# NCERT Solutions Class 8 Maths Chapter 7 Exercise 7.1

The Central Board of Secondary Education is one of India’s largest and most well-known educational boards, commonly known as the CBSE. Numerous schools, most of which are found in India’s major cities, are connected with the CBSE board. When it comes to its educational model, CBSE is incredibly objective. The CBSE prioritises a learning environment that guarantees that students comprehend the subjects and concepts they are studying. When learning something new and developing new ideas, CBSE teaches its students to have a tendency to do so with significant depth and a strong foundation. It is important for students to develop a critical thinking process. The CBSE teaches its students how to separate relevant information from repetitive information. Exam questions are structured in a way that is incredibly objective. Questions that are primarily brief and direct are part of an objective pattern. The questions that are typically included in exams are brief, but they are deeply rooted in the subject’s basics. Students will not be able to accurately answer the questions if they are unfamiliar with the book and the topics, respectively. The learning curve for a CBSE curriculum is high and demands a significant amount of effort and commitment. Students must maintain consistency in their study habits.

CBSE’s extensive curriculum is well-known among students and parents. Teachers and other experts with extensive training and high regard in their fields of specialisation have created the CBSE curriculum. These instructors have extensive knowledge of instructing CBSE students. The syllabus was put up based on the prevalent global educational trends at the time. Students have a comprehensive education plan created by the syllabus and the objective exam format. The CBSE wants its students to acquire new concepts and enjoy the process in order to transform the educational landscape of the nation. Students who want to do well on their CBSE examinations must study consistently and go over the chapters they have already completed even more carefully. They must also take their topics and their curriculum extremely seriously. As a result, students must begin to develop a solid understanding of all the subjects they must study. Making ends meet depends on a student practising the curriculum’s chapters on a regular basis.

A centralised organisation, the National Council of Educational Research and Training (NCERT), was established in 1961. The Indian government established NCERT in order to give India a self-governing division in its education ministry that would make difficult decisions pertaining to the nation’s educational growth. The NCERT is made up of highly qualified experts who are capable of making executive judgements regarding the academic advancement and proficiency of the nation. Together, NCERT and CBSE make choices in a highly synergistic relationship. If students want to perform better in the tests, they must completely abide by the norms and regulations that NCERT publishes. Nevertheless, NCERT demands that the curriculum be strictly followed by all of the schools connected to the CBSE board. NCERT has a publishing division that meticulously adheres to the curriculum as well as all laws and regulations. The importance of using the NCERT textbook as their primary textbook has been stressed by teachers at Extramarks. With so much material available, students frequently become overwhelmed, and the authority of the CBSE board frequently does not assist them. Teachers have informed kids that there is nothing to be afraid of or that they should find intimidating.

One of the most significant and difficult courses that a student in Class 8 studies as part of their curriculum is mathematics. Every student in Class 8 who is following the CBSE curriculum is required to take Mathematics. The eighth-grade class now includes students who are in their last year of middle school. As a result, CBSE works to get its students ready for the high school level of advanced education. Students tend to shy away from Mathematics in general, and the main reason given by students for this is that the subject is challenging. However, teachers have observed that students are frequently not intimidated by the amount of challenge. In general, students are more concerned with the procedures that must be followed in order to perform well on Mathematics exams. Students need to practice with great precision and regularity. Students frequently fail to give this subject proper attention due to the size of the syllabus and the scope of the programme. Students have been informed by their teachers that they need not be afraid of the subject. Teachers may guarantee that students will not have issues with the subject that they typically have if they implement the small changes that they are asked to make.

Class 8 Mathematics Is very important. To get good grades, students need to focus and learn the concepts properly. The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 helps build a good foundation in Mathematics for higher grades. The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1, should be practised thoroughly. Students must practice every day and solve as many problems as possible. They should solve the practice problems and practice with the help of NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 to better understand the concepts. They should solve the sample papers and refer to the NCERT solutions for additional help. They can practice expressions and learn how to implement them. Another important thing is that students should study the chapters and related topics carefully. No matter how useful a key question is, it will be of no help if students do not have a thorough knowledge of the topic and concepts. They should use the NCERT Solutions, like the NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1, for solving the key questions.

Class 8 is a critical stage in the academic life of a student, and these NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 provide in-depth knowledge of the concepts that are covered. Extramarks’ team of experts solves Chapter 7 problems with the NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1, in a step-by-step manner to help students reinforce their concepts. The concepts discussed in this chapter include the Cube Of Numbers, Finding Cubes of Two-Digit Numbers by the Column Method, the Cube of Negative Integers, the Cube of Rational Numbers, the Cube of Natural Numbers, and the Cube Root. Negative Perfect Cube, Cube Root of Product Integers, Cube Root finding using Cube Root Tables.

**NCERT Solutions For Class 8 Maths Chapter 7 Cubes And Cube Roots (EX 7.1) Exercise 7.1 **

The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 explains the pattern of Cubes which is required when a number is multiplied by itself three times. The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 show that whenever a number is multiplied by itself three times we get another number. The relations can be made with respect to the new number which one calls the cube of the original number. The Class 8 Mathematics NCERT Solutions Chapter 7 helps students learn the calculation of Cube Roots.

The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 provided by Extramarks contains answers to all questions in Exercise 7.1. This chapter contains two exercises, Exercise 7.1 with cubes and Exercise 7.2 with Cube Roots. Here students will look at what is covered in the Cubes and Cube Roots chapter.

The PDF version of the NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1, was created by expert teachers from the latest edition of the CBSE (NCERT) book. Students can earn more points on the exam by practising important Class 8 questions with the help of NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 for each chapter. Extramarks is a platform that provides students with the NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1, and other learning materials. Mathematics students looking for better solutions can download the NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 to revise the entire syllabus and score more points on the exam.

**Access NCERT Solution For Class 8 Mathematics Chapter 7 – Cubes And Cube Roots**

Students may have heard people say that the Mathematics students learned in school (especially Algebra and the Pythagorean theorem) becomes useless when students grow up.

However, Arithmetic and Mathematics are used on a daily basis much more often than one thinks. It is not always the Angles of a Triangle, but there are calculations that the student’s brain can perform quickly without much thought if students master basic Mathematics Skills. Mathematics also surrounds people in invisible ways. Mathematics can guarantee that all the technologies someone uses in Mathematics perform calculations (ATMs, self-checkouts), and as part of the programming and algorithms that make them work.

People also use Mathematics to save lives when they need a certain dose of medicine or to calculate how often to take a medicine. It even makes very quick calculations to determine that even when people do not use Mathematics in their professions, they are surrounded by it. From the few examples above, students can see how low-level Mathematics can affect some aspects of their life. Many of these things are difficult for people who do not have the opportunity to practice their numeracy skills early in lives. This can cause students to miss out on a few bargains at best and jobs and other opportunities at worst. The best way for adults to ensure good Mathematics skills and comprehension is through repeated practice (even if it is just 5 or 10 minutes a day) from a very young age.

The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 helps students find Cubes and Cube Roots of different numbers, understand the difference between Cubes and Cube Roots, and have fun with some interesting patterns. This chapter also helps students understand how to find Cubes and Cube Roots of numbers using the prime factorization method. The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 also explains how to find the Cube Root of a Cubic Number.

**Class 8 Maths Exercise 7.1 Cubes And Cube Roots – Exercise Overview In A Quick Glimpse**

A deeper knowledge of numbers is essential for understanding higher Mathematics topics. As a result, the NCERT team arranged the questions for each exercise with well-thought-out real-life situations, helping students understand the problem and easily associate concepts with it. All the concepts mentioned in Chapter 7 can be understood with the help of NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1.

The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 covers the concept of perfect Cubes, Even and Odd models of Cubes, Prime Factors of Cubes, Square Roots of a Number, Square Root of a Cube, Finding the Square Root Using The Prime Factorization Method with an explanation of the smallest multiple being a perfect Cube. The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 Cubes and roots consists of 7 questions along with the solutions.

A list of formulas is included in the NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1, for students to easily understand them. The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1, describes the relationships and patterns shown by the shapes using appropriate examples, related graphs, and tables so that students can understand the pattern and find more on their own. Students can refer to various other solutions, like the NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1, for a good understanding of all the chapters.

Here are some important facts and formulas explained in NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1. In NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1, Cubes and Cube Roots, students work with numbers and their multiples and can easily work with complex numbers. Dice and Cube Roots teaches students how to cube a number and find the cube root of a number using simple Mathematics and examples for better understanding.

Introduction to Cubes And Cube Roots, Cubes, some interesting patterns, smallest multiples that are perfect Cubes, Cube Roots, Cube Roots by Prime Factorization Method, and Cube Roots of Cubes covered in this chapter are some main topics. Interesting explanations of concepts, activities, exercises and simple language make this chapter and NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 interesting and enjoyable.

The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 are solved by expert Mathematics teachers and are available on Extramarks which provides step-by-step solutions to Class 8 Mathematics textbook questions following CBSE guidelines from the latest Class 8 NCERT Mathematics book.

**Class 8 Ex 7.1 Solution – All Questions**

The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1, covers important topics that form the basis for students working with numbers and complex numerical operations NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 Cubes and Cube Roots helps students learn and master multiplication and division at an advanced level. Summaries and assessments can be understood with the help of NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1. These solutions help students work with the chapter and solve the assignments given in the chapter. From the basics of using Cubes and Cube Roots, this chapter and NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 will help students understand what a Cube is, how it is derived, and other basics. New concepts, interesting problems, and solved and unsolved examples are explained in simple language, making this chapter interesting and enjoyable. The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1, are compiled in accordance with the latest CBSE guidelines and updates.

**Exercise 7.1 Class 8 Maths – Other Exercises**

Apart from the exercises given, students should also practice all the solved examples along with the NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 available on the Extramarks’ website to clarify the concepts about Cubes and Cube Roots. Students can also download a PDF of Chapter 7 Cubes and Cube Roots and print it for offline access to help them prepare for their exams. Students can also download the NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 for all Class 8 exercises to revise their entire syllabus and score more points on their exams. Students can download the NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 and use them to prepare for their examinations. Students can also find the NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1, on the website to learn more about different topics. The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1, are up-to-date and should help students with their academic journey.

**NCERT Solutions For Class 8**

The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 are curated by experts with years of experience in the field to provide complete and concise solutions to all exercises. The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 are explained step by step in very simple terms to help the student solidify the foundation of the chapter. Practising the problems with the help of NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 will improve the student’s grades and improve their problem-solving skills. The NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 is available for download in PDF format, and students can access this PDF anytime, anywhere.

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Extramarks’ website provides students with a variety of learning resources. Students can access these resources from the Extramarks website or mobile application for a thorough and holistic understanding of all the concepts. These resources include NCERT solutions, past years’ papers, sample question papers, revision notes, and important questions for all the chapters. Students from all classes can access these resources, as they are available for classes 1 to 12. These solutions can be found in Hindi as well as English.

**Q.1 **Which of the following numbers are not perfect cubes?

(i) 216 (ii) 128 (iii) 1000 (iv)100 (v) 46656

**Ans**

$\begin{array}{l}\text{(i)The prime factorisation of 216 is as follows:}\\ \begin{array}{cc}2& 216\\ 2& 108\\ 2& 54\\ 3& 27\\ 3& 9\\ 3& 3\\ & 1\end{array}\\ \\ \text{216}=\underset{\xaf}{\text{2}\times \text{2}\times \text{2}}\times \underset{\xaf}{\text{3}\times \text{3}\times \text{3}}\\ \text{Since all the factors appears in a group of three,so 216}\\ \text{is a perfect cube}.\end{array}$ $\begin{array}{l}\text{(ii)The prime factorisation of 128 is as follows:}\\ \begin{array}{cc}2& 128\\ 2& 64\\ 2& 32\\ 2& 16\\ 2& 8\\ 2& 4\\ 2& 2\\ & 1\end{array}\\ \\ 128=\underset{\xaf}{\text{2}\times \text{2}\times \text{2}}\times \underset{\xaf}{\text{2}\times \text{2}\times \text{2}}\times 2\\ \text{Since 2 is not appearing in a group of three,so 128}\\ \text{is not a perfect cube}.\\ \\ \text{(iii)The prime factorisation of 1000 is as follows:}\\ \begin{array}{cc}2& 1000\\ 2& 500\\ 2& 250\\ 5& 125\\ 5& 25\\ 5& 5\\ & 1\end{array}\\ \\ 1000=\underset{\xaf}{\text{2}\times \text{2}\times \text{2}}\times \underset{\xaf}{\text{5}\times \text{5}\times \text{5}}\\ \text{Since 2 and 5 appears in a group of three,so 1000}\\ \text{is a perfect cube}.\end{array}$ $\begin{array}{l}\text{(iv)The prime factorisation of 100 is as follows:}\\ \begin{array}{cc}2& 100\\ 2& 50\\ 5& 25\\ 5& 5\\ & 1\end{array}\\ \\ 100=2\times 2\times 5\times 5\\ \text{Since 2 and 5 are not appearing in a group of three,so}\\ \text{100 is not a perfect cube}.\\ \\ \text{(v)The prime factorisation of 46656 is as follows:}\\ \begin{array}{cc}2& 46656\\ 2& 23328\\ 2& 11664\\ 2& 5832\\ 2& 2916\\ 2& 1458\\ 3& 729\\ 3& 243\\ 3& 81\\ 3& 27\\ 3& 9\\ 3& 3\\ & 1\end{array}\end{array}$ $\begin{array}{l}46656=\underset{\xaf}{\text{2}\times \text{2}\times \text{2}}\times \underset{\xaf}{\text{2}\times \text{2}\times \text{2}}\times \underset{\xaf}{3\times 3\times 3}\times \underset{\xaf}{3\times 3\times 3}\\ \text{Since all the factors appears in a group of three,so}\\ \text{46656 is a perfect cube}.\end{array}$

**Q.2** Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube.

(i) 243 (ii) 256 (iii) 72 (iv) 675 (v) 100

**Ans**

(i)

$\begin{array}{l}\text{The prime factorisation of 243 is as follows:}\\ \begin{array}{cc}3& 243\\ 3& 81\\ 3& 27\\ 3& 9\\ 3& 3\\ & 1\end{array}\\ \\ 243=\underset{\xaf}{3\times 3\times 3}\times 3\times 3\end{array}$

Here, two 3s are left which does not appear in a group of three. To make 243 a cube, one more 3 is required.

In that case, we have to multiply 243 by 3

i.e. 243 × 3 = __3 × 3 × 3__ × __3 × 3 × 3__ = 729, which is a perfect cube.

Hence, the smallest natural number by which 243 should be multiplied to make it a perfect cube is 3.

(ii)

$\begin{array}{l}\text{The prime factorisation of 256 is as follows:}\\ \begin{array}{cc}2& 256\\ 2& 128\\ 2& 64\\ 2& 32\\ 2& 16\\ 2& 8\\ 2& 4\\ 2& 2\\ & 1\end{array}\\ \\ 256=\underset{\xaf}{2\times 2\times 2}\times \underset{\xaf}{2\times 2\times 2}\times 2\times 2\end{array}$

Here, two 2s are left which does not appear in a group of three. To make 256 a cube, one more 2 is required.

If we multiply 256 by 2, we get

256 × 2 = __2 × 2 × 2__ × __2 × 2 × 2__ × __2 × 2 × 2__ = 512, which is a perfect cube.

Hence, the smallest natural number by which 256 should be multiplied to make it a perfect cube is 2.

(iii)

$\begin{array}{l}\text{The prime factorisation of 72 is as follows:}\\ \begin{array}{cc}2& 72\\ 2& 36\\ 2& 18\\ 3& 9\\ 3& 3\\ & 1\end{array}\\ \\ 72=\underset{\xaf}{2\times 2\times 2}\times 3\times 3\end{array}$

Here, two 3s are left which are not in a group of three. To make 72 a perfect cube, one more 3 is required.

Then, we obtain

72 × 3 = __2 × 2 × 2__ × __3 × 3 × 3__ = 216, which is a perfect cube.

Hence, the smallest natural number by which 72 should be multiplied to make it a perfect cube is 3.

(iv)

$\begin{array}{l}\text{The prime factorisation of 675 is as follows:}\\ \begin{array}{cc}3& 675\\ 3& 225\\ 3& 75\\ 5& 25\\ 5& 5\\ & 1\end{array}\end{array}$

$\text{675}=\underset{\xaf}{\text{3}\times \text{3}\times \text{3}}\times \text{5}\times \text{5}$

Here, two 5s are left which are not in a group of three. To make 675 a cube, one more 5 is required.

If we multiply 675 by 5, we get

675 × 5 = __3 × 3 × 3__ × __5 × 5 × 5__ = 3375, which is a perfect cube.

Hence, the smallest natural number by which 675 should be multiplied to make it a perfect cube is 5.

(v)

$\begin{array}{l}\text{The prime factorisation of 100 is as follows:}\\ \begin{array}{cc}2& 100\\ 2& 50\\ 5& 25\\ 5& 5\\ & 1\end{array}\\ \\ \text{1}00=\text{2}\times \text{2}\times \text{5}\times \text{5}\end{array}$

Here, two 2s and two 5s are left which are not in a triplet. To make 100 a cube, we require one more 2 and one more 5.

Then, we obtain

100 × 2 × 5 = __2 × 2 × 2__ × __5 × 5 × 5__ = 1000, which is a perfect cube

Hence, the smallest natural number by which 100 should be multiplied to make it a perfect cube is 2 × 5 = 10.

**Q.3 **Find the smallest number by which each of the following numbers must be divided to obtain a perfect cube.

(i) 81 (ii) 128 (iii) 135 (iv) 192 (v) 704

**Ans**

(i)

$\begin{array}{l}\text{The prime factorisation of 81 is as follows:}\\ \begin{array}{cc}3& 81\\ 3& 27\\ 3& 9\\ 3& 3\\ & 1\end{array}\end{array}$

81 = __3 × 3 × 3__ × 3

Here, one 3 is left which is not in a triplet.

If we divide 81 by 3, then it will become a perfect cube.

Therefore, 81 ÷ 3 = 27 = __3 × 3 × 3__ is a perfect cube.

Hence, the smallest number by which 81 should be divided to make it a perfect cube is 3.

(ii)

$\begin{array}{l}\text{The prime factorisation of 128 is as follows:}\\ \begin{array}{cc}2& 128\\ 2& 64\\ 2& 32\\ 2& 16\\ 2& 8\\ 2& 4\\ 2& 2\\ & 1\end{array}\end{array}$

128 = __2 × 2 × 2__ × __2 × 2 × 2__ × 2

Here, one 2 is left which is not in a group of three.

If we divide 128 by 2, then it will become a perfect cube.

Therefore, 128 ÷ 2 = 64 = __2 × 2 × 2__ × __2 × 2 × 2__ is a perfect cube.

Hence, the smallest number by which 128 should be divided to make it a perfect cube is 2.

(iii)

$\text{The prime factorisation of 135 is as follows:}$

$\begin{array}{cc}3& 135\\ 3& 45\\ 3& 15\\ 5& 5\\ & 1\end{array}$

135 = __3 × 3 × 3__ × 5

Here, one 5 is left which is not in a group of three.

If we divide 135 by 5, then it will become a perfect cube.

Thus, 135 ÷ 5 = 27 = __3 × 3 × 3__ is a perfect cube.

Hence, the smallest number by which 135 should be divided to make it a perfect cube is 5.

(iv)

$\text{The prime factorisation of 192 is as follows:}$

$\begin{array}{cc}2& 192\\ 2& 96\\ 2& 48\\ 2& 24\\ 2& 12\\ 2& 6\\ 3& 3\\ & 1\end{array}$

192 = __2 × 2 × 2__ × __2 × 2 × 2__ × 3

Here, one 3 is left which is not in a group of three.

If we divide 192 by 3, then it will become a perfect cube.

Thus, 192 ÷ 3 = 64 = __2 × 2 × 2__ × __2 × 2 × 2__ is a perfect cube.

Hence, the smallest number by which 192 should be divided to make it a perfect cube is 3.

(v)

$\text{The prime factorisation of 704 is as follows:}$

$\begin{array}{cc}2& 704\\ 2& 352\\ 2& 176\\ 2& 88\\ 2& 44\\ 2& 22\\ 11& 11\\ & 1\end{array}$

704 = __2 × 2 × 2__ × __2 × 2 × 2__ × 11

Here, one 11 is left which is not in a group of three.

If we divide 704 by 11, then it will become a perfect cube.

Thus, 704 ÷ 11 = 64 = __2 × 2 × 2__ × __2 × 2 × 2__ is a perfect cube.

Hence, the smallest number by which 704 should be divided to make it a perfect cube is 11.

**Q.4 **Parikshit makes a cuboid of plasticine of sides 5 cm, 2 cm, 5 cm. How many such cuboids will he need to form a cube?

**Ans**

Volume of the cube of sides 5 cm,2 cm ,5 cm

=5 cm ×5 cm ×2 cm =5 ×5 ×2 cm^{3}

Here, two 5s and one 2 are left which are not in a triplet. If we multiply this expression by 5 × 2 × 2 = 20, then it will become a perfect cube.

Thus, 5 × 5 × 2 × 5 × 2 × 2 = __2 × 2 × 2__ × __5 × 5 × 5__ = 1000 is a perfect cube

Hence, 20 cuboids of 5 cm, 2 cm, and 5 cm are required to form a cube.

## FAQs (Frequently Asked Questions)

### 1. What types of questions are there in Class 8 Maths Chapter 7 Exercise 7.1?

All types of short and long answers are included in Class 8 Maths Exercise 7.1 Solution. By the end of this chapter, students will have improved their problem-solving and time-management skills. This will help students get good grades in the finals.

### 2. Are the NCERT Solutions for Class 8 Maths Exercise 7.1 sufficient to answer the questions in the final exam?

Yes, it is enough to solve all the questions with the help of NCERT Class 8 Maths Chapter 7 Exercise 7.1 for the exam. Working through this chapter will help students learn the concepts perfectly. These questions are developed according to the NCERT syllabus and guidelines. This ensures that the students do well in their finals. Students can download the NCERT Solutions For Class 8 Maths Chapter 7 Exercise 7.1 from the Extramarks’ website for offline access.

### 3. Do students need to study all the topics provided in Chapter 7 of NCERT Solutions for Class 8 Mathematics?

Yes, it is mandatory to study all subjects offered in NCERT Solutions for Class 8 Mathematics Chapter 7 in order to do well in the Class 8 exams. It also focuses on solving questions with the help of Mathematics solutions in a way that is easy for students to understand.