NCERT Solutions Class 10 Maths Chapter 5 Exercise 5.3

” Mathematics is essential for students’ overall development. Mathematics knowledge can help students improve their logical thinking ability and analytical skills. Mathematics fundamentals are extremely useful in everyday activities. Basic arithmetic calculations are useful in carrying out everyday tasks. Mathematics is crucial for developing mental discipline Mathematical concepts are crucial for improving global comprehension and communication. Many official tasks necessitate basic mathematical operations and calculations. Students’ career opportunities are enhanced by their understanding of mathematical principles. With Mathematics knowledge, a student can work as a Business Analyst, Statistician, Mathematician, Information Research Scientist, and so on.

One of the core subjects in the Class 10 curriculum is Mathematics. Students are advised to develop analytical skills in order to study subjects in Class 10. Mathematics concepts can aid in the development of analytical thinking for all students. Mathematics is one of the required core subjects for students in Class 10. The most important aspect of learning mathematical concepts is practice. Class 10 students are encouraged to regularly practise chapter-based questions in order to improve their knowledge. Students must continually assess their Mathematics preparation level in order to improve their learning process.

With the help of revision notes for each chapter, students can easily revise the chapters of Mathematics. The concepts in a subject like Mathematics must be studied daily by students. Since questions from every chapter are covered in the Mathematics board examination, it is crucial for students to pay equal attention to each chapter. It is vital to periodically review the concepts in addition to studying them. The chapters of Mathematics should be studied and reviewed using all available online resources.

Each topic in the Mathematics textbook is explained with the aid of solved examples. For ease of understanding, each solved example is usually accompanied by a step-by-step guide. To fully understand the topics, students should read through the examples provided in the textbook.

Mathematics is easier than most students think. It is a very high-scoring subject if prepared well. Students can easily perform well on the Mathematics exam with adequate planning and effective study techniques.

It is suggested that students develop a list of all the equations in a chapter and periodically review it. In order to improve their Mathematics board examination preparation, students from the Central Board of Secondary Education (CBSE) Class 10 should continue to use online resources. To assist Class 10 students in effectively studying for the Mathematics examination, Extramarks provides sample papers, mock tests, NCERT solutions, past years’ papers, etc. Mathematics principles are applied in almost every other subject. Mathematics consists of applications in the field of Medical Science, Social Science, Engineering, and many more. In Science, Mathematics is necessary for modelling phenomena so that it can be applied for predictions. Numerical calculations are very important in subjects like Physics, Chemistry, etc. Students must focus on practising Mathematics questions on a regular basis. They can easily score higher marks in Mathematics with a proper strategy. Revision is very necessary for understanding the theoretical parts of Mathematics. All the concepts and topics need to be revised again and again for clear understanding.

The Ministry of Education created an educational board known as the Central Board of Secondary Education (CBSE). The CBSE Board is an Indian educational board that operates on a national scale. Every year, the CBSE Board conducts and manages final examinations for students in Class 10 and Class 12. The CBSE syllabus is followed by the majority of college entrance exams in India. The CBSE Board syllabus is used in the majority of private and public schools in India. To save time and effort, students of all classes are advised to learn the subject according to the CBSE syllabus. Class 10 students must improve their ongoing board exam preparations. Each subject is essential for achieving a high score in the CBSE Board Class 10 Examinations. While studying for the board examinations, students should focus on learning all of the topics and subtopics of a subject. Students should use the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 to improve their ability to solve mathematical problems. Students can use the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 to answer the exercise questions in Class 10 Chapter 5. Students in Class 10 can access the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 in PDF format from the Extramarks website and mobile application.

It is critical that students keep assessing their preparation to make necessary changes. Extramarks has mock tests that students can attend in order to test their knowledge of each subject. Mock tests are essential for improving performance in the final examination. Students will become familiar with the types of questions that can be framed from the topics in their syllabus after taking mock tests.Extramarks also generates personalised reports and analysis for students to get an overview of their preparation. They are very helpful in improving the learning strategies of students. Students from kindergarten to class 12 can take advantage of Extramarks to prepare for their respective examinations. They will be able to improve their learning experience in each subject with the guidance of the in-house teachers of Extramarks. Students from ICSE, CBSE, and other major state boards can take the help of Extramarks to get reliable study resources. Extramarks also has foundation courses for the preparation of Olympiad and NTSE examinations. The National Talent Search Examination (NTSE) is a national-level examination that is conducted by NCERT to find talented students from across the country and provide them with scholarships for higher education.

Class 10 is a crucial stage in students’ careers, and they should prepare well for the examinations. The Central Board of Secondary Education conducts examinations for Class 10 every year. Scoring well in Class 10 examinations has many benefits. The marks obtained in Class 10 are necessary for getting admission into top schools in India for higher studies. Many of the concepts learned in the Class 10 curriculum provide the groundwork for studying advanced subjects in higher education. Students are advised to concentrate well on learning all the subjects of Class 10 to be able to score higher marks in the upcoming examinations.

Chapter 5 is one of the important chapters in the Class 10 syllabus, that can be tested in the board examination. All its topics need to be carefully studied by students. It is important for Class 10 students to keep reviewing the topics in order to learn new concepts effectively. Students should develop a strategy to prepare for the Mathematics examination. Accessing the latest syllabus of Mathematics is very helpful in planning a strategy for learning the chapters. Students will be able to prepare effectively for the Mathematics examinations if they go through the topics in accordance with the syllabus. This will help students stay on the right track of preparation. The questions that appear in the Mathematics examinations are framed from topics given in the syllabus. Class 10 students can access the latest CBSE syllabus of Class 10 Mathematics from Extramarks.

It is recommended for students to rely on the Extramarks learning platform for accessing all the essential study materials needed for board examination preparation. Extramarks comprises very authentic and trustworthy study materials for students of all the classes. Students from CBSE, ICSE, and other major state boards can obtain study resources from the Extramarks website and mobile application. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are available on Extramarks in PDF format. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are beneficial resources for preparation for the Class 10 Mathematics examination. Students can utilise the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 to get appropriate solutions to questions of Exercise 5.3. There are 20 questions in Exercise 5.3. It is important to solve all 20 questions in order to improve your understanding of Chapter 5. A few questions of Exercise 5.3 can be difficult for students to solve. Students can solve those questions by referring to Class 10 Maths Chapter 5 Exercise 5.3 Solution. Students can practise questions in an effective manner with the aid of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. All the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are well-structured and given in an easy-to-understand language.

Solving the difficult questions will help develop a positive mindset in students, and they will be able to practise more.. It is critical to understand the requirements of each question before practising it. It is necessary to practise exercises again and again for a better understanding of the topics. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 can be utilised to practise Exercise 5.3 in an efficient manner. All the definitions and formulae of Chapter 5 need to be revised again and again. Students can also revise the important formulae and definitions of Chapter 5 with the assistance of NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. They must access the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 from the Extramarks website and mobile application.

Students belonging to Class 10 are advised to solve past years’ papers and sample papers of Mathematics. Students will be able to ascertain the marking scheme of Mathematics when they solve past years’ papers. It will help them focus more on practising topics that have higher weightage in Mathematics. Class 10 students can download the past years’ papers and sample papers of Mathematics from Extramarks.  All questions of Exercise 5.3 are based on the Sum of the First n Terms of an AP topic. Students must go through each portion of the topic to get a thorough understanding. If students get stuck while practising questions of Exercise 5.3, they should get the help of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are essential for getting an idea of how to solve questions related to the Sum of the First n Terms of an AP.

Confidence is necessary for practising questions regularly. When students feel confident, they are able to practise more. Solving questions with the use of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 is very helpful in boosting the confidence of Class 10 students. They can easily score higher marks in Mathematics examination with the help of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. Students are advised to keep practising the questions of Exercise 5.3 on a regular basis to prepare efficiently for the upcoming Mathematics examination. Class 10 students must learn to manage their time efficiently in order to score higher marks in the Mathematics examination. All the topics of Chapter 5 are explained well in the NCERT textbook of Mathematics. It is advisable to rely on the NCERT textbook when preparing for the Class 10 Mathematics examination as it is the recommended textbook by the CBSE Board. All the ideas and concepts are explained well in the NCERT textbooks. Students can easily understand all the topics if they refer to textbooks from time to time. All the important topics of Chapter 5 are thoroughly explained in the NCERT textbook. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 can be decisive for scoring well in the Mathematics examination. It is important for students to maintain a timetable for learning subjects in Class 10. All the subjects are necessary for obtaining higher marks in the board examination. They must keep referring to the study materials from time to time to prepare well for the upcoming examinations.

The in-house educators at Extramarks can help students with their problems. Extramarks’ faculties are always available to address their concerns. Extramarks focuses on concept development via video modules. These modules have been created by highly qualified teachers from across India. Extramarks is a learning platform that connects students and teachers. With the help of Extramarks, all students can develop subject concepts in an interactive manner. The Extramarks website and mobile application provide students with dependable and trustworthy study materials. Students can use the Extramarks learning platform to study subjects when it is convenient for them. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are also developed for boosting the ongoing preparation of Class 10 students. They can easily score well in the Mathematics examination with the assistance of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. It is advisable for Class 10 students to keep assessing their current preparation for the Mathematics examination. Students can take the help of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 in order to get a self-assessment of the current preparation in Mathematics. Class 10 students of the Central Board of Secondary Education can get reliable and trustworthy study materials from the Extramarks learning platform. They can refer to the study materials during the board examination preparations. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 can be downloaded from the Extramarks learning platform in PDF format. Students can also review the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 in offline mode as well. Students can easily gain higher marks in the Mathematics examination if they refer to the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 on a regular basis.

In a subject like Mathematics, it is essential for students to routinely practise questions. It can be difficult for some students to practise Mathematics chapters. In a subject like Mathematics, students have weaker areas that need to be identified and given extra practice. Students may find it challenging to create a study schedule for preparing Mathematics chapters. It is advised that students access the most recent Mathematics syllabus to become familiar with the topics and subtopics covered in Class 10 Mathematics. The Extramarks website and learning app allow students to access the most recent Class 10 Mathematics syllabus. Each chapter in Mathematics has its own requirement, and it is necessary to prepare in a manner that can fulfil its requirement. The topics of Mathematics tend to be interconnected with one another. Students should keep reviewing the topics that are already prepared in order to start preparing for the new topics. It is advised to keep solving the questions related to each topic of Chapter 5 regularly to get acquainted with the whole chapter. Students must solve all the problems of the Sum of First n Terms of an AP on a regular basis for improving their ongoing preparation for the Mathematics examination. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 assist students in solving questions based on the Sum of the First n Terms of an AP.

The National Council of Educational Research and Training (NCERT) publishes course books for all classes of the CBSE Board. The books of NCERT are created with the purpose of imparting well-balanced knowledge to students. Moreover, NCERT also conducts training for teachers at the primary and secondary levels.All the teachers are given the training they need to teach students in the best way possible. The NCERT is a government agency that comes under the Ministry of Education. It is also concerned with carrying out research in the field of school education in India. Research helps in bringing out necessary changes in the way schools conduct classes. NCERT joins with various education departments and universities of India to find solutions to problems being faced in school-based learning in India.NCERT also publishes the CBSE Board’s syllabus for all classes. The textbooks published by NCERT are very reliable and affordable.

It is necessary for students of Class 10 to develop a habit of solving problems on a regular basis in order to practise all the questions before the board examination. Practising Exercise 5.3 with the assistance of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 is beneficial for students to develop a habit of solving questions. They will develop the habit of solving math problems on a daily basis. Mathematics concepts covered in Class 10 are very vast and therefore require consistent revision and practice. Students must practise all the questions related to a chapter regularly. They must revise all the definitions, theorems, formulae, etc., of all the chapters.

It is necessary for students to access study materials from credible sources. Extramarks has very reliable and authentic learning materials for all subjects. Students can easily access them from the Extramarks’ website and mobile application. All the study materials are regularly updated with new changes in the syllabus. Students can rely on Extramarks for learning effectively for the upcoming examinations. Extramarks also provides study materials for the preparation of JEE, NEET, NTSE, etc. All students can easily download the study materials and boost their preparation for examinations. Extramarks is one of the most trusted learning platforms.

All the in-house teachers are experienced and very  competent. Students can easily get their doubts solved by them. They will find experts in each subject on Extramarks. They have years of experience in teaching. Extramarks live lectures can be used to learn concepts in an engaging and comprehensive manner.In Extramarks’ live lectures, all points related to a topic are thoroughly discussed.They are very interactive. Students can easily get solutions to problems related to a topic during the live sessions. Students will find it easier to prepare well for examinations under the guidance of Extramarks teachers.

There are figures used in explaining the topics of Chapter 5. Students can also use figures to understand the topics well. Students should make use of diagrams while solving questions related to certain topics. They can learn to give solutions along with diagrams with the help of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. Class 10 students must access the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 from the Extramarks learning platform. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are created in accordance with the latest syllabus of Class 10 Mathematics. Solving questions with the use of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 is helpful in motivating students to practise more questions. Class 10 students should trust the authenticity of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 as experienced Mathematics teachers have prepared them. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 assist in enhancing the learning process of students.

The topics covered in Chapter 5 are very important in terms of the board examination; therefore, it is necessary to practise questions related to all of the chapter’s topics.Most of the questions are helpful in improving the students’ understanding of arithmetic progression. It is also essential to focus on the derivations given in the chapter. All of the derivations are required for a thorough understanding of the topics.They will enable students to find solutions to problems posed to them in Chapter 5. All the derivations can be easily referred to with the assistance of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. Class 10 students must make use of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 in order to score higher marks in the Mathematics examination. When they practise questions with the NCERT Solutions for Class 10 Maths Chapter 5 Exercise 5.3, they will learn to provide efficient solutions.

It is necessary to be aware of the topics being dealt with when solving a question. Questions that appear in the examination are framed from the topics. All the topics specific to the questions inExercise 5.3 can also be revised through the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. Question 1 of Exercise 5.3 requires students to find the sum of given arithmetic progressions. Students who are unable to solve questions must refer to the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. All the formulae and derivations of the Sum of First n Terms of an AP topic are required for solving questions of Exercise 5.3. Class 10 students may also find it challenging to solve question 15 of the exercise, and it is important to refer to the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3.

There are various topics in Chapter 5 of Class 10 Mathematics. It is necessary to practise questions based on all of them. Solving questions related to a specific topic not only enhances knowledge of the topic but also increases preparation for the subject. Students can practise all the questions on a specific topic with the help of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are given in a simple format so that students can easily understand them. Students of Class 10 can also download the NCERT Solutions for other exercises of other chapters of Mathematics from Extramarks. The NCERT Solutions are very essential for effective preparation for the Mathematics examination. It is crucial for Class 10 students to practise questions regularly. Students are able to practise questions regularly if all their doubts and confusions are resolved. Mathematics teachers available on the Extramarks learning platform are always ready to help students find solutions to their doubts and confusions related to the subject.

Study materials like the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are essential to prepare efficiently for the upcoming board examination. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are designed in such a way that students can easily utilise them while practising questions. All the exercises in Chapter 5 are created in accordance with the latest mathematics syllabus.. Class 10 students must find reliable and authentic NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 in order to solve questions of Class 10 Maths Chapter 5 Exercise 5.3.

It is very important to carefully go through the topics of Chapter 5 and get acquainted with the formulae, definitions and diagrams given in the chapter. Students are supposed to revise them from time to time to be able to practise questions from the Arithmetic Progressions chapter. They can easily practise questions of the chapter by utilising NCERT Solutions. Maths Class 10 Chapter 5 Exercise 5.3 can be readily practised with the help of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3.

Reading the NCERT textbook is very effective for understanding the topics. It is the main source of information for students belonging to the CBSE Board. They can easily start preparing for the examinations with the help of NCERT textbooks. Students who are not able to fully understand the topics are recommended to take help from the Extramarks learning platform. The live classes of Extramarks are very essential for understanding topics in an efficient manner, and all the points are explained in detail. Class 10 students can also make use of the live lectures to prepare for the Mathematics examination. All the classes are conducted by the best educators in each subject. They are very qualified and capable of teaching students effectively. The knowledge gained in live lectures is very significant in preparing for the examinations. Class 10

Revision is very necessary for scoring well in the Mathematics examination. It helps students  quickly review the important topics, formulae, theorems, etc., of the chapters. Class 10 students can download the revision notes of Mathematics from Extramarks. Many of the topics are interconnected, therefore, it is crucial that students keep revising them. When topics are revised, again and again, students are able to find quick solutions to the questions. Revision notes are very useful in getting a review of all the important topics before the examinations. Students can also download the  NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 from Extramarks apart from the revision notes. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are very trusted and authentic resources for students to prepare for the upcoming Mathematics examination. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are prepared by expert teachers of Mathematics. Students will be able to score higher marks in Mathematics with the aid of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are very helpful learning materials.

There can be many ways of solving particular questions in Mathematics. It is necessary to learn the best method of solving questions in order to complete them in the allotted time. Students of Class 10 can learn to give solutions in a proper manner when they practise questions regularly. Solving problems with the help of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 is beneficial for learning the best method of solving questions. When they refer to the NCERT Solutions for Class 10 Maths, Chapter 5, Exercise 5.3, they will be able to provide proper solutionsSome of the questions of Exercise 5.3 can be daunting for students, and they will need the assistance of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. All the exercises of Chapter 5 are based on the topics covered in the chapter. Students will be able to prepare effectively for the Mathematics examination when they consistently practise the exercises of Chapter 5 along with the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3.

NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progression (Ex 5.3) Exercise 5.3

All the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are meant for helping Class 10 students to score well in the Mathematics examination. They will be able to give appropriate solutions to the questions in the Mathematics examination. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are accessible in PDF format on Extramarks. Some of the questions can be complex and it may become difficult for students to solve them. It is necessary to break down a complex problem into small and easy steps. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 will assist students in learning to break down complex problems into smaller steps. Continuous practise is essential for increasing the calculation speed of students. Practising questions with the help of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 is beneficial for increasing the calculation speed of Class 10 students. All the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are explained very thoroughly. Each step is given with a proper explanation.

Access NCERT Solutions for Class 10 Maths Chapter 5 – Arithmetic Progression

They will be able to thoroughly practise Chapter 5 with the assistance of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. They must access the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 from the Extramarks learning platform. Students can download the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 in PDF format.

Tips to Ace the Chapter!

The main theme of Chapter 5 is Arithmetic Progressions. It is crucial for students to get well acquainted with the meaning behind each topic for an easy understanding of the whole chapter. Each topic needs to be focused on well by students. Practising exercise questions of Chapter 5 is critical for the preparation for the Mathematics examination. Students are expected to try solving questions on their own and if they come across any difficulties they can refer to the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are important study materials that can be utilised to score well in the Class 10 Mathematics examination.

Students must learn appropriate methods of solving questions in order to solve problems in an efficient manner. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 can be used for learning appropriate methods of solving questions in Mathematics. Problem-solving is an important technique when preparing for a subject like Mathematics. Consistent practice is necessary for learning problem-solving techniques.  All the students in Class 10 are advised to practise all the exercises in Chapter 5 to increase their chances of scoring well in the Mathematics examination. When students access the NCERT Solutions for Class 10 Maths, Chapter 5, Exercise 5.3, they will learn how to implement new strategies in their own solutions.All 20 questions ofExercise 5.3 can be solved well with the aid of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. They are very useful for understanding the Sum of the First n Terms of AP topic in detail.

NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progression Exercise 5.3

It is advisable for students to practise sample papers and past years’ papers in Mathematics. It is necessary to practise sample papers and previous years’ papers of mathematics in order to perform well in the mathematics examination.. They are helpful in knowing the paper pattern and marking scheme of Mathematics. Students will be able to focus more on the topics that have more weightage. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are also useful for solving past years’ papers and sample papers of Mathematics. Many of the questions given in Exercise 5.3 are new for students, and it could be challenging for them to solve them. Students should then consult the NCERT Solutions for Class 10 Maths, Chapter 5, Exercise 5.3.The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 will assist them in finding exact solutions to the questions of Exercise 5.3. All of the NCERT Solutions for Class 10 Maths, Chapter 5, Exercise 5.3, are written in plain English.Students can refer to the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 whenever they are stuck during their practise sessions. All the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are accessible in PDF format on Extramarks.

On the Extramarks website and mobile application, learners will find the NCERT Solutions for all classes offered by the Central Board of Secondary Education (CBSE). Class 12 students can access NCERT Solutions Class 12 for all topics to improve their level of exam preparation. Students in Class 11 must do exercises while learning a subject’s chapters. The Extramarks website and mobile application both provide access to the NCERT Solutions for Class 11 for all topics. The Extramarks website and mobile application provide access to the NCERT Solutions Class 10 for English, Mathematics, Hindi, and other subjects. When preparing for the final exams, students must make use of the NCERT Solutions Class 9 book. For better test results, Class 8 students should constantly practise the exercise questions. All Class 8 students get access to the Extramarks NCERT Solutions Class 8.

All of the Class 7 Mathematics topics are significant, and students should concentrate on regularly practising the exercise questions. For proper answers to the questions in the NCERT Mathematics textbook, students can use the NCERT Solutions Class 7. On the Extramarks website and mobile app, students can obtain NCERT solutions Class 7 for topics other than Mathematics. Students should read the concepts from the NCERT textbooks on a regular basis.

It is recommended that all Class 6 students  use the NCERT Solutions Class 6 from the Extramarks learning platform to effectively prepare for their exams. Class 6 students must use the NCERT Solutions Class 6 to answer exercise questions from all subjects. Students in Class 5 can also access the NCERT Solutions Class 5 through the Extramarks learning platform. Students should read the concepts from the NCERT textbooks on a regular basis. Students in Class 4 are advised to use the NCERT Solutions Class 4 in order to score higher marks in the upcoming exams. NCERT Solutions Class 3 for English, Mathematics, Hindi, and other subjects are available to all Class 3 students via the Extramarks website and mobile application. The NCERT Solutions Class 2 are also available on the Extramarks website and mobile application to assist Class 2 students in exam preparation. NCERT Solutions Class 1 can be downloaded by all Class 1 students from Extramarks.

NCERT Solutions for Class 10 Maths Chapter 5 Exercises

Class 10 students are advised to make use of the Extramarks website and mobile application in order to download solutions for all the exercises of Chapter 5. Students can get all the NCERT solutions in PDF format on Extramarks. They can be referred to without an internet connection after being downloaded. Students will be able to obtain higher marks in Mathematics with the assistance of these NCERT solutions.

NCERT Solutions for Class 10 Maths

The Extramarks learning platform has NCERT solutions for all the chapters in Class 10 Mathematics. Students can access chapter-wise NCERT solutions in PDF format. All the chapters of Mathematics can be practised well with these solutions. There are formulae in Chapter 5 that are very necessary for finding solutions to given problems. It is necessary for students to review the formulae of the chapter, again and again, to be able to implement them while solving questions. The Class 10 students can revise the formulae of Chapter 5 with the help of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. It is very useful to keep referring to the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 from time to time. Students must access the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 from the Extramarks website and mobile application.

Q.1

Find the sums given below :(i) 7+1012+14+ . . . +84 (ii) 34+32+30+ . . . +10(iii) −5+(−8)+(−11)+. . .+(−230)

Ans.

(i) 7+1012+14+ . . . +84 Here, a=7,  d=a2−a1=1012−7=312=72,  l=84We know that         l=a+(n−1)dSo,  84=7+(n−1)72or 84−7=(n−1)72or 77×27+1=nor n=23We know that sum of first  n terms of an AP is given by            Sn=n2(a+l)So,    S23=232(7+84)=232×91or S23=1046.5So, the requird sum is 1046.5.(ii) 34+32+30+ . . . +10Here, a=34,  d=a2−a1=32−34=−2,  l=10We know that         l=a+(n−1)dSo,  10=34+(n−1)(−2)or 10−34=(n−1)(−2)or −24−2=n−1or n=13We know that sum of first  n terms of an AP is given by            Sn=n2(a+l)So,    S13=132(34+10)=132×44or S13=286So, the requird sum is 286.(iii) −5+(−8)+(−11)+. . .+(−230)Here, a=−5,  d=a2−a1=−8−(−5)=−3,  l=−230We know that         l=a+(n−1)dSo,  −230=−5+(n−1)(−3)or −230+5=(n−1)(−3)or −225−3+1=nor n=76We know that sum of first  n terms of an AP is given by            Sn=n2(a+l)So,    S75=762(−5−230)=38×(−235)or S75=−8930So, the requird sum is −8930.

Q.2

In an AP:(i) given a=5, d=3, an=50, find n and Sn.(ii) given a=7, a13=35, find d and S13.(iii) given a12=37, d=3, find a and S12.(iv) given a3=15, S10=125, find d and a10.(v) given d=5, S9=75, find a and a9.(vi) given a=2, d=8, Sn=90, find n and an.(vii) given a=8, an=62, Sn=210, find n and d.(viii) given an=4, d=2, Sn=−14, find n and a.(ix) given a=3, n=8, S=192, find d.(x) given l=28, S=144, and there are total 9 terms. Find a.

Ans.

(i) Here, a=5,  d=3,  an=50We have to find n and Sn.We know that         an=a+(n−1)dSo,  50=5+(n−1)3or 50−5=(n−1)3or 453+1=nor n=16We know that sum of first  n terms of an AP is given by            Sn=n2(a+an)So,    S16=162(5+50)=8×55or S16=440(ii) Here, a=7,   a13=35We have to find d and S13.We know that         an=a+(n−1)dSo,  a13=7+(13−1)dor 35−7=12dor 2812=dor d=73We know that sum of first  n terms of an AP is given by            Sn=n2(a+an)So,    S13=132(7+35)=132×42or S13=273(iii) Here,  a12=37, d=3We have to find a and S12.We know that         an=a+(n−1)dSo,  a12=a+(12−1)3or 37=a+33or    a=37−33=4We know that sum of first  n terms of an AP is given by            Sn=n2(a+an)So,    S12=122(a+a12)=6(4+37)or S12=246(iv) Here,  a3=15, S10=125We have to find d and a10.We know that         an=a+(n−1)dSo,  a3=a+(3−1)dor    a+2d=15                                                                            ...(1)We know that sum of first  n terms of an AP is given by            Sn=n2[2a+(n−1)d]So,    S10=102[2a+(10−1)d]=5[2a+9d]or 125=5[2a+9d]or 2a+9d=25                                                                      or      2(15−2d)+9d=25 [From (1), a=15−2d]or         5d=25−30=−5or d=−1 putting this value of d in (1), we get a=17.Now,             a10=a+(10−1)d=17+9×(−1)=8(v) Here,  d=5, S9=75We have to find a and a9.We know that         an=a+(n−1)dSo,  a9=a+(9−1)5or    a9−a=40                                                                            ...(1)We know that sum of first  n terms of an AP is given by            Sn=n2[2a+(n−1)d]So,    S9=92[2a+(9−1)5]=92[2a+40]or 75=9[a+20]or a=759−20=75−1809=−1059=−353or      a=−353On putting this value of a in (1), we get          a9−−353=40⇒ a9=  40−353=120−353=853(vi) Here,  a=2, d=8, Sn=90We have to find n and an.We know that         an=a+(n−1)dSo,  an=2+(n−1)8                                                                        ...(1)We know that sum of first  n terms of an AP is given by            Sn=n2[2a+(n−1)d]So,    Sn=n2[2×2+(n−1)8]or 90=2n+4n(n−1)=2n+4n2−4nor 90=4n2−2nor       2n2−n−45=0or 2n2−10n+9n−45=0or 2n(n−5)+9(n−5)=0or (2n+9)(n−5)=0or n=5On putting this value of n in (1), we get          a5=2+(5−1)8=34 (vii)Here,  a=8, an=62, Sn=210We have to find n and d.We know that         an=a+(n−1)dSo,  62=8+(n−1)d                                                                       ...(1)We know that sum of first  n terms of an AP is given by            Sn=n2(a+an)So,    210=n2(8+62)or 210=35nor n=21035=6On putting this value of n in (1), we get          62=8+(n−1)d =8+(6−1)d=8+5dor d=62−85 =545(viii) Here,  an=4, d=2, Sn=−14We have to find n and a.We know that         an=a+(n−1)dSo,  4=a+2(n−1)=a+2n−2  or    a+2n=6or    a=6−2n                                                                         ...(1)We know that sum of first  n terms of an AP is given by            Sn=n2(a+an)So, −14=n2(a+4)or n(a+4)=−28or n(6−2n+4)=−28                                             [From (1)]or 10n−2n2+28=0or n2−5n−14=0or n2−7n+2n−14=0or n(n−7)+2(n−7)=0or (n−7)(n+2)=0or n−7=0or n=7 [n is a natural number]On putting this value of n in (1), we get          a=6−2n  =6−2×7=−8(ix) Here,   a=3, n=8, S=192We know that sum of first  n terms of an AP is given by            S=n2[2a+(n−1)d]So,    192=82[2×3+(8−1)d]or 192=4[6+7d]or 6+7d=1924=48or 7d=48−6=42or d=427=6(x) Here,  l=28, S=144, n=9We have to find a.We know that sum of first  n terms of an AP is given by            S=n2(a+l)So,   144=92(a+28)or a+28= 144×29=16×2=32or a=32−28=4  

Q.3 

How many terms of the AP : 9, 17, 25, . . . must be taken to give a sum of 636?

Ans.

Here,   a=9, d=a2−a1=17−9=8, Sn=636We know that sum of first  n terms of an AP is given by            S=n2[2a+(n−1)d]So,   636=n2[2×9+(n−1)8]or 636=n2×2[9+4n−4]=4n2+5nor 4n2+5n−636=0or 4n2+53n−48n−636=0or n(4n+53)−12(4n+53)=0or (4n+53)(n−12)=0or n=12 [n is a natural number]Therefore, 12 terms of the given AP must be taken to give a sum of 636.

Q.4 The first term of an AP is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference.

Ans.

Here,  a=5, an=l=45, Sn=400We have to find n and d.We know that         an=a+(n−1)dSo,  45=5+(n−1)d                                                                       ...(1)We know that sum of first  n terms of an AP is given by            Sn=n2(a+an)So,    400=n2(5+45)or 400=25nor n=40025=16On putting this value of n in (1), we get          45=5+(n−1)d =5+(16−1)d=5+15dor d=45−515 =4015=83

Q.5 The first and the last terms of an AP are 17 and 350 respectively. If the common difference is 9, how many terms are there and what is their sum?

Ans.

Here,  a=17, an=l=350, d=9We have to find n and Sn.We know that         an=a+(n−1)dSo,  350=17+(n−1)9 or n−1=350−179=3339=37or n=37+1=38We know that sum of first  n terms of an AP is given by            Sn=n2(a+an)So,    S38=382(17+350)=19×367or S38=6973

Q.6 Find the sum of first 22 terms of an AP in which d = 7 and 22nd term is 149.

Ans.

Here,   a22=149, d=7We have to find S22.We know that         an=a+(n−1)dSo,  a22=a+(22−1)dor 149=a+21×7 =a+147or a=149−147=2We know that sum of first n terms of an AP is given by            Sn=n2(a+an)So,    S22=222(a+a22)=11(2+149)=11×151or S22=1661

Q.7 Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18 respectively.

Ans.

Here,   a2=14, a3=18Therefore, d=a3−a2=18−14=4We know that         an=a+(n−1)dSo,  a2=a+(2−1)dor 14=a+1×4 =a+4or a=14−4=10We know that sum of first n terms of an AP is given by            Sn=n2[2a+(n−1)d]So,    S51=512[2×10+(51−1)4]=512(20+200)=51×110or S51=5610

Q.8 If the sum of first 7 terms of an AP is 49 and that of 17 terms is 289, find the sum of first n terms.

Ans.

Here,   S7=49, S17=289We know that sum of first n terms of an AP is given by            Sn=n2[2a+(n−1)d]So,    S7=72[2a+(7−1)d]or 49=72(2a+6d)or 497=22(a+3d)or a+3d=7 ...(1)Also,            S17=172[2a+(17−1)d]or 289=172(2a+16d)=172×2(a+8d)or a+8d=17or 7−3d+8d=17 [From (1), a=7−3d]or 5d=17−7=10or d=105=2On putting this value of d in (1), we get             a=7−3d=7−3×2=1Therefore, sum of first n terms of the AP with a=1 and d=2 isgiven by Sn=n2[2×1+(n−1)2]=n(1+n−1)=n2

Q.9 Show that a1, a2, . . ., an, . . . form an AP where an is defined as below : (i) an = 3 + 4n (ii) an = 9 – 5n Also find the sum of the first 15 terms in each case.

Ans.

(i)Here,          an=3+4n⇒an+1=3+4(n+1)=3+4n+4=7+4nNow,an+1−an=7+4n−3−4n=4i.e., difference between a term and its preceding term is always 4.Therefore, a1, a2, . . ., an, . . . form an AP where an=3+4n.Now, we haved=an+1−an=4anda=a1=3+4×1=7 We know that sum of first n terms of an AP is given by            Sn=n2[2a+(n−1)d]So,    S15=152[2×7+(15−1)4]or S15=152×2[7+14×2]=15×35=525(ii)Here,         an=9−5n⇒an+1=9−5(n+1)=9−5n−5=4−5nNow,an+1−an=4−5n−(9−5n)=4−5n−9+5n=−5i.e., difference between a term and its preceding term isalways −5.Therefore, a1, a2, . . ., an, . . . form an AP where an=9−5n.Now, we haved=an+1−an=−5anda=a1=9−5×1=4We know that sum of first n terms of an AP is given by            Sn=n2[2a+(n−1)d]So,    S15=152[2×4+(15−1)(−5)]or S15=152×2[4−5×7]=−31×15=−465

Q.10 If the sum of the first n terms of an AP is 4n – n2, what is the first term (that is S1)? What is the sum of first two terms? What is the second term? Similarly, find the 3rd, the 10th and the nth terms.

Ans.

Here,          S=−n2⇒   S1=×1−12=3i.e., a=S1=3S2=×2−22=4Now,      a2= S2−S1=×2−22−3=8−4−3=1Similarly,a3= S3−S2=×3−32−×2−22     =12−9−8−4          =3−4=−1a10= S10−S9=×10−102−×9−92             =40−100−36−81=−60−−45                        =−60+45=−15an= Sn−Sn−1=×n−n2−×(n−1)−(n−1)2                            =n(4−n)−n−14−n+1                            =n(4−n)−n−15−n                            =4n−n2−5n+n2+5−n                           =−2n+5       =5−2n

Q.11 Find the sum of the first 40 positive integers divisible by 6.

Ans.

First 40 positive integers divisible by 6 forms an AP with a=6 and d=6.We know that sum of first n terms of an AP is given by         Sn=n2[2a+(n−1)d]So, S40=402[2×6+(40−1)6]=20[12+39×6]or S40=20[12+234]=20×246=4920

Q.12 Find the sum of the first 15 multiples of 8.

Ans.

First 15 multiples of 8 forms an AP with a=8 and d=8.We know that sum of first n terms of an AP is given by         Sn=n2[2a+(n−1)d]So, S15=152[2×8+(15−1)8]=152×8[2+14]or S15=60×16=960

Q.13 Find the sum of the odd numbers between 0 and 50.

Ans.

Odd numbers between 0 and 50 forms an AP with a=1 and d=2.Also, last term of this AP is 49.Therefore,    l=an=49⇒a+(n−1)d=49⇒1+(n−1)2=49⇒n−1=49−12=24⇒n=24+1=25We know that sum of first n terms of an AP is given by         Sn=n2[2a+(n−1)d]So, S25=252[2×1+(25−1)2]=252×2[1+24]or S25=25×25=625

Q.14 A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: ₹ 200 for the first day, ₹ 250 for the second day, ₹300 for the third day, etc., the penalty for each succeeding day being ₹ 50 more than for the preceding day. How much money the contractor has to pay as penalty, if he has delayed the work by 30 days?

Ans.

The given 30 penalties forms an AP with first term as 200and common difference as 50.So, we have a=200, d=50 and n=30.We know that sum of first n terms of an AP is given by         Sn=n2[2a+(n−1)d]So, S30=302[2×200+(30−1)50]=15[400+29×50]or S30=15[400+1450]=1850×15=27,750Therefore, the contractor has to pay ₹ 27,750 as penalty.

Q.15 A sum of ₹ 700 is to be used to give seven cash prizes to students of a school for their overall academic performance. If each prize is ₹ 20 less than its preceding prize, find the value of each of the prizes.

Ans.

The given 7 cash prizes forms an AP with common differenceas −20 and sum of all the 7 prizes as 700.So, we have S7=700, d=−20 and n=7.We know that sum of first n terms of an AP is given by         Sn=n2[2a+(n−1)d]So, S7=72[2a+(7−1)(−20)]=72×2[a−60]or 700=7[a−60]or a−60=7007=100or a=100+60=160Therefore, the values of all the 7 prizes are ₹ 160, ₹ 140, ₹ 120,₹ 100, ₹ 80, ₹ 60 and ₹ 40.

Q.16 In a school, students thought of planting trees in and around the school to reduce air pollution. It was decided that the number of trees, that each section of each class will plant, will be the same as the class, in which they are studying, e.g., a section of Class I will plant 1 tree, a section of Class II will plant 2 trees and so on till Class XII. There are three sections of each class. How many trees will be planted by the students?

Ans.

It is given that a section of Class I will plant 1 tree, a sectionof Class II will plant 2 trees and so on till Class XII. The number of trees planted by a section of each classforms an AP with a=1 and d=1.So, we have a=1, d=1 and n=12.We know that sum of first n terms of an AP is given by         Sn=n2[2a+(n−1)d]So, S12=122[2×1+(12−1)1]=6[2+11]or S12=78Therefore,       Sum of trees planted by a section of each class=78⇒ Sum of trees planted by 3 sections of each class=78×3                                                                                                            =234

Q.17 A spiral is made up of successive semicircles, with centres alternately at A and B, starting with centre at A, of radii 0.5 cm, 1.0 cm, 1.5 cm, 2.0 cm, . . . as shown in the following figure. What is the total length of such a spiral made up of thirteen consecutive semicircles? (Take π =22/7)

[Hint: Length of successive semicircles is l1, l2, l3, l4, . . . with centres at A, B, A, B, . . ., respectively.]

Ans.

Here, successive semicircles are of raddi 0.5 cm, 1.0 cm,1.5 cm, 2.0 cm, .… Let l1, l2, l3, l4, . . . are the lengths of successive semicirclesin the spiral.We know that length of semicircle is πr.So, lengths of successive semicircles are 0.5π cm, π cm,1.5π cm, 2π cm, .… Sum of lengths of 13 semicircles is π(0.5+1.0+1.5+2.0+ ...to 13th terms) cm.Now,List of numbers involved in sum 0.5+1.0+1.5+2.0+ ...to 13th terms forms an AP with a=0.5 and d=0.5We know that sum of first n terms of an AP is given by         Sn=n2[2a+(n−1)d]So, S13=132[2×0.5+(13−1)(0.5)]=132×0.5[2+12]or S13=132×0.5×14=45.5Therefore, Sum of lengths of 13 semicircles=π(0.5+1.0+1.5+2.0+...to 13th terms) cm=45.5π cm=45.5×227 cm=143 cmTherefore, total length of the spiral is 143 cm.

Q.18 200 logs are stacked in the following manner: 20 logs in the bottom row, 19 in the next row, 18 in the row next to it and so on (see the following figure). In how many rows are the 200 logs placed and how many logs are in the top row?

Ans.

It is given that 200 logs are stacked in such a way that20 logs are in the bottom row, 19 logs are in the next row,18 logs are in the row next to it and so on.List of numbers 20, 19, 18, ... involved in stacking of logsform an AP with a=20, d=−1 and Sn=200.We know that sum of first n terms of an AP is given by         Sn=n2[2a+(n−1)d]So, 200=n2[2×20+(n−1)(−1)]=n2[40+−n+1]or 200=n2[41−n]or 400=41n−n2or n2−41n+400=0or n2−16n−25n+400=0or n(n−16)−25(n−16)=0or (n−16)(n−25)=0or n=16, n=25Now,a25=a+24d=20+24×(−1)=−4But, number of logs can not be negative.Therefore, number of rows of logs can not be 25 i.e., n≠25.Also,a16=a+15d=20+15×(−1)=5Therefore, 200 logs are placed in 16 rows and 5 logs areplaced in the top row.

Q.19 In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato, and the other potatoes are placed 3 m apart in a straight line. There are ten potatoes in the line(see the following figure)

A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and she continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to run?
[Hint: To pick up the first potato and the second potato, the total distance (in metres) run by a competitor is 2 × 5 + 2 × (5 + 3)]

Ans.

In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato, and the other potatoes are placed 3 m apart in a straight line. There are ten potatoes in the line(see the following figure)

A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and she continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to run?
[Hint: To pick up the first potato and the second potato, the total distance (in metres) run by a competitor is 2 × 5 + 2 × (5 + 3)]

Q.20 Which term of the AP: 121, 117, 113, . . ., is its first negative term? [Hint: Find n for an < 0]

Ans.

The given AP is: 121, 117, 113, . . .Here, a=121, d=117−121=−4Now,an=a+(n−1) d =121+(n−1)(−4)      = 121−4n+4      = 125−4nWe have to find the first negative term of this A.P.So,     an<0⇒125−4n<0⇒4n>125⇒n>1254⇒n>31.25∴n=32Hence, 32nd term of the given AP is first negative term.

Please register to view this section

FAQs (Frequently Asked Questions)

1. What are the advantages of referring to the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3?

Students of Class 10 can score well in the forthcoming Mathematics examination with the assistance of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. They will learn better problem-solving skills with the help of the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3. Practising questions with the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are necessary for boosting the confidence of students and motivating them to practise more.

2. Which is the best place to download the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3?

Students can download the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 from the Extramarks website and mobile application. The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 are authentic and consist of appropriate solutions to Exercise 5.3 questions.

3. Are the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 accessible in PDF format?

The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 can be accessed in PDF format on the Extramarks learning platform. Students can also use the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 in offline mode  once it is downloaded.

4. What are the topics and subtopics covered in Class 10 Mathematics?

To ascertain the topics and subtopics that are covered in Class 10 Mathematics, it is essential to download the syllabus. Students can download it from the NCERT official website. They can also access the latest syllabus of Mathematics from Extramarks. The NCERT Solutions for Class 10 Maths, Chapter 5 Exercise 5.3 are written in accordance with the most recent mathematics curriculum.Are the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 available on Extramarks reliable?

The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 available on Extramarks are very genuine and reliable as they are curated by expert teachers of Mathematics. The NCERT Solutions for Class 10 Maths, Chapter 5, Exercise 5.3, are updated on a regular basis to reflect changes in the latest Mathematics syllabus.They are also checked from time to time for any errors.

5. Do the NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 consist of solutions for all the questions of Exercise 5.3?

The NCERT Solutions For Class 10 Maths Chapter 5 Exercise 5.3 consist of detailed and exact solutions for all  20 questions present in Exercise 5.3. When practising this exercise, it is critical to keep referring to the NCERT Solutions for Class 10 Maths, Chapter 5, Exercise 5.3.