NCERT Solutions for Class 9 Maths Ganit Manjari Chapter 4 Exercise 4.2

The NCERT Solutions for Class 9 Maths Ganit Manjari Chapter 4 Exercise 4.2 – Exploring Algebraic Identities provide clear, step-by-step solutions to all the questions in the exercise.

These solutions help students understand algebraic identities, learn their applications, and develop better problem-solving skills. A printable PDF of the solutions is also provided for easy revision and offline practice.

NCERT Solutions for Class 9 Maths Chapter 4 Exercise 4.2

NCERT Solutions for Class 9 Maths Chapter 4 Exercise Set 4.2

Exercise Set 4.2 focuses on factorisation using the identities (a + b)² = a² + 2ab + b² and (a - b)² = a² - 2ab + b².

Question 1. Factor completely.

(i) 9x² + 24xy + 16y²

Answer:
9x² = (3x)²
16y² = (4y)²
24xy = 2(3x)(4y)

So:

9x² + 24xy + 16y² = (3x + 4y)²

Final answer:
(3x + 4y)²

(ii) 4s² + 20st + 25t²

Answer:
4s² = (2s)²
25t² = (5t)²
20st = 2(2s)(5t)

So:

4s² + 20st + 25t² = (2s + 5t)²

Final answer:
(2s + 5t)²

(iii) 49x² + 28xy + 4y²

Answer:
49x² = (7x)²
4y² = (2y)²
28xy = 2(7x)(2y)

So:

49x² + 28xy + 4y² = (7x + 2y)²

Final answer:
(7x + 2y)²

(iv) 64p² + 32pq/3 + 4q²/9

Answer:
64p² = (8p)²
4q²/9 = (2q/3)²
32pq/3 = 2(8p)(2q/3)

So:

64p² + 32pq/3 + 4q²/9 = (8p + 2q/3)²

Final answer:
(8p + 2q/3)²

(v) 3a² + 4ab + 4b²/3

Answer:
Take 1/3 common:

3a² + 4ab + 4b²/3
= 1/3(9a² + 12ab + 4b²)

Now:

9a² = (3a)²
4b² = (2b)²
12ab = 2(3a)(2b)

So:

1/3(9a² + 12ab + 4b²)
= 1/3(3a + 2b)²

Final answer:
(3a + 2b)²/3

(vi) 9s²/5 + 6sv + 5v²

Answer:
Take 1/5 common:

9s²/5 + 6sv + 5v²
= 1/5(9s² + 30sv + 25v²)

Now:

9s² = (3s)²
25v² = (5v)²
30sv = 2(3s)(5v)

So:

1/5(9s² + 30sv + 25v²)
= 1/5(3s + 5v)²

Final answer:
(3s + 5v)²/5

Question 2. Find the values using the identity (a - b)² = a² - 2ab + b².

(i) 79²

Answer:
79 = 80 - 1

79² = (80 - 1)²
= 80² - 2(80)(1) + 1²
= 6400 - 160 + 1
= 6241

Final answer:
6241

(ii) 193²

Answer:
193 = 200 - 7

193² = (200 - 7)²
= 200² - 2(200)(7) + 7²
= 40000 - 2800 + 49
= 37249

Final answer:
37249

(iii) 299²

Answer:
299 = 300 - 1

299² = (300 - 1)²
= 300² - 2(300)(1) + 1²
= 90000 - 600 + 1
= 89401

Final answer:
89401

NCERT Solutions for Class 9 Maths Chapter 4 - Related Links