# NCERT Solutions For Class 7 Maths Chapter 13 Exponents and Powers (EX 13.1) Exercise 13.1

The NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 covers all of the important topics and offers complete answers, step by step, along with the questions. The NCERT textbook questions are easily solved with the help of NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 . The questions in the NCERT textbooks are arranged chapter-wise, and are supposed to be solved with precision in order to get the correct results. As the questions given in the NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1  are thorough and prepared by Extramarks experts, students must download them. Students are advised to download the NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 from Extramarks’ website.

## NCERT Solutions For Class 7 Maths Chapter 13 Exponents and Powers (EX 13.1) Exercise 13.1

This chapter deals with Exponents and Powers. Power is an expression that suggests repeated multiplication of the equal factor, and Exponent manner the variety of instances a number of is expanded through itself. Exponents are used for writing the lengthy numbers as brief notations to make those numbers easy to understand, study and compare. There are many guidelines of Exponents. In the NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1, there are various solutions for solving these types of problems. The NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 are easier to understand because it has given simpler ways of solving questions from the textbooks.

The NCERT Solutions for Class 7 Maths, Chapter 13, Exercise 13.1 help students gain a better understanding of concepts.The NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 will assist students in finding all of the guidelines of exponents, which are multiplication, multiplying, and dividing the powers with exponents, and numbers with exponent 0 with a couple of examples, and this helps in developing and strengthening the topics and concepts more accurately for students in Class 7 who are practising this Chapter.The NCERT Solutions for Class 7 Maths, Chapter 13, Exercise 13.1 will teach students about the Decimal and Variety of Decimal Systems, as well as specific formulas and their forms.

The most important topics and subtopics included in Class 7 Mathematics are:

• Exponents
• Laws of Exponent
• Multiplying powers with the equal base
• Dividing powers with an equal base
• Taking the strength of a strength
• Multiplying powers with an equal base
• Examples the usage of legal guidelines for exponents
• Decimal variety system
• Expressing big numbers in fashionable form

Exponents and Powers is a crucial chapter in Class 7, and NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 covers the fundamental principles of exponents and powers.Students will study the Exponent Properties, Formulation, Notation, Orders, Magnitude, and other Properties of Exponents and different associated basics of this Chapter. The questions of Exponents and Powers can be solved without problems after students can go through the NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 and apprehend them in detail.

The topics and subtopics included in this textbook are as follows :

• Introduction
• Exponents
• Laws of exponents
• Multiplying Powers With the Same Base
• Dividing Powers with the Same Base
• Taking Power of a Power
• Multiplying Powers with the Same Exponents
• Dividing Powers with the Same Exponents
• Miscellaneous Examples Using the Laws of Exponents
• Decimal Number System
• Expressing Large Numbers the use of Standard Form

The Exponents are the repeated multiplication of the identical wide variety of same number with recognize to the wide variety of times. For example, 8 = 2 x 2 x 2. Therefore, the use of Exponents method elevating more than a few time to a Power, wherein the Exponent is the Power of the number. The extent to which the Power is raised is known as the limit of the power, thus, in any number, the bottom is the base and upper on number is the Exponent. The distinction among the Power and Exponents are, the Exponent is the Power raised to the bottom and therefore the power denotes the strength of that number.

• Exponents and Powers Class 7 Formulas

If p is a rational wide variety and feature a non-0 fee, m is a herbal wide variety, then,

p × p × p × p ×…..× p(m times) is written as pm, wherein p is the base value and m is the Exponent and p to the Power m is the strength and ‘p to the power m’ is stated as ‘p – raised to the strength m’. This is the overall illustration of Exponents and Powers.

Example: nine × nine × nine × nine × nine × nine × nine = 9 to the Power 7, wherein nine is the base value and seven is the exponent.

There are some basic principles of Exponents described to clear up complicated questions  primarily based totally on Powers And Exponents.

### Access NCERT Solution For Class 7 Chapter 13- Exponents And Powers

All the Chapter of Class 7 Mathematics NCERT Solutions available on the Extramarks website are discussed in brief here:

NCERT Solutions – Integers for Class 7 Mathematics Chapter 1

Chapter 1 talks in detail about the properties of Integers. An Integer is an entire variety that may be Positive, Negative Or Zero. In this Chapter, students can learn about different kinds of Integers, their properties and operations. Likewise, the addition and the subtraction of the Integers,  properties of addition and subtraction of Integers, multiplication and division of Integers, and other important topics of Integers. Students can find various solutions along with NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1

NCERT Solutions – Fractions and Decimals for Class 7 Mathematics Chapter 2

Chapter 2 of the NCERT textbook is about Fractions And Decimals. Students have learned about Fractions and Decimals, addition and subtraction in the previous course. Now they will explore multiplication and division operations with both fractions and decimals.

Similarly, multiply Fractions by Integers, multiply Fractions by Fractions, divide Integers by Fractions, divide fractions by Integers, multiply Decimals by 10, 100, 100, and so on. They will Multiply Decimals by Decimals, divide Decimals by 10, 100, 1000, etc., divide Decimals by Whole Numbers. Students must visit Extramarks for accessing various learning tools like the NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1.

NCERT Solutions for Class 7 Mathematics Chapter three – Data Handling

The third chapter of the textbook is about data handling.Data Handling refers to the procedure of gathering, recording, and offering records in a manner that is useful to others – for instance, in graphs or charts. The NCERT texts also describe data processing. In previous courses, students have worked with different types of data. Students have also learned how to collect Data, tabulate it, and present it in the form of Bar Charts. Now, in this chapter, it will take them one step further in learning how to do that. This chapter covers topics such as Data Collection, Data Organisation, Representative Values, Arithmetic Means, Modes For Large Data Sets, Medians, Using Bar Charts for various purposes, Scales, Probabilities, and other probabilities. Students can visit the website of Extramarks and download the NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 along with other solutions.

NCERT Mathematics  Solutions Chapter 7 – Compare Sets

Chapter 7 of the NCERT sample text relates to Comparing Sets. Two quantities are compared only when, their units are same. Two ratios can be compared by converting them to equal Fractions. Two given Ratios are said to be equal if the two Fractions are equal. Related topics are Equivalence Ratio, Converting Fractions to Percentages, Converting Decimals to Percentages, and Converting Percentages to Fractions or Decimals.

NCERT Solutions for Mathematics Class 7 Chapter 8 – Rational Numbers

Chapter 8 of the NCERT Exemplar text covers the topic of Rational Numbers. A Rational Number is a number that can be expressed as the quotient of Two Integers with a numerator p and a nonzero denominator q or as a fraction p/q. All Integers are Rational because q can be 1. Topics covered in this chapter include Positive and Negative Rational Numbers, Rational Numbers on the Number Line, Rational Numbers in Standard Form, Comparison of Rational Numbers, and Arithmetic on Rational Numbers.

NCERT Solutions for Class 7 Mathematics Chapter 9 – Perimeter and Area

In this chapter, the main topic of discussion is Perimeter and Area. Perimeter is the distance around the closed shape, and area is the portion of the plane or area occupied by the closed shape. In this chapter, students will learn about Squares and Rectangles, Triangles as part of Rectangles, Areas of Parallelograms, Triangles and Circles, and Perimeters of Circles. Students must visit the Extramarks website and download NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 along with other Mathematics solutions.

NCERT Solutions for Class 7 Mathematics Chapter 10 – Algebraic Expressions

In Chapter 10, an Algebraic Expression is a Mathematical expression that includes Variables, Numbers and Operations. The Algebraic Expression of  textbook consists of various subtopics such as no. to terms, Monomials, Binomials, Trinomials and Polynomials, Addition and Subtraction of Algebraic Expressions, which are available on Extramarks. Students can also download the NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1

NCERT Solutions for Class 7 Mathematics Chapter eleven – Exponents and Powers

Chapter eleven of the NCERT Exemplar textbook discusses the subject Exponents and Powers. Exponents are  made from rational numbers that have numerous instances, which are known asPowers.  They are used to express huge numbers in a shorter form to make them easier to read, understand, evaluate, and perform upon. The chapter discusses properties such as multiplying powers with an equal base, dividing powers with an equal base, elevating powers to powers, and powers ruling.Students can consult NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 and the Extramarks website for solutions to other chapters.NCERT Solutions for Class 7 Mathematics Chapter 12 – Practical Geometry Symmetry and Visualising Solid Shapes

This Chapter deals with Practical Geometry Symmetry and Visualising Solid Shapes. Symmetry is the approach that one form or shape will be identical to other part if it is totally similar to the other part. Topics covered in this Chapter are of Symmetry for everyday Polygons, Line Symmetry and Rotational Symmetry. Practical Geometry Symmetry and Visualising Solid Shapes of NCERT textbook deals with the figures and solids, faces, edges, vertices, methods for constructing 3D shapes, drawing solids on a flat surface, indirect sketches, isometric sketches.

The NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 are taken into consideration as one of the most important study material for Class 7 students who want guidance in  Mathematics. The NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 will help them to ace the without fear. The NCERT Solutions for Class 7 Maths, Chapter 13, Exercise 13.1 solutions have a systematic layout with exceptional shortcut strategies to ensure that students develop the idea and score the highest marks in Mathematics.NCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers Exercise 13.1

To gain some extra marks in the examination, school students need to go through the subject matter thoroughly, in addition to the instruction in the NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1. A proper practisemethod needs to be observed that allows students to gain extra marks in the annual examination. The NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 include solutions for all of the important questions of the NCERT textbook.

Regularly reading the textbook questions and solving questions with the help of NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 will help students as the usage of these NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 enhances the problem-solving skills of school students, which is necessary for preparing for the examination without fear. Extramarks’ website contains the NCERT Solutions for Class 7 Maths, Chapter 13, Exercise 13.1.The answers in the NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 are in PDF format, which can be downloaded and accessed through the website effortlessly. Both the NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 and other solutions are designed by professional teachers who have experience in the respective fields.

Students can clear up textbook issues by completing NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 and getting their questions answered right away.Students in Class 7 who are having difficulty answering textbook questions can use NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 to discuss their donuts.The NCERT Solutions for Class 7 Maths, Chapter 13, Exercise 13.1 curates the answers in accordance with the CBSE syllabus and CBSE board recommendations.The solutions in NCERT Solutions for Class 7 Maths, Chapter 13, Exercise 13.1 help to improve logical reasoning and analytical skills in order to solve difficult questions.

Q.1

$\begin{array}{l}\text{Find the value of:}\\ \left(\text{i}\right){\text{ 2}}^{\text{6}}\text{ }\left(\text{ii}\right){\text{ 9}}^{\text{3}}\text{ }\left(\text{iii}\right){\text{ 11}}^{\text{2}}\text{ }\left(\text{iv}\right){\text{ 5}}^{\text{4}}\end{array}$

Ans

$\begin{array}{l}\left(\mathrm{i}\right)\text{ }{2}^{6}\\ =2×2×2×2×2×2\\ =64\\ \\ \left(\mathrm{ii}\right)\text{ }{9}^{3}\\ =9×9×9\\ =729\\ \\ \left(\mathrm{iii}\right)\text{ }{11}^{2}\\ =11×11\\ =121\\ \\ \left(\mathrm{iv}\right)\text{ }{5}^{4}\\ =5×5×5×5\\ =625\end{array}$

Q.2

$\begin{array}{l}\text{Express the following in exponential form:}\\ \left(\text{i}\right)\text{ 6 × 6 × 6 × 6 }\left(\text{ii}\right)\text{ t × t }\left(\text{iii}\right)\text{ b × b × b × b}\\ \left(\text{iv}\right)\text{ 5 × 5× 7 × 7 × 7 }\left(\text{v}\right)\text{ 2 × 2 × a × a}\\ \left(\text{vi}\right)\text{ a × a × a × c × c × c × c × d}\end{array}$

Ans

$\begin{array}{l}\left(\mathrm{i}\right)\text{ }6×6×6×6\\ ={6}^{4}\\ \\ \left(\mathrm{ii}\right)\text{ }\mathrm{t}×\mathrm{t}\\ ={\text{t}}^{2}\\ \\ \left(\mathrm{iii}\right)\text{ }\mathrm{b}×\mathrm{b}×\mathrm{b}×\mathrm{b}\\ ={\text{b}}^{4}\\ \\ \left(\mathrm{iv}\right)\text{ }5×5×7×7×7\\ ={5}^{2}×{7}^{3}\\ \\ \left(\mathrm{v}\right)\text{ }2×2×\mathrm{a}×\mathrm{a}\\ ={2}^{2}×{\text{a}}^{2}\\ \\ \left(\mathrm{vi}\right)\text{ }\mathrm{a}×\mathrm{a}×\mathrm{a}×\mathrm{c}×\mathrm{c}×\mathrm{c}×\mathrm{c}×\mathrm{d}\\ ={\mathrm{a}}^{3}×{\mathrm{c}}^{4}×\mathrm{d}\end{array}$

Q.3

$\begin{array}{l}\text{Express each of the following numbers using}\\ \text{exponential notation:}\\ \left(\text{i}\right)\text{ 512 }\left(\text{ii}\right)\text{ 343 }\left(\text{iii}\right)\text{ 729 }\left(\text{iv}\right)\text{ 3125}\end{array}$

Ans

$\begin{array}{l}\left(\mathrm{i}\right)\text{ }512\\ =2×2×2×2×2×2×2×2×2\\ ={2}^{9}\\ \\ \left(\mathrm{ii}\right)\text{ }343\\ =7×7×7\\ ={7}^{3}\\ \\ \left(\mathrm{iii}\right)\text{ }729\\ =3×3×3×3×3×3\\ ={3}^{6}\\ \\ \left(\mathrm{iv}\right)\text{ }3125\\ =5×5×5×5×5\\ ={5}^{5}\end{array}$

Q.4

$\begin{array}{l}\text{Identify the greater number, wherever possible, in}\\ \text{each of the following?}\\ \left(\text{i}\right){\text{4}}^{\text{3}}{\text{or 3}}^{\text{4}}\text{ }\left(\text{ii}\right){\text{5}}^{\text{3}}{\text{or 3}}^{\text{5}}\text{ }\left(\text{iii}\right){\text{2}}^{\text{8}}{\text{or 8}}^{\text{2}}\\ \left(\text{iv}\right){\text{100}}^{\text{2}}{\text{or 2}}^{\text{100}}\text{ }\left(\text{v}\right){\text{2}}^{\text{10}}{\text{or 10}}^{\text{2}}\end{array}$

Ans

$\begin{array}{l}\left(\mathrm{i}\right)\text{ }{4}^{3}\mathrm{or}{3}^{4}\\ {4}^{3}=4×4×4=64\\ {3}^{4}=3×3×3×3=81\\ {\text{Therefore, 3}}^{4}>{4}^{3}\\ \\ \left(\mathrm{ii}\right)\text{ }{5}^{3}\mathrm{or}{3}^{5}\\ {5}^{3}=5×5×5=125\\ {3}^{5}=3×3×3×3×3=243\\ {\text{Therefore, 3}}^{5}>{5}^{3}\\ \\ \left(\mathrm{iii}\right)\text{ }{2}^{8}\mathrm{or}{8}^{2}\\ {2}^{8}=2×2×2×2×2×2×2×2=256\\ {8}^{2}=8×8=64\\ {\text{Therefore, 2}}^{8}>{8}^{2}\end{array}$

$\begin{array}{l}\left(\mathrm{iv}\right)\text{ }{100}^{2}\mathrm{or}{2}^{100}\\ {100}^{2}=100×100=10000\\ \text{Since,}\\ {\text{2}}^{10}=2×2×2×2×2×2×2×2×2×2=1024\\ \text{So},\\ {2}^{100}={\text{2}}^{10}×{\text{2}}^{10}×{\text{2}}^{10}×{\text{2}}^{10}×{\text{2}}^{10}×{\text{2}}^{10}×{\text{2}}^{10}×{\text{2}}^{10}×{\text{2}}^{10}×{\text{2}}^{10}\\ \text{\hspace{0.17em} \hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=1024×1024×1024×1024×1024×1024×1024\\ \text{\hspace{0.17em} \hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}×1024×1024×1024\\ {\text{Therefore, 2}}^{100}>{100}^{2}\\ \\ \left(\mathrm{v}\right)\text{ }{2}^{10}\mathrm{or}{10}^{2}\\ {2}^{10}=2×2×2×2×2×2×2×2×2×2=1024\\ {10}^{2}=10×10=100\\ {\text{Therefore, 2}}^{10}>{10}^{2}\end{array}$

Q.5

$\begin{array}{l}\text{Express each of the following as product of powers of}\\ \text{their prime factors:}\\ \left(\text{i}\right)\text{648 }\left(\text{ii}\right)\text{405 }\left(\text{iii}\right)\text{540 }\left(\text{iv}\right)\text{ 3,600}\end{array}$

Ans

$\begin{array}{l}\left(\text{i}\right)\text{648}=2×2×2×3×3×3×3={2}^{3}×{3}^{4}\\ \\ \left(\text{ii}\right)\text{405}=3×3×3×3×5={3}^{4}\cdot 5\end{array}$

$\begin{array}{l}\left(\text{iii}\right)\text{540}=2×2×3×3×3×5={2}^{2}×{3}^{3}×{5}^{1}\\ \\ \left(\text{iv}\right)\text{3600}=2×2×2×2×3×3×5×5={2}^{4}×{3}^{2}\cdot {5}^{2}\end{array}$

Q.6

$\begin{array}{l}\text{Simplify :}\\ \left(\text{i}\right){\text{2 × 10}}^{\text{3}}\text{ }\left(\text{ii}\right){\text{7}}^{\text{2}}{\text{× 2}}^{\text{2}}\text{ }\left(\text{iii}\right){\text{2}}^{\text{3}}\text{× 5}\\ \left(\text{iv}\right){\text{3 × 4}}^{\text{4}}\text{ }\left(\text{v}\right){\text{0 × 10}}^{\text{2}}\text{ }\left(\text{vi}\right){\text{5}}^{\text{2}}{\text{× 3}}^{\text{3}}\\ \left(\text{vii}\right){\text{2}}^{\text{4}}{\text{× 3}}^{\text{2}}\text{ }\left(\text{viii}\right){\text{3}}^{\text{2}}{\text{×10}}^{\text{4}}\end{array}$

Ans

$\begin{array}{l}\left(\mathrm{i}\right)\text{ }2×{10}^{3}\\ =2×10×10×10=2000\\ \\ \left(\mathrm{ii}\right)\text{ }{7}^{2}×{2}^{2}=7×7×2×2=196\\ \\ \left(\mathrm{iii}\right)\text{ }{2}^{3}×5=2×2×2×5=40\\ \\ \left(\mathrm{iv}\right)\text{ }3×{4}^{4}\\ =3×4×4×4×4=768\\ \\ \left(\mathrm{v}\right)\text{ }0×{10}^{2}\\ =0×10×10=0\\ \\ \left(\mathrm{vi}\right)\text{ }{5}^{2}×{3}^{3}\\ =5×5×3×3×3=675\end{array}$

$\begin{array}{l}\left(\mathrm{vii}\right)\text{ }{2}^{4}×{3}^{2}\\ =2×2×2×2×3×3=144\\ \\ \left(\mathrm{viii}\right)\text{ }{3}^{2}×{10}^{4}\\ =3×3×10×10×10×10=90000\end{array}$

Q.7

$\begin{array}{l}\text{Simplify:}\\ \left(\text{i}\right)\text{ }{\left(\text{–4}\right)}^{\text{3}}\\ \left(\text{ii}\right)\text{ }\left(\text{–3}\right)\text{×}{\left(\text{–2}\right)}^{\text{3}}\\ \left(\text{iii}\right)\text{ }{\left(\text{–3}\right)}^{\text{2}}\text{×}{\left(\text{–5}\right)}^{\text{2}}\\ \left(\text{iv}\right)\text{ }{\left(\text{–2}\right)}^{\text{3}}\text{×}{\left(\text{–10}\right)}^{\text{3}}\end{array}$

Ans

$\begin{array}{l}\left(\text{i}\right)\text{ }{\left(-\text{4}\right)}^{\text{3}}\\ \text{= }\left(-\text{4}\right)\text{×}\left(-\text{4}\right)\text{×}\left(-\text{4}\right)\text{= }-\text{64}\\ \\ \left(\text{ii}\right)\text{ }\left(-\text{3}\right)\text{×}{\left(-\text{2}\right)}^{\text{3}}\\ \text{= }\left(-\text{3}\right)\text{×}\left(-\text{2}\right)\text{×}\left(-\text{2}\right)\text{×}\left(-\text{2}\right)\text{ = 24}\\ \\ \left(\text{iii}\right)\text{ }{\left(-\text{3}\right)}^{\text{2}}\text{×}{\left(-\text{5}\right)}^{\text{2}}\text{ = }\left(-\text{3}\right)\text{×}\left(-\text{3}\right)\text{×}\left(-\text{5}\right)\text{×}\left(-\text{5}\right)\text{ = 225}\\ \\ \left(\text{iv}\right)\text{ }{\left(-\text{2}\right)}^{\text{3}}\text{×}{\left(-\text{10}\right)}^{\text{3}}\\ \text{= }\left(-\text{2}\right)\text{×}\left(-\text{2}\right)\text{×}\left(-\text{2}\right)\text{×}\left(-\text{10}\right)\text{×}\left(-\text{10}\right)\text{×}\left(-\text{10}\right)\text{ = 8000}\end{array}$

Q.8

$\begin{array}{l}\text{Compare the following numbers:}\\ \left(\text{i}\right){\text{ 2.7×10}}^{\text{12}}{\text{; 1.5×10}}^{\text{8}}\\ \left(\text{ii}\right){\text{ 4×10}}^{\text{14}}{\text{; 3×10}}^{\text{17}}\end{array}$

Ans

$\begin{array}{l}\left(\text{i}\right){\text{ 2.7×10}}^{\text{12}}{\text{; 1.5×10}}^{\text{8}}\\ \text{Since, 2.7 has more positive power of 10.}\\ {\text{So, 2.7×10}}^{\text{12}}{\text{>1.5×10}}^{\text{8}}\\ \left(\text{ii}\right){\text{ 4×10}}^{\text{14}}{\text{; 3×10}}^{\text{17}}\\ \text{Since, 3 has more positive power of 10.}\\ {\text{So, 3×10}}^{\text{17}}{\text{>4×10}}^{\text{14}}\end{array}$

## FAQs (Frequently Asked Questions)

### 1. What topics from the Class 7 Maths Chapter 13 Exercise 13.1 are important for the exams?

All the topics in Maths Class 7 Chapter 13 Exercise 13.1 are crucial. Few of the chapters from the textbook have more weightage of marks in comparison to others. The NCERT Solutions For Class 7 Maths Chapter 13 Exercise 13.1 may also assist students  to enhance their normal rating in the Class 7 examination. Some of the essential chapters may also be studied in higher Classes and should be understood clearly. Square and Rectangular Roots, Mensuration, Advent to Graphs, Quadrilaterals etc. are some of the crucial chapters to prepare thoroughly for the examinations.

### 2. Can the NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 help in time of the Examinations?

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### 3. How can a student start preparing with the help of tools like NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1?

Choosing the proper study material is a hard task for the students of the CBSE board. Class 7 students ought to first know the NCERT Syllabus for the correct information after which they can start their preparation in the right manner. All the subjects need to be covered a month back before the examination to make revision easier. The topics which are crucial and are of more weightage for the examination should be given extra preference because it helps students gain more marks in the paper. After doing so students should solve the questions with the help of NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1 for better understanding of the chapter.

### 4. Where can students get the solutions of NCERT Solutions Class 7 Maths Chapter 13 Exercise 13.1?

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