# NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion (Ex 12.2) Exercise 12.2

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**NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion (Ex 12.2) Exercise 12.2**

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**Access NCERT Solutions for Class 6 Maths Chapter 12- Ratio and Proportion**

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**NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Exercise 12.2**

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**Q.1 **Determine if the following are in proportion.

(a) 15, 45, 40, 120 (b) 33, 121, 9,96

(c) 24, 28, 36, 48 (d) 32, 48, 70, 210

(e) 4, 6, 8, 12 (f) 33, 44, 75, 100

**Ans.**

(a) Ratio of 15 and 45 = 15:45

= 1:3

Ratio of 40 and 120 = 40:120

= 1:3

Since, 15:45 = 40:120

Therefore, 15, 45, 40 and 120 are in proportion.

(b) Ratio of 33 and 121= 33:121

= 3:11

Ratio of 9 and 96 = 9:96

= 3:32

since, 33:121 ≠ 9:96

Therefore, 33, 121, 9 and 96 are not in proportion.

(c) Ratio of 24 and 28 = 24:28

= 6:7

Ratio of 36 and 48 = 36:48

= 3:4

since, 24:28 ≠ 36:48

Therefore, 24, 28, 36 and 48 are not in proportion.

(d) Ratio of 32 and 48 = 32:48

= 2:3

Ratio of 70 and 210 = 70:210

= 1:3

since, 32:48 ≠ 70:210

Therefore, 32, 48, 70 and 210 are not in proportion.

(e) Ratio of 4 and 6 = 4:6

= 2:3

Ratio of 8 and 12 = 8:12

= 2:3

since, 4:6 = 8:12

Therefore, 4, 6, 8 and 12 are in proportion.

(f) Ratio of 33 and 44 = 33:44

= 3:4

Ratio of 75 and 100 = 75:100

= 3:4

since, 33:44 = 75:100

Therefore, 33, 44, 75 and 100 are in proportion.

**Q.2 **Write True (T) or False (F) against each of the following statements:

(a) 16 : 24 :: 20 : 30 (b) 21: 6 :: 35 : 10

(c) 12 : 18 :: 28 : 12 (d) 8 : 9 :: 24 : 27

(e) 5.2 : 3.9 :: 3 : 4 (f) 0.9 : 0.36 :: 10 : 4

**Ans.**

$\begin{array}{l}\left(\mathrm{a}\right)\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Ratio}\text{of 16 and 24}=\frac{16}{24}\\ =\frac{8\times 2}{8\times 3}\\ =\frac{2}{3}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Ratio}\text{of 20 and 30}=\frac{20}{30}\\ =\frac{10\times 2}{10\times 3}\\ =\frac{2}{3}\\ \mathrm{So},\text{\xe2\u20ac\u2039 \hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}16:24::20:30}\\ \mathrm{Therefore},\text{it is true.}\\ \left(\mathrm{b}\right)\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Ratio}\text{of 21 and 6}=\frac{21}{6}\\ =\frac{3\times 7}{3\times 2}\\ =\frac{7}{2}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Ratio}\text{of 35 and 10}=\frac{35}{10}\\ =\frac{5\times 7}{5\times 2}\\ =\frac{7}{2}\\ \mathrm{So},\text{\xe2\u20ac\u2039 \hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}21:6::35:10}\\ \mathrm{Therefore},\text{it is true.}\\ \left(\mathrm{c}\right)\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Ratio}\text{of 12 and 18}=\frac{12}{18}\\ =\frac{6\times 2}{6\times 3}\\ =\frac{2}{3}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Ratio}\text{of 28 and 12}=\frac{28}{12}\\ =\frac{4\times 7}{4\times 3}\\ =\frac{7}{3}\\ \mathrm{So},\text{\xe2\u20ac\u2039 \hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}12:18}\ne \text{28:12}\\ \mathrm{Therefore},\text{it is False.}\\ \left(\mathrm{d}\right)\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Ratio}\text{of 8 and 9}=\frac{8}{9}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Ratio}\text{of 24 and 27}=\frac{24}{27}\\ =\frac{3\times 8}{3\times 9}\\ =\frac{8}{9}\\ \mathrm{So},\text{\xe2\u20ac\u2039 \hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}8:9}=\text{24:27}\\ \mathrm{Therefore},\text{it is True.}\\ \left(\mathrm{e}\right)\text{\hspace{0.17em}}\mathrm{Ratio}\text{of 5.2 and 3.9}=\frac{5.2}{3.9}\\ =\frac{1.3\times 4}{1.3\times 3}\\ =\frac{4}{3}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Ratio}\text{of 3 and 4}=\frac{3}{4}\\ \mathrm{So},\text{\xe2\u20ac\u2039 \hspace{0.17em}\hspace{0.17em}5.2:3.9}\ne \text{3:4}\\ \mathrm{Therefore},\text{it is False.}\\ \left(\mathrm{f}\right)\text{\hspace{0.17em}}\mathrm{Ratio}\text{of 0.9 and 0.36}=\frac{0.9}{0.36}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{0.9\times 1}{0.9\times 4}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{1}{4}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Ratio}\text{of 10 and 4}=\frac{10}{4}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{2\times 5}{2\times 2}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{5}{2}\\ \mathrm{So},\text{\xe2\u20ac\u2039 \hspace{0.17em}0.9:0.36}\ne \text{10:4}\\ \mathrm{Therefore},\text{it is False.}\end{array}$

**Q.3 **Are the following statements true?

(a) 40 persons: 200 persons = 15: 75

(b) 7.5 litres: 15 litres = 5 kg: 10 kg

(c) 99 kg: 45 kg = 44: 20

(d) 32 m: 64 m = 6 sec: 12 sec

(e) 45 km: 60 km = 12 hours: 15 hours

**Ans.**

$\begin{array}{l}\left(\mathrm{a}\right)\text{Ratio of 40 persons and 200 persons}=\frac{40}{200}\\ =\frac{40\times 1}{40\times 5}\\ =\frac{1}{5}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}Ratio of 15 and 75}=\frac{15}{75}\\ =\frac{15\times 1}{15\times 5}\\ =\frac{1}{5}\\ \mathrm{So},\text{}40\text{}\mathrm{persons}:200\text{}\mathrm{persons}=\text{}15:\text{}75\\ \mathrm{Therefore},\text{the given statement is true.}\\ \left(\mathrm{b}\right)\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}Ratio of 7.5 litres and 15 litres}=\frac{7.5}{15}\\ =\frac{7.5\times 1}{7.5\times 2}\\ =\frac{1}{2}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}Ratio of 5 kg and 10 kg}=\frac{5}{10}\\ =\frac{5\times 1}{5\times 2}\\ =\frac{1}{2}\\ \mathrm{So},\text{}7.5\text{}\mathrm{litres}:15\text{}\mathrm{litres}=5\text{}\mathrm{kg}:10\text{\hspace{0.17em}}\mathrm{kg}.\\ \mathrm{Therefore},\text{the given statement is true.}\\ \left(\mathrm{c}\right)\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}Ratio of 99 kg and 45 kg}=\frac{99}{45}\\ =\frac{9\times 11}{9\times 5}\\ =\frac{11}{5}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}Ratio of 44 and 20}=\frac{44}{20}\\ =\frac{4\times 11}{4\times 5}\\ =\frac{11}{5}\\ \therefore \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}99\text{}\mathrm{kg}:45\text{}\mathrm{kg}=\text{}44:\text{}20.\\ \mathrm{Therefore},\text{the given statement is true.}\\ \left(\mathrm{d}\right)\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}Ratio of 32 m and 64 m}=\frac{32}{64}\\ =\frac{32\times 1}{32\times 2}\\ =\frac{1}{2}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}Ratio of 6\hspace{0.17em}sec and 12\hspace{0.17em}sec}=\frac{6}{12}\\ =\frac{6\times 1}{6\times 2}\\ =\frac{1}{2}\\ \therefore \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}32\text{}\mathrm{m}:64\text{}\mathrm{m}=6\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{sec}:12\text{\hspace{0.17em}}\mathrm{sec}.\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Therefore},\text{the given statement is true.}\\ \left(\mathrm{e}\right)\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}Ratio of 45 km and 60 km}=\frac{45}{60}\\ =\frac{3\times 15}{4\times 15}\\ =\frac{3}{4}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}Ratio of 12 hours and 15 hours}=\frac{12}{15}\\ =\frac{3\times 4}{3\times 5}\\ =\frac{4}{5}\\ \therefore \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}45 km}:\text{60 km}\ne \text{12 hours}:\text{15 hours}.\\ \mathrm{Therefore},\text{the given statement is false.}\end{array}$

**Q.4 **Determine if the following ratios form a proportion. Also, write the middle terms and extreme terms where the ratios form a proportion.

(a) 25 cm : 1 m and 40 : 160

(b) 39 litres : 65 litres and 6 bottles : 10 bottles

(c) 2 kg: 80 kg and 25 g: 625 g

(d) 200 ml : 2.5 litre and 4 : 50

**Ans.**

$\begin{array}{l}\left(\mathrm{a}\right)\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Ratio}\text{of}25\text{}\mathrm{cm}\text{and}1\text{}\mathrm{m}=\frac{25}{100}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{1}{4}\\ \text{\hspace{0.17em}\hspace{0.17em}}\mathrm{Ratio}\text{of}\text{}40\text{and}\text{}160=\frac{40}{160}\\ =\frac{40\times 1}{40\times 4}\\ =\frac{1}{4}\\ \mathrm{Here},\text{\hspace{0.17em}}25\text{}\mathrm{cm}:1\text{}\mathrm{m}=\text{}40:\text{}160.\\ \mathrm{So},\text{}25\text{}\mathrm{cm}:1\text{}\mathrm{m}\text{}\mathrm{and}\text{}\text{}40:\text{}160\text{are in proportion.}\\ \text{Middle terms of the proportion are: 1m and 40.}\\ \text{Extreme terms of the proportion are: 25 cm and 160.}\\ \left(\mathrm{b}\right)\text{\hspace{0.17em}Ratio of}39\text{}\mathrm{litres}\text{}\mathrm{and}\text{}65\text{}\mathrm{litres}=\frac{39}{65}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{13\times 3}{13\times 5}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{3}{5}\\ \text{\hspace{0.17em}\hspace{0.17em}Ratio}\mathrm{of}\text{\hspace{0.17em}}6\text{}\mathrm{bottles}\text{}\mathrm{and}\text{}10\text{}\mathrm{bottles}=\frac{6}{10}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{2\times 3}{5\times 5}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{3}{5}\\ \mathrm{Here},\text{\hspace{0.17em}}39\text{}\mathrm{litres}:65\text{}\mathrm{litres}=6\text{}\mathrm{bottles}:10\text{}\mathrm{bottles}.\\ \mathrm{So},\text{}39\text{}\mathrm{litres}:65\text{}\mathrm{litres}::6\text{}\mathrm{bottles}:10\text{}\mathrm{bottles}\text{are in proportion.}\\ \text{Middle terms of the proportion are:}65\text{}\mathrm{litres}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{and}\text{\hspace{0.17em}\hspace{0.17em}}6\text{}\mathrm{bottles}\text{.}\\ \text{Extreme terms of the proportion are:}39\text{}\mathrm{litres}\text{and}10\text{}\mathrm{bottles}\text{.}\\ \left(\mathrm{c}\right)\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}Ratio of}2\text{}\mathrm{kg}\text{}\mathrm{and}\text{}80\text{}\mathrm{kg}=\frac{2}{80}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{1}{40}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}Ratio}\mathrm{of}\text{\hspace{0.17em}}25\text{}\mathrm{g}\text{}\mathrm{and}\text{}625\text{}\mathrm{g}=\frac{25}{625}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{25\times 1}{25\times 25}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{1}{25}\\ \mathrm{Here},\text{\hspace{0.17em}}2\text{}\mathrm{kg}:80\text{}\mathrm{kg}\ne 25\text{}\mathrm{g}:625\text{}\mathrm{g}.\\ \mathrm{So},\text{}2\text{}\mathrm{kg}:80\text{}\mathrm{kg}\text{}\mathrm{and}\text{\hspace{0.17em}}25\text{}\mathrm{g}:625\text{}\mathrm{g}\text{are}\mathrm{not}\text{in proportion.}\\ \left(\mathrm{d}\right)\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}Ratio of}200\text{}\mathrm{ml}\text{}\mathrm{and}\text{}2.5\text{}\mathrm{l}=\frac{200}{2500}\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}[\xe2\u02c6\mu 1\mathrm{l}=1000\text{\hspace{0.17em}}\mathrm{ml}]\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{2}{25}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}Ratio}\mathrm{of}\text{\hspace{0.17em}}4\text{}\mathrm{and}\text{}50=\frac{4}{50}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{2\times 2}{2\times 25}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{2}{25}\\ \mathrm{Here},\text{\hspace{0.17em}}200\text{}\mathrm{ml}:2.5\text{}\mathrm{l}::4:50.\\ \mathrm{So},\text{}200\text{}\mathrm{ml}:2.5\text{}\mathrm{l}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{and}\text{\hspace{0.17em}\hspace{0.17em}}4:50\text{are in proportion.}\\ \text{Middle terms of the proportion are: 2.5}\mathrm{litres}\text{and}4.\\ \text{Extreme terms of the proportion are: 200 ml and 50.}\end{array}$

##### FAQs (Frequently Asked Questions)

## 1. Where can students find the NCERT Solutions Class 6 Maths Chapter 12 Exercise 12.2?

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## 2. How can students prepare for the Class 6 Mathematics examinations?

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## 4. How many chapters are there in the curriculum of Class 6 Mathematics?

There are fourteen chapters in the NCERT textbook of Class 6 Mathematics. Extramarks provides students with the NCERT Solutions Class 6 Maths Chapter 12 Exercise 12.2 and many other learning tools which provide them with a comprehensive and enjoyable learning process. It is also recommended that students practice the NCERT Exemplar questions in order to score well in any in-school or competitive examination. Through Extramarks, they can have access to a variety of tools and resources to help them learn, practice, and excel in their studies.

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There are numerous benefits of reviewing the NCERT Solutions Class 6 Maths Chapter 12 Exercise 12.2. These solutions outline the basic concepts of the chapter, so it is important for students to understand them. Also, the NCERT Solutions Class 6 Maths Chapter 12 Exercise 12.2 make it easier for the students to understand the concepts of the chapter as they are curated by Extramarks subject experts. As a result, students are able to grasp the concepts without having to deal with any linguistic difficulties. The Extramarks website provides students with all the resources they need to succeed in examinations and grow academically. Since these solutions are curated in a clear and simple manner, students can easily understand the concepts of the chapter. Furthermore, these solutions also provide learners with an idea of the format in which answers should be written in the examinations. Since the subject’s curriculum is entirely based on the NCERT curriculum, these solutions are also used as the primary source of teaching in CBSE schools.

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