# NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion (Ex 12.3) Exercise 12.3

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**NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion (Ex 12.3) Exercise 12.3 **

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**Access NCERT solutions for Class 6 Chapter 12- Ratio and Proportion**

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**NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion Exercise 12.3**

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In the NCERT Solutions Class 6 Maths Chapter 12 Exercise 12.3, there are questions in Ratio and Proportion that deal with using the unitary technique to solve issues. Students can use the idea of Ratio and Proportion to answer arithmetic problems in this activity, which consists of 11 engaging questions. Students will gain a solid understanding of the concepts required to solve a variety of issues by completing these sums. Students can benefit from NCERT Solutions Class 6 Maths Chapter 12 Exercise 12.3, which helps them build their foundational Ratio and Proportion skills.

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**Q.1 **If the cost of 7 m of cloth is 294, find the cost of 5 m of cloth.

**Ans.**

$\begin{array}{l}\mathrm{The}\text{cost of 7\hspace{0.17em}m of cloth}=\text{\hspace{0.17em}}294\\ \mathrm{The}\text{cost of 1\hspace{0.17em}m of cloth}=\frac{\text{\hspace{0.17em}}294}{7}\\ \text{\hspace{0.17em}\hspace{0.17em}}=\text{\hspace{0.17em}}42\\ \mathrm{The}\text{cost of 5\hspace{0.17em}m of cloth}=\text{\hspace{0.17em}}42\times 5\\ \text{\hspace{0.17em}\hspace{0.17em}}=\text{\hspace{0.17em}}210\end{array}$

**Q.2 **Ekta earns 1500 in 10 days. How much will she earn in 30 days?

**Ans.**

$\begin{array}{l}\mathrm{Ekta}\text{earns money in 10 days}=\text{\hspace{0.17em}}1500\\ \mathrm{Ekta}\text{earns money in 1 day}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}=\text{\hspace{0.17em}}\frac{1500}{10}\\ \mathrm{Ekta}\text{earns money in 30 days}=\text{\hspace{0.17em}}150\times 30\\ \text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}=\text{\hspace{0.17em}}4500\end{array}$

**Q.3 **If it has rained 276 mm in the last 3 days, how many cm of rain will fall in one full week (7 days)? Assume that the rain continues to fall at the same rate.

Ans.

$\begin{array}{l}\mathrm{The}\text{height of rain water in 3 days}=276\text{\hspace{0.17em}}\mathrm{mm}\\ \text{\hspace{0.17em}\hspace{0.17em}}\mathrm{The}\text{height of rain water in 1 day}=\frac{276}{3}\text{\hspace{0.17em}}\mathrm{mm}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=92\text{\hspace{0.17em}}\mathrm{mm}\\ \mathrm{The}\text{height of rain water in 7 days}=92\text{\hspace{0.17em}}\mathrm{mm}\times 7\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=644\text{\hspace{0.17em}}\mathrm{mm}\\ \mathrm{Thus},\text{644\hspace{0.17em}mm of rain will fall in one full week.}\end{array}$

**Q.4** Cost of 5 kg of wheat is 30.50.

(a) What will be the cost of 8 kg of wheat?

(b) What quantity of wheat can be purchased in 61?

**Ans.**

$\begin{array}{l}\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{The}\text{cost of 5 kg of wheat}=30.50\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{The}\text{cost of 1 kg of wheat}=\frac{30.50}{5}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=6.10\\ \left(\mathrm{a}\right)\mathrm{The}\text{cost of 8 kg of wheat}=6.10\times 8\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=48.80\\ \left(\mathrm{b}\right)\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Wheat}\text{bought for 30.50}=5\text{\hspace{0.17em}}\mathrm{kg}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Wheat}\text{bought for 1}=\frac{5}{30.10}\text{\hspace{0.17em}}\mathrm{kg}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Wheat}\text{bought for 61}=\frac{5}{30.10}\text{\hspace{0.17em}}\mathrm{kg}\times 61\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=10.13\text{\hspace{0.17em}}\mathrm{kg}~10\text{\hspace{0.17em}}\mathrm{kg}\end{array}$

**Q.5 **The temperature dropped 15 degree celsius in the last 30 days. If the rate of temperature drop remains the same, how many degrees will the temperature drop in the next ten days?

**Ans.**

$\begin{array}{l}\mathrm{The}\text{temperature dropped in 30 days}=15\text{\hspace{0.17em}}\mathrm{\xb0}\mathrm{C}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{The}\text{temperature dropped in 1 day}=\frac{15}{30}\text{\hspace{0.17em}}\mathrm{\xb0}\mathrm{C}\\ \text{\hspace{0.17em}\hspace{0.17em}}=0.5\text{\hspace{0.17em}}\mathrm{\xb0}\mathrm{C}\\ \mathrm{The}\text{temperature dropped in 10 days}=0.5\text{\hspace{0.17em}}\mathrm{\xb0}\mathrm{C}\times 10\\ \text{\hspace{0.17em}\hspace{0.17em}}=5\text{\hspace{0.17em}}\mathrm{\xb0}\mathrm{C}\\ \mathrm{Therefore},\text{5\hspace{0.17em}\xb0C temperature will fall in next 10 days.}\end{array}$

**Q.6** Shaina pays 7500 as rent for 3 months. How much does she has to pay for a whole year, if the rent per month remains same?

Ans.

$\begin{array}{l}\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{Sheena}\text{pays rent for 3 months}=\text{7500}\\ \text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\mathrm{\hspace{0.17em}}\mathrm{Sheena}\mathrm{pays}\mathrm{rent}\mathrm{for}1\mathrm{month}=\text{}\frac{\text{7500}}{3}\\ \text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}=\text{\hspace{0.17em}}\text{\hspace{0.17em}}2500\\ \mathrm{Sheena}\mathrm{pays}\mathrm{rent}\mathrm{for}12\mathrm{months}=\text{2500}\times \text{12}\\ \text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}=\text{\hspace{0.17em}}30,000\end{array}$

**Q.7 **Cost of 4 dozens bananas is 60. How many bananas can be purchased for 12.50?

**Ans.**

$\begin{array}{l}\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Bananas}\text{purchased for 60}=4\text{\hspace{0.17em}}\mathrm{dozens}\\ \text{\hspace{0.17em}}\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\text{\hspace{0.17em}}48[\xe2\u02c6\mu 1\text{\hspace{0.17em}}\mathrm{dozen}=12]\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Banana}\text{purchased for 1}=\frac{48}{60}\\ \mathrm{Banana}\text{purchased for 1}2.50=\frac{4}{5}\times 12.50\\ \text{\hspace{0.17em}}=10\\ \mathrm{Therefore},\text{10 bananas are purchased for 12.50.}\end{array}$

**Q.8** The weight of 72 books is 9 kg. What is the weight of 40 such books?

**Ans.**

$\begin{array}{l}\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Weight}\mathrm{of}72\mathrm{books}=9\text{\hspace{0.17em}}\mathrm{kg}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{Weight}\text{of 1 book}=\frac{9}{72}\text{\hspace{0.17em}}\mathrm{kg}\\ \mathrm{Weight}\text{of 40 such books}=\frac{1}{8}\times 40\text{\hspace{0.17em}}\mathrm{kg}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=5\mathrm{kg}\\ \mathrm{Thus},\text{the weight of 40 book is 5 kg.}\end{array}$

**Q.9 **A truck requires 108 litres of diesel for covering a distance of 594 km. How much diesel will be required by the truck to cover a distance of 1650 km?

**Ans.**

$\begin{array}{l}\mathrm{A}\text{truck requires diesel for covering distance of 594 km}\\ =108\text{\hspace{0.17em}}\mathrm{l}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\mathrm{A}\text{truck requires diesel for covering distance of 1 km}\\ =\frac{108}{594}\text{\hspace{0.17em}}\mathrm{l}\\ \mathrm{A}\text{truck requires diesel for covering distance of 1650 km}\\ =\frac{108}{594}\times 1650\text{\hspace{0.17em}}\mathrm{l}\\ =300\text{\hspace{0.17em}}\mathrm{l}\\ \mathrm{Thus},\text{300}\mathrm{l}\text{diesel is required for covering 1650 km.}\end{array}$

**Q.10 **Raju purchases 10 pens for 150 and Manish buys 7 pens for 84. Can you say who got the pens cheaper?

**Ans**.

$\begin{array}{l}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\mathrm{Raju}\mathrm{paid}\mathrm{money}\mathrm{for}10\mathrm{pens}=150\\ \text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\mathrm{Raju}\mathrm{paid}\mathrm{money}\mathrm{for}1\mathrm{pen}=\frac{150}{10}\\ \text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}=15\\ \mathrm{Manish}\mathrm{paid}\mathrm{money}\mathrm{for}7\mathrm{pens}=84\\ \text{\hspace{0.17em}}\text{\hspace{0.17em}}\mathrm{Manish}\mathrm{paid}\mathrm{money}\mathrm{for}1\mathrm{pen}=\frac{84}{7}\\ \text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}=12\\ \mathrm{Therefore},\mathrm{Manish}\mathrm{got}\mathrm{the}\mathrm{pens}\mathrm{cheaper}\mathrm{.}\end{array}$

**Q.11 **Anish made 42 runs in 6 overs and Anup made 63 runs in 7 overs. Who made more runs per over?

**Ans.**

$\begin{array}{l}\mathrm{Ashish}\mathrm{made}\mathrm{runs}\mathrm{in}6\mathrm{overs}=42\\ \text{\hspace{0.17em}}\hspace{0.17em}\mathrm{Ashish}\mathrm{made}\mathrm{runs}\mathrm{in}1\mathrm{over}=\frac{42}{6}\\ \text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}=7\\ \text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\mathrm{Anup}\mathrm{made}\mathrm{runs}\mathrm{in}7\mathrm{overs}=63\\ \text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\mathrm{Anup}\mathrm{made}\mathrm{runs}\mathrm{in}1\mathrm{over}=\frac{63}{7}\\ \text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}=9\\ \mathrm{Therefore},\mathrm{}\mathrm{Anup}\mathrm{made}\mathrm{more}\mathrm{runs}\mathrm{per}\mathrm{over}\mathrm{.}\end{array}$

##### FAQs (Frequently Asked Questions)

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The easiest approach for students to acquire the knowledge encapsulated in topics is reading the NCERT Solutions Class 6 Maths Chapter 12 Exercise 12.3 to diligently and consistently practice. Before trying the practice problems, students must get a profound understanding of each of the chapter’s subjects. Theorems, equations, and problems must all be continually revised by students. The student’s ability to solve any sort of test question will increase as a result of their firm conceptual basis.

## 3. How many questions are there in the NCERT Solutions Class 6 Maths Chapter 12 Exercise 12.3?

Students can use the NCERT Solutions Class 6 Maths Chapter 12 Exercise 12.3 based on Ratio and Proportion to answer arithmetic problems in this exercise, which consists of 11 engaging questions. Students will get a strong understanding of the ideas required to solve a variety of problems by completing these sums. To answer every question, the appropriate strategy or technique is applied. Students can succeed in their examinations by using the NCERT Solutions Class 6 Maths Chapter 12 Exercise 12.3.