NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Exercise 6.3

A highly structured curriculum is a hallmark of the Indian educational system. The NCERT books are one of the system’s most significant components. All around the nation, students study these textbooks, which are regarded as the pillars of quality education. The National Council of Educational Research and Training in India is the organisation that publishes learning resources, which are provided in the form of textbooks. In all parts of the nation, they are employed in educational institutions. The books are published in Hindi and English and cover a variety of topics, including Science, History, and Geography in addition to Mathematics and English. The most reliable sources of information on Indian history and culture are considered to be the NCERT textbooks. In India, the education system is thought to have its roots in these books. The CBSE Board highly advises using them as the primary text of reference for students in Class 1 through Class 12. The NCERT textbooks are advised by state boards around the country in addition to the CBSE. Extramarks provides NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 for Class 7 students to apprehend the concepts and procedures of Triangles and their Properties.

The NCERT series of books is intended to make it easier for students to study and comprehend difficult subjects. The content in the books is simple and concise, making them easy to read and comprehend. Additionally, the material adheres to the latest CBSE syllabus and board rules, which have attractive and engaging visuals. Studying and practising are made more engaging by visuals, which also aid in conceptual understanding for students. Scoring high marks are extremely important, and NCERT books are a necessity for students. They give them a solid scholastic foundation and aid in getting them ready for further education.

Class 7 Mathematics is an important subject that all students must study. It covers a range of topics that students need to know to be able to succeed in high school and beyond. In Class 7 Mathematics, students learn about Integers, Fractions and Decimal numbers, Data Handling, Lines and Angles, Triangles and their Properties, Practical Geometry, and several supplementary Chapters. Students also learn about the basic properties of Triangles and how to solve equations and inequalities involving them. Further, students study Comparing Quantities and Rational numbers, and how to find the Perimeter and Area of different shapes and units. Students in Class 7 Mathematics get to gather knowledge about how to solve problems involving Algebraic Expressions. They can take help from the NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 in order to understand and solve the questions given in the Exercises.

Students must comprehend the equation, to be able to plot points on a coordinate plane, and then be able to draw a line across the points in order to succeed. The order of operations must be understood and used by students.This entails memorising the sequence of operations symbols, comprehending the meaning of each sign, and being able to use the symbols to solve mathematical problems. Although difficult, Mathematics is an essential subject in class 7. Students who are engaged in their studies will be able to achieve success in high school and beyond.

CBSE Class 7 NCERT Solutions Maths Chapter 6 Exercise 6.3

CBSE is one of the most renowned education boards in India. It is known for its quality education and demanding examination process. The CBSE Board also known as the Central Board of Secondary Education was established in 1962 and has since then played a major role in the education system of the country. In response to the need for a national-level board to standardise education across the country, the CBSE Board was established. The CBSE Board introduced new curriculum and programmes and began to expand its reach to more students. Today, CBSE is one of the most popular and respected educational boards in India. The board has played a major role in the development of academics in the country and has helped millions of students achieve their pedagogic goals. It has now achieved national prominence as one of the country’s most popular education boards. Its accurate test method and high-quality educational programs have made CBSE one of the leading education boards in India.

It is possible that students will find it difficult to grasp the concepts presented in the NCERT textbooks, Extramarks’ provided NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 may be of valuable use to them. The NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 also give students strong support for preparing for regular exams. As an additional tool to the books, the NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 are quite helpful. These Extramarks recommended NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 must be downloaded in PDF Format by students to have a better understanding of what type of questions can be expected in the exam.

You will learn about Triangles NCERT Maths Solution Class 7 Chapter 6 Exercise 6.3

Chapter 6 of Mathematics subject in Class 7 contains numerous theorems and themes that can be decoded with the guidance of the NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 that Extramarks offers on its website. The NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 include in-depth explanations for each of the textbook’s problems, which may be of great use to students who are strategising and preparing for their Mathematics exam. The NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 can be used to have a thorough understanding of the Properties of Triangles.

You will Learn about Triangles NCERT Maths Solution Class 7 Chapter 6 Exercise 6.3

Triangles and its Properties is a chapter in Class 7 Mathematics that covers topics such as:-

  1.  Triangles – Sides, Angles, and Vertices
  2.  Medians of a Triangle
  3.  Altitudes of a Triangle – Height and Altitude
  4. Exterior Angle of a Triangle and its Property – Interior opposite angles
  5.  Angle Sum Property of a Triangle
  6. Two Special Triangles – Equilateral and Isosceles

Students should comprehend the NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 so that they can solve the questions of Class 7 Maths Chapter 6 Exercise 6.3.

Moreover, NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 have two questions which specify the following:

1) In question number one, students need to find the value of the integer x with the help of the values provided in the figures with the question.

2) Similarly, question number two of Class 7 Maths Ch 6 Ex 6.3 asks students to find the unknown value of the integers x and y in the given figures.

Students can easily answer these questions by using the NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 available on the website and mobile application of Extramarks.

Makes Studying Interesting

There are some significant questions and subject matters in Math Class 7 Chapter 6 Exercise 6.3 that may be taught in high school. The solutions for NCERT Class 7 Maths Chapter 6 Exercise 6.3 can be beneficial for students. They can solve the exercise questions with the help of NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3. The solutions to Class 7th Maths Chapter 6 Exercise 6.3 provided by Extramarks make studying Mathematics very interesting and fascinating. The reason behind this is that they consist of many engaging and simple solutions to the questions. Apart from this, the Extramarks website and mobile application have tremendous amenities and services that can be effortlessly accessed by students. The NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 make the studying process interesting and rewarding for students.

Grows your Interest in the Subject

With the help of the Class 7 Maths Chapter 6 Exercise 6.3 Solution, students can develop an interest in Mathematics. One of the most challenging subjects that students always feel concerned about is Mathematics. The course of Mathematics of Class 7 has some complex chapters that can be helpful for students in higher classes. On the basis of  NCERT Maths Class 7 Chapter 6 Exercise 6.3, students can get the opportunity to understand advanced-level questions that can be useful for competitive exams like NEET or JEE (IIT). NCERT Solutions, for example, NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 can help students  grow their interest in the subject by providing them with the correct information and examples. The NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 can also help students to understand the mathematical concepts more clearly, which in turn will help them score better in their exams. Additionally, the NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 can help students stay updated with the latest changes in the syllabus.

Rules Out the Fear

With the assistance of NCERT Solutions including solutions for Class 7th Math Exercise 6.3 students will be able to understand how to solve difficult questions. The subject-matter experts and academic professionals also suggest students study from the NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3. The major reason for practising with the help of the NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 is suggested is that they raise the enthusiasm of students that rule out their fear of solving challenging Mathematics problems. By providing detailed explanations for all questions in textbooks, the NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 helps students understand concepts better and identify any areas where they might be struggling. In addition, the practise questions and answer keys provided can help students assess their understanding and locate areas for improvement. The step-by-step solutions can help students understand how to approach problems and work through them systematically. All of these factors can help students feel more confident in their abilities and reduce the fear of not being able to understand and solve problems.

The Interactive Way of Teaching

Extramarks has a learning and teaching application for both students and teachers that can be downloaded from the Google Play Store on Android and from the Apple App Store on iPhones. These applications help students  have an engaging learning experience. The NCERT Solutions For Class 7 Maths Chapter 6 Exercise 6.3 are designed to be user-friendly so that students can easily navigate and find the information they need. Extramarks’ NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 are also updated regularly to reflect changes in the curriculum. The solutions are comprehensive and easy to understand. They are available online and can be accessed by students at anytime from the Extramarks website. Students may utilise the NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 that have various important mock questions.

All Questions and Answers are Provided

NCERT Solutions have solutions for every class, starting from Class 6 to Class 12. The solutions can be found in the form of NCERT Solutions for Class 6, NCERT Solutions for Class 7, NCERT Solutions for Class 8, NCERT Solutions for Class 9, NCERT Solutions for Class 10, NCERT Solutions for Class 11, and NCERT Solutions for Class 12. The NCERT Solutions are available for every question that is in the NCERT textbooks. Students can also find sample questions and past years’ papers on the Extramarks website, along with the NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3.

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By using these NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3, students are able to put less effort into their work and get impressive results. In the NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3, solutions are explained in a comprehensible manner. Students can use the Extramarks application or website to find solutions and get the desired output without putting in too much effort. Students can make use of the NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 to comfortably get the answers to the exercise questions. To have noticeable results in the Mathematics examination, students should employ the NCERT Solutions Class 7 Maths Chapter 6 Exercise 6.3 while preparing for it.

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Find the value of the unknown x in the following diagrams:


Since, the sum of all interior angles of a triangle is 180°. So, (i) x+50°+60°=180° x+110°=180° x=180°110°= 70° (ii) x+90°+30°=180° x+120°=180° x=180°120°= 60° (iii)x+110°+30°=180° x+140°=180° x=180°140°= 40° (iv)x+x+50°=180° 2x+50°=180° 2x=180°50° =130° x= 130° 2 = 65° (v)x+x+x=180° 3x=180° x= 180° 3 = 60° (vi)x+2x+90°=180° 3x+90°=180° x=180°90° 3x=90° x= 90° 3 = 30° MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaacaqGtbGaaeyAaiaab6gacaqGJbGaaeyz aiaabYcacaqGGaGaaeiDaiaabIgacaqGLbGaaeiiaiaabohacaqG1b GaaeyBaiaabccacaqGVbGaaeOzaiaabccacaqGHbGaaeiBaiaabYga caqGGaGaaeyAaiaab6gacaqG0bGaaeyzaiaabkhacaqGPbGaae4Bai aabkhacaqGGaGaaeyyaiaab6gacaqGNbGaaeiBaiaabwgacaqGZbGa aeiiaiaab+gacaqGMbGaaeiiaiaabggacaqGGaGaaeiDaiaabkhaca qGPbGaaeyyaiaab6gacaqGNbGaaeiBaiaabwgacaqGGaGaaeyAaiaa bohacaqGGaGaaeymaiaabIdacaqGWaGaeyiSaaRaaeOlaiaabccaae aacaqGtbGaae4BaiaabYcaaeaacaqGOaGaaeyAaiaabMcacaqGGaGa amiEaiabgUcaRiaaiwdacaaIWaGaeyiSaaRaey4kaSIaaGOnaiaaic dacqGHWcaScqGH9aqpcaaIXaGaaGioaiaaicdacqGHWcaSaeaacaWG 4bGaey4kaSIaaGymaiaaigdacaaIWaGaeyiSaaRaeyypa0JaaGymai aaiIdacaaIWaGaeyiSaalabaGaamiEaiabg2da9iaaigdacaaI4aGa aGimaiabgclaWkabgkHiTiaaigdacaaIXaGaaGimaiabgclaWkabg2 da9maaL4babaGaaG4naiaaicdacqGHWcaSaaaabaGaaeikaiaabMga caqGPbGaaeykaiaabccacaWG4bGaey4kaSIaaGyoaiaaicdacqGHWc aScqGHRaWkcaaIZaGaaGimaiabgclaWkabg2da9iaaigdacaaI4aGa aGimaiabgclaWcqaaiaadIhacqGHRaWkcaaIXaGaaGOmaiaaicdacq GHWcaScqGH9aqpcaaIXaGaaGioaiaaicdacqGHWcaSaeaacaWG4bGa eyypa0JaaGymaiaaiIdacaaIWaGaeyiSaaRaeyOeI0IaaGymaiaaik dacaaIWaGaeyiSaaRaeyypa0ZaauIhaeaacaaI2aGaaGimaiabgcla WcaaaeaacaGGOaGaamyAaiaadMgacaWGPbGaaiykaiaaysW7caWG4b Gaey4kaSIaaGymaiaaigdacaaIWaGaeyiSaaRaey4kaSIaaG4maiaa icdacqGHWcaScqGH9aqpcaaIXaGaaGioaiaaicdacqGHWcaSaeaaca WG4bGaey4kaSIaaGymaiaaisdacaaIWaGaeyiSaaRaeyypa0JaaGym aiaaiIdacaaIWaGaeyiSaalabaGaamiEaiabg2da9iaaigdacaaI4a GaaGimaiabgclaWkabgkHiTiaaigdacaaI0aGaaGimaiabgclaWkab g2da9maaL4babaGaaGinaiaaicdacqGHWcaSaaaabaGaaiikaiaadM gacaWG2bGaaiykaiaaysW7caWG4bGaey4kaSIaamiEaiabgUcaRiaa iwdacaaIWaGaeyiSaaRaeyypa0JaaGymaiaaiIdacaaIWaGaeyiSaa labaGaaGOmaiaadIhacqGHRaWkcaaI1aGaaGimaiabgclaWkabg2da 9iaaigdacaaI4aGaaGimaiabgclaWcqaaiaaikdacaWG4bGaeyypa0 JaaGymaiaaiIdacaaIWaGaeyiSaaRaeyOeI0IaaGynaiaaicdacqGH WcaSaeaacqGH9aqpcaaIXaGaaG4maiaaicdacqGHWcaSaeaacaWG4b Gaeyypa0ZaaSaaaeaacaaIXaGaaG4maiaaicdacqGHWcaSaeaacaaI Yaaaaiabg2da9maaL4babaGaaGOnaiaaiwdacqGHWcaSaaaabaGaai ikaiaadAhacaGGPaGaaGjbVlaadIhacqGHRaWkcaWG4bGaey4kaSIa amiEaiabg2da9iaaigdacaaI4aGaaGimaiabgclaWcqaaiaaiodaca WG4bGaeyypa0JaaGymaiaaiIdacaaIWaGaeyiSaalabaGaamiEaiab g2da9maalaaabaGaaGymaiaaiIdacaaIWaGaeyiSaalabaGaaG4maa aacqGH9aqpdaqjEaqaaiaaiAdacaaIWaGaeyiSaalaaaqaaiaacIca caWG2bGaamyAaiaacMcacaaMe8UaamiEaiabgUcaRiaaikdacaWG4b Gaey4kaSIaaGyoaiaaicdacqGHWcaScqGH9aqpcaaIXaGaaGioaiaa icdacqGHWcaSaeaacaaIZaGaamiEaiabgUcaRiaaiMdacaaIWaGaey iSaaRaeyypa0JaaGymaiaaiIdacaaIWaGaeyiSaalabaGaamiEaiab g2da9iaaigdacaaI4aGaaGimaiabgclaWkabgkHiTiaaiMdacaaIWa GaeyiSaalabaGaaG4maiaadIhacqGH9aqpcaaI5aGaaGimaiabgcla WcqaaiaadIhacqGH9aqpdaWcaaqaaiaaiMdacaaIWaGaeyiSaalaba GaaG4maaaacqGH9aqpdaqjEaqaaiaaiodacaaIWaGaeyiSaalaaaaa aa@9045@


Find the values of the unknowns x and y in the following diagrams:


(i)y+120°=180° (Linear pair) y=180°120°=60° Now, x+y+50°=180° (angle sum property) x+60°+50°=180° x=180°110°= 70° (ii) y=80° (vertically opposite angle) y+x+50°=180° 80°+x+50°=180° x+130°=180° x=180°130°= 50° (iii) y+50°+60°=180° (angle sum property) y+110°=180° y=180°110°= 70° (iv) x=60° (vertically opposite angle) 30°+x+y=180° 30°+60°+y=180° y=180°90°= 90° (v) y=90° (vertically opposite angle) x+x+y=180° 2x+90°=180° 2x=180°90°=90° 2x=90° x= 90° 2 = 45° (vi) y=x (vertically opposite angle) a=x (vertically opposite angle) b=x (vertically opposite angle) a+b+y=180° x+x+x=180° 3x=180° x= 180° 3 =60° So, we get x=y=60° MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaacaqGOaGaaeyAaiaabMcacaaMe8UaaeyE 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