# NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals (EX 2.4) Exercise 2.4

Students need to understand the topics of Mathematics thoroughly, as it is a purely conceptual subject. Fractions and Decimals are the topic of Chapter 2 of Class 7 Mathematics. The concepts and calculations of this chapter can be understood properly with practice and proper guidance. Real-life concepts like the conversion of units such as Centimetre to Metre or Kilometre and Gram to Kilogram are explained in this chapter. The chapter includes- Introduction, Multiplication, and Division of Fractions, Multiplication, and Division of Decimal Numbers etc. The chapter contains seven exercises in all and several interesting concepts. Students learn about Equivalent Fractions, Addition, and Multiplication of Fractions, Rearrangement of Fractions in Ascending and Descending Order, Multiplication of a Fraction with a Whole Number and Conversion of an Improper Fraction into a Mixed Fraction. Apart from this, it includes a comparison between fractions, different place values of a decimal number, a comparison between decimal numbers, and many more concepts. With proper practice, students can grasp the concepts of this chapter and learn it with interest. By utilising all the resources provided by Extramarks, they can make their learning experience comprehensive and effortless and excel in their examinations.

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## NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals (EX 2.4) Exercise 2.4

Students can download the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, provided by Extramarks in PDF format. They can easily access and download the solutions, making it easy to review them whenever they want. These solutions are curated by expert educators at Extramarks and are properly detailed in a step-by-step approach. That is why Extramarks recommends that students review these solutions carefully before the examinations. The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, help students understand the concept and logic behind every answer. They are excellent preparation tools for Class 7 Mathematics examinations.

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## Access NCERT Solutions for Class 7 Maths Chapter 2 – Fractions and Decimals

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### Fraction and Decimals Class 7 Exercise 2.4 – In a Nutshell

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### Class 7th Maths Chapter 2 Exercise 2.4 – Other exercises

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### NCERT Solutions for Class 7

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Q.1

$\begin{array}{l}\text{Find:}\\ \text{(i)}\text{\hspace{0.17em}}\text{12÷}\frac{\text{3}}{\text{4}}\text{(ii)}\text{14÷}\frac{\text{5}}{\text{6}}\text{(iii)}\text{\hspace{0.17em}}\text{8÷}\frac{\text{7}}{\text{3}}\\ \text{(iv)}\text{​}\text{\hspace{0.17em}}\text{4÷}\frac{\text{8}}{\text{3}}\text{(v)}\text{\hspace{0.17em}}\text{3÷2}\frac{\text{1}}{\text{3}}\text{(vi)}\text{\hspace{0.17em}}\text{5÷3}\frac{\text{4}}{\text{7}}\end{array}$

Ans.

$\begin{array}{l}\text{(i) 12÷}\frac{\text{3}}{\text{4}}\text{=12×}\frac{\text{4}}{\text{3}}\text{=}\frac{\text{48}}{\text{3}}\text{=}\overline{)\text{16}}\\ \text{(ii) 14÷}\frac{\text{5}}{\text{6}}\text{=14×}\frac{\text{6}}{\text{5}}\text{=}\frac{\text{84}}{\text{5}}\text{=}\overline{)\text{16}\frac{\text{4}}{\text{5}}}\\ \text{(iii) 8÷}\frac{\text{7}}{\text{3}}\text{=8×}\frac{\text{3}}{\text{7}}\text{=}\frac{\text{24}}{\text{7}}\text{=}\overline{)\text{3}\frac{\text{3}}{\text{7}}}\text{ }\\ \text{(iv) 4÷}\frac{\text{8}}{\text{3}}\text{=4×}\frac{\text{3}}{\text{8}}\frac{\text{3}}{}\text{=}\frac{\text{3}}{\text{2}}\text{=}\overline{)\text{1}\frac{\text{1}}{\text{2}}}\\ \text{(v) 3÷2}\frac{\text{1}}{\text{3}}\text{=3÷}\frac{\text{7}}{\text{3}}\text{=3×}\frac{\text{3}}{\text{7}}\text{=}\frac{\text{9}}{\text{7}}\text{=}\overline{)\text{1}\frac{\text{2}}{\text{7}}}\\ \text{(vi) 5÷3}\frac{\text{4}}{\text{7}}\text{=5÷}\frac{\text{25}}{\text{7}}\text{=5×}\frac{\text{7}}{\text{25}}\frac{\text{7}}{}\text{=}\frac{\text{7}}{\text{5}}\text{=}\overline{)\text{1}\frac{\text{2}}{\text{5}}}\end{array}$

Q.2

$\begin{array}{l}\mathrm{Find}\mathrm{the}\mathrm{reciprocal}\mathrm{of}\mathrm{each}\mathrm{of}\mathrm{the}\mathrm{following}\\ \mathrm{fractions}.\mathrm{Classify}\mathrm{the}\mathrm{reciprocals}\mathrm{as}\mathrm{proper}\\ \mathrm{fractions},\mathrm{improper}\mathrm{fractions}\mathrm{and}\mathrm{whole}\mathrm{numbers}.\\ \left(\mathrm{i}\right)\text{\hspace{0.17em}}\frac{3}{7}\text{}\left(\mathrm{ii}\right)\text{\hspace{0.17em}}\frac{5}{8}\text{\hspace{0.17em}}\left(\mathrm{iii}\right)\text{\hspace{0.17em}}\frac{9}{7}\text{\hspace{0.17em}}\left(\mathrm{iv}\right)\text{​\hspace{0.17em}}\frac{6}{5}\\ \left(\mathrm{v}\right)\text{​\hspace{0.17em}}\frac{12}{7}\left(\mathrm{vi}\right)\text{\hspace{0.17em}}\frac{1}{8}\text{\hspace{0.17em}}\left(\mathrm{vii}\right)\text{\hspace{0.17em}}\frac{1}{11}\end{array}$

Ans.

$\begin{array}{l}\left(\mathrm{i}\right)\text{\hspace{0.17em}}\frac{3}{7}\\ \text{Reciprocal of\hspace{0.17em}}\frac{3}{7}\text{\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}\frac{7}{3}\text{\hspace{0.17em}}\text{and it is an improper fraction}.\\ \left(\mathrm{ii}\right)\text{\hspace{0.17em}}\frac{5}{8}\\ \text{Reciprocal of\hspace{0.17em}}\frac{5}{8}\text{\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}\frac{8}{5}\text{\hspace{0.17em}}\text{and it is an improper fraction}\\ \text{(iii)\hspace{0.17em}}\frac{9}{7}\\ \text{Reciprocal of\hspace{0.17em}}\frac{9}{7}\text{\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}\frac{7}{9}\text{\hspace{0.17em}}\text{and it is an proper fraction}\\ \left(\mathrm{iv}\right)\text{​\hspace{0.17em}}\frac{6}{5}\\ \text{Reciprocal of\hspace{0.17em}}\frac{6}{5}\text{\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}\frac{5}{6}\text{\hspace{0.17em}}\text{and it is an proper fraction}\\ \left(\mathrm{v}\right)\text{\hspace{0.17em}}\frac{12}{7}\\ \text{Reciprocal of\hspace{0.17em}}\frac{12}{7}\text{\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}\frac{7}{12}\text{\hspace{0.17em}}\text{and it is an proper fraction}\\ \left(\mathrm{vi}\right)\text{\hspace{0.17em}}\frac{1}{8}\\ \text{Reciprocal of\hspace{0.17em}}\frac{1}{8}\text{\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}\frac{8}{1}\text{\hspace{0.17em}}\text{and it is an whole fraction}\\ \left(\mathrm{vii}\right)\text{\hspace{0.17em}}\frac{1}{11}\\ \text{Reciprocal of\hspace{0.17em}}\frac{1}{11}\text{\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}11\text{\hspace{0.17em}}\text{and it is a\hspace{0.17em}whole number.}\end{array}$

Q.3

$\begin{array}{l}Find:\\ \left(i\right)\text{\hspace{0.17em}}\frac{7}{3}÷2\left(ii\right)\text{\hspace{0.17em}}\frac{4}{9}÷5\left(iii\right)\text{\hspace{0.17em}}\frac{6}{13}÷7\\ \left(iv\right)\text{\hspace{0.17em}}4\frac{1}{3}÷3\left(v\right)\text{\hspace{0.17em}}3\frac{1}{2}÷4\left(vi\right)\text{\hspace{0.17em}}4\frac{3}{7}÷7\end{array}$

Ans.

$\begin{array}{l}\left(i\right)\text{\hspace{0.17em}}\frac{7}{3}÷2=\frac{7}{3}×\frac{1}{2}=\frac{7}{6}=\overline{)1\frac{1}{6}}\\ \left(ii\right)\text{\hspace{0.17em}}\frac{4}{9}÷5=\frac{4}{9}×\frac{1}{5}=\overline{)\frac{4}{45}}\\ \left(iii\right)\text{\hspace{0.17em}}\frac{6}{13}÷7=\frac{6}{13}×\frac{1}{7}=\overline{)\frac{6}{91}}\\ \left(iv\right)\text{\hspace{0.17em}}4\frac{1}{3}÷3=\frac{13}{3}×\frac{1}{3}=\frac{13}{9}=\overline{)1\frac{4}{9}}\\ \left(v\right)\text{\hspace{0.17em}}3\frac{1}{2}÷4=\frac{7}{2}×\frac{1}{4}=\overline{)\frac{7}{8}}\\ \left(vi\right)\text{\hspace{0.17em}}4\frac{3}{7}÷7=\frac{31}{7}×\frac{1}{7}=\overline{)\frac{31}{49}}\end{array}$

Q.4

$\begin{array}{l}\text{Find}\\ \left(i\right)\text{\hspace{0.17em}}\frac{2}{5}÷\frac{1}{2}\text{}\\ \left(ii\right)\text{​}\text{\hspace{0.17em}}\frac{4}{9}÷\frac{2}{3}\text{}\\ \left(iii\right)\text{\hspace{0.17em}}\frac{3}{7}÷\frac{8}{7}\\ \left(iv\right)\text{\hspace{0.17em}}2\frac{1}{3}÷\frac{3}{5}\\ \left(v\right)\text{\hspace{0.17em}}3\frac{1}{2}÷\frac{8}{3}\\ \left(vi\right)\text{\hspace{0.17em}}\frac{2}{5}÷1\frac{1}{2}\\ \left(vii\right)\text{\hspace{0.17em}}3\frac{1}{5}÷1\frac{2}{3}\\ \left(viii\right)\text{\hspace{0.17em}}2\frac{1}{5}÷1\frac{1}{5}\end{array}$

Ans.

$\begin{array}{l}\left(i\right)\text{\hspace{0.17em}}\frac{2}{5}÷\frac{1}{2}=\frac{2}{5}×\frac{2}{1}=\overline{)\frac{4}{5}}\\ \left(ii\right)\text{\hspace{0.17em}}\frac{4}{9}÷\frac{2}{3}=\frac{4}{9}×\frac{3}{2}=\frac{\left(2×\overline{)2}\right)}{\left(3×\overline{)3}\right)}×\frac{\overline{)3}}{\overline{)2}}=\overline{)\frac{2}{3}}\\ \left(iii\right)\text{\hspace{0.17em}}\frac{3}{7}÷\frac{8}{7}=\frac{3}{\overline{)7}}×\frac{\overline{)7}}{8}=\overline{)\frac{3}{8}}\\ \left(iv\right)\text{\hspace{0.17em}}2\frac{1}{3}÷\frac{3}{5}=\frac{7}{3}×\frac{5}{3}=\frac{35}{9}=\overline{)3\frac{8}{9}}\\ \left(v\right)\text{\hspace{0.17em}}3\frac{1}{2}÷\frac{8}{3}=\frac{7}{2}×\frac{3}{8}=\frac{21}{16}=\overline{)1\frac{5}{16}}\\ \left(vi\right)\text{\hspace{0.17em}}\frac{2}{5}÷1\frac{1}{2}=\frac{2}{5}÷\frac{3}{2}=\frac{2}{5}×\frac{2}{3}=\overline{)\frac{4}{15}}\\ \left(vii\right)\text{\hspace{0.17em}}3\frac{1}{5}÷1\frac{2}{3}=\frac{16}{5}÷\frac{5}{3}=\frac{16}{5}×\frac{3}{5}=\frac{48}{25}=\overline{)1\frac{23}{25}}\\ \left(viii\right)\text{\hspace{0.17em}}2\frac{1}{5}÷1\frac{1}{5}=\frac{11}{5}÷\frac{6}{5}=\frac{11}{\overline{)5}}×\frac{\overline{)5}}{6}=\frac{11}{6}=\overline{)1\frac{5}{6}}\end{array}$

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