# NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2

The Central Board of Secondary Education (CBSE) is one of the most reputed educational boards that operate in India. Many schools are affiliated with the CBSE board, which is spread across the country. The CBSE board is very popular among students and parents alike because of itscomprehensive study patterns. CBSE follows an extremely objective curriculum regarding its paper pattern and the structure of studying. An objective approach to education and the curriculum comprise questions that are highly analytical and conceptual. Students must know the chapter and the topic inside out and with substantial depth. Students must learn how to separate all the important information from the redundant information that is provided in the textbooks, and they must do it carefully and with precision without missing out on any important ideas. Students must thoroughly review their entire syllabus and chapters because CBSE focuses on questions that are highly cognitive, challenge the fundamentals of the topic, and can only be answered when the student has a thorough understanding of the entire chapter.

The questions that are generally asked in the CBSE exams are very direct, straightforward, and objective, although the answers are entrenched deep into the basics of the topic from which the questions are asked. As a result, Extramarks teachers have repeatedly reminded students that they must take the CBSE syllabus seriously and that they must regularly study and revise the chapters that they had completed previously.Most importantly, students must inculcate a habit of practising where they regularly go back to the exercises that they have been doing. Students are frequently overwhelmed by the abrupt change in scale of the curriculum that occurs when they advance to a higher secondary level.CBSE is widely known for its massive syllabus, and teachers have often found that students struggle greaty with finishing it.Students frequently become preoccupied with completing the syllabus and fail to revise the chapters in their curriculum that they had solved, or vice versa. Teachers at Extramarks have reassured students that if they incorporate small changes and tweak their daily routine, they can strategise a plan that would cause a significant decrease in the level of stress that has been hindering the student’s progress.

The National Council for Educational Research and Training NCERT is a central institution that functions in India. NCERT was set up by the Indian Government in 1961 because the newly formed Indian Government wanted an expert opinion from a group of highly qualified people who were appointed just to research and find the right solutions to all the issues related to the educational development of the country. NCERT provided assistance to both the Central Government and the State Governments on educational development issues.NCERT and CBSE share an extremely a symbiotic relationship where both depend on each other immensely. NCERT regularly puts out its set of rules and guidelines, which students must follow strictly. NCERT also has its own publishing house, with which they publish their books based on the well-curated curriculum and the syllabus that they have themselves prescribed. Therefore, since the NCERT textbooks directly adhere to their guidelines and rules, teachers unanimously ask all of their students to follow the NCERT textbook. The NCERT textbook must be treated by students as their primary textbook because, since these books are completely syncopated with the NCERT syllabus practising problems and questions from these books will sufficiently preparethe students for the distinct type of questions that are asked in the exams. In recent years, NCERT has made significant progress to improve the educational environment of the country.

They have provided students with different kinds of essential facilities which students can use to further their educational aspirations and desires. NCERT has made provisions for annual journals where students can get their niche academic opinions and papers published, based on which theycan begin their academic careers. NCERT also hosts various competitions all over India, which promote solidarity among students countrywide, and this is how different students can interact; creating a feeling of community where everyone can help each other out. NCERT has recently launched an amazing foreign exchange program for students who are interested in a more holistic understanding of the subject and the complicated ideas discussed in the chapters.

Mathematics is one of the core subjects that students in their Class 10 have. For the majority of students, all of the subjects in the Mathematics syllabus are the same.Students are generally graded based on the aggregate of what they have scored in all the other subjects. Therefore, students who aspire to ace the exams and get good grades have to take Mathematics very seriously. Students generally understandMathematics and deem it to be one of the most difficult subjects in their curriculum. The reason behind this is that, as teachers have noted, in order for students to score well in Mathematics, they need to practise the sums regularly. A student cannot expect to master the subject or the chapter in one go. The consistent approach and hard work that are required from students often cannot be matched, and therefore students tend to be scaredTherefore, the teachers at Extramarks have come up with and compiled the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2. Mostly all the ideas that are discussed in the Class 10 level of Mathematics are echoed and repeated in the other Science subjects that students have besides Mathematics like Physics and Chemistry. Ideas and concepts like Trigonometry, Calculus, Coordinate geometry and other ideas are present in almost every other Science subject. Students therefore must take Mathematics seriously if they desire to score well in their CBSE exams. Students are given their final grade based on the aggregate of all the subjects that they appear for in their exams, and therefore they cannot divide their attention to a subject, in a very uniform way. Students are implored by teachers that they must seriously attempt to finish the syllabus with sufficient time left for them to revise the chapters.

The NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 provide solutions to all the unsolved questions that are provided for students to solve and practise in the NCERT Class 10 CBSE textbook. The NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 provide comprehensive and meticulous solutions to all the problems. The NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 are compiled and curated by top educators at Extramarks. The teachers who provide the solutions for NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 are highly qualified and trained. These teachers have years of experience teaching students who are in Class 10 preparing for their boards. The NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 adhere to all the guidelines and follow every rule that CBSE and NCERT provide. It is very important that the solutions follow the NCERT guidelines. This is because when students practise problems based on solutions, they become familiar with the pattern and type of questions that are commonly found in exams.Therefore, solving problems and using the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 is counterproductive to the whole premise. Teachers who have compiled the solutions, therefore, have taken extra care to formulate the answers.

**NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry (Ex 7.2) Exercise 7.2**

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All the solutions that are provided for the following Classes completely correspond to the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2. The exact way the solutions for NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 were compiled by the teachers at Extramarks is how the solutions for all the other subjects of all the other Classes have been compiled. The NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 is one of the best learning tools that are available on the Extramarks website.

Click on the link below to access the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 on their website. The NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 are also available on their mobile application.Class 10 Maths Ex 7.2 can be solved using the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2, which can help students score higher marks in their exams.The solutions to 7.2 Class 10 Maths are trustworthy and comprehensive because they were compiled by experts..

**Topics Covered in Exercise 7.2**

Coordinate geometry is one of the most important topics on the syllabus, and it is highly relevant.. A large number of questions come from this section, and if students do not pay attention to these chapters, they could lose marks; therefore, students must practise the chapter regularly. The solutions to the Class 10 Maths Chapter 7 Exercise 7.2 can be downloaded in PDF format for offline access.

**What is Section Formula? **

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**Access NCERT Solutions for Class-10 Maths Chapter 7 – Coordinate Geometry**

The NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 are one of the most amazing resources that have been made available for students. The NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 are curated and compiled with care and precision, making sure they are completely devoid of errors. Students are encouraged by teachers at Extramarks to always refer to the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 because the guidance provided is immaculate.

**NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Exercise 7.2**

The NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 can be used dynamically. One of the primary uses of the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 is when students are solving mathematical problems for the first time in the NCERT textbook. When students are solving unsolved questions for the first time, it is very natural that they will come across various doubts. Students are always told by the teachers at Extramarks that doubts are nothing to be feared because they help students figure out the areas that need attention.. NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 is written in such a simple language that students irrespective of their academic background can easily comprehend them. When students use the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 while they are solving problems, they get very used to the correct way of answering questions that they must provide for their exams. The NCERT Solutions for Class 10 Maths, Chapter 7, Exercise 7.2, can help students improve their board exam preparation and score higher marks.

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The kind of questions that CBSE asks in their exams are highly analytical and conceptual, and students must have a very solid foundation for the subjects and topics. CBSE wants its students to be able to visualise and implement everything that they are learning in the practical world. When students understand and know how many things around them work. The NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 have been compiled by subject-matter specialists and can be relied upon.

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**NCERT Solutions for Class 10 Maths Chapter 7 All Other Exercises**

Extramarks has a repertoire of amazing resources on its website. Students in Class 10 often struggle with keeping up with their classes, so there is a provision for recorded lectures.. These lectures are recorded by teachers at Extramarks who are highly qualified and highly esteemed in their particular fields. These lectures are very scientific, and they are made in a very interactive manner, which makes sure that students retain all the information. These solutions are also referred to by students when they are looking back at the sums because when they redo the problems that they had solved long ago, they can keep track of their progress, whichhelps them strategise their exam plan. When students regularly use the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 they are very familiar with the language in which the answers must be provided in the exams, CBSE values and marks answers and sums that follow a distinct pattern. CBSE wants the mathematical problems solved in a way that enables students to approach these sums in a more analytical manner.

**Q.1 **

**Ans**

$\begin{array}{l}\text{We find the coordinates of the point which divides the}\\ \text{join of (}-\text{1, 7) and (4,}-\text{3) in the ratio 2}:\text{3 using section}\\ \text{formula.}\\ \text{So, we have}\\ \mathrm{x}=\frac{2\times 4+3(-1)}{2+3}=1\\ \text{and}\\ \mathrm{y}=\frac{2\times (-3)+3\times 7}{2+3}=3\\ \text{Therefore, coordinates of the required point are (1, 3).}\end{array}$

**Q.2** Find the coordinates of the points of trisection of the line segment joining (4, –1) and (–2, –3).

**Ans**

$\begin{array}{l}{\text{Let P(x}}_{1}{\text{, y}}_{1}{\text{) and Q(x}}_{2}{\text{, y}}_{2}\text{) are the points of trisection of}\\ \text{the line segment joining the given points A(4,}-1)\text{and}\\ \text{B(}-2,\text{\hspace{0.17em}\hspace{0.17em}}-3).\\ \text{So, AP}=\text{PQ}=\text{BQ and}\\ \text{Therefore, point P divides AB internally in the ratio 1}:2.\\ \text{By section formula, we have}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}{\mathrm{x}}_{1}=\frac{1\times (-2)+2\times 4}{1+2}=2\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}{\mathrm{y}}_{1}=\frac{1\times (-3)+2\times (-1)}{1+2}=\frac{-5}{3}\\ \text{Therefore, coordinates of the point P are}(2,\text{}\frac{-5}{3}).\\ \text{Point Q divides AB internally in the ratio 2}:1.\text{\hspace{0.17em}So, we have}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}{\mathrm{x}}_{2}=\frac{2\times (-2)+1\times 4}{2+1}=0\\ \text{and}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}{\mathrm{y}}_{2}=\frac{2\times (-3)+1\times (-1)}{2+1}=\frac{-7}{3}\\ \text{Therefore, coordinates of the point Q are}\left(\text{0,}\frac{-7}{3}\right)\text{.}\end{array}$

**Q.3 **

\begin{array}{l}\text{To conduct Sports Day activities, in your rectangular}\\ \text{shaped school ground ABCD, lines have been drawn}\\ \text{with chalk powder at a distance of 1m each}\text{. 100 flower}\\ \text{pots have been placed at a distance of 1m from each}\\ \text{other along AD, as shown in the following figure}\text{. Niharika}\\ \text{runs}\frac{1}{4}\text{th the distance AD on the 2nd line and posts a}\\ \text{green flag}\text{. Preet runs}\frac{\text{1}}{5}\text{th the distance AD on the eighth}\\ \text{line and posts a red flag}\text{. What is the distance between}\\ \text{both the flags? If Rashmi has to post a blue flag exactly}\\ \text{halfway between the line segment joining the two flags,}\\ \text{where should she post her flag?}\end{array}

**Ans**

$\begin{array}{l}\text{Niharika posts the green flag at}\frac{1}{4}\text{of the distance AD i.e.,}\frac{100}{4}\text{m}=25\text{m}\\ \text{from the starting point of 2nd line.}\\ \text{Therefore, the coordinates of this point G are (2, 25).}\\ \text{Also, Preet posts red flag at}\frac{1}{5}\text{of the distance AD i.e.,}\frac{100}{5}\text{m}=20\text{m}\\ \text{from the starting point of 8th line.}\\ \text{Therefore, the coordinates of this point R are (8, 20).}\\ \text{Distance between these flags}=\sqrt{{(2-8)}^{2}+{(25-20)}^{2}}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\sqrt{36+25}=\sqrt{61}\text{m}\\ \text{Rashmi has to post blue flag at the mid-point A(x, y) of the line segment}\\ \text{joining the red and green flags.}\\ \text{So, we have}\\ \mathrm{x}=\frac{2+8}{2}=5\text{and}\mathrm{y}=\frac{25+20}{2}=\frac{45}{2}=22.5\\ \text{Coordinates of the point where blue flag should be posted are (5, 22.5).}\\ \text{Therefore, Rashmi should post her blue flag at 22.5 m on the 5th line.}\end{array}$

**Q.4 ** Find the ratio in which the line segment joining the points (–3, 10) and (6, –8) is divided by (–1, 6).

**Ans**

$\begin{array}{l}\text{Let the ratio in which the line segment joining the points}\\ (-3,\text{}10)\text{and}(6,\text{\hspace{0.17em}\hspace{0.17em}}-8)\text{is divided by}(-1,\text{}6)\text{be}\mathrm{k}:1.\\ \text{Therefore,}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}-1=\frac{6\mathrm{k}-3}{\mathrm{k}+1}\\ \text{or}-\mathrm{k}-1=6\mathrm{k}-3\\ \text{or}-\mathrm{k}-6\mathrm{k}-1+3=0\\ \text{or}-7\mathrm{k}+2=0\\ \text{or \hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{k}=\frac{2}{7}\\ \text{Therefore, the required ratio is 2:7.}\end{array}$

**Q.5 ** **Find the ratio in which the line segment joining A(1, – 5) and B(– 4, 5) is divided by the x-axis. Also find the coordinates of the point of division.
**

**Ans**

$\begin{array}{l}\text{Let the ratio in which the line segment joining A}(1,\text{}-5)\\ \text{and B}(-4,\text{}5)\text{is divided by the x-axis be}\mathrm{k}:1.\\ \text{Therefore,}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{x}=\frac{-4\mathrm{k}+1}{\mathrm{k}+1}\text{and}0=\frac{5\mathrm{k}-5}{\mathrm{k}+1}\text{}\\ \text{Now,}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}0=\frac{5\mathrm{k}-5}{\mathrm{k}+1}\text{}\\ \text{or}0=5\mathrm{k}-5\\ \text{or \hspace{0.17em}}\mathrm{k}=1\\ \text{Therefore, the required ratio is 1:1.}\\ \text{Also,}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{x}=\frac{-4\mathrm{k}+1}{\mathrm{k}+1}=\frac{-4+1}{1+1}=\frac{-3}{2}\\ \text{Therefore, the given line segment is divided by the point}\\ (\frac{-3}{2},\text{0})\text{in the ratio 1:1.}\end{array}$

**Q.6 ** If (1, 2), (4, y), (x, 6) and (3, 5) are the vertices of a parallelogram taken in order, find x and y.

**Ans**

$\begin{array}{l}\text{Let A}\left(\text{1, 2}\right)\text{, B}\left(\text{4, y}\right)\text{, C}\left(\text{x, 6}\right)\text{and D}\left(\text{3, 5}\right)\text{are the vertices}\\ \text{of a parallelogram ABCD. Diagonals of a parallelogram}\\ \text{bisect each other. Therefore, intersection point O of}\\ \text{diagonals AC and BD is the mid-point of these diagonals.}\\ \text{Now, O is the mid-point of AC.}\\ \text{Therefore, coordinates of O are}(\frac{1+\mathrm{x}}{2},\text{}\frac{2+6}{2})\text{i.e.,}(\frac{1+\mathrm{x}}{2},\text{}4).\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\\ \text{Also, O is the mid-point of BD.}\\ \text{Therefore, coordinates of O are}(\frac{4+3}{2},\text{}\frac{\mathrm{y}+5}{2})\text{i.e.,}(\frac{7}{2},\text{}\frac{\mathrm{y}+5}{2}).\\ \text{So, we have}\\ \frac{1+\mathrm{x}}{2}=\frac{7}{2}\text{i.e.,}\mathrm{x}=6\\ \text{and}\\ \frac{\mathrm{y}+5}{2}=4\text{i.e.,}\mathrm{y}=3\end{array}$

**Q.7 ** Find the coordinates of a point A, where AB is the diameter of a circle whose centre is (2, –3) and B is (1, 4).

**Ans**

$\begin{array}{l}\text{Let the coordinates of point A be (x, y).}\\ \text{Mid-point of AB is (2,}-\text{3), which is the centre of the circle.}\\ \text{Therefore,}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em} (2,}-\text{3)}=(\frac{\mathrm{x}+1}{2},\text{}\frac{\mathrm{y}+4}{2})\\ \text{i.e., 2}=\frac{\mathrm{x}+1}{2}\text{and}-\text{3}=\frac{\mathrm{y}+4}{2}\\ \text{i.e.,}\mathrm{x}=3\text{and}\mathrm{y}=-10\\ \text{Therefore, the coordinates of A are (3,}-10).\end{array}$

**Q.8 **

$\begin{array}{l}\text{If A and B are (}-\text{2,}-\text{2) and (2,}-\text{4), respectively,}\\ \text{find the coordinates of P such that AP}=\frac{3}{7}\text{AB and P}\\ \text{lies on the line segment AB.}\end{array}$

**Ans**

$\begin{array}{l}\text{Point P divides the line segment AB in the ratio}3:4.\\ \text{Therefore,}\\ \text{coordinates of P}=(\frac{3\times 2+4\times (-2)}{3+4},\text{}\frac{3\times (-4)+4\times (-2)}{3+4})\\ \text{\hspace{0.17em}}=(\frac{-2}{7},\text{}\frac{-20}{7})\end{array}$

**Q.9 **

$\begin{array}{l}\text{Find the coordinates of the points which divide the}\\ \text{line segment joining A(}-\text{2, 2) and B(2, 8) into four}\\ \text{equal parts.}\end{array}$

**Ans**

$\begin{array}{l}\text{From the above figure, we observe that points P, Q, R divide}\\ \text{the line segment in ratio}1:3,\text{1:1, 3:1 respectively.}\\ \text{Therefore,}\\ \text{coordinates of P}=(\frac{2\times 1-2\times 3}{1+3},\text{}\frac{1\times 8+3\times 2}{1+3})=(-1,\text{}\frac{7}{2}),\\ \text{coordinates of Q}=(\frac{2-2}{1+1},\text{}\frac{8+2}{1+1})=(0,\text{}5),\\ \text{and}\\ \text{coordinates of R}=(\frac{3\times 2-2\times 1}{1+3},\text{}\frac{3\times 8+1\times 2}{1+3})=(1,\text{}\frac{13}{2}).\end{array}$

**Q.10 **

$\begin{array}{l}\text{Find the area of a rhombus if its vertices are (3, 0),}\\ \text{(4, 5), (}-\text{1, 4) and (}-\text{2,}-\text{1) taken in order.}\\ \text{[Hint : Area of a rhombus}=\frac{1}{2}\text{(product of its diagonals)]}\end{array}$

**Ans**

$\begin{array}{l}\text{Let A}\left(\text{3, 0}\right)\text{, B}\left(\text{4, 5}\right)\text{, C}(-1\text{, 4})\text{and D}(-\text{2,}-1)\text{are the vertices}\\ \text{of a rhombus ABCD.}\end{array}$

$\begin{array}{l}\text{Length of diagonal AC}=\sqrt{{\left[3-(-1)\right]}^{2}+{(0-4)}^{2}}=4\sqrt{2}\\ \text{Length of diagonal BD}=\sqrt{{\left[4-(-2)\right]}^{2}+{[5-(-1\left)\right]}^{2}}=6\sqrt{2}\\ \\ \text{Therefore, area of rhombus ABCD}=\frac{1}{2}\times 4\sqrt{2}\times 6\sqrt{2}\\ \text{}=24\text{square units.}\end{array}$

## FAQs (Frequently Asked Questions)

### 1. How must a student use the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2?

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- The NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 can be used by students as they are solving the Mathematics exercise for the first time.
- The NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 can be used by students when they are revisiting the chapter for the first time. When students are revising they must try to attempt and answer the questions by themselves first and they must use the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 only when they cannot solve the problem at all.
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### 2. Why should a student use the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2?

There are various uses of the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 and they are as follows-

- Students must use the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 because these solutions can be accessed anytime and anywhere online. The Extramarks website has more resources than just the NCERT solutions.
- The solutions in NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 are provided by the top educators at Extramarks and they are highly qualified. Therefore students using NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 are always under professional supervision and expert guidance.
- Students using the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 save a lot of time. When students come across a doubt they must never overlook it. Students generally wait for external help like that of their teachers to get their doubts cleared. When students refer to NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 instead of relying on someone else, students progress with their syllabus seamlessly.
- The NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 are also available on the Extramarks website and the mobile application. These solutions are also available in the Hindi language. For students who would appear in their final exam of Hindi, the Hindi-translated solutions are an amazing resource for these students.

### 3. What are the other resources available on the Extramarks website besides the NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2?

The NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.2 is one of the many resources available on the Extramarks website. The other resources that were made available to students are-

- Recorded lectures.
- Live lectures.
- Test series and various sets of quizzes.
- Analysis report for the performance of the students.
- Options for live chat.