NCERT Solutions For Class 9 Maths Chapter 14- Statistics Exercise 14.3

The Central Board of Secondary Education CBSE is one of the most reputable and highly esteemed boards that operate in India. There are numerous CBSE-affiliated schools located throughout the country.CBSE is highly popular among everyone for its very distinct study pattern, which they also implement in their exams and question papers. The CBSE pattern is very objective, which means that the questions that are asked are based on the fundamental aspects of the syllabus. The answers that they seek are very short, but the answers are based on the core ideas, and therefore a student must have the entire chapter figured out properly and with depth. The basic ideas should be well understood as they are very important for students if they desire to score well in the exams. CBSE wants its students to go through the chapter and understand the ideas properly instead of memorising just for the sake of marks.CBSE wants its students to learn, so theyhave employed the best ways to make that possible. CBSE wants its students to be able to sift through the texts and chapters for all the redundant information so that they can focus on the important and salient features of the text. The types of questions they ask in their exams are heavily based on these fundamental concepts.

The CBSE board is widely known among students and teachers for its vast syllabus. The syllabus is built in a way where students can be introduced to a variety of ideas from a varied assortment of subjects. Therefore, the Class 9 curriculum can be pretty challenging because, at this stage, students have not decided about their professional stream, and therefore, they need to learn something from every stream. Students often find this pretty daunting, and they often get very overwhelmed because of it. Although the teachers at Extramarks have shared little tricks and hacks that they have seen students employ to deal with similar struggles. The changes are minor, and with a few implementations in their routine, students can easily deal with the struggles. Teachers have constantly reassured students that there is nothing for them to be  scared of and that with a little dedication and consistency, they can easily score well in these exams.

The National Council of Educational Research and Training, NCERT is an organisation that is centrally operated. It was founded by the Indian government in 1961 so that it could assist the country in making the right decisions and facilitate the educationaldevelopment of the country. NCERT employs esteemed and qualified personnel who understand the Indian educational milieu well. NCERT assists both the Central government and the State governments so that they make the right decision regarding the academic prowess of the country, which would be responsible for the future of countless Indian children.NCERT and CBSE are very dependent on each other and share a very symbiotic relationship. CBSE follows all the rules that NCERT employs and asks its students to do the same, and it is crucial for students to follow, them strictly if they desire to score better marks in their exams. NCERT puts out a series of rules and regulations for everyone to follow and students should go through them properly. NCERT even curates their syllabus following all the major educational trends worldwide. The syllabus is extremely important for students because itexplains comprehensively everything that a student must focus on regarding each chapter. NCERT also owns its own publishing house and publishes its books. All the NCERT textbooks strictly follow all the rules and regulations and adhere to them completely based on the syllabus. The teachers at Extramarks have constantly reminded students that they must treat their NCERT textbook as their primary textbook and solve all the unsolved questions in the book before moving on to a different reference book. When students refer to the NCERT textbook as their primary textbook, they get used to the way the chapters are written and the kind of questions that might come in the final exam. Teachers at Extramarks have worked tirelessly to release the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 which can be accessed through the link below.

Mathematics is one of the most important subjects in the entire curriculum for Class 9 CBSE students because it is one of those subjects which has grave interdisciplinary echoes. Class 9 students are unsure about the stream they are going to take after Class 9 so  Mathematics topics are included in the syllabus. Mathematics is a high-scoring subject, but students often think it is difficult. Teachers at Extramarks have reassured students that it is not the case. All that a student needs to do is practise the mathematical problems regularly, and when they have made progress, they must revise the chapters and problems that they have solved long ago. Nothing can stop students from getting good grades on exams if they are consistent with their practise and revision.Students are generally under a lot of stress about Mathematics and the primary reason behind this is that one cannot master the subject in a day. Although teachers who have been teaching CBSE Class 9 children for a significant amount of time have shared that the CBSE pattern might seem very challenging, there is nothing that they should be scared of. These teachers observe the struggles of every class 9 student and have come up with the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3.

The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 is an attempt made by teachers at Extramarks to make learning easier and more fun for students. The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 provide solutions for every unsolved question in the NCERT textbook. The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 have extremely well-put-together and lucid explanations for every problem. For every problem, the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 provides step-by-step explanations of all the steps that are involved in the problem-solving process. There are usually many steps when a student issolving mathematics problems. The solutions provide detailed explanations for every step. This is done so that while students are using the solutions to solve the problems, they do not come across any other issues. The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 is meant to make the learning process extremely easy. Students who have used the solutions have shared positive experiences with them.

The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 have been provided by top educators who have been a part of the Extramarks’ team for a very long time. These teachers are highly qualified and very reputablein their fields. These teachers have years of experience in teaching Class 9 CBSE children. Therefore, they have compiled the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 keeping all these in mind. The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 adhere to every rule and regulation that the NCERT has prescribed for everyone to follow. The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 strictly correspond to theNCERT syllabus. These solutions have been an amazing and extremely useful tool for every student who uses them. Students use the solutions in different ways. When students refer to the solutions all the time, they get very used to the kinds of questions that might appear on the question paper. Students ought to understand the paper pattern well because the CBSE pattern is very different from all the other traditional ways of teaching. Therefore, the use of the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 is very crucial for a student’s performance.

The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 provide all the solutions in extreme detail. The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 is constantly updated. This is important because NCERT and CBSE keep updating their rules and regulations. NCERT and CBSE even update the syllabus regularly. Thus, if the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 are not updated regularly, then the solutions would not help the students the way they were intended to. The solutions are extensively checked for any errors before they are put out. Therefore, there is a very small chance that there might be inaccuracies in the solutions. All the answers in NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 have been assured by teachers to be accurate and precise. Every teacher who is a part of the Extramarks team recommends that students use these solutions regularly.

The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 can be used in a versatile manner.. The solutions do not just help  students with their academics; they also help themin other ways. Maths Class 9 Chapter 14 Exercise 14.3 contains nine problems, and the solutions include them all.

One of the best ways that teachers have seen the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 being used by students is when they are solving the chapters for the first time. When a student approaches a chapter for the first time, they are told that they must go through the theory of the chapter first. They must go through the theory, well enough to understand the fundamentals of the chapters. After students have gone through the theory they must go through all the formulas involved in the chapter. Once they are done with all these, they must go through all the solved examples very carefully before starting to solve the problems. Students must only refer to the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 after they have done all the above. When students refer to the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 they get first-hand experience with the correct way of answering questions that CBSE would accept and grade. Since the study pattern of CBSE is not very generalised, students using the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 have an upper hand. The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 trains students wonderfully for their CBSE exams.

NCERT Solutions For Class 9 Maths Chapter 14 Statistics (Ex 14.3) Exercise 14.3 

The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 provide solutions for the third exercise of chapter 14 of the Class 9 CBSE curriculum. Chapter 14 of the syllabus is Statistics. Statistics is a very separate branch of Mathematics. It deals with data, its analysis, and the different ways to interpret and analyse it.The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 explains the new section of Mathematics to Class 9 students very lucidly. This chapter often incorporates various charts and graphs, and the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 provide very clear and well-defined graphs so that students can understand the solutions with great ease.

Access NCERT Answers For Class 9 Mathematics Chapter 14 – Statistics

Extramarks has released the NCERT Solutions for Class 9 Maths, Chapter 14, Exercise 14.3.Extramarks teachers with extensive experience teaching Class 9 students have worked tirelessly to provide the most efficient NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3.solutions are extremely helpful for students. Students who have used the NCERT solutions have shared their great experiences. The Extramarks website is a one-stop solution for every student because it is home to different kinds of resources. NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 is just one of many incredible tools available to students.Students generally find Exercise 14.3 Class 9 Maths to be tricky. Students may access the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 on the Extramarks website. The solutions can also be accessed through the Extramarks application.Exercise  14.3

The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 provide solutions for the third exercise of the chapter Statistics. There are 6 short answers and 3 long answers that are needed from the students.

NCERT Solution Class 9 Maths Of Chapter 14 All Exercises

There are a total of 4 exercises in Chapter 14 Statistics. NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 provides solutions for the third exercise of the chapter. There are NCERT solutions for every exercise in the chapter. Click on the link below to access the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3.

NCERT Solutions For Class 9 Maths Chapter 14 Exercise 14.3 Free PDF

The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 are provided for access on the Extramarks website. They can also be accessed through their mobile applications, which makes them even more reliable during exam preparation. The solutions are provided for free for anyone to download, and they are available in PDF format.

Chapter 14 Maths Class 9 Exercise 14.3

All the problems of the exercise are explained below.

Exercise 14.3 Class 9 NCERT Solutions Question 1

The solution to the question is provided in NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3.

14.3 Maths Class 9 Question 2

The solution to this question is provided in the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3.  There is a chart that offers percentages of girls and boys and all the data is given in tabular form. A student is asked to put the representation and draw a bar graph based on that.

Chapter 14 Exercise 14.3 Question 3

The solution to this question is provided in the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3. There is data given on political parties and the seats that they have occupied in the government. Based on this data, students are asked to draw a bar graph, and they are asked questions based on the graph that the student has drawn.

Chapter 14.3 Maths Class 9 Question 4

The solution to this question is provided in the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3. This is a long answer type question, and students need to interpret all the data in a continuous form, and then they must answer the questions.

Class 9 Maths Chapter 14 Exercise 14.3 Question 5

The solution to this question is provided in the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3.  This is a very simple and direct question, and students can easily answer itbased on the formulas that they have learned. Class 9 Chapter 14 Maths Exercise 14.3 is a very important exercise that deals with basic ideas that develop in the later classes.

Ex 14.3 Class 9 Question 6

The solution to this question is provided in NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3. This particular problem is about the representation of polygons, and then they need to find the cumulative frequency of the data. Then students are asked to find the median, and based on that, they are asked to answer further questions.

Ex 14.3 Class 9 Solutions Question 7

The solution to this question is provided in the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3. This question follows a similar pattern as the last one because this one too is based on a polygon. Based on all the data, there are similar questions that are asked of the student.

Class 9 Maths Chapter 14 Exercise 14.3 Question 8

The solution to this question is provided in the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3. There is data given of children playing in a park.The data is continuous, and therefore, there are regular intervals between them; therefore, students have to be extra careful while solving this problem. Chapter 14 Exercise 14.3 Question 9

The solution to this question is provided in the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3. The data is based on a telephone directory. There are two questions based on the data. The first one asks the student to draw a histogram of all the data, and then they are asked to find the greatest interval.

The solution to this question is provided in the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 provided by teachers at Extramarks and they are very reliable.

Key Takeaways Of NCERT Solutions Class 9 Maths Chapter 14 Exercise 14.3 

Extramarks has released the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 and they were compiled and curated with care to make sure there were no errors. Teachers have shared that these solutions can be used in versatile waysSince the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 are available online they can be accessed by many people. Students can download the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 in PDF format for offline access.

NCERT Solutions For Class 9

The NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 are easy-to-read solutions to every NCERT problem that is unsolved, irrespective of course and class.

CBSE Study Materials For Class 9

The Extramarks’ website has a plethora of materials for students to refer to. The NCERT Solutions for Class 9 Maths, Chapter 14, Exercise 14.3, is just one of the many incredible resources made available to students.CBSE Study Materials

Extramarks strives to provide holistic education to students who want it. Besides the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 they have released NCERT solutions for the following classes and subjects. The solutions to Class 9 Maths Chapter 14 Exercise 14.3 can be accessed through the link below.

Q.1 A survey conducted by an organization for the cause of illness and death among the women between the ages 15 – 44(in years) worldwide, found the following figures (in %):

S.No. Causes Female fatality rate (%)
1.

2.

3.

4.

5.

6.

Reproductive health conditions

Neuropsychiatric conditions

Injuries

Cardiovascular conditions

Respiratory conditions

Other causes

31.8

25.4

12.4

4.3

4.1

22.0

(i) Represent the information given above graphically.

(ii) Which condition is the major cause of women’s ill health and death worldwide?

(iii) Try to find out, with the help of your teacher, any two factors which play a major role in the cause in (ii) above being the major cause.

 

 

 

 

 

Ans

(i) The graphical representation of the given information is given below:

(ii) Reproductive health condition is the major cause of women’s ill health and death worldwide.
(iii) The two factors which play a major role in the cause of reproductive health conditions are:

(i) Improper diet (ii) Lack of medical facility.

Q.2 The following data on the number of girls (to the nearest ten) per thousand boys in different sections of Indian society is given below.

Section Number of girls per thousand boys
Schedule Cast (SC)

Schedule Tribe(ST)

Non SC/ST

Backward districts

Non-backward districts

Rural

Urban

940

970

920

950

920

930

910

(i) Represent the information above by a bar graph.

(ii) In the classroom discuss what conclusions can be arrived at from the graph.

 

 

 

 

 

 

 

Ans

(i) Bar graph showing given information is given below:

(ii) From the graph we see that number of girls per thousand boys is less in urban areas.

Q.3 Given below are the seats won by different political parties in the polling outcome of a state assembly elections:

Political Party A B C D E F
Seats Won 75 55 37 29 10 37

(i) Draw a bar graph to represent the polling results.

(ii) Which political party won the maximum number of seats?

Ans

(i) A bar graph representing the polling results is given below:

(ii) Political party ‘A’ won the maximum number of seats.

Q.4 The length of 40 leaves of a plant are measured correct to one millimeter, and the obtained data is represented in the following table:

Length (in mm) Number of leaves
118 – 126

127 – 135

136 – 144

145 – 153

154 – 162

163 – 171

172 – 180

3

5

9

12

5

4

2

(i) Draw a histogram to represent the given data. (ii) Is there any other suitable graphical representation for the same data?
(iii) Is it correct to conclude that the maximum numbers of leaves are 153 mm long? Why?

 

 

 

 

 

 

 

Ans

(i) Difference of upper limit of 118 – 126 and lower limit of

127 – 135 = 127 – 16
= 1
Half of the difference = (1/2)
= 0.5

New class interval formed from 118 – 126 is
(118 – 0.5) – (126 + 0.5) i.e., 117.5 – 126.5.
New class interval formed from 127 – 135 is
(127 – 0.5) – (135 + 0.5) i.e., 126.5 – 135.5.
In the same manner, new table with new class interval is given below:

Length (in mm) Number of leaves
117.5 – 126.5

126.5 – 135.5

135.5 – 144.5

144.5 – 153.5

153.5 – 162.5

162.5 – 171.5

171.5 – 180.5

3

5

9

12

5

4

2

Total 40


(ii) Frequency polygon is other suitable graphical representation for the same data.
(iii) No, it is not correct to conclude that the maximum numbers of leaves are 153 mm long because upper limit of a class interval is not included in the interval.

 

Q.5 The following table gives the life times of 400 neon lamps:

Life time (in hours) Number of lamps
300 – 400

400 – 500

500 – 600

600 – 700

700 – 800

800 – 900

900 – 1000

14

56

60

86

74

62

48

(i) Represent the given information with the help of a histogram.

(ii) How many lamps have a life time of more than 700 hours?

 

 

 

 

 

 

 

Ans

(i) The given information is shown by histogram in the figure given below:

(ii) Number of lamps has a life time of more than 700 hours is 184(74+62+48).

Q.6 The following table gives the distribution of students of two sections according to the marks obtained by them:

Section A Section B
Marks Frequency Marks Frequency
0 – 10 3 0 – 10 5
10 – 20 9 10 – 20 19
20 – 30 17 20 – 30 15
30 – 40 12 30 – 40 10
40 – 50 9 40 – 50 1

Represent the marks of the students of both the sections on the same graph by two frequency polygons. From the two polygons compare the performance of the two sections.

 

 

 

 

 

Ans

Class mark=Lower class limit+Upper class limit2For class interval (010):Class mark=0+102=5For class interval (1020):Class mark=10+202=15


I
n this way, frequency table will be as given below:

Section A Section B
Marks Class Mark Frequency Marks Class Mark Frequency
0 – 10 5 3 0 – 10 5 5
10 – 20 15 9 10 – 20 15 19
20 – 30 25 17 20 – 30 25 15
30 – 40 35 12 30 – 40 35 10
40 – 50 45 9 40 – 50 45 1

The frequency polygons are drawn as given below:

Q.7 The runs scored by two teams A and B on the first 60 balls in a cricket match are given below:

Number of balls Team A Team B
1 – 6

7 – 12

13 – 18

19 – 24

25 – 30

31 – 36

37 – 42

43 – 48

49 – 54

55 – 60

2

1

8

9

4

5

6

10

6

2

5

6

2

10

5

6

3

4

8

10

Represent the data of both the teams on the same graph by frequency polygons.

Ans

Difference of upper limit of 1 – 6 and lower limit of 7 – 12 = 7 – 6 = 1
Half of the difference = (1/2) = 0.5

New class interval formed from 1 – 6 is
(1 – 0.5) – (6 + 0.5) i.e., 0.5 – 6.5.
New class interval formed from 7 – 12 is
(7 – 0.5) – (12 + 0.5) i.e., 6.5 – 12.5.
In the same manner, new table with new class interval is given below:

Number of balls Midpoint Team A Team B
0.5 – 6.5 3.5 2 5
6.5 – 12.5 9.5 1 6
12.5 – 18.5 15.5 8 2
18.5 – 24.5 21.5 9 10
24.5 – 30.5 27.5 4 5
30.5 – 36.5 33.5 5 6
36.5 – 42.5 39.5 6 3
42.5 – 48.5 45.5 10 4
48.5 – 54.5 51.5 6 8
54.5 – 60.5 57.5 2 1

Polygons for both teams are shown in the following graphs:

Q.8 A random survey of the number of children of various age groups playing in a park was found as follows:

Age (in years) Number of children
1 – 2

2 – 3

3 – 5

5 – 7

7 – 10

10 – 15

15 – 17

5

3

6

12

9

10

4

Draw a histogram to represent the data above.

Ans

The modified frequency table is given below:

Age (in years) Number of children Width of interval Length of rectangle
1 – 2 5 1 5 1 ×1=5 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKfMBHbqedmvETj2BSbqefm0B1jxALjhiov2DaerbuLwBLnhiov2DGi1BTfMBaebbnrfifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8frFve9Fve9Ff0dmeaabaqaaiaacaGaaeqabaWaaqaafaaakeaadaWcaaqaaiaaiwdaaeaacaaIXaaaaiaaysW7cqGHxdaTcaaMe8UaaGymaiaaysW7cqGH9aqpcaaMe8UaaGynaaaa@451E@
2 – 3 3 1 3 1 ×1=3 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKfMBHbqedmvETj2BSbqefm0B1jxALjhiov2DaerbuLwBLnhiov2DGi1BTfMBaebbnrfifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8frFve9Fve9Ff0dmeaabaqaaiaacaGaaeqabaWaaqaafaaakeaadaWcaaqaaiaaiodaaeaacaaIXaaaaiaaysW7cqGHxdaTcaaMe8UaaGymaiaaysW7cqGH9aqpcaaMe8UaaG4maaaa@451A@
3 – 5 6 2 6 2 ×1=3 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKfMBHbqedmvETj2BSbqefm0B1jxALjhiov2DaerbuLwBLnhiov2DGi1BTfMBaebbnrfifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8frFve9Fve9Ff0dmeaabaqaaiaacaGaaeqabaWaaqaafaaakeaadaWcaaqaaiaaiAdaaeaacaaIYaaaaiaaysW7cqGHxdaTcaaMe8UaaGymaiaaysW7cqGH9aqpcaaMe8UaaG4maaaa@451E@
5 – 7 12 2 12 2 ×1=6 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKfMBHbqedmvETj2BSbqefm0B1jxALjhiov2DaerbuLwBLnhiov2DGi1BTfMBaebbnrfifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8frFve9Fve9Ff0dmeaabaqaaiaacaGaaeqabaWaaqaafaaakeaadaWcaaqaaiaaigdacaaIYaaabaGaaGOmaaaacaaMe8Uaey41aqRaaGjbVlaaigdacaaMe8Uaeyypa0JaaGjbVlaaiAdaaaa@45D8@
7 – 10 9 3 9 3 ×1=3 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKfMBHbqedmvETj2BSbqefm0B1jxALjhiov2DaerbuLwBLnhiov2DGi1BTfMBaebbnrfifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8frFve9Fve9Ff0dmeaabaqaaiaacaGaaeqabaWaaqaafaaakeaadaWcaaqaaiaaiMdaaeaacaaIZaaaaiaaysW7cqGHxdaTcaaMe8UaaGymaiaaysW7cqGH9aqpcaaMe8UaaiOlaiaaiodaaaa@45D4@
10 – 15 10 5 10 5 ×1=2 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKfMBHbqedmvETj2BSbqefm0B1jxALjhiov2DaerbuLwBLnhiov2DGi1BTfMBaebbnrfifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8frFve9Fve9Ff0dmeaabaqaaiaacaGaaeqabaWaaqaafaaakeaadaWcaaqaaiaaigdacaaIWaaabaGaaGynaaaacaaMe8Uaey41aqRaaGjbVlaaigdacaaMe8Uaeyypa0JaaGjbVlaaikdaaaa@45D5@
15 – 17 4 2 4 2 ×1=2 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKfMBHbqedmvETj2BSbqefm0B1jxALjhiov2DaerbuLwBLnhiov2DGi1BTfMBaebbnrfifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8frFve9Fve9Ff0dmeaabaqaaiaacaGaaeqabaWaaqaafaaakeaadaWcaaqaaiaaisdaaeaacaaIYaaaaiaaysW7cqGHxdaTcaaMe8UaaGymaiaaysW7cqGH9aqpcaaMe8UaaGOmaaaa@451B@

The histogram based on the above data is given below:

Q.9 100 surnames were randomly picked up from a local telephone directory and a frequency distribution of the number of letters in the English alphabet in the surnames was found as follows:

Number of letters Number of surnames
1 – 4

4 – 6

6 – 8

8 – 12

12 – 20

6

30

44

16

4

(i) Draw a histogram to depict the given information.

(ii) Write the class interval in which the maximum number of surnames lie.

Ans

(i) The modified frequency table is given below:

Number of letters Number of surnames Width of interval Length of rectangle
1 – 4 6 3 6 3 ×2=4 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKfMBHbqedmvETj2BSbqefm0B1jxALjhiov2DaerbuLwBLnhiov2DGi1BTfMBaebbnrfifHhDYfgasaacH8MrFz0xbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8frFve9Fve9Ff0dmeaabaqaaiaacaGaaeqabaWaaqaafaaakeaadaWcaaqaaiaaiAdaaeaacaaIZaaaaiabgEna0kaaikdacqGH9aqpcaaI0aaaaa@3F30@
4 – 6 30 2 30 2 ×2=30 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKfMBHbqedmvETj2BSbqefm0B1jxALjhiov2DaerbuLwBLnhiov2DGi1BTfMBaebbnrfifHhDYfgasaacH8MrFz0xbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8frFve9Fve9Ff0dmeaabaqaaiaacaGaaeqabaWaaqaafaaakeaadaWcaaqaaiaaiodacaaIWaaabaGaaGOmaaaacqGHxdaTcaaIYaGaeyypa0JaaG4maiaaicdaaaa@409F@
6 – 8 44 2 44 2 ×2=44 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKfMBHbqedmvETj2BSbqefm0B1jxALjhiov2DaerbuLwBLnhiov2DGi1BTfMBaebbnrfifHhDYfgasaacH8MrFz0xbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8frFve9Fve9Ff0dmeaabaqaaiaacaGaaeqabaWaaqaafaaakeaadaWcaaqaaiaaisdacaaI0aaabaGaaGOmaaaacqGHxdaTcaaIYaGaeyypa0JaaGinaiaaisdaaaa@40A9@
8 – 12 16 4 16 4 ×2=8 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKfMBHbqedmvETj2BSbqefm0B1jxALjhiov2DaerbuLwBLnhiov2DGi1BTfMBaebbnrfifHhDYfgasaacH8MrFz0xbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8frFve9Fve9Ff0dmeaabaqaaiaacaGaaeqabaWaaqaafaaakeaadaWcaaqaaiaaigdacaaI2aaabaGaaGinaaaacqGHxdaTcaaIYaGaeyypa0JaaGioaaaa@3FF0@
12 – 20 4 8 4 8 ×2=1 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKfMBHbqedmvETj2BSbqefm0B1jxALjhiov2DaerbuLwBLnhiov2DGi1BTfMBaebbnrfifHhDYfgasaacH8MrFz0xbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8frFve9Fve9Ff0dmeaabaqaaiaacaGaaeqabaWaaqaafaaakeaadaWcaaqaaiaaisdaaeaacaaI4aaaaiabgEna0kaaikdacqGH9aqpcaaIXaaaaa@3F30@

The histogram of given data is given below:

(ii) Maximum number of surnames is in interval 6 – 8.

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1. Are the NCERT Solutions for Class 9 Maths Chapter 14 Exercise 14.3 available in Hindi?

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