we can easily observe that the numerator and the denominator are the multiples of numbers three and five.
= (3 × 1)/ (5 × 1) and (3 × 2)/ (5 × 2), (3 × 3)/ (5 × 3), (3 × 4)/ (5 × 4)
Thus, the next four rational numbers present in this same pattern are as follows,
= (3 × 5)/ (5 × 5) and (3 × 6)/ (5 × 6), (3 × 7)/ (5 × 7), (3 × 8)/ (5 × 8)
= 15/25, 18/30, 21/35, 24/40 ….
(b) 1/4, 2/8, 3/12, …..
Answer:
In the above given question, we can easily observe that the numerator and the denominator are the multiples of the numbers one and four.
= (1 × 1)/ (4 × 1) and (1 × 2)/ (4 × 2), (1 × 3)/ (1 × 3)
Then we get, the next four rational numbers present in this pattern will be,
= (1 × 4)/ (4 × 4) and (1 × 5)/ (4 × 5), (1 × 6)/ (4 × 6), (1 × 7)/ (4 × 7)
= 4/16, 5/20, 6/24, 7/28 and so on.
(c) 1/6, 2/12, 3/18, 4/24 and so on.
Answer:
In the above given question, we can easily observe that the numerator and the denominator are the multiples of numbers one and six.
= (1 × 1)/ (6 × 1) and (1 × 2)/ (6 × 2), (1 × 3)/ (6 × 3) and (1 × 4)/ (6 × 4)
Then, the next four rational numbers present in this pattern are as follows,
= (1 × 5)/ (6 × 5) and (1 × 6)/ (6 × 6), (1 × 7)/ (6 × 7) and (1 × 8)/ (6 × 8)
= 5/30, 6/36, 7/42, 8/48 ….
(d) 2/3, 2/3, 4/6, 6/9 …..
Answer:
In the above given question, we can easily observe that the numerator and the denominator are the multiples of numbers two and three.
= (2 × 1)/ (3 × 1) and (2 × 1)/ (3 × 1), (2 × 2)/ (3 × 2) and (2 × 3)/ (3 × 3)
Then, the next four rational numbers present in this pattern are as follows,
= (2 × 4)/ (3 × 4) and (2 × 5)/ (3 × 5), (2 × 6)/ (3 × 6) and (2 × 7)/ (3 × 7)
= 8/12, 10/15, 12/18 and 14/21 ….
Question 3. Give any four rational numbers equivalent to:
(a) 2/7
Answer:
The four rational numbers present whic are equivalent to the fraction 2/7 are,
= (2 × 2)/ (7 × 2) and (2 × 3)/ (7 × 3), (2 × 4)/ (7 × 4) and (2 × 5)/ (7× 5)
= 4/14, 6/21, 8/28 and 10/35
(b) 5/3
Answer:
The four rational numbers present which are equivalent to the fraction 5/3 are,
= (5 × 2)/ (3 × 2), (5 × 3)/ (3 × 3), (5 × 4)/ (3 × 4) and (5 × 5)/ (3× 5)
= 10/6, 15/9, 20/12 and 25/15
(c) 4/9
Answer:
The four rational numbers present which are equivalent to the fraction 5/3 are,
= (4 × 2)/ (9 × 2), (4 × 3)/ (9 × 3), (4 × 4)/ (9 × 4) and (4 × 5)/ (9× 5)
= 8/18, 12/27, 16/36 and 20/45
Question 4. Which of these following pairs represents the same rational number?
(i) (7/21) and (3/9)
Answer:
We have to check whether the given pair represents the same rational number.
Then,
7/21 = 3/9
1/3 = 1/3
∵ 1/3 ≠ 1/3
Hence 7/21 ≠ 3/9
So, the given pair do not represent the same rational number.
(ii) (16/20) and (20/25)
Answer:
We have to check whether the given pair represents the same rational number.
Then,
16/20 = 20/25
4/5 = 4/5
∵ 4/5 = 4/5
Hence 16/20 = 20/25
So, the given pair represents same rational number.
(iii) (2/3) and (2/3)
Answer:
We have to check whether the given pair represents the same rational number.
Then,
2/3 = 2/3
2/3= 2/3
∵ 2/3 = 2/3
Hence, 2/3 = 2/3
So, the given pair represents same rational number.
(iv) (3/5) and (12/20)
Answer:
We have to check whether the given pair represents the same rational number.
Then,
3/5 = – 12/20
3/5 = 3/5
∵ 3/5 = 3/5
Hence 3/5= 12/20
So, the given pair represents same rational number.
(v) (8/5) and (24/15)
Answer:
We have to check whether the given pair represents the same rational number.
Then,
8/5 = 24/15
8/5 = 8/5
∵ 8/5 = 8/5
Hence 8/5 = 24/15
So, the given pair represents same rational number.
(vi) (1/3) and (1/9)
Answer:
We have to check whether the given pair represents the same rational number.
Then,
1/3 = 1/9
∵ 1/3 ≠ 1/9
Hence, 1/3 ≠ 1/9
So, the given pair does not represent same rational number.
(vii) (5/9) and (5/9)
Answer:
We have to check if these given pairs represent the same rational number.
Then,
5/9 equals to 5/9
Therefore, 5/9 ≠ 5/9
Hence 5/9 ≠ 5/9
So, these given pairs do not represent the same rational number.
Question 5. Rewrite the following rational numbers given below in the simplest form:
(i) 8/6
Solution:
The given above rational numbers can be simplified further,
Then,
= 4/3 … [∵ Divide both the numerator and denominator by 2]
(ii) 25/45
Solution:
The given above rational numbers can be simplified further,
Then,
= 5/9 … [∵ Divide both the numerator and denominator by 5]
(iii) 44/72
Solution:
The given above rational numbers can be simplified further,
Then,
= 11/18 … [∵ Divide both the numerator and denominator by 4]
(iv) 8/10
Solution:
The given above rational numbers can be simplified further,
Then,
= 4/5 … [∵ Divide both the numerator and denominator by 2]
Question 6. Fill in the below boxes with the correct symbol of >, <, and =.
(a) 5/7 [ ] 2/3
Answer:
The LCM of the denominators of numbers 7 and 3 is the number 21
Therefore, (5/7) = [(5 × 3)/ (7 × 3)] is = (15/21)
And (2/3) = [(2 × 7)/ (3 × 7)] equals to (14/21)
Now,
15 < 14
So, (15/21) < (14/21)
5/7 [<] 2/3
(b) 4/5 [ ] 5/7
Answer:
The LCM of the denominators of 5 and 7 is the number 35
Therefore (4/5) = [(4 × 7)/ (5 × 7)] is = (28/35)
And (5/7) = [(5 × 5)/ (7 × 5)] equals to (25/35)
Now,
28 < 25
So, (28/35) < ( 25/35)
4/5 [<] 5/7
(c) 7/8 [ ] 14/16
Answer:
14/16 can simplified further,
Then,
7/8 … [∵ Divide both the numerator and denominator by 2]
So, (7/8) = (7/8)
Hence, 7/8 [=] 14/16
(d) 8/5 [ ] 7/4
Answer:
The LCM of the denominators of 5 and 4 is the no 20
Therefore (8/5) = [(8 × 4)/ (5 × 4)] = (32/20)
And (7/4) = [(7 × 5)/ (4 × 5)] is equal to (35/20)
Now,
32 > – 35
So, (32/20) > ( 35/20)
8/5 [>] 7/4
(e) 1/3 [ ] 1/4
Answer:
The LCM of the denominators of 3 and 4 is the no 12
Hence, (1/3) = [(1 × 4)/ (3 × 4)] is = (4/12)
And (1/4) = [(1 × 3)/ (4 × 3)] is equal to (3/12)
Now,
4 < – 3
So, (4/12) is less than ( 3/12)
Hence, 1/3 [<] 1/4
(f) 5/11 [ ] 5/11
Answer:
Since, (5/11) = (5/11)
Hence, 5/11 [=] 5/11
(g) 0 [ ] 7/6
Answer:
Since every negative rational number is said to be less than zero.
We have:
= 0 [>] 7/6
Question 7. Which is greater in each of these following:
(a) 2/3, 5/2
Answer:
The LCM of the denominators of 3 and 2 is 6
(2/3) = [(2 × 2)/ (3 × 2)] equals to (4/6)
And (5/2) equals to [(5 × 3)/ (2 × 3)] = (15/6)
Now,
4 < 15
So, (4/6) < (15/6)
∴ 2/3 < 5/2
Hence, 5/2 is greater.
(b) 5/6, 4/3
Answer:
The LCM of the denominators of 6 and 3 is 6
∴ (5/6) = [(5 × 1)/ (6 × 1)] is = (5/6)
And (4/3) = [(4 × 2)/ (3 × 2)] equals to (12/6)
Now,
5 > 12
So, (5/6) > ( 12/6)
∴ 5/6 > 12/6
Hence, – 5/6 is greater.
(c) 3/4, 2/3
Answer:
The LCM of the denominators of 4 and 3 is the number 12
∴ (3/4) = [(3 × 3) divided by (4 × 3)] is = (9/12)
And (2/3) = [(2 × 4)/ (3 × 4)] equals to (8/12)
Now,
9 < 8
So, (9/12) is less than ( 8/12)
Therefore 3/4 < 2/3
Hence, 2/3 is greater.
(d) ¼, ¼
Answer:
The given fraction is like friction,
So, ¼ < ¼
Hence ¼ is greater,
Question 8. Write the following rational numbers in an ascending order:
(i) 3/5, 2/5, 1/5
Answer:
The above given rational numbers are in the form of like fraction,
Hence,
(3/5)< (2/5) < (1/5)
(ii) 1/3, 2/9, 4/3
Answer:
To convert the above given rational numbers into the like fraction we have to first find LCM,
LCM of the numbers 3, 9, and 3 is 9
Now,
(1/3)is equal to [(1 × 3)/ (3 × 9)] = (3/9)
(2/9) is equal to [(2 × 1)/ (9 × 1)] = (2/9)
(4/3) is equal to [(4 × 3)/ (3 × 3)] = (12/9)
Clearly,
(12/9) < (3/9) < (2/9)
So,
(4/3) < (1/3) < (2/9)
(iii) 3/7, 3/2, 3/4
Answer:
To convert the given rational numbers into the like fraction we have to first find LCM,
LCM of 7, 2, and 4 is the number 28
Now,
(3/7)= [(3 × 4)/ (7 × 4)] is equal to (12/28)
(3/2)= [(3 × 14)/ (2 × 14)] is equal to (42/28)
(3/4)= [(3 × 7)/ (4 × 7)] is equal to (21/28)
Clearly,
(42/28) < (21/28) < (12/28)
Hence,
(3/2) < (3/4) < (3/7)
Question 9. Find the sum:
(a) (5/4) + (11/4)
Answer:
We have:
= (5/4) – (11/4)
= [(5 – 11)/4] … [∵ the denominator is same in both the rational numbers]
= (6/4)
= 3/2 … [∵ Divide both the numerator and denominator by 3]
(b) (5/3) + (3/5)
Answer:
Take the LCM of these denominators of the above given rational numbers.
LCM of 3 and 5 is 15
Express each of the above given rational numbers with the above found LCM as common denominator.
So,
(5/3)= [(5×5)/ (3×5)] equals to (25/15)
(3/5) equals to [(3×3)/ (5×3)] = (9/15)
Then,
= (25/15) + (9/15) … [∵ the denominator is same in both the rational numbers]
= (25 + 9)/15
= 34/15
(c) (9/10) + (22/15)
Answer:
Take the LCM of these denominators of the above given rational numbers.
LCM of 10 and 15 is 30
Express each of the above given rational numbers with the above LCM, by taking as the common denominator.
Now,
(9/10)= [(9×3)/ (10×3)] = (27/30)
(22/15)= [(22×2)/ (15×2)] = (44/30)
Then,
= (27/30) + (44/30) … [∵ the denominator is same in both the rational numbers]
= (27 + 44)/30
= (17/30)
(d) (3/11) + (5/9)
Answer:
We have,
= 3/11 + 5/9
Take the LCM of these denominators of the above given rational numbers.
Hence, the LCM of 11 and 9 is the number 99
Express each of these given rational numbers while taking the above LCM by taking it as the common denominator.
Now,
(3/11) equals to [(3×9)/ (11×9)] = (27/99)
(5/9) equals to [(5×11)/ (9×11)] = (55/99)
Then,
= (27/99) + (55/99) … [∵ the denominator is same in both the rational numbers]
= (27 + 55)/99
= (82/99)
(e) (8/19) + (2/57)
Answer:
We have
= 8/19 – 2/57
Take the LCM of the following denominators of the given rational numbers.
LCM of the numbers 19 and 57 is 57
Express each of the given rational numbers by taking the above LCM as the common denominator.
Now,
(8/19)= [(8×3)/ (19×3)] = (24/57)
(2/57)= [(2×1)/ (57×1)] = (2/57)
Then,
= (24/57) – (2/57) … [∵ the denominator is same in both the rational numbers]
= (24 – 2)/57
= (26/57)
(e) 2/3 + 0
Answer:
We know that when any number or fraction is added to the number zero the answer will be the same number or fraction.
Hence,
= 2/3 + 0
= ⅔
Question 10. Find
(a) 7/24 – 17/36
Answer:
Take the LCM of these denominators of the above given rational numbers.
LCM of the numbers 24 and 36 is 72
Express each of these given rational numbers with the above LCM, by taking it as the common denominator.
Now,
(7/24) is equal to [(7×3)/ (24×3)] = (21/72)
(17/36) equals to [(17×2)/ (36×2)] = (34/72)
Then,
= (21/72) – (34/72) … [∵ the denominator is same in both the rational numbers]
= (21 – 34)/72
= (13/72)
(b) 5/63 – (6/21)
Answer:
We can also write that 6/21 = 2/7
= 5/63 – (2/7)
We have,
= 5/63 + 2/7
Now Take the LCM of the denominators of the above given rational numbers.
LCM of the numbers 63 and 7 is 63
Express each of these given rational numbers with the above LCM, by taking it as the common denominator.
Now,
(5/63)= [(5×1)/ (63×1)] equals to (5/63)
(2/7)= [(2×9)/ (7×9)] equals to (18/63)
Then,
= (5/63) + (18/63) … [∵ the denominator is same in both the rational numbers]
= (5 + 18)/63
= 23/63
(c) 6/13 – (7/15)
Answer:
We have,
= 6/13 + 7/15
LCM of the numbers 13 and 15 is 195
Express each of these given rational numbers with the above LCM, by taking it as the common denominator.
Now,
(6/13)= [(6×15)/ (13×15)] = (90/195)
(7/15) equals to [(7×13)/ (15×13)] = (91/195)
Then,
= (90/195) + (91/195) … [∵ the denominator is same in both the rational numbers]
= (90 + 91)/195
= (1/195)
(d) 3/8 – 7/11
Answer:
Take the LCM as the denominators of the above given rational numbers.
LCM of the numbers 8 and 11 is 88
Express each of the above given rational numbers with the above LCM, taking them as the common denominator.
Now,
(3/8)= [(3×11)/ (8×11)] equals to (33/88)
(7/11) equal to [(7×8)/ (11×8)] = (56/88)
Then,
= (33/88) – (56/88) … [∵ the denominator is same in both the rational numbers]
= (33 – 56)/88
= (89/88)
Question 11. Find the given product:
(a) (9/2) × (7/4)
Answer:
The product of the two rational numbers is equal to = (product of their numerator) divided (product of their denominator)
The above question can also be written as (9/2) × (7/4)
We have,
= (9×7)/ (2×4)
= 63/8
(b) (3/10) × (9)
Answer:
The product of two rational numbers is equal to (product of their numerator) divided by (product of their denominator)
The above question can also be written as (3/10) × (9/1)
We have,
= (3×9)/ (10×1)
= 27/10
(c) (6/5) × (9/11)
Answer:
The product of two rational numbers is equal to = (product of their numerator)/ (product of their denominator)
We have,
= (6×9)/ (5×11)
= 54/55
(d) (3/7) × (2/5)
Answer:
The product of two rational numbers is equal to = (product of their numerator)/ (product of their denominator)
We have,
= (3×2)/ (7×5)
= 6/35
(e) (3/11) × (2/5)
Answer:
The product of two rational numbers is equal to = (product of their numerator)/ (product of their denominator)
We have,
= (3×2)/ (11×5)
= 6/55
(f) (3/5) × (5/3)
Answer:
The product of two rational numbers is equal to = (product of their numerator)/ (product of their denominator)
We have,
= (3×5)/ (5×3)
On simplifying,
= (1×1)/ (1×1)
= 1/1
= 1
Question 12. Find the value of:
(a) (4) ÷ (2/3)
Answer:
We have,
= (4/1) × (3/2) … [∵ the reciprocal of the fraction (2/3) is (3/2)]
The product of two rational numbers is equal to = (product of their numerator) divided by (product of their denominator)
= (4×3) / (1×2)
= (2×3) / (1×1)
= 6
(b) (3/5) ÷ 2
Answer:
We have,
= (3/5) × (1/2) … [the reciprocal of (2/1) is (1/2)]
The product of the two rational numbers = (product of their numerator) divided by (product of their denominator)
= (3×1) / (5×2)
= 3/10
(c) (4/5) ÷ (3)
Answer:
We have,
= (4/5) × (1/3) … [∵ the reciprocal of (3) is (1/3)]
The product of two rational numbers is equal to = (product of their numerator)/ (product of their denominator)
= (4× (1)) / (5× (3))
= 4/15
= 4/15
(d) (1/8) ÷ 3/4
Answer:
We have,
= (1/8) × (4/3) … [the reciprocal of the fraction (3/4) is (4/3)]
The product of these two rational numbers is equal to = (product of their numerator)/ (product of their denominator)
= (1×4) / (8×3)
= (1×1) / (2×3)
= 1/6
(e) (2/13) ÷ 1/7
Answer :
We have,
= (2/13) × (7/1) … [∵ the reciprocal of (1/7) is (7/1)]
The product of the following two rational numbers is equal to = (product of their numerator)/ (product of their denominator)
= (2×7) / (13×1)
= 14/13
(f) (7/12) ÷ (2/13)
Answer:
We have,
= (7/12) × (13/2) … [the reciprocal of (2/13) is (13/2)]
The product of two rational numbers is equal to = (product of their numerator)/ (product of their denominator)
= (7× 13) / (12× (2))
= 91/24
= 91/24
(g) (3/13) ÷ (4/65)
Answer:
We have,
= (3/13) × (65/4) … [∵ the reciprocal of (4/65) is (65/4)]
The product of two rational numbers is equal to = (product of their numerator)/ (product of their denominator)
= (3×65) / (13× (4))
= 195/52
= 15/4
Benefits of Solving Important Questions Class 7 Mathematics Chapter 9
Many students tend to be scared of Mathematics. It is simply because they need help understanding the subject matter. Practice helps students to clear their doubts and generate interest in the subject matter. The experts have collected the questions from various sources so students can take their preparation to another level. The benefits of solving the Important Questions Class 7 Mathematics Chapter 9 are as follows
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FAQs (Frequently Asked Questions)
1. How can the Important Questions Class 7 Mathematics Chapter 9 help students?
The experts have collected the questions from different sources and solved the answers. Thus, the students can follow the questions and solve the sums regularly. They can also check the answers if they cannot solve the questions. Students often need more than textbook exercises to practice regularly. Thus, the Important Questions Class 7 Mathematics Chapter 9 will help students to clear their concepts and generate interest in the subject matter. Thus, it will help them to score better in exams.
2. What is the content of Class 7 Mathematics Chapter 9?
Class 7 Mathematics Chapter 9 is about rational numbers. Rational numbers are those numbers which ratios can express, that is, by denominator and numerator. In other words, it is the ratio of two integers. Thus, such numbers can be positive or negative. Students will get concepts about rational numbers and should regularly practice questions from the chapter to score better in exams. They can follow the Important Questions Class 7 Mathematics Chapter 9 to score better in exams.