# NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals (EX 2.4) Exercise 2.4

Students need to understand the topics of Mathematics thoroughly, as it is a purely conceptual subject. Fractions and Decimals are the topic of Chapter 2 of Class 7 Mathematics. The concepts and calculations of this chapter can be understood properly with practice and proper guidance. Real-life concepts like the conversion of units such as Centimetre to Metre or Kilometre and Gram to Kilogram are explained in this chapter. The chapter includes- Introduction, Multiplication, and Division of Fractions, Multiplication, and Division of Decimal Numbers etc. The chapter contains seven exercises in all and several interesting concepts. Students learn about Equivalent Fractions, Addition, and Multiplication of Fractions, Rearrangement of Fractions in Ascending and Descending Order, Multiplication of a Fraction with a Whole Number and Conversion of an Improper Fraction into a Mixed Fraction. Apart from this, it includes a comparison between fractions, different place values of a decimal number, a comparison between decimal numbers, and many more concepts. With proper practice, students can grasp the concepts of this chapter and learn it with interest. By utilising all the resources provided by Extramarks, they can make their learning experience comprehensive and effortless and excel in their examinations.

There are no solutions provided for the exercises in NCERT Textbooks. Students can understand the questions given in the NCERT Textbook with the help of clear solutions and approach to each question provided by the Extramarks’ Class 7 Maths Chapter 2 Exercise 2.4 Solutions. NCERT textbook forms the basis for the concepts of any Mathematics chapter. The Class 7 Maths Exercise 2.4 should be practised thoroughly by the learners.

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**NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals (EX 2.4) Exercise 2.4**

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**Access NCERT Solutions for Class 7 Maths Chapter 2 – Fractions and Decimals**

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**Fraction and Decimals Class 7 Exercise 2.4 – In a Nutshell**

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**Class 7th Maths Chapter 2 Exercise 2.4 – Other exercises**

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**NCERT Solutions for Class 7**

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**Q.1 **

$\begin{array}{l}\text{Find:}\\ \text{(i)}\text{\hspace{0.17em}}\text{12\xf7}\frac{\text{3}}{\text{4}}\text{(ii)}\text{14\xf7}\frac{\text{5}}{\text{6}}\text{(iii)}\text{\hspace{0.17em}}\text{8\xf7}\frac{\text{7}}{\text{3}}\\ \text{(iv)}\text{}\text{\hspace{0.17em}}\text{4\xf7}\frac{\text{8}}{\text{3}}\text{(v)}\text{\hspace{0.17em}}\text{3\xf72}\frac{\text{1}}{\text{3}}\text{(vi)}\text{\hspace{0.17em}}\text{5\xf73}\frac{\text{4}}{\text{7}}\end{array}$

**Ans.**

$\begin{array}{l}\text{(i)\hspace{0.33em}12\xf7}\frac{\text{3}}{\text{4}}\text{=12\xd7}\frac{\text{4}}{\text{3}}\text{=}\frac{\text{48}}{\text{3}}\text{=}\overline{)\text{16}}\\ \text{(ii)\hspace{0.33em}14\xf7}\frac{\text{5}}{\text{6}}\text{=14\xd7}\frac{\text{6}}{\text{5}}\text{=}\frac{\text{84}}{\text{5}}\text{=}\overline{)\text{16}\frac{\text{4}}{\text{5}}}\\ \text{(iii)\hspace{0.33em}8\xf7}\frac{\text{7}}{\text{3}}\text{=8\xd7}\frac{\text{3}}{\text{7}}\text{=}\frac{\text{24}}{\text{7}}\text{=}\overline{)\text{3}\frac{\text{3}}{\text{7}}}\text{\hspace{0.33em}}\\ \text{(iv)\hspace{0.33em}4\xf7}\frac{\text{8}}{\text{3}}\text{=4\xd7}\frac{\text{3}}{\text{8}}\frac{\text{3}}{}\text{=}\frac{\text{3}}{\text{2}}\text{=}\overline{)\text{1}\frac{\text{1}}{\text{2}}}\\ \text{(v)\hspace{0.33em}3\xf72}\frac{\text{1}}{\text{3}}\text{=3\xf7}\frac{\text{7}}{\text{3}}\text{=3\xd7}\frac{\text{3}}{\text{7}}\text{=}\frac{\text{9}}{\text{7}}\text{=}\overline{)\text{1}\frac{\text{2}}{\text{7}}}\\ \text{(vi)\hspace{0.33em}5\xf73}\frac{\text{4}}{\text{7}}\text{=5\xf7}\frac{\text{25}}{\text{7}}\text{=5\xd7}\frac{\text{7}}{\text{25}}\frac{\text{7}}{}\text{=}\frac{\text{7}}{\text{5}}\text{=}\overline{)\text{1}\frac{\text{2}}{\text{5}}}\end{array}$

**Q.2 **

$\begin{array}{l}\mathrm{Find}\mathrm{the}\mathrm{reciprocal}\mathrm{of}\mathrm{each}\mathrm{of}\mathrm{the}\mathrm{following}\\ \mathrm{fractions}.\mathrm{Classify}\mathrm{the}\mathrm{reciprocals}\mathrm{as}\mathrm{proper}\\ \mathrm{fractions},\mathrm{improper}\mathrm{fractions}\mathrm{and}\mathrm{whole}\mathrm{numbers}.\\ \left(\mathrm{i}\right)\text{\hspace{0.17em}}\frac{3}{7}\text{}\left(\mathrm{ii}\right)\text{\hspace{0.17em}}\frac{5}{8}\text{\hspace{0.17em}}\left(\mathrm{iii}\right)\text{\hspace{0.17em}}\frac{9}{7}\text{\hspace{0.17em}}\left(\mathrm{iv}\right)\text{\hspace{0.17em}}\frac{6}{5}\\ \left(\mathrm{v}\right)\text{\hspace{0.17em}}\frac{12}{7}\left(\mathrm{vi}\right)\text{\hspace{0.17em}}\frac{1}{8}\text{\hspace{0.17em}}\left(\mathrm{vii}\right)\text{\hspace{0.17em}}\frac{1}{11}\end{array}$

**Ans.**

$\begin{array}{l}\left(\mathrm{i}\right)\text{\hspace{0.17em}}\frac{3}{7}\\ \text{Reciprocal of\hspace{0.17em}}\frac{3}{7}\text{\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}\frac{7}{3}\text{\hspace{0.17em}}\text{and it is an improper fraction}.\\ \left(\mathrm{ii}\right)\text{\hspace{0.17em}}\frac{5}{8}\\ \text{Reciprocal of\hspace{0.17em}}\frac{5}{8}\text{\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}\frac{8}{5}\text{\hspace{0.17em}}\text{and it is an improper fraction}\\ \text{(iii)\hspace{0.17em}}\frac{9}{7}\\ \text{Reciprocal of\hspace{0.17em}}\frac{9}{7}\text{\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}\frac{7}{9}\text{\hspace{0.17em}}\text{and it is an proper fraction}\\ \left(\mathrm{iv}\right)\text{\hspace{0.17em}}\frac{6}{5}\\ \text{Reciprocal of\hspace{0.17em}}\frac{6}{5}\text{\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}\frac{5}{6}\text{\hspace{0.17em}}\text{and it is an proper fraction}\\ \left(\mathrm{v}\right)\text{\hspace{0.17em}}\frac{12}{7}\\ \text{Reciprocal of\hspace{0.17em}}\frac{12}{7}\text{\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}\frac{7}{12}\text{\hspace{0.17em}}\text{and it is an proper fraction}\\ \left(\mathrm{vi}\right)\text{\hspace{0.17em}}\frac{1}{8}\\ \text{Reciprocal of\hspace{0.17em}}\frac{1}{8}\text{\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}\frac{8}{1}\text{\hspace{0.17em}}\text{and it is an whole fraction}\\ \left(\mathrm{vii}\right)\text{\hspace{0.17em}}\frac{1}{11}\\ \text{Reciprocal of\hspace{0.17em}}\frac{1}{11}\text{\hspace{0.17em}}\mathrm{is}\text{\hspace{0.17em}}11\text{\hspace{0.17em}}\text{and it is a\hspace{0.17em}whole number.}\end{array}$

**Q.3 **

$\begin{array}{l}Find:\\ \left(i\right)\text{\hspace{0.17em}}\frac{7}{3}\xf72\left(ii\right)\text{\hspace{0.17em}}\frac{4}{9}\xf75\left(iii\right)\text{\hspace{0.17em}}\frac{6}{13}\xf77\\ \left(iv\right)\text{\hspace{0.17em}}4\frac{1}{3}\xf73\left(v\right)\text{\hspace{0.17em}}3\frac{1}{2}\xf74\left(vi\right)\text{\hspace{0.17em}}4\frac{3}{7}\xf77\end{array}$

**Ans.**

\begin{array}{l}(i)\text{\hspace{0.17em}}\frac{7}{3}\xf72=\frac{7}{3}\times \frac{1}{2}=\frac{7}{6}=\overline{)1\frac{1}{6}}\\ (ii)\text{\hspace{0.17em}}\frac{4}{9}\xf75=\frac{4}{9}\times \frac{1}{5}=\overline{)\frac{4}{45}}\\ (iii)\text{\hspace{0.17em}}\frac{6}{13}\xf77=\frac{6}{13}\times \frac{1}{7}=\overline{)\frac{6}{91}}\\ (iv)\text{\hspace{0.17em}}4\frac{1}{3}\xf73=\frac{13}{3}\times \frac{1}{3}=\frac{13}{9}=\overline{)1\frac{4}{9}}\\ (v)\text{\hspace{0.17em}}3\frac{1}{2}\xf74=\frac{7}{2}\times \frac{1}{4}=\overline{)\frac{7}{8}}\\ (vi)\text{\hspace{0.17em}}4\frac{3}{7}\xf77=\frac{31}{7}\times \frac{1}{7}=\overline{)\frac{31}{49}}\end{array}

**Q.4 **

\begin{array}{l}\text{Find}\\ (i)\text{\hspace{0.17em}}\frac{2}{5}\xf7\frac{1}{2}\text{}\\ (ii)\text{}\text{\hspace{0.17em}}\frac{4}{9}\xf7\frac{2}{3}\text{}\\ (iii)\text{\hspace{0.17em}}\frac{3}{7}\xf7\frac{8}{7}\\ (iv)\text{\hspace{0.17em}}2\frac{1}{3}\xf7\frac{3}{5}\\ (v)\text{\hspace{0.17em}}3\frac{1}{2}\xf7\frac{8}{3}\\ (vi)\text{\hspace{0.17em}}\frac{2}{5}\xf71\frac{1}{2}\\ (vii)\text{\hspace{0.17em}}3\frac{1}{5}\xf71\frac{2}{3}\\ (viii)\text{\hspace{0.17em}}2\frac{1}{5}\xf71\frac{1}{5}\end{array}

**Ans.**

\begin{array}{l}(i)\text{\hspace{0.17em}}\frac{2}{5}\xf7\frac{1}{2}=\frac{2}{5}\times \frac{2}{1}=\overline{)\frac{4}{5}}\\ (ii)\text{\hspace{0.17em}}\frac{4}{9}\xf7\frac{2}{3}=\frac{4}{9}\times \frac{3}{2}=\frac{\left(2\times \overline{)2}\right)}{\left(3\times \overline{)3}\right)}\times \frac{\overline{)3}}{\overline{)2}}=\overline{)\frac{2}{3}}\\ (iii)\text{\hspace{0.17em}}\frac{3}{7}\xf7\frac{8}{7}=\frac{3}{\overline{)7}}\times \frac{\overline{)7}}{8}=\overline{)\frac{3}{8}}\\ (iv)\text{\hspace{0.17em}}2\frac{1}{3}\xf7\frac{3}{5}=\frac{7}{3}\times \frac{5}{3}=\frac{35}{9}=\overline{)3\frac{8}{9}}\\ (v)\text{\hspace{0.17em}}3\frac{1}{2}\xf7\frac{8}{3}=\frac{7}{2}\times \frac{3}{8}=\frac{21}{16}=\overline{)1\frac{5}{16}}\\ (vi)\text{\hspace{0.17em}}\frac{2}{5}\xf71\frac{1}{2}=\frac{2}{5}\xf7\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}=\overline{)\frac{4}{15}}\\ (vii)\text{\hspace{0.17em}}3\frac{1}{5}\xf71\frac{2}{3}=\frac{16}{5}\xf7\frac{5}{3}=\frac{16}{5}\times \frac{3}{5}=\frac{48}{25}=\overline{)1\frac{23}{25}}\\ (viii)\text{\hspace{0.17em}}2\frac{1}{5}\xf71\frac{1}{5}=\frac{11}{5}\xf7\frac{6}{5}=\frac{11}{\overline{)5}}\times \frac{\overline{)5}}{6}=\frac{11}{6}=\overline{)1\frac{5}{6}}\end{array}

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