NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities (EX 8.1) Exercise 8.1
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NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities (EX 8.1) Exercise 8.1
“Comparing Quantities ” refers to the quantitative relationship between two quantities that represents their respective quantities. It is simply a tool for comparing data.
The concepts of ratio and proportion are taught to students in Class 7th 8.1 Maths on Comparing Quantities. Additionally, they will learn about the Unitary Method, Percentages, And Simple Interest concepts and how to use them in realworld situations. This chapter also discusses the Conversion Of Fractions, Decimals, and Percentages into one another. If students had access to the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1, learning would be simpler. Many sites offer the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1, and it gets tough for them to understand which site they should refer to.
Students should refer to the Extramarks website for the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 as it is an authenticated website that provides reliable solutions to the students who are registered with it. The NCERT Solutions for Class 7 Maths Chapter 8 Exercise 8.1, Comparing Quantities, expands on this concept by giving comparisons of precise names in Mathematics, which are Ratios, Proportions, and Percentages. The Chapter deals with realworld problems that will assist students in comprehending how to compare quantities. It also explains the concepts of profit, loss, and basic interest. In addition to teaching whole numbers, NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 teaches how to convert fractions and decimals into ratios and percentages.Students will learn some crucial information, such as the necessity of using the same unit when comparing any two quantities. The four quantities in question are said to be in proportion if any two ratios are equivalent.
Access NCERT Solutions for Class 7 Mathematics Chapter 8 Comparing Quantities
The best option for CBSE students to practise the chapter titled Comparing Quantities in terms of exam preparation is choosing the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1. There are numerous exercises in this chapter. On the Extramarks website, in PDF format, it offers the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1. Students can study this answer straight from the website or mobile application, or they can download it as needed. Extramarks’ internal subjectmatter experts, carefully and in accordance with all CBSE regulations, solved the problems and questions from the exercise.
Any student in Class 7 who is familiar with all the concepts in the Mathematics textbook and is wellversed in all the exercises in it can easily achieve the highest scores on the final examination. Students may readily comprehend the types of problems that may be given in the examination from this chapter. They can also learn the chapter weightage in terms of overall grade by using the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 so that they can adequately prepare for the final examination.
There are numerous exercises in this chapter that also have numerous questions in addition to these NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1. As previously noted, the internal topic experts have already resolved the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 in a way that makes it easier for students to comprehend every topic. Extramarks’ NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 are of the highest quality, and anyone can use them to study for examinations. It is crucial to comprehend all the concepts in the textbooks and work through the exercises that are provided in order to secure higher grades.
Exercise 8.1
The NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 are available on the Extramarks website so that students may fully understand the material. The best professionals in India who are authorities in their fields are available on Extramarks to instruct the students. The website contains extensive mediabased learning modules. It adds graphics and animations to its modules to encourage students to study.To help students prepare for and do well in the examination, Extramarks offers the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1. The NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 are based on the most recent syllabus of the CBSE Board.
Students can efficiently prepare for the board examination by practising the key questions for each chapter of the Class 7 Mathematics course. Complete solutions will be given to them. Students can refer to the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 on the internet if they are having difficulty understanding the topics. Students may study all the concepts by accessing the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 on the Extramarks website. Moreover, Extramarks provides instructors, allowing students to ask them any questions they may have regarding the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1. To help students discover their areas of weakness so they may work on them and do well on the examination, teachers offer worksheets for their students. Students who are reluctant to ask their school teachers questions concerning the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 are assisted by Extramarks tutors in clarifying their concepts.
NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.1
Students can adequately prepare for the chapter using the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1. With the aid of the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1, students may strengthen their fundamental understanding and get ready for any chapterrelated issues. They can also practise past years’ papers and sample papers for improved preparation. Higher test scores are attained by those who understand the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 as a whole. The Extramarks website offers its students the opportunity to learn better with their experts’ published NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1.
The study material provided by the Extramarks website is recommended for students to employ in order to ensure that they thoroughly understand all the concepts and formulas covered in the chapter by the time they appear for the examination. Extramarks provides interactive activities, a neverending supply of practise questions, worksheets based on chapters, and more. Students who are registered with the website can track their progress using the adaptive quizzes, multiplechoice questions, and mock exams available on the Extramarks website. To ensure that students get the most out of their time learning on the platform, the Extramarks professionals create indepth reports and analyses. In this performance analysis, students’ strong and weak concepts are highlighted, enabling them to concentrate on the concept they find difficult in order to perform well in their examinations.
Q.1
$\begin{array}{l}\mathrm{Find}\mathrm{the}\mathrm{ratio}\mathrm{of}:\\ \left(\mathrm{a}\right)\mathrm{Rs}5\mathrm{to}50\mathrm{paise}\left(\mathrm{b}\right)15\mathrm{kg}\mathrm{to}210\mathrm{g}\\ \left(\mathrm{c}\right)9\mathrm{m}\mathrm{to}27\mathrm{cm}\left(\mathrm{d}\right)30\mathrm{days}\mathrm{to}36\mathrm{hour}\end{array}$
Ans.
\begin{array}{l}\left(\text{a}\right)\text{Rs 5 to 5}0\text{paise}\\ \text{}1\text{ruppe}=\text{100 paise}\\ \text{So,}\text{\hspace{0.17em}}\text{5 rupee}=\text{500 paise}\\ \text{So,}\frac{\text{Rs}5}{50\text{paise}}=\frac{500}{50}=\frac{10}{1}\\ \text{Thus, the required ratio is}\overline{)\text{10:1}}.\\ \left(\text{b}\right)\text{15 kg to 21}0\text{g}\\ \text{1 kg}=\text{1000 g}\\ \text{So, 15 kg}=\text{15000 g}\\ \text{So,}\frac{15\text{kg}}{210\text{g}}=\frac{15000}{210}=\frac{500}{7}\\ \text{Thus, the required ratio is}\overline{)\text{500:7}}.\\ \left(\text{c}\right)\text{9 m to 27 cm}\\ \text{1 m}=\text{100 cm}\\ \text{So, 9 m}=\text{900 cm}\\ \text{So,}\frac{9\text{m}}{27\text{cm}}=\frac{900}{27}=\frac{100}{3}\\ \text{Thus, the required ratio is}\overline{)\text{100:3}}.\\ \left(\text{d}\right)\text{3}0\text{days to 36 hour}\\ \text{1 day}=\text{24 hours}\\ \text{So, 30 days}=\text{720 hours}\\ \text{So,}\frac{30\text{days}}{36\text{hour}}=\frac{720}{36}=\frac{20}{1}\\ \text{Thus, the required ratio is}\overline{)\text{20:1}}.\end{array}
Q.2
$\begin{array}{l}\mathrm{In}\mathrm{a}\mathrm{computer}\mathrm{lab},\mathrm{there}\mathrm{are}3\mathrm{computers}\mathrm{for}\mathrm{every}6\\ \mathrm{students}.\mathrm{How}\mathrm{many}\mathrm{computers}\mathrm{will}\mathrm{be}\mathrm{needed}\mathrm{for}24\\ \mathrm{students}?\end{array}$
Ans.
\begin{array}{l}\text{For 6 students, number of computers required}=\text{3}\\ \text{So, for 1 student, number of computers required}=\frac{3}{6}=\frac{1}{2}\\ \text{Thus, for 24 students, number of computers required}=\frac{1}{2}\times 24\\ \text{}\text{}\text{}\text{}\text{}\text{}\text{}\text{}\text{}\text{}\text{}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}=\overline{)12}\\ \text{Therefore, 12 computers are needed for 24 students}\text{.}\end{array}
Q.3
$\begin{array}{l}\mathrm{Population}\mathrm{of}\mathrm{Rajasthan}=570\mathrm{lakhs}\mathrm{and}\\ \mathrm{population}\mathrm{of}\mathrm{UP}=1660\mathrm{lakh}\\ \mathrm{Area}\mathrm{of}\mathrm{Rajasthan}=\; 3\mathrm{lakh}{\mathrm{km}}^{\mathrm{2}}\mathrm{and}\\ \mathrm{area}\mathrm{of}\mathrm{UP}=\; 2\mathrm{lakh}{\mathrm{km}}^{\mathrm{2}}\mathrm{.}\\ \left(\mathrm{i}\right)\mathrm{How}\mathrm{many}\mathrm{people}\mathrm{are}\mathrm{there}\mathrm{per}{\mathrm{km}}^{\mathrm{2}}\mathrm{in}\mathrm{both}\mathrm{these}\mathrm{States}?\\ \left(\mathrm{ii}\right)\mathrm{Which}\mathrm{State}\mathrm{is}\mathrm{less}\mathrm{populated}?\end{array}$
Ans.
\begin{array}{l}{\text{(i) Population of Rajasthan in 3 lakh km}}^{\text{2}}=\text{570 lakhs}\\ {\text{Population of Rajasthan in 1 lakh km}}^{\text{2}}\text{}=\frac{\text{570}}{3}\\ \text{}\text{}\text{}\text{}\text{}\text{}\text{}\text{}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{}=\overline{)190\text{}}\\ {\text{Population of UP in 2 lakh km}}^{\text{2}}\text{}\text{}\text{}=\text{1660 lakhs}\\ {\text{Population of UP in 1 lakh km}}^{\text{2}}\text{}\text{}\text{}=\frac{1660}{2}\\ \text{}\text{}\text{}\text{}\text{}\text{}\text{}\text{}\text{}=\overline{)830\text{\hspace{0.17em}}}\\ \text{(ii)}\\ \text{From above data, clearly Rajasthan is less populated}\text{.}\end{array}