# NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations (EX 4.4) Exercise 4.4

Class 7 is considered one of the most important stages in a student’s academic career. This is the class that motivates students to learn new things with relevant information and knowledge. The CBSE Class 7 Mathematics textbooks are published by NCERT, which constantly updates them and revises the syllabus. This is done according to the current educational scenario. These books are compiled by experts after extensive research to provide relevant and reliable information. The thematic material is balanced with useful content specially designed for students. They are intended to convey the basic concepts and foundations of all topics.

Learning key concepts is essential to getting better grades in exams. Better understanding helps faster learning. Also, Mathematicsis a conceptually rich subject, and practise is essential to succeeding in this subject.. Without the NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4, students may find it difficult to answer all the questions. To address this issue, Extramarks provides NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 to help students systematically cover all topics. The format and language used in NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 set these apart from other online solutions. PDF versions of NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 are available on Extramarks. Students are strongly encouraged to download these solutions after studying them.

Chapter 4 of Class 7 Mathematics is called Simple Equations. It is important to understand the meaning of equation. An equation is a mathematical statement about variables which have two values on both sides and equal values on either side of the equal sign. This simple equation expresses the relationship between two expressions on either side of the sign and has one variable. The expressions of the two sides are called LHS (left side) and RHS (right side). Variables take on different numbers, while constants have a fixed value. In NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4, students will learn the meaning of equations. All equations consist of an equal sign. This indicates that the value of the expression on the sign to the left of the equal sign is equal to the value on the right side of the equationIn Exercise 4.2, students will learn how to compute or solve equations. Both sides of the equation must be equal. Whether LHS and RHS are interchanged, the same number is added to both sides, the same number is subtracted from both sides, the same number is multiplied by the RHS on both sides, and the LHS is divided by the same number, so the equation does not change. In Exercise 4.3, students learn how to shift numbers left and right instead of adding and subtracting numbers from both sides of an equation. In NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 students will learn how to use simple equations in practical problems.

For detailed information of the topics students can visit NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4

**NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations (EX 4.4) Exercise 4.4 **

The NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 are provided by Extramarks. In this chapter, students will learn how to derive the values of algebraic variables from simple linear equations. This lesson introduces some formula patterns that are an important part of the Mathematics curriculum. Students should practise this exercise thoroughly with the aid of NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4, if they want to strengthen their conceptual foundation in algebraic equations. Given the relevance of the NCERT textbooks to the CBSE curricula, students are sure to find many problems that match those provided in the NCERT textbooks. Each NCERT solution and NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 are provided to make learning at Extramarks easy and interesting. Subjects such as Science, Mathematics, and English are easier to learn with access to NCERT Class 7 Science solutions. Students can also download the NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 and Class 7 Mathematics NCERT solutions to understand the entire syllabus and score more points in the exams.

**Access NCERT Solutions for Class 7 Mathematics Chapter 4 – Simple Equations**

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There is evidence that basic addition and subtraction are innate skills in children. Mathematical concepts are often based on previous skills that can be observed in two different ways. In the first case, the initial skill often reappears later as a subroutine component to achieve a more complex skill. The fact that Arithmetic underpins Algebra is hardly new. Second, there is what is called a “learning transfer,” in which understanding one principle makes it easier to learn another. Learning transfer has been repeatedly demonstrated in early childhood education research. To quote an example, understanding the numbers on the number line makes it easier to learn simple addition. Acquiring mathematical skills early sets the stage for the proper synthesis of this knowledge as processes and theories expand into more complex domains. Helping students acquire these skills early on can improve their grasp of Mathematics.

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Extramarks’ experienced mentors and subject matter experts have engineered NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4. These NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 resolve doubts by allowing students to fully understand difficult problems and the subject as a whole. The NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 help improve students’ academic performance. The language used in the explanation is easy to understand, so every student can understand the solutions. There are solutions related to each chapter and topic, no topic is considered less important. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 provide solutions to every chapter and resolve the confusion caused by problems in understanding concepts. The solutions in NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 are highly recommended for self-study for students. If students still have persistent queries, they could access the doubt-solving classes of Extramarks.

**What do you learn from Class 7 Maths exercise 4.4?**

A simple algebraic equation teaches students a lesson about using a set of variables and constants and the relationships between them to derive the values of the variables. In Algebra, students use the alphabet to represent variables. Letters such as x, y, z, a, and b are actively used to represent variables in the classroom. Linear equations themselves may not seem like a very difficult lesson at first, but this exercise introduces students to a number of different problems. There are many patterns to the problem, and students need to learn the most effective technique for deriving the value of ‘x’.

The NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 encapsulate methods to solve the problems included in exercises organised in various patterns. All four exercises in the chapter have different types of questions. Each question comes with a method for reasoning. Answering exam questions in time requires a lot of practice. For example, students may be asked to create an equation based on unknown variables and certain constant values. The paper also allows for the inclusion of anecdotal questions that require both setting up equations and deriving values for variables. At first, it is best to try completing the exercises alone. If students get unfavourable results on their first attempt, students can always rely on the NCERT solutions to try to solve the problem.

**Class 7 exercise 4.4 solution PDF**

Extramarks NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 PDF contain all the answers to the problem-based simple equations lesson. The NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 consist of all answers to the exercises provided in the NCERT textbook. With all the correct answers given in NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 next to the question, students may find it easier to compare patterns and choose the one that works best for them. Students have access to comprehensive reference materials with the help of Extramarks’ NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 are compiled by a panel of experts who have many years of experience teaching students of the CBSE Board. For better understanding, students can download NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 as these provide the simplest form of the procedure to solve questions. The steps in NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 are precise and succinct, so students can safely mark the steps until they guess the answer. Mathematics scores are not determined by how many formulas students remember, but by how many patterns they can find within modified formulas.

**Benefits of NCERT Solutions for Class 7 Maths Chapter 4.4 PDF**

Given the NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4, students will have to retain crucial formulas and patterns. Students must utilise the assistance of NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 which are organised in a well-defined sequence. Algebra continues to play a major role in advanced Mathematics, Engineering, Architecture, Physics, Chemistry, and many other college-level subjects.

As a result, if students want to learn one of the most important lessons in the Class 7 curriculum with confidence, they should get the NCERT Solutions for Class 7 Maths Chapter 4 Exercise 4.4 from Extramarks.The NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 have many advantages..

The academic content encapsulated in NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 is updated according to the guidelines established by the NCERT and CBSE.

Precise and clear steps defined in NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 by tutors of Extramarks for each problem will help students achieve a perfect score on every question they face, whether it is an exam or practising questions from past years’ papers.

**Class 7 Chapter 4 exercise 4.4 Solutions PDF**

Students who want to improve their Class 7 Mathematics performance should make an extra effort to practise the NCERT exercises multiple times. The NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 should be given emphasis. This is because these solutions serve as a building block for students to understand Algebra. Using the NCERT solution from Extramarks, NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 students can deal with any of the problems in this section. Students can visit the Extramarks website and download the NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4. The PDF format of NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 like all other NCERT learning materials, can be downloaded for all classes from the website. A PDF categorised into Class 7 subjects will be displayed. After downloading the file, students can open it on their computer, laptop, smartphone, tablet, or whatever is convenient for them. This makes digital solutions for Mathematics tasks even more accessible if students want to study on the go. All the solutions displayed next to relevant questions have been accurately resolved by the Extramarks mentorswho are familiar with the updated CBSE syllabus. The NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4, with simplified steps for each solution; are the best study materials available for students of Class 7.

**Q.1 **

$\begin{array}{l}\mathrm{Set}\mathrm{up}\mathrm{equations}\mathrm{and}\mathrm{solve}\mathrm{them}\mathrm{to}\mathrm{find}\mathrm{the}\mathrm{unknown}\\ \mathrm{numbers}\mathrm{in}\mathrm{the}\mathrm{following}\mathrm{case}:\\ \left(\mathrm{a}\right)\mathrm{Add}4\mathrm{to}\mathrm{eight}\mathrm{times}\mathrm{a}\mathrm{number};\mathrm{you}\mathrm{get}60.\\ \left(\mathrm{b}\right)\mathrm{One}\mathrm{fifth}\mathrm{of}\mathrm{a}\mathrm{number}\mathrm{minus}4\mathrm{gives}3.\\ \left(\mathrm{c}\right)\mathrm{If}\mathrm{I}\mathrm{take}\mathrm{three}\mathrm{fourths}\mathrm{of}\mathrm{a}\mathrm{number}\mathrm{and}\mathrm{count}\mathrm{up}3\mathrm{more},\\ \mathrm{I}\mathrm{get}21.\\ \left(\mathrm{d}\right)\mathrm{When}\mathrm{I}\mathrm{subtracted}11\mathrm{from}\mathrm{twice}\mathrm{a}\mathrm{number},\mathrm{the}\mathrm{result}\\ \mathrm{was}15.\\ \left(\mathrm{e}\right)\mathrm{Munna}\mathrm{subtracts}\mathrm{thrice}\mathrm{the}\mathrm{number}\mathrm{of}\mathrm{notebooks}\mathrm{he}\mathrm{has}\\ \mathrm{from}50,\mathrm{he}\mathrm{finds}\mathrm{the}\mathrm{result}\mathrm{to}\mathrm{be}8.\\ \left(\mathrm{f}\right)\mathrm{Ibenhal}\mathrm{thinks}\mathrm{of}\mathrm{a}\mathrm{number}.\mathrm{If}\mathrm{she}\mathrm{adds}19\mathrm{to}\mathrm{it}\mathrm{and}\\ \mathrm{divides}\mathrm{the}\mathrm{sum}\mathrm{by}5,\mathrm{she}\mathrm{will}\mathrm{get}8.\\ \left(\mathrm{g}\right)\mathrm{Anwar}\mathrm{thinks}\mathrm{of}\mathrm{a}\mathrm{number}.\mathrm{If}\mathrm{he}\mathrm{takes}\mathrm{away}7\mathrm{from}\\ 52\mathrm{of}\mathrm{the}\mathrm{number},\mathrm{the}\mathrm{result}\mathrm{is}\frac{\mathrm{11}}{\mathrm{2}}\mathrm{.}\end{array}$

**Ans.**

\begin{array}{l}\text{(a) Let the number be x}\text{.}\\ \text{8 times of this number = 8x}\\ \text{So, we get}\\ 8x+4=6\text{0}\\ 8x=\text{56}\\ \text{x=}\frac{56}{8}\\ Thus,\overline{)x=7}\\ \text{(b) Let the number be}x.\\ \text{One-fifth of this number=}\frac{x}{5}\\ \text{So, we get}\\ \frac{x}{5}-4=3\\ \frac{x}{5}=7\\ \overline{)x=35}\\ \text{(c) Let the number be}x.\\ \text{Three-fourth of this number}=\frac{3x}{4}\\ \text{So,}\text{\hspace{0.17em}}\text{we}\text{\hspace{0.17em}}\text{get}\\ \frac{3x}{4}+3=21\\ \frac{3x}{4}=18\\ 3x=72\\ x=\frac{72}{3}\\ Thus,\text{\hspace{0.17em}}\overline{)x=24}\\ (d)\text{\hspace{0.17em}}\text{Let the number be}x.\\ \text{So, we have}\\ \text{2x-11=15}\\ \text{2x=26}\\ \text{x=}\frac{26}{13}=13\\ Thus,\overline{)x=13}\\ (e)\text{\hspace{0.17em}}\text{Let the number be}x\\ \text{Thrice the number of books}=\text{3}x\\ \text{So, we get}\\ \text{50}-3x=\text{8}\\ -3x=8-50=-42\\ \text{Divide both sides by -3 to get}\\ \text{x=}\frac{-42}{-3}=14\\ Thus,\overline{)x=14}\\ (f)\text{\hspace{0.17em}}\text{Let the number be}x.\\ \text{We, have}\\ \frac{x+19}{5}=8\\ x+19=8\times 5=40\\ x=40-19=21\\ \text{Thus,}\text{\hspace{0.17em}}\overline{)x=21}\\ (g)\text{\hspace{0.17em}}\text{Let the number be}x.\\ \overline{)So,\text{\hspace{0.17em}}we\text{\hspace{0.17em}}have}\\ \frac{5x}{2}-7=23\\ \frac{5x}{2}=23+7=30\\ 5x=30\times 2=60\\ x=\frac{60}{5}=12\\ \text{Thus},\text{\hspace{0.17em}}\overline{)x=12}\end{array}

**Q.2 **

$\begin{array}{l}\mathrm{Solve}\mathrm{the}\mathrm{following}:\\ \left(\mathrm{a}\right)\mathrm{The}\mathrm{teacher}\mathrm{tells}\mathrm{the}\mathrm{class}\mathrm{that}\mathrm{the}\mathrm{highest}\mathrm{marks}\\ \mathrm{obtained}\mathrm{by}\mathrm{a}\mathrm{student}\mathrm{in}\mathrm{her}\mathrm{class}\mathrm{is}\mathrm{twice}\mathrm{the}\mathrm{lowest}\\ \mathrm{marks}\mathrm{plus}7.\mathrm{The}\mathrm{highest}\mathrm{score}\mathrm{is}87.\mathrm{What}\mathrm{is}\mathrm{the}\\ \mathrm{lowest}\mathrm{score}?\\ \left(\mathrm{b}\right)\mathrm{In}\mathrm{an}\mathrm{isosceles}\mathrm{triangle},\mathrm{the}\mathrm{base}\mathrm{angles}\mathrm{are}\mathrm{equal}.\\ \mathrm{The}\mathrm{vertex}\mathrm{angle}\mathrm{is}40\xb0.\mathrm{What}\mathrm{are}\mathrm{the}\mathrm{base}\mathrm{angles}\mathrm{of}\mathrm{the}\\ \mathrm{triangle}?\; (\mathrm{Remember},\mathrm{the}\mathrm{sum}\mathrm{of}\mathrm{three}\mathrm{angles}\mathrm{of}\mathrm{a}\mathrm{triangle}\\ \mathrm{is}180\xb0)\end{array}$

**Ans.**

\begin{array}{l}\text{(a) Let the lowest score be}l\text{.}\\ \text{So, we get}\\ \text{2}\times \text{\hspace{0.17em}}\text{Lowest mark}+7=\text{Highest marks}\\ 2l+7=87\\ 2l=87\u20137=80\\ l=\frac{80}{2}=40\\ \text{Thus,}\text{\hspace{0.17em}}\text{the lowest score is 40}\text{.}\\ \text{(b) Let the base angle be}b\text{.}\\ \text{Since the sum of angle of a triangle is 180}\xb0\\ \text{So, we get}\\ b+b+40\xb0=180\xb0\\ 2b+40\xb0=180\xb0\\ 2b=180\xb0-40\xb0=140\xb0\\ 2b=140\xb0\\ b=\frac{140\xb0}{2}=70\xb0\\ \text{Thus, the base angle is 70}\xb0\\ \text{(c) Let the Rahul\u2019s score be x}\\ \text{Then, sachin score is 2x}\text{.}\\ \text{So,we}\text{\hspace{0.17em}}\text{have}\\ \text{Rahul}score+Sachin\text{}score=200-2\\ x+2x=198\\ 3x=198\\ x=\frac{198}{3}=66\\ \text{Therefore,}\\ \text{Rahul score is}\overline{)\text{66}}\text{and Sachin score is 2}\times \text{66=}\overline{)\text{132}}.\end{array}

**Q.3 **

$\begin{array}{l}\mathrm{Solve}\mathrm{the}\mathrm{following}:\\ \left(\mathrm{i}\right)\mathrm{Irfan}\mathrm{says}\mathrm{that}\mathrm{he}\mathrm{has}7\mathrm{marbles}\mathrm{more}\mathrm{than}\mathrm{five}\mathrm{times}\\ \mathrm{the}\mathrm{marbles}\mathrm{Parmithas}.\mathrm{Irfan}\mathrm{has}37\mathrm{marbles}.\mathrm{How}\mathrm{many}\\ \mathrm{marbles}\mathrm{does}\mathrm{Parmit}\mathrm{have}?\\ \left(\mathrm{ii}\right)\mathrm{Laxmi}\u2018\mathrm{s}\mathrm{father}\mathrm{is}49\mathrm{year}\mathrm{sold}.\mathrm{He}\mathrm{is}4\mathrm{years}\mathrm{older}\mathrm{than}\\ \mathrm{three}\mathrm{times}\mathrm{Laxmi}\u2018\mathrm{s}\mathrm{age}.\mathrm{What}\mathrm{is}\mathrm{Laxmi}\u2018\mathrm{sage}?\\ \left(\mathrm{iii}\right)\mathrm{Maya},\mathrm{Madhura}\mathrm{and}\mathrm{Mohsina}\mathrm{are}\mathrm{friends}\mathrm{studying}\mathrm{in}\mathrm{the}\\ \mathrm{same}\mathrm{class}.\mathrm{In}\mathrm{a}\mathrm{class}\mathrm{testin}\mathrm{geography},\mathrm{Maya}\mathrm{got}16\\ \mathrm{out}\mathrm{of}25.\mathrm{Madhura}\mathrm{got}20.\mathrm{Their}\mathrm{average}\mathrm{score}\mathrm{was}19.\\ \mathrm{How}\mathrm{much}\mathrm{did}\mathrm{Mohsina}\mathrm{score}?\end{array}$

$\begin{array}{l}\left(\mathrm{iv}\right)\mathrm{People}\mathrm{of}\mathrm{Sundargram}\mathrm{planted}\mathrm{a}\mathrm{total}\mathrm{of}102\mathrm{trees}\mathrm{in}\mathrm{the}\\ \mathrm{village}\mathrm{garden}.\mathrm{Some}\mathrm{of}\mathrm{the}\mathrm{trees}\mathrm{were}\mathrm{fruit}\mathrm{trees}.\mathrm{The}\\ \mathrm{number}\mathrm{of}\mathrm{non}-\mathrm{fruit}\mathrm{trees}\mathrm{were}\mathrm{two}\mathrm{more}\mathrm{than}\mathrm{three}\mathrm{times}\\ \mathrm{the}\mathrm{number}\mathrm{of}\mathrm{fruit}\mathrm{trees}.\mathrm{What}\mathrm{was}\mathrm{the}\mathrm{number}\mathrm{of}\mathrm{fruit}\\ \mathrm{trees}\mathrm{planted}?\end{array}$

**Ans.**

\begin{array}{l}\text{(i) Let Parmit has}m\text{marbles}\text{.}\\ \text{Then, according to the question, we have}\\ \text{5}\times \text{Number of marbles Parmit has +7}=\text{Number of marbles}\\ \text{}\text{}\text{}\text{}\text{}\text{}\text{}\text{}\text{}\text{Irfan has}\\ \text{}\text{}\text{}\text{}\text{}\text{}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{5}\times m+\text{7}=\text{37}\\ \text{So, we get}\\ \text{}\text{}\text{}\text{}\text{}\text{}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{5}m+\text{7}=\text{37}\\ 5m=37-7=30\\ 5m=30\\ m=\frac{30}{5}=6\\ \text{Therefore,}\text{\xe2\u20ac\u2039}\text{Parmit}\text{\hspace{0.17em}}\text{has}\text{\hspace{0.17em}}\overline{)\text{6}\text{\hspace{0.17em}}\text{marbles}}\text{.}\\ \text{(ii) Let Laxmi be}y\text{years old}\\ \text{Then, according to the question, we have}\\ \text{3}\times \text{Laxmi\u2019s age}+\text{4}=\text{Laxmi\u2019s father age}\\ \text{3}\times y+4=\text{49}\\ \text{3}y+\text{4}=\text{49}\\ 3y=49-4=45\\ 3y=45\\ y=\frac{45}{3}=15\\ \text{Therefore,}\text{\hspace{0.17em}}\text{laxmi\u2019s}\text{\hspace{0.17em}}\text{age}\text{\hspace{0.17em}}\text{is}\text{\hspace{0.17em}}\overline{)\text{15}\text{\hspace{0.17em}}\text{years}}\text{.}\\ \text{(iii) Let the number of fruit trees be}x.\\ \text{So, we have}\\ \text{3}\times \text{Number of fruit trees}+2=\text{Number of non-fruit trees}\\ 3x+2=77\\ 3x=77\u20132=75\\ 3x=75\\ x=\frac{75}{3}=25\\ \text{Therefore,}\text{\hspace{0.17em}}\text{the}\text{\hspace{0.17em}}\text{number}\text{\hspace{0.17em}}\text{of}\text{\hspace{0.17em}}\text{fruit}\text{\hspace{0.17em}}\text{trees}\text{\hspace{0.17em}}\text{was}\text{\hspace{0.17em}}\overline{)25}.\end{array}

**Q.4 **

$\begin{array}{l}\mathrm{Solve}\mathrm{the}\mathrm{following}\mathrm{riddle}.\\ \mathrm{I}\mathrm{am}\mathrm{a}\mathrm{number},\\ \mathrm{Tell}\mathrm{my}\mathrm{identity}!\\ \mathrm{Take}\mathrm{me}\mathrm{seven}\mathrm{times}\mathrm{over}\\ \mathrm{And}\mathrm{add}\mathrm{a}\mathrm{fifty}!\\ \mathrm{To}\mathrm{reach}\mathrm{a}\mathrm{triple}\mathrm{century}\\ \mathrm{You}\mathrm{still}\mathrm{need}\mathrm{forty}\end{array}$

**Ans.**

$\begin{array}{l}\mathrm{Let}\mathrm{the}\mathrm{number}\mathrm{be}\mathrm{x}\mathrm{.}\\ \mathrm{Then}\mathrm{we}\mathrm{have}\\ (7\mathrm{x}+50)+40=300\\ 7\mathrm{x}+50+40=300\\ 7\mathrm{x}+90+300\\ 7\mathrm{x}=300-90\\ 7\mathrm{x}=210\\ \mathrm{x}=\frac{210}{7}=30.\\ \mathrm{Therefore},\mathrm{the}\mathrm{number}\mathrm{is}\overline{)\mathrm{30}}\mathrm{.}\end{array}$

##### FAQs (Frequently Asked Questions)

## 1. Where can students find the NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 and why are the Class 7 Maths Chapter 4 Exercise 4.4 Solutions important for Class 7?

On the Extramarks website and Extramarks Learning App, students can find NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 The questions are answered on NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 by experts to help students understand and learn properly from each step. The theory is also explained briefly to simplify understanding. In order to understand the formulas effectively, students need to read through the theory and solve NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 before delving into the formulas and their applications.

## 2. What problems do students face and how do the NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 help?

Students find it difficult to recognise correct methods and the application of methods in Mathematics. Self-studying Mathematics can be very time-consuming. Students should have a deeper understanding of concepts and formulas. Extramarks’ NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 address these concerns. A step-by-step solution is provided for each problem to help students better understand and achieve the highest marks. Extramarks provides NCERT Solutions For Class 7 Maths Chapter 4 Exercise 4.4 in PDF format for NCERT Class 7 Mathematics which are available on the Extramarks website. The solutions are thematically arranged in the correct order.

## 3. How do students download an offline PDF of the Class 7 Maths Exercise 4.4? Are NCERT solutions to Class 7 Maths Chapter 4 Exercise 4.4 helpful?

Students can download an offline PDF of the NCERT solution for all exercises in Chapter 4 of Class 7 Mathematics of Extramarks. Solutions provide exact answers and include all the steps for each question. They are of great help to students in comprehensive preparation for exams. These solutions provide students with carefully worded responses in the manner expected by the board. NCERT solutions to the exercises are most useful to students as they provide all solutions prepared by subject matter experts. Students can get the PDF from the Extramarks website for offline use. It can be used for reference or for reflection. These solutions make learning accessible and engaging with all available learning materials.

## 4. How many exercises are included in Chapter 3 to which NCERT Class 7 Maths Chapter 4 Exercise 4.4 pertain?

It has a total of 4 Exercises. Students can get absolute knowledge of the chapters and learn how to write equations in NCERT solutions. These NCERT solutions also provide students with detailed answers to each question in each exercise of the chapter.