# NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals (EX 2.2) Exercise 2.2

The Central Board of Secondary Education is one of the most prestigious and premier educational boards available for students in India. A vast number of schools affiliated with the CBSE board are present all over India. CBSE deploys a particular learning scheme for students who are a part of the CBSE board. There is inherent objectivity to all the questions that are asked on the CBSE exams. An objective study pattern includes learning techniques that ensure students learn something from the syllabus. Students must go through the chapter thoroughly and understand it inside out. Students can grasp the fundamental ideas of the chapter and have their basic ideas about the chapter clear as well. Such a pattern is followed because the kinds of questions that frequent the exams are deeply entrenched in the rudimentary ideas of the subject. The questions that appear in the exams are both long-answer type and short-answer type questions, and therefore, unless students have their basic ideas clear they would fail to answer and solve these questions accurately. This observation has been frequently made that students can retain details and information from a chapter without understanding it and then they score well in the exams. This is a practice that is not encouraged at all by CBSE. This is the primary reason CBSE has developed a structure that directly develops and hones the analytical and cognitive abilities of the students. This is required because the questions from the exam can be answered using these qualities. CBSE very vividly makes it clear for the students that they prioritise understanding the fundamental ideas rather than retention of facts. This way students might be able to score well and make progress in their academic careers, but in the long run, students might find it very difficult to carry on with their careers. Teachers who are a part of Extramarks are highly qualified and they have relevant experience in teaching students Mathematics. These teachers are very aware of all the different kinds of struggles that students go through with regard to learning and therefore they have collaborated with Extramarks to provide students with Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English provide detailed explanations of every problem for which they have provided their answers. These teachers have shared all the various skills and tips that they have observed and formulated in their years of being teachers. Teachers have reassured students that there is nothing to be inhibited about in this curriculum. Teachers have ensured that students would not be struggling with hindrances to learning anymore. The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English is one of the most trusted tools compiled by qualified mentors and they implore the students to use the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English as well.

CBSE is widely known among students and teachers alike for its vast syllabus. The syllabus that CBSE follows is compiled by the top educators in the country, and curricula are based on all the modern educational trends worldwide. CBSE strives to provide its students with the best education and learning resources possible. When the vast syllabus is complemented with the distinct objective question paper pattern, it provides a curriculum that just values a student’s grasp of the topics. Students often feel overwhelmed by this distinct pattern. The paradigm that CBSE follows is extremely different to that of a traditional classroom. Students have been found struggling with the syllabus and the kind of questions that are asked in the exams. Therefore, they can conveniently access Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English. Teachers have suggested students never omit chapters and if they are struggling with the syllabus then they can use Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English. Mostly all the questions in the exam are based on multiple-choice based questions. The options in the answers are provided in a way to confuse the students. This is done to ensure that students have gotten a firm grasp of the implicit concepts. This is why it is crucial to focus on the importance of the use of Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2, in Hindi and English. If students consistently study from the beginning of the session, then they will not struggle with the syllabus at all. Although just consistency would not ensure a good grade. Students must regularly revisit the chapters that they had solved early on in the process. The more a student revises the better they get at answering the questions from that section. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English is an amazing resource for students. Teachers have already ensured that Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2, in Hindi and English are accurate, reliable, and comprehensive.

The National Council of Educational Research and Training, or NCERT, is a centrally operated organisation. NCERT was founded in 1961. NCERT is an autonomous organisation that can make difficult decisions related to the education of the citizens of the country and its students. NCERT employs people who are very well-versed in the varied terrain of the country. It is not easy to make a univocal decision. The decisions therefore must be well researched and objected towards the betterment of the country as a whole. NCERT assists the Central government as well as the State Governments to legislate on issues related to the development of the educational ambience of the country which directly affects the students as well. NCERT curates the syllabus based on all the important ideas that are being taught to students. This ensures that students are provided with all-encompassing and eclectic resources. NCERT has a publishing branch, and all the NCERT books are published there. The NCERT textbooks are incorporated into the CBSE curriculum and completely syncopate with the rules and regulations outlined in the NCERT. Even Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English follow the NCERT syllabus and the rules and regulations as well. Teachers have requested that students treat their NCERT textbook as their main book of reference because while following the NCERT textbook, students get very familiar with the study pattern and the kinds of questions that appear in the exams. While students are studying and using the NCERT textbook, the use of Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English during this time could make the learning process simpler. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English have been seen to have various uses. The teachers at Extramarks have shared the different ways students can use Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English.

Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English provide solutions to the second chapter of the Class 8 CBSE maths called Fractions and Decimals. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2, in Hindi and English provide detailed and well-explained solutions to every exercise of the chapter in a chronological manner. The question number and the markings of the questions are kept the same to optimise the ease of access to these solutions. All the steps that are involved in the problem-solving process are detailed in the NCERT solutions. The solutions are written in a very meticulous way. This way, students belonging to varied backgrounds can access the NCERT solutions and use them to their benefit. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English provide a step-by-step demonstration of how to proceed with a problem. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English never omit any steps because that will be very counterproductive to the premise of the NCERT solutions. Before its release, Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English are reviewed multiple times to make sure that there are no inconsistencies in the solutions.

Mathematics is generally a subject students struggle with a lot. The primary reason behind this is that acquiring the knowledge of Mathematics takes a lot of practice and consistency. Given the syllabus that students have to complete before their exams, it is understandable, therefore, that it is difficult for students to find time to revise and also be very consistent with their education. Students cannot master the subject in one go and students cannot always find a way to solve mathematical problems daily. Although since the release of Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English the studying pattern has become efficient for various students. Every time students come across a hurdle while solving the chapter, they can use Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English.

Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English have varied uses. Students can use Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English in whichever way they like. One of the primary uses of Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English is when students are studying a topic for the first time. Students must first go through the chapter and the concepts that are being taught in the book. After they have done this, they must go through the solved examples given in the book. When students do this, they get familiar with the syllabus, and the topics in the chapter and it makes solving problems easy and engaging. It is only after students have done this, can they refer to Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English. Students must use the NCERT solutions only after trying to attempt and solve the problem. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English are written in such a way that anyone can get their doubts clear with it. The language and the explanations are very crucial for students. NCERT is not just providing academic materials to students but they are helping students to get various other information which is important for the exams. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English could become a staple for Class 8 students. Teachers could encourage students to use Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English while they are preparing for their exams.

One of the other major uses of Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English is when students are revising. After students have made significant progress with the syllabus then they must come back to the chapters that they have solved long back. When students come back to a chapter then often, they remember parts of the idea and some parts are a bit fuzzy. If a student does not use Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English and revise, then by the time they are done with the syllabus and they want to begin the revision process, these chapters will have become completely new. Therefore, students must come back to the chapters that they have already completed, as soon as they have made significant progress with the syllabus. Teachers could implore students to use Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English after they have gone through the chapter and the solved examples once. When students have done all the necessary things, they must look into the unsolved questions. Students the second time around must wait longer and think more before they refer to Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2, in Hindi and English. It is only after the students have tried solving the problem multiple times that they must look into Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2, in Hindi and English. The solutions in Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English are very detailed, and students should not have any more hurdles with the problem. Whenever students get some time, they must look into the chapters that they had solved a while back. The more a student use Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English while they are revising, the better they get at solving problems from the chapter.

It has been observed that students while using Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English look over the errors that they encounter. CBSE discourages students from falling prey to this narrative. Doubts are very important for a student’s preparation. The doubts that students encounter while solving the NCERT textbook and using Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English give information about the strengths and weaknesses of the students. These doubts give a clear indication to the students on how they must strategise their exam plan. Students can observe all the questions that might be coming in the exams and based on Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English they can figure out for themselves the right way to answer questions in the exams. Students must make sure that the doubts and mistakes that they are having must never be retained after they have used the NCERT solutions. Students must use Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English whenever they can. As can be seen Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English are a crucial tool for students to get good grades.

One of the other primary uses of Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English is when students are preparing for their final exam. The few days before the exam is extremely stressful for students. Teachers have observed and deemed the stress and a lack of belief in themselves to be the reason for it. Therefore, Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English are bound to be one of the best tools to help out students struggling with these issues. When students can solve their doubts and problems with help from nothing but Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English, it helps enhance their confidence and self-esteem. This way students learn to trust their abilities making them more self-reliant. Teachers have observed that oftentimes students do not get the grades that they deserve, often students who have practised well for their exams but get low grades. Teachers have looked into this and they have found that these students lost marks not because they could not answer a question but because they answered wrong. These students have proceeded with the problem correctly but by the time the sum is done, they have made a negligent error. Students are so overwhelmed that they have committed these negligent errors. Therefore, Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English are one of the best resources available for students. It is bound to happen that after students started regularly using Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English they could make significant progress in making no more negligent errors.

Mathematics is a tricky subject and a lot of students often apprehend the subject. The primary reason behind this is that one cannot master the subject overnight. Students need to have a dedicated and consistent attitude towards the subject. Class 7 is a challenging stage. Students are learning about new ideas and they are getting used to studying consistently and rigorously. Students must practise the sums regularly and revise whenever they can. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English could become one of the best resources for students to use during self-study. Generally, while students are solving an exercise or they are studying and they come across a doubt, they keep it aside and move on to the next problem. The sum in which the student had a doubt is later clarified by the teacher. Although, often the solution to the subsequent problems is contingent on the solution of the problem where the first doubt originated. In situations similar to this, if a student possesses Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English, they can solve their doubts in their own time by themselves. This way Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English teach students to hope to manage their time. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2, in Hindi and English provide other information as well to students. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2, in Hindi and English show students the topic weightage each chapter holds. Students as they use the NCERT solutions get acquainted with the question paper pattern and they also learn about the different questions and the marks each entails.

Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English provide the solution for the second chapter of the Class 8 Mathematics CBSE curriculum. Mathematics is the combination of district branches of Mathematics like – Arithmetics, Algebra, Geometry, Statistics, etc. Each section of the syllabus demands a different kind of studying strategy. The second chapter, fractions and decimals, is a chapter of crucial importance. Not only do a huge proportion of questions come from this section but also in later classes. The concepts and ideas taught in this chapter will echo in larger classes across multiple subjects. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2, in Hindi and English, therefore, are curated very carefully. In this chapter, students tend to make various errors in the calculations of Arithmetic. Thus, Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English, provide all the solutions and all the background calculations very clearly to make sure students understand how to proceed with a sum correctly.

Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English are available for download in a PDF format. One can access Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English either through the computer website or their mobile application. With the aid and assistance of Extramarks’ mobile application, these crucial resources can be accessed by any student at any time they would want. Students are always under expert guidance and therefore students must never feel unattended and without assistance. Students are encouragedto use Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English more. Students could click on the link below to access Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2.

**NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals (EX 2.2) Exercise 2.2 **

Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English provide solutions to the second chapter of the Class 8 CBSE curriculum. Various new ideas are being covered in this section and they are as follows –

- Fraction multiplications.
- Fraction multiplication with a whole number.
- Multiplication among more than two fractions.
- Value calculation of a product.

**Access NCERT Solutions for Class 7 Maths Chapter 2 – Fractions and Decimals**

Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English can be accessed through the Extramarks website. They are also available on the mobile application of Extramarks. Since Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English can be even accessed through mobile, these NCERT solutions can be accessed conveniently by students who belong to remote areas where they cannot access premiere coaching. The NCERT solutions are available in PDF format, after students who have successfully accessed Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English and can use these solutions anytime they like. Students in the possession of the NCERT solutions are not without help. Students whenever they are studying are in reach of the best guidance they can get. Since Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English are compiled and reviewed by top educators in the field, students are always under expert guidance. The Exyramarks website also has various other useful and highly efficient resources.

**Chapter 2 – Fractions and Decimals**

Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English provide the solutions for the 2nd chapter of the Class 7 CBSE curriculum. One cannot make significant progress and make advancement in the subject without understanding the concepts of Fractions and decimals. The entire milieu of contemporary Mathematics and the entire branch of Arithmetic is based on this chapter. Therefore, teachers have emphasised the importance of this chapter.

**Introduction**

Students have learned about fractions and decimals separately in earlier classes. In the earlier classes whenever fractions and decimals were taught, they were taught in the form of rudimentary ideas. In the Class 7 curriculum, advanced ideas from each chapter are taught and then both ideas are merged. The exercise which focuses more on the alignment of both concepts is the most challenging one. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English do great justice in making sure students have understood the complicated topics discussed in these chapters. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English, therefore, clarifies the ideas of this chapter with great adroitness. The Class 7 Maths Chapter 2 Exercise 2.2 Solutions make sure that students are prepared for any kind of unprecedented situation.

**How Well You Have Learned About Fractions**

The ideas that are discussed in Chapter 2 of the Class 7 curriculum are Fractions and Decimals. The ideas of this chapter have real-world applications and since it is an arithmetic concept students were just familiar with basic ideas. In this stage and chapter, students are taught about improper fractions and the various properties that it demonstrates. The chapter is replete with various solved and unsolved examples allowing students to completely grasp the chapter. The sums which are to be solved by students are provided in the exercise. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English provide the solutions for these exercises. After students have rigorously used Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English, they could improve their academic performance in this regard.

**Multiplication of Fractions**

Multiplication of fractions is one of the most recurrent properties that is consistently used in every corner of education and real life. Students must have this idea very clear. There are a plethora of questions that regularly frequent the paper. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English help students anticipate the kind of problems that might arise in the examinations.

**Multiplication of a Fraction by a Whole Number**

This section of the chapter is pretty similar to the previous section. This section divulges the rules and properties that a fraction would inherit if it were multiplied by a whole number. The idea of decimals comes up here as well because fractions and decimals are interchangeable most of the time. There are various properties of a fraction and decimals, and students must know which one of them must be used. Therefore, this section prepares students exactly for that. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English additionally give more scope for students to develop their skills even more. The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2, in Hindi and English are so lucidly written that students would face no hindrances while using them.

**Exercise 2.2 Questions and Answers**

Students are recommended to click on the link below to access Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English. Therefore, the Class 7 Maths Chapter 2 Exercise 2.2 Solutions are very crucial for a student’s performance.

**Multiplication of a Fraction by a Fraction**

A fraction can be also multiplied with another fraction. There are exact rules for this and students are suggested to use Extramarks solutions for’ NCERT Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English to get a better understanding of the concepts.

**Value of the Products**

The ideas that are generally valid with whole numbers often do not directly correspond with fractions. It is important for students to know the value of the fractions and which instances are bigger and smaller. While students solve questions from this section, they are advised to always use Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English to make sure they understand the nuances of the topic. These solutions focus on the Class 7 Maths Chapter 2 Exercise 2.2.

**NCERT Solutions for Class 7**

There are solutions available for each subject and all the constituent exercises. Students can access them through Extramarks’ website.

**Q.1 **

$\begin{array}{l}\mathrm{Which}\mathrm{of}\mathrm{the}\mathrm{following}\mathrm{drawing}\left(\mathrm{a}\right)\mathrm{to}\left(\mathrm{d}\right)\mathrm{show}:\\ \left(\mathrm{i}\right)\text{\hspace{0.17em}}2\times \frac{1}{5}\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\left(\mathrm{ii}\right)\text{\hspace{0.17em}}2\times \frac{1}{2}\\ \left(\mathrm{iii}\right)\text{\hspace{0.17em}}3\times \frac{2}{3}\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\left(\mathrm{iv}\right)\text{\hspace{0.17em}}3\times \frac{1}{4}\text{\hspace{0.17em}}\end{array}$

**Ans.**

$\begin{array}{l}\text{(i)\hspace{0.17em}}2\times \frac{1}{5}=\frac{2}{5}\\ \left(\mathrm{ii}\right)\text{\hspace{0.17em}}2\times \frac{1}{2}=1\\ \left(\mathrm{iii}\right)\text{\hspace{0.17em}}3\times \frac{2}{3}=2\\ \left(\mathrm{iv}\right)\text{\hspace{0.17em}}3\times \frac{1}{4}=\frac{3}{4}\\ \text{(a)\hspace{0.17em}Here},\text{there are three pictures and each pictures}\\ \text{show\hspace{0.17em}}\frac{2}{3}\text{\hspace{0.17em}part}=\frac{2}{3}+\frac{2}{3}+\frac{2}{3}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{2+2+2}{3}\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{6}{3}=2\\ \text{Hence},\text{}\left(\text{iii}\right)\text{denotes picture}\left(\text{a}\right).\\ \text{(b)\hspace{0.17em}Here},\text{there are two pictures}.\text{Each pictures show}\frac{1}{2}\\ \text{part.}\\ \text{So},\frac{1}{2}+\frac{1}{2}=\frac{1+1}{2}=\frac{2}{2}=1\\ \text{Hence},\text{}\left(\text{ii}\right)\text{denotes picture}\left(\text{b}\right).\\ \left(\mathrm{c}\right)\text{\hspace{0.17em}Here},\text{there are three pictures}.\text{Each pictures show}\frac{1}{4}\text{\hspace{0.17em}}\mathrm{part}.\\ \text{Therefore},\frac{1}{4}+\frac{1}{4}+\frac{1}{4}=\frac{1+1+1}{4}=\frac{3}{4}\\ \text{Hence},\text{}\left(\text{iv}\right)\text{denotes picture}\left(\text{c}\right).\\ \left(\mathrm{d}\right)\text{\hspace{0.17em}Here},\text{there are two pictures and each pictures denotes}\\ \frac{1}{5}\text{\hspace{0.17em}part.}\\ \text{Therefore},\frac{1}{5}+\frac{1}{5}=\frac{1+1}{5}=\frac{2}{5}\\ \text{Hence},\text{}\left(\text{i}\right)\text{denotes picture}\left(\text{d}\right).\\ \text{Thus}:\\ \overline{)\begin{array}{l}\left(\text{i}\right)\text{denotes picture}\left(\text{d}\right)\\ \left(\text{ii}\right)\text{denotes picture}\left(\text{b}\right)\\ \left(\text{iii}\right)\text{denotes picture}\left(\text{a}\right)\\ \left(\text{iv}\right)\text{denotes picture}\left(\text{c}\right)\end{array}}\end{array}$

**Q.2 **

$\begin{array}{l}\text{Some pictures}\left(\text{a}\right)\text{to}\left(\text{c}\right)\text{are given below.}\\ \text{Tell which of them show}\\ \left(\mathrm{i}\right)\text{\hspace{0.33em}}3\times \frac{1}{5}=\frac{3}{5}\text{\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}}\left(\mathrm{ii}\right)\text{\hspace{0.33em}}2\times \frac{1}{3}=\frac{2}{3}\text{\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}}\left(\mathrm{iii}\right)\text{\hspace{0.33em}}3\times \frac{3}{4}=2\frac{1}{4}\end{array}$

**Ans.**

\begin{array}{l}\text{In picture}\left(\text{a}\right):\\ \text{There are two pictures in left hand side},\text{each denotes}\frac{1}{3}\\ \text{and picture in right hand side denotes}\text{\hspace{0.17em}}\frac{2}{3}.\\ \text{Therefore},\text{it denotes}\frac{1}{3}\times 2=\frac{2}{3}\text{which denotes}\left(\text{ii}\right).\\ \text{In picture}\left(\text{b}\right)\text{:}\\ \text{Here are three pictures in left hand side},\text{each shows}\frac{3}{4}.\\ \text{There are three pictures in right hand side in which each}\\ \text{of first two denotes 1}.\\ \text{Therefore},\frac{3}{4}\times 3=2\frac{1}{4}\\ \text{Thus picture}\left(\text{b}\right)\text{denotes}\left(\text{iii}\right).\\ \text{In picture}\left(\text{c}\right):\\ \text{There are three pictures in left hand side and each}\\ \text{of them denotes}\frac{1}{5}.\\ \text{Hence},\\ \overline{)\begin{array}{l}\left(\text{i}\right)\text{denotes picture}\left(\text{c}\right)\\ \left(\text{ii}\right)\text{denotes picture}\left(\text{a}\right)\\ \left(\text{iii}\right)\text{denotes picture}\left(\text{b}\right)\end{array}}\end{array}

**Q.3 **

$\begin{array}{l}\mathrm{Multiply}\mathrm{and}\mathrm{reduce}\mathrm{to}\mathrm{lowest}\mathrm{form}:\\ \left(\mathrm{i}\right)\text{\hspace{0.17em}}7\times \frac{3}{5}\left(\mathrm{ii}\right)\text{\hspace{0.17em}}4\times \frac{1}{3}\left(\mathrm{iii}\right)\text{\hspace{0.17em}}2\times \frac{6}{7}\\ \left(\mathrm{iv}\right)\text{\hspace{0.17em}}5\times \frac{2}{9}\left(\mathrm{v}\right)\text{\hspace{0.17em}}\frac{2}{3}\times 4\left(\mathrm{vi}\right)\text{\hspace{0.17em}}\frac{5}{2}\times 6\\ \left(\mathrm{vii}\right)\text{\hspace{0.17em}}11\times \frac{4}{7}\left(\mathrm{viii}\right)\text{\hspace{0.17em}}20\times \frac{4}{5}\left(\mathrm{ix}\right)\text{\hspace{0.17em}}13\times \frac{1}{3}\\ \left(\mathrm{x}\right)\text{\hspace{0.17em}}15\times \frac{3}{5}\end{array}$

**Ans.**

$\begin{array}{c}\left(\mathrm{i}\right)\text{\hspace{0.17em}}7\times \frac{3}{5}=\frac{7}{1}\times \frac{3}{5}=\frac{21}{5}\\ =\overline{)4\frac{1}{5}}\\ \left(\mathrm{ii}\right)\text{\hspace{0.17em}}4\times \frac{1}{3}=\frac{4}{1}\times \frac{1}{3}=\frac{4}{3}\\ =\overline{)1\frac{1}{3}}\\ \left(\mathrm{iii}\right)\text{\hspace{0.17em}}2\times \frac{6}{7}=\frac{2}{1}\times \frac{6}{7}=\frac{12}{7}\\ =\overline{)1\frac{5}{7}}\\ \left(\mathrm{iv}\right)\text{\hspace{0.17em}}5\times \frac{2}{9}=\frac{5}{1}\times \frac{2}{9}=\frac{10}{9}\\ =\overline{)1\frac{1}{9}}\\ \left(\mathrm{v}\right)\text{\hspace{0.17em}}\frac{2}{3}\times 4=\frac{2}{3}\times \frac{4}{1}=\frac{8}{3}\\ =\overline{)2\frac{2}{3}}\\ \left(\mathrm{vi}\right)\text{\hspace{0.17em}}\frac{5}{2}\times 6=\frac{5\times 6}{2}=\frac{30}{2}\\ =\overline{)15}\\ \left(\mathrm{vii}\right)\text{\hspace{0.17em}}11\times \frac{4}{7}=\frac{11}{1}\times \frac{4}{7}=\frac{44}{7}\\ =\overline{)6\frac{2}{7}}\\ \left(\mathrm{viii}\right)\text{\hspace{0.17em}}20\times \frac{4}{7}=\frac{20}{1}\times \frac{4}{5}=\frac{80}{5}\\ =\overline{)16}\\ \left(\mathrm{ix}\right)\text{\hspace{0.17em}}13\times \frac{1}{3}=\frac{13}{1}\times \frac{1}{3}=\frac{13}{3}\\ =\overline{)4\frac{1}{3}}\\ \left(\mathrm{x}\right)\text{\hspace{0.17em}}15\times \frac{3}{5}=\frac{15}{1}\times \frac{3}{5}=\frac{45}{5}\\ =\overline{)9}\end{array}$

**Q.4 **

$\begin{array}{l}\mathrm{Shade}:\\ \left(\mathrm{i}\right)\text{\hspace{0.17em}}\frac{1}{2}\text{}\mathrm{of}\mathrm{the}\mathrm{circles}\mathrm{in}\mathrm{box}\left(\mathrm{a}\right)\\ \left(\mathrm{ii}\right)\text{\hspace{0.17em}}\frac{2}{3}\text{\hspace{0.17em}}\mathrm{of}\mathrm{the}\mathrm{triangles}\mathrm{in}\mathrm{box}\left(\mathrm{b}\right)\\ \left(\mathrm{iii}\right)\text{\hspace{0.17em}}\frac{3}{5}\text{\hspace{0.17em}}\mathrm{of}\mathrm{the}\mathrm{squares}\mathrm{in}\mathrm{box}\left(\mathrm{c}\right)\end{array}$

**Ans.**

$\begin{array}{l}\left(\text{i}\right)\\ \text{Here},\text{there are 12 circles in box}\left(\text{a}\right).\\ \text{Therefore},\\ \frac{1}{2}\text{\hspace{0.17em}}\mathrm{of}\text{\hspace{0.17em}}12=\frac{1}{2}\times 12=6\\ \text{Hence 6 circles to be coloured in}\left(\text{a}\right).\\ \left(\mathrm{ii}\right)\\ \text{Here},\text{there are 9 triangles in box}\left(\text{b}\right)\text{and\hspace{0.17em}}\frac{2}{3}\text{\hspace{0.17em}of the}\\ \text{triangles are to be coloured}.\\ \text{So},\text{\hspace{0.17em}}\frac{2}{3}\text{\hspace{0.17em}}\mathrm{of}\text{\hspace{0.17em}}9=\frac{2}{3}\times 9\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{18}{3}=6\\ \text{Thus},\text{6 triangles are needed to be coloured}.\\ \left(\text{iii}\right)\\ \text{Here},\text{there are 15 rectangles in box}\left(\text{c}\right)\text{and}\frac{3}{5}\text{of them}\\ \text{are needed to be coloured}.\\ \text{So},\\ \frac{3}{5}\text{\hspace{0.17em}}\mathrm{of}\text{\hspace{0.17em}}15=\frac{3}{5}\times 15\\ \text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}=\frac{45}{5}=9\\ \text{Thus},\text{9 rectangles are needed to be coloured}.\end{array}$

**Q.5 **

$\begin{array}{l}\mathbf{F}\mathbf{i}\mathbf{n}\mathbf{d}:\\ \left(\mathbf{a}\right)\text{\hspace{0.17em}}\text{\hspace{0.17em}}\frac{1}{2}\text{\hspace{0.17em}}\text{of}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\left(\mathbf{i}\right)\text{}\mathbf{2}\mathbf{4}\left(\mathbf{i}\mathbf{i}\right)\text{}\mathbf{4}\mathbf{6}\\ \left(\mathbf{b}\right)\text{\hspace{0.17em}}\text{\hspace{0.17em}}\frac{2}{3}\text{\hspace{0.17em}}\text{of}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\left(\mathbf{i}\right)\text{}\mathbf{1}\mathbf{8}\left(\mathbf{i}\mathbf{i}\right)\text{}\mathbf{2}\mathbf{7}\\ \left(\mathbf{c}\right)\text{\hspace{0.17em}}\text{\hspace{0.17em}}\frac{3}{4}\text{\hspace{0.17em}}\text{of}\left(\mathbf{i}\right)\text{}\mathbf{1}\mathbf{6}\text{\hspace{0.17em}}\left(\mathbf{i}\mathbf{i}\right)\text{}\mathbf{3}\mathbf{6}\\ \left(\mathbf{d}\right)\text{\hspace{0.17em}}\text{\hspace{0.17em}}\frac{4}{5}\text{\hspace{0.17em}}\text{of}\left(\mathbf{i}\right)\text{}\mathbf{2}\mathbf{0}\text{\hspace{0.17em}}\left(\mathbf{i}\mathbf{i}\right)\text{}\mathbf{3}\mathbf{5}\end{array}$

**Ans.**

\begin{array}{l}(a)\\ (i)\text{\hspace{0.17em}}\frac{1}{2}\text{\hspace{0.17em}}of\text{\hspace{0.17em}}24=\frac{1}{2}\times 24=\frac{24}{2}=\overline{)12}\\ (ii)\text{\hspace{0.17em}}\frac{1}{2}\text{\hspace{0.17em}}of46=\frac{1}{2}\times 46=\frac{46}{2}=\overline{)23}\\ (b)\\ (i)\text{\hspace{0.17em}}\frac{2}{3}\text{\hspace{0.17em}}of\text{\hspace{0.17em}}18=\frac{2}{3}\times 18=\frac{36}{3}=\overline{)12}\\ (ii)\frac{2}{3}\text{\hspace{0.17em}}of\text{\hspace{0.17em}}27=\frac{2}{3}\times 27=\frac{54}{3}=\overline{)18}\text{\hspace{0.17em}}\\ (c)\\ (i)\text{\hspace{0.17em}}\frac{3}{4}\text{\hspace{0.17em}}of\text{\hspace{0.17em}}16=\frac{3}{4}\times 16=\frac{48}{4}=\overline{)12}\\ (ii)\text{\hspace{0.17em}}\frac{3}{4}\text{\hspace{0.17em}}of\text{\hspace{0.17em}}36=\frac{3}{4}\times 36=\frac{108}{4}=\overline{)27}\\ (d)\\ (i)\text{\hspace{0.17em}}\frac{4}{5}\text{\hspace{0.17em}}of\text{\hspace{0.17em}}20=\frac{4}{5}\times 20=\frac{80}{5}=\overline{)16}\end{array}

**Q.6 **

$\begin{array}{l}\mathrm{Multiply}\mathrm{and}\mathrm{express}\mathrm{as}\mathrm{a}\mathrm{mixed}\mathrm{fraction}:\\ \left(a\right)\text{\hspace{0.17em}}3\times 5\frac{1}{5}\left(b\right)\text{}\text{\hspace{0.17em}}5\times 6\frac{3}{4}\left(c\right)\text{\hspace{0.17em}}7\times 2\frac{1}{4}\\ \left(d\right)\text{\hspace{0.17em}}4\times 6\frac{1}{3}\left(e\right)\text{}\text{\hspace{0.17em}}3\frac{1}{4}\times 6\left(f\right)\text{\hspace{0.17em}}3\frac{2}{5}\times 8\end{array}$

**Ans.**

\begin{array}{l}\left(\text{a}\right)\text{\hspace{0.17em}}\text{\hspace{0.17em}}3\times 5\frac{1}{5}=3\times \frac{26}{5}=\frac{78}{5}=\overline{)15\frac{3}{5}}\\ \left(\text{b}\right)\text{\hspace{0.17em}}\text{\hspace{0.17em}}5\times 6\frac{3}{4}=5\times \frac{27}{4}=\frac{135}{4}=\overline{)33\frac{3}{4}}\\ \left(\text{c}\right)\text{\hspace{0.17em}}\text{\hspace{0.17em}}7\times 2\frac{1}{4}=7\times \frac{9}{4}=\frac{63}{4}=\overline{)15\frac{3}{4}}\\ \left(\text{d}\right)\text{\hspace{0.17em}}\text{\hspace{0.17em}}4\times 6\frac{1}{3}=4\times \frac{19}{3}=\frac{76}{3}=\overline{)25\frac{1}{3}}\\ \left(\text{e}\right)\text{\hspace{0.17em}}\text{\hspace{0.17em}}3\frac{1}{4}\times 6=\frac{13}{4}\times 6=\frac{78}{7}=\overline{)19\frac{1}{2}}\\ \left(\text{f}\right)\text{\hspace{0.17em}}\text{\hspace{0.17em}}3\frac{2}{5}\times 8=\frac{17}{5}\times 8=\frac{136}{5}=\overline{)27\frac{1}{5}}\end{array}

**Q.7 **

$\begin{array}{l}Find\\ \left(a\right)\text{\hspace{0.17em}}\frac{1}{2}\text{\hspace{0.17em}}\mathrm{of}\left(\mathrm{i}\right)2\frac{3}{4}\text{\hspace{0.17em}}\left(\mathrm{ii}\right)\text{\hspace{0.17em}}4\frac{2}{9}\\ \left(b\right)\text{\hspace{0.17em}}\frac{5}{8}\text{\hspace{0.17em}}\mathrm{of}\left(\mathrm{i}\right)\text{\hspace{0.17em}}3\frac{5}{6}\text{\hspace{0.17em}}\left(\mathrm{ii}\right)\text{}9\frac{2}{3}\end{array}$

**Ans.**

\begin{array}{l}\left(\text{a}\right)\\ \left(\text{i}\right)\text{\hspace{0.17em}}\frac{1}{2}\text{\hspace{0.17em}}\text{of}\text{\hspace{0.17em}}2\frac{3}{4}=\frac{1}{2}\times \frac{11}{4}=\frac{11}{8}\text{\hspace{0.17em}}=\overline{)1\frac{3}{8}}\\ \left(\text{ii}\right)\text{\hspace{0.17em}}\frac{1}{2}\text{\hspace{0.17em}}\text{of}\text{\hspace{0.17em}}4\frac{2}{9}=\frac{1}{2}\times \frac{38}{9}=\frac{19}{9}=\overline{)2\frac{1}{9}}\\ \left(\text{b}\right)\\ \left(\text{i}\right)\text{\hspace{0.17em}}\frac{5}{8}\text{\hspace{0.17em}}\text{of}\text{\hspace{0.17em}}3\frac{5}{6}=\frac{5}{8}\times \frac{23}{6}=\frac{115}{48}\text{\hspace{0.17em}}=\overline{)2\frac{19}{48}}\\ \left(\text{ii}\right)\text{\hspace{0.17em}}\frac{5}{8}\text{\hspace{0.17em}}\text{of}\text{}\text{\hspace{0.17em}}9\frac{2}{3}=\frac{5}{8}\times \frac{29}{3}=\frac{145}{24}=\overline{)6\frac{1}{24}}\end{array}

**Q.8 **

$\begin{array}{l}\mathrm{Vidya}\mathrm{}\mathrm{and}\mathrm{}\mathrm{Pratab}\mathrm{}\mathrm{went}\mathrm{}\mathrm{for}\mathrm{}\mathrm{a}\mathrm{}\mathrm{picnic}.\mathrm{}\mathrm{Their}\mathrm{}\mathrm{mother}\\ \mathrm{gave}\mathrm{}\mathrm{them}\mathrm{}\mathrm{a}\mathrm{}\mathrm{water}\mathrm{}\mathrm{bag}\mathrm{}\mathrm{that}\mathrm{}\mathrm{contained}\mathrm{}5\mathrm{}\mathrm{liters}\mathrm{}\mathrm{of}\\ \mathrm{water}.\mathrm{}\mathrm{Vidya}\mathrm{}\mathrm{consumed}\frac{2}{5}\mathrm{of}\mathrm{}\mathrm{the}\mathrm{}\mathrm{water}.\mathrm{}\mathrm{Pratap}\\ \mathrm{consumed}\mathrm{}\mathrm{the}\mathrm{}\mathrm{remaining}\mathrm{}\mathrm{water}.\phantom{\rule{0ex}{0ex}}\left(\mathrm{i}\right)\mathrm{}\mathrm{How}\mathrm{}\mathrm{much}\mathrm{water}\mathrm{}\mathrm{did}\mathrm{}\mathrm{Vidya}\mathrm{}\mathrm{drink}?\\ \phantom{\rule{0ex}{0ex}}\left(\mathrm{ii}\right)\mathrm{}\mathrm{What}\mathrm{}\mathrm{fraction}\mathrm{}\mathrm{of}\mathrm{}\mathrm{total}\\ \mathrm{quantity}\mathrm{}\mathrm{of}\mathrm{}\mathrm{water}\mathrm{}\mathrm{did}\mathrm{}\mathrm{Pratab}\mathrm{}\mathrm{drink}?\end{array}$

**Ans.**

\begin{array}{l}\text{Total quantity of water}=\text{5 litres}\\ \text{Vidya consumed}\text{\hspace{0.17em}}\frac{2}{5}\text{\hspace{0.17em}}\text{of water and Pratap consumed rest}\\ \text{of the water}.\\ \text{Water consumed by Vidya}=5\times \frac{2}{5}\text{\hspace{0.17em}}\text{litre}=2\text{\hspace{0.17em}}\text{litre}\\ \text{Therefore water consumed by Pratap}\\ =\text{Total water}\u2013\text{Water consumed by Vidya}.\\ =\text{5}\text{\hspace{0.17em}}\text{litre-2}\text{\hspace{0.17em}}\text{litre=}\overline{)\text{3}\text{\hspace{0.17em}}\text{litre}}\\ \text{Therefore},\text{fraction of water consumed by Pratap}=\frac{3}{5}\\ \text{Therefore},\left(\text{i}\right)\text{Vidya consumed 2 litre of water}\\ \left(\text{ii}\right)\text{Pratap consumed}\frac{3}{5}\text{of water}.\end{array}

##### FAQs (Frequently Asked Questions)

## 1. What are the other Extramarks resources besides Extramarks' NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2?

There is a plethora of resources on Extramarks’ website. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 in Hindi and English belong to the NCERT solution section. Other resources include –

- Live classes and recorded lectures.
- Personalised courses.
- Tests and quizzes.
- Analysis report and performance report.
- Live chat options.

## 2. What are similar resource one can get on Extramarks' website like the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2?

The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.2 belong to the NCERT Solutions which are provided by Extramarks. Other similar resources are available for the following classes and subjects –

NCERT solutions Class 12 are available on Extramarks for a variety of subjects, including

English, Physics, Chemistry, Mathematics, Economics, and others.

NCERT solutions Class 11 are available on Extramarks covering a wide range of subjects, including English, Physics, Chemistry, Mathematics, Economics, and others.

NCERT solutions Class 10 are available from Extramarks covering a multitude of subjects, including Hindi, English, Mathematics, Science, and Social Science.

NCERT solutions Class 9 are available from Extramarks for many subjects including Hindi, English, Mathematics, Science, and Social Science.

NCERT solutions Class 8 are available from Extramarks for diverse academic disciplines, including Hindi, English, Mathematics, Science, Social Science, and Sanskrit.

NCERT solutions Class 7 are available from Extramarks for numerous disciplines, including

Hindi, English, Mathematics, Science, Social Science, and Sanskrit.

NCERT solutions Class 6 are available from Extramarks for many academic disciplines including Hindi, English, Mathematics, Science, Social Science, and Sanskrit.

NCERT solutions Class 5 are available from Extramarks for various subjects, including

Hindi, English, Mathematics, and EVS.

NCERT solutions Class 4 are available from Extramarks for a number of subjects, including

Hindi, English, Mathematics, and EVS.

Click on the link below to access the solutions to Class 7 Maths Exercise 2.2.