# NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals (EX 2.5) Exercise 2.5

The best option for students to study basic concepts about diverse topics and for their exams in Class 7 is to take a glance at the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5. Class 7 students will learn about Scientific theories, English stories, and Mathematical formulas to get the best grades possible. On the other hand, examinations are an important part of the educational process, and they can play a significant role in helping students achieve success in their academic careers. This is the time when they start preparing for high school and CBSE Board exams. The marks that students get in these years will determine their future. Exams can be an effective way for students to learn new things and skills. They can provide a way for students to assess their knowledge and understanding, and identify any gaps in their understanding. Examinations can also help students to focus their learning and to revise and consolidate their knowledge into something they desire to pursue in the future.

There are many benefits of examinations for students. In addition to measuring what students have learned, examinations can also motivate them to gain and gather more. That is why Extramarks supplies the facilities of the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5, that can be accessed by students to prepare for their Mathematics examination. Further, exams can help students identify their areas of strength and weakness so that they can focus on their studies. Finally, exams can also prepare students for the challenges of the real world. For students in Class 7, examinations are an important way to assess their understanding of the material that has been taught in class. They can also help students identify any areas that they need to focus on further and prepare for the challenges that they are going to face.

## NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals (EX 2.5) Exercise 2.5

There are several reasons why NCERT Solutions can be useful for students. They can aid them in comprehending the ideas presented in their textbooks, which is the first and most evident benefit. Explanatory instructions on how to solve problems are included in the solutions, which are written straightforwardly and briefly. Students who are having trouble understanding the subject may find this to be of great value. NCERT Solutions such as the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5, can also be beneficial because they can assist students in exam preparation.

Students can get ready for exams and quizzes by using the solutions, which also include practice questions and assessments. Students can analyse the subject that they have studied using the solutions, which is another wonderful benefit of NCERT Solutions. Lastly, NCERT Solutions can be advantageous for students, which enables them to raise their scholastic level. Further, practice problems and quizzes can help students raise their test-taking efficiency, and the solutions are made to help students in understanding the ideas presented in their textbooks. The solutions, similar to NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5, can be effortlessly downloaded from the website or application of Extramarks. These NCERT solutions deliver students an abundance of information that can be of great use to them.

## Access NCERT Solutions for Class 7 Maths Chapter 2 – Fractions and Decimals

Students may access the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5, on the Extramarks website. Students can utilise the solutions to comprehend the material covered in the Chapter to the fullest extent with the aid of the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5 provided by Extramarks. Step-by-step responses to all questions are given in the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5. Similarly, the NCERT solutions for Exercise 2.5 of Chapter 2 in Class 7 nourish students with a significant number of example questions, practice tests, and past year’s papers that help them prepare for their exams on a fundamental level. Students can get the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5, that Extramarks proposes on its website if they are having problems locating the answers to the intent questions or if they are unable to solve them.

Extramarks NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5, are easily obtainable, and students may download them in PDF format for further use. The solutions are quite detailed and give in-depth explanations for each problem. The Extramarks website includes the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5, as a crucial tool that students may use when finishing their test preparation. Students may better learn how to tackle the Mathematics Syllabus by indulging in it and finishing the solutions included in the Class 7 Maths Chapter 2 Exercise 2.5 Solutions. These solutions, along with other key solutions for other courses, are available to students who can access the solutions for Class 7 Maths Exercise 2.5 on the Extramarks website or mobile app.

### NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.5

The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5, are likely to be very helpful for students to improve their Mathematics knowledge and problem-solving capabilities. Students will be better able to comprehend the topics included in the NCERT textbook with the help of the Extramarks mobile application and NCERT Solutions, such as, the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5 supplied by this resource. Through Extramarks, students may readily get the NCERT Solutions, enabling them to effectively study for their exams. When it comes to learning any topic, NCERT Solutions, such as those NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5, may without a doubt be of wonderful support. The NCERT Solutions also include chapter-wise explanations of each chapter of the Mathematics textbook, making it simple for students to understand and fully grasp the concepts.

Several special criteria may be used to tailor Mathematics courses to the needs of students. They must use the NCERT Solutions, which contain the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5, to properly study and be prepared for their examinations. Students who want to thrive academically must avail themselves of the NCERT Solutions for other classes as well as for Class 7, Mathematics Chapter 2, since they sustain them in getting top test grades. As a result, students are given precise and concise information on the subjects covered in the NCERT textbooks. Students may make use of the sample problems and solutions in the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5 as an extra resource for test preparation.

Class 7 Maths Chapter 2 Exercise 2.5 has various questions that can be solved by NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5. Students are going to solve questions related to the topics given below and the questions in the Exercise are also mentioned in the list:

2) Questions in the Exercise are:

1. Which Decimal number is greater than the other?
2. Expressing – as rupees using Decimals, metres and kilometres, centimetres and millimetres, kilograms, and grams.
3. Expansion of Decimal numbers
4. The distance travelled and who travelled the most

Students should apply the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5, when they are preparing for examinations.

### NCERT Solutions for Class 7

NCERT Solutions are advantageous to students for a number of reasons. First, they provide a detailed guide to solving each problem. This makes it easier for students to follow along and understand the concepts. Second, the solutions are explained in detail, which helps students learn from the mistakes that they have made while solving a Mathematical query. Lastly, the solutions are aligned with the latest CBSE syllabus, so students can be sure that they are studying the correct material. There is no doubt that NCERT Solutions can help improve students’ grades. Additionally, the solutions are also accompanied by instructions, which can help students understand the concepts better. There are many benefits to using NCERT Solutions for test preparation. Preferably, these solutions can help students understand the concepts covered in the textbook. Besides that, using these solutions can help students practice problem-solving skills and improve their test scores. Finally, NCERT Solutions can help students identify any weaknesses they may have in specific subject areas.

NCERT Solutions can assist students to study smartly. One way that NCERT Solutions can help students more intelligently in their academic pursuits is by providing them with a clear understanding of the concepts that they are learning. When students have a good understanding of the material, they can focus on the details and understand the concepts more easily. NCERT Solutions can also aid students in studying smarter by providing them with practice questions and exercises. These questions and exercises help students apply the concepts they are studying and see how they can be used differently in real-world situations. Eventually, NCERT Solutions can help students study effectively by providing them with feedback. When students receive feedback on their work, they can identify their strengths and weaknesses, and hence, they can focus on areas that need improvement. Moreover, the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5 should be studied by students to be able to enhance their analytical thinking abilities.

Q.1

$\begin{array}{l}Find:\\ \left(i\right)0.2×6\\ \left(ii\right)8×4.6\\ \left(iii\right)2.71×5\\ \left(iv\right)20.1×4\\ \left(v\right)0.05×7\\ \left(vi\right)211.02×4\\ \left(vii\right)2×0.86\end{array}$

Ans.

$\begin{array}{l}\left(\text{i}\right)\text{}0.\text{2}×\text{6 =}\overline{)1.2}\\ \left(\text{ii}\right)\text{8}×\text{4}.\text{6}\text{\hspace{0.17em}}=\overline{)36.8}\\ \left(\text{iii}\right)\text{2}.\text{71}×\text{5}=\overline{)13.55}\\ \left(\text{iv}\right)\text{2}0.\text{1}×\text{4}\text{\hspace{0.17em}}\text{=}\overline{)\text{80}\text{.4}}\\ \left(\text{v}\right)\text{}0.0\text{5}×\text{7}\text{\hspace{0.17em}}\text{=}\overline{)\text{0}\text{.35}}\\ \left(\text{vi}\right)\text{211}.0\text{2}×\text{4}\text{\hspace{0.17em}}=\overline{)844.08}\\ \left(\text{vii}\right)\text{2}×\text{}0.\text{86}\text{\hspace{0.17em}}\text{=}\overline{)\text{1}\text{.72}}\end{array}$

Q.2

$\begin{array}{l}\mathrm{Find}\mathrm{the}\mathrm{are}\mathrm{a}\mathrm{of}\mathrm{rectangle}\mathrm{whose}\mathrm{length}\mathrm{is}5.7\mathrm{cm}\\ \mathrm{and}\mathrm{breadth}\mathrm{is}3\mathrm{cm}.\end{array}$

Ans.

$\begin{array}{l}\text{The area of a rectangle is given by length}×\text{breadth.}\\ \text{So, the area of given rectangle would be 5.7 cm}×3\text{\hspace{0.17em}cm}\\ \text{=}\overline{){\text{17.1 cm}}^{2}}\end{array}$

Q.3

$\begin{array}{l}Find:\\ \left(i\right)1.3×10\text{}\left(ii\right)36.8×10\text{}\left(iii\right)153.7×10\\ \left(iv\right)168.07×10\text{}\left(v\right)31.1×100\text{}\left(vi\right)156.1×100\\ \left(vii\right)3.62×100\left(viii\right)43.07×100\text{}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\left(ix\right)0.5×10\\ \left(x\right)0.08×10\text{\hspace{0.17em}}\left(xi\right)0.9×100\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\left(xii\right)0.03×1000\end{array}$

Ans.

$\begin{array}{l}\left(\text{i}\right)\text{1}.\text{3}×\text{1}0=\overline{)13}\\ \left(\text{ii}\right)\text{36}.\text{8}×\text{1}0=\overline{)368}\\ \left(\text{iii}\right)\text{153}.\text{7}×\text{1}0=\overline{)1537}\\ \left(\text{iv}\right)\text{168}.0\text{7}×\text{1}0=\overline{)1680.7}\\ \left(\text{v}\right)\text{31}.\text{1}×\text{1}00=\overline{)3110}\\ \left(\text{vi}\right)\text{156}.\text{1}×\text{1}00=\overline{)15610}\\ \left(\text{vii}\right)\text{3}.\text{62}×\text{1}00=\overline{)362}\\ \left(\text{viii}\right)\text{43}.0\text{7}×\text{1}00=\overline{)4307}\\ \left(\text{ix}\right)\text{}0.\text{5}×\text{1}0=\overline{)5}\\ \left(\text{x}\right)\text{}0.0\text{8}×\text{1}0=\overline{)0.8}\\ \left(\text{xi}\right)\text{}0.\text{9}×\text{1}00=\overline{)90}\\ \left(\text{xii}\right)\text{}0.0\text{3}×\text{1}000=\overline{)30}\end{array}$

Q.4

$\begin{array}{l}\mathrm{A}\mathrm{two}–\mathrm{wheeler}\mathrm{covers}\mathrm{a}\mathrm{distance}\mathrm{of}55.3\mathrm{km}\mathrm{in}\mathrm{one}\\ \mathrm{litre}\mathrm{of}\mathrm{petrol}.\mathrm{How}\mathrm{much}\mathrm{distance}\mathrm{will}\mathrm{it}\mathrm{cover}\mathrm{in}10\mathrm{litres}\\ \mathrm{of}\mathrm{petrol}?\end{array}$

Ans.

$\begin{array}{l}\text{Distance covered by a two-wheeler in 1 litres}\\ \text{= 55.3 km}\\ \text{So, distance covered by a two-wheeler in 10 litres}\\ \text{=55.3 km}×\text{10}\\ \text{=}\overline{)\text{553 km}}\end{array}$

Q.5

$\begin{array}{l}Find:\\ \left(i\right)2.5×0.3\text{}\text{}\left(ii\right)0.1×51.7\text{}\left(iii\right)0.2×316.8\\ \left(iv\right)1.3×3.1\text{}\text{}\left(v\right)0.5×0.05\text{}\left(vi\right)11.2×0.15\\ \left(vii\right)1.07×0.02\left(viii\right)10.05×1.05\text{}\left(ix\right)101.01×0.01\\ \left(x\right)100.01×1.1\end{array}$

Ans.

$\begin{array}{l}\left(\text{i}\right)\text{2}.\text{5}×\text{}0.\text{3 =}\overline{)\text{0}\text{.75}}\\ \left(\text{ii}\right)\text{}0.\text{1}×\text{51}.\text{7}=\overline{)5.17}\\ \left(\text{iii}\right)\text{}0.\text{2}×\text{316}.\text{8}=\overline{)63.36}\\ \left(\text{iv}\right)\text{1}.\text{3}×\text{3}.\text{1=}\overline{)\text{4}\text{.03}}\\ \left(\text{v}\right)\text{}0.\text{5}×\text{}0.0\text{5}=\overline{)0.025}\\ \left(\text{vi}\right)\text{11}.\text{2}×\text{}0.\text{15=}\overline{)\text{1}\text{.68}}\\ \left(\text{vii}\right)\text{1}.0\text{7}×\text{}0.0\text{2=}\overline{)\text{0}\text{.0214}}\\ \left(\text{viii}\right)\text{1}0.0\text{5}×\text{1}.0\text{5=}\overline{)\text{10}\text{.5525}}\\ \left(\text{ix}\right)\text{1}0\text{1}.0\text{1}×\text{}0.0\text{1=}\overline{)\text{1}\text{.0101}}\\ \left(\text{x}\right)\text{1}00.0\text{1}×\text{1}.\text{1=}\overline{)\text{110}\text{.011}}\end{array}$

## Please register to view this section

### 1. Are there any miscalculations or typo errors in the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5? Can students ensure that they are well-prepared for their examinations after studying these solutions?

If students want to ace their Mathematics examinations and get higher scores, it is necessary to consistently review the chapters, solve sample questions, and go through mock tests that are specified in the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5. Class 7 Mathematics NCERT Solutions is a study resource that students may use to decode the questions covered in the Exercise with ease. Students should evaluate the solutions for Class 7 Chapter 2 Exercise 2.5 so that they can get rapid answers for questions where they are lacking in relevant concepts and subjects. Extramarks’ NCERT Solutions make exam preparation clear for those who are seeking help online.

### 2. What are the key themes and ideas covered in Chapter 2 on Fractions and Decimals?

Chapter 2 of the textbook “Fractions and Decimals” for Class 7 focuses on the fundamental idea of Fractions and Decimals, and the different use of Fractions and Decimals in the form of Multiplication, Division, and by Whole numbers. Before each exam, students could examine the past years’ papers to have a better understanding of the topics like Reciprocal of the Fraction and others. Students can also look at the unsolved sums in Exercise 2.5 and Chapter 2 of the NCERT Solutions for Class 7 Mathematics. Students can refer to NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5 for more details on the kind of questions that are posed in exams as well as how they are asked. The NCERT Solutions for Classes, for instance, Class 10 and Class 12 are also extremely crucial, for students who wish to study for their CBSE board examinations since it also includes questions and practice papers that are of high quality.

### 3. Where can students get the latest Class 7 Mathematics course materials or syllabus?

Students can obtain the most updated syllabus for the Class 7 Mathematics course by logging onto the Extramarks website and viewing the curriculum. The option for students to get the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5 via Extramarks online platform and mobile applications may be advantageous. The curriculum helps to give students a wealth of information on the Mathematics topic as well as the other chapters and their related themes. On the other hand, students may use the NCERT Solutions for Mathematics subject in Class 7 for Chapter 2, as suggested by Extramarks, to study more about certain Mathematics-related topics. Extramarks advised NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5, which is part of the NCERT Solutions series, covers the CBSE Mathematics curriculum and example test questions. These resources can assist students in organising their study time effectively and ensuring they are completely prepared for their examinations.

### 4. When is the most appropriate time to acquire the PDF files for NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.5 to study for the exams?

By visiting the Extramarks website and installing their smartphone app from the Google Play Store or Apple App Store, students may get the NCERT Solutions for Class 7 in the subject Mathematics for Chapter 2. The time when the Class 7 exams will be approaching would be the most acceptable and appropriate time for students to get the solutions for NCERT Class 7 Maths Chapter 2 Exercise 2.5. Students may analyse these solutions from the Extramarks site to have a better idea of how the Mathematical questions that are stated in the NCERT textbook of Chapter 2, Fractions and Decimals, are smoothly answered.