NCERT Solutions for Class 6 Maths Chapter 8 Decimals (Ex 8.4) Exercise 8.4
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NCERT Solutions for Class 6 Maths Chapter 8 Decimals (Ex 8.4) Exercise 8.4
Class 6 marks the beginning of secondary education under the Central Board of Secondary Education (CBSE). Students are required to learn a variety of new subjects in their secondary classes. In Class 6, students are required to study some new subjects such as Social Science, Science, etc. Studying various subjects together and understanding the concepts in them can be very challenging for students in Class 6. One of the most crucial and difficult subjects for many students in Class 6 is Maths. Students need to study all the topics in Maths, focusing on every small detail, to do well in their examinations. One of the most helpful resources for studying Maths in Class 6 is the NCERT textbook. Often, numerous questions are found in the examinations from the NCERT textbook. Students should study each and every chapter from the NCERT book, as all of them are important for the examinations. As the NCERT book includes all the concepts according to the CBSE syllabus, it will be helpful for students to complete all the topics according to the CBSE syllabus and hence score high marks.
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ToggleThe Maths NCERT book for Class 6 includes a number of crucial chapters, such as Algebra, Mensuration, Integers, Fractions, etc. One of the most important of these chapters is the one on Decimals. Chapter 8 on Decimals covers a variety of important topics such as, Fractions as Decimals, Decimals as Fractions, Comparing Decimals, and so on. Students should not ignore any topic in the chapter because they are very useful not only for exams but also for future studies. It is also vital to practise the NCERT exercises, as these act as the source of numerous questions in exams. NCERT Class 6 Maths Chapter 8 Exercise 8.4 is one of the most important exercises in the chapter because it includes questions that apply the chapter’s previously learned concepts. Class 6th Math Exercise 8.4 is on the topic of using Decimals. The questions in Class 6th Maths Chapter 8 Exercise 8.4 are applicationbased questions that apply the concepts of decimals in reallife situations. There are questions based on Money, Length, etc. Some of these questions are too complex for students to understand. It is essential that students try to solve these questions on their own. However, it is not an easy task to solve all the questions when attempting them for the first time. Hence, students should have some helpful resources that can help them solve these questions easily as well as save their crucial time. To help students solve these questions easily, Extramarks provides NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4.
The NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4 on Extramarks, can help students in a number of ways. Students are assisted in answering difficult problems by following the thorough, stepbystep solutions offered in the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4. Complex questions must be made simpler in order to be solved. The solution to this issue can be found in the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4. Students’ grasp of the most difficult subject improves when they use the NCERT textbook. By comparing their answers to the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4, students will be able to assess their performance and progress. Extramarks offers thorough and genuine solutions for every NCERT exercise question in addition to the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4. Even though these solutions are offered on many different platforms, their accuracy is still in doubt. The importance of Maths necessitates that students employ reliable study materials. Experts have confirmed the legitimacy of the study resources that Extramarks provides. Simple language is used to describe the comprehensive NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4. The proper format for answering questions is taught to the students. They offer the most effective and simple techniques for resolving problems on the topic – Decimals.
Access Other Exercises of Class 6 Maths Chapter 8
Chapter 8 – Decimals Exercises  
Exercise 8.1 
10 Questions & Solutions

Exercise 8.2 
7 Questions & Solutions

Exercise 8.3 
2 Questions & Solutions

Exercise 8.5 
7 Questions & Solutions

Exercise 8.6 
7 Questions & Solutions

NCERT Solutions for Class 6 Maths Chapter 8 Decimals (Ex 8.4) Exercise 8.4
Even if NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4 are available online, having regular access to them is usually preferred. If they have offline access, students can learn whenever and wherever they choose to. The NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4 are available on Extramarks for students to use whenever they want to learn. Unexpected network issues and poor internet connectivity will therefore no longer be an impediment to learning. The expertcurated NCERT solutions provide a chance for learning and exam practise by covering all the problems in the textbook. Students can access the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4 in PDF format from the Extramarks website and mobile application for quick test preparation.
Access NCERT Class 6 Maths Chapter 8 Decimals
Students have access to a wide range of questions and wellwritten solutions to prepare for exams. The majority of question banks use NCERT textbook problems as the basis for their content. When students have access to the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4, answering questions is a lot easier. As a result, they can understand the concepts better. Students are better positioned for any exam when they can acquire new material quickly and efficiently. They have more study time and can concentrate on other learning goals. By understanding the concepts presented in the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4, students can advance in their preparation. The NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4, are hence available in PDF format on Extramarks.
NCERT Solutions for Class 6 Maths, Chapter 8: Decimals, Exercise 8.4
For students in Class 6, finding the ideal resource to meet their learning objectives might be difficult. Their educational requirements are suitably and successfully met by NCERT solutions. NCERT solutions satisfy the exam preparation needs of students. The CBSE’s endorsement of the NCERT textbook is an additional benefit. The NCERT textbooks are a necessary part of the CBSE curriculum. The textbooks contain many unique and challenging questions. These questions typically confuse students, which makes them feel less confident in the topic and the chapter. Starting with a solid understanding of the principles is crucial. When solving the questions in the NCERT textbooks, students who have access to the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4, will greatly profit from having a firm grasp of both theoretical and practical concepts. Students will have a firm conceptual understanding of the chapter by the time they are done. They can assess their own performance and make the necessary corrections by evaluating their responses with the use of the solutions. Students who have access to the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4 can assess their current understanding of the chapter and identify their specific strong and weak points. Additionally, the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4, support students in developing a wide range of skills, including logical and reasoning skills, while also helping in reviewing and analysing the knowledge that they have already attained. Besides, the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4 assist students in making an efficient and successful exam preparation. As a result, it is considered to be a crucial component of exam preparation.
Exercise 8.4 Maths, Class 6 includes five questions. On the Extramarks website, students can find the answers to each question. Also, students can use a variety of examples from the book to help them answer the questions in the exercises. Students can learn different approaches to solving questions by completing all of these problems. Students should finish all the questions in order to fully understand this chapter and get better grades. NCERT exercises are the most important source for reviewing questions for the CBSE Class 6 exams. Students are therefore constantly encouraged to answer the NCERT textbook’s exercise questions. They also need accurate answers to the questions in order to confirm the correctness of their answers. Therefore, when they prepare for their exams, students can obtain the help they need from the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4, provided by Extramarks. Students will be better able to apply the ideas from the chapter to each problem in the exercises by using the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4. These solutions are written by a number of exceptionally skilled teachers while maintaining correctness and removing errors. To achieve top scores in exams, students should carefully follow the directions in the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4.
The exercises in Chapter 8 of the NCERT Class 6 textbook contain a lot of important questions. There are a total of six exercises in this chapter. Each of these exercises is equally important for the Class 6 yearly exams. To see which chapters and topics are covered for Class 6, students should also check the most recent CBSE syllabus. Students who thoroughly complete all the topics will not only perform better on their Class 6 annual examinations, but they will also find it simpler to comprehend the ideas in their subsequent classes. Therefore, a full comprehension of the ideas in Class 6 can also support students’ academic progress in higher classes. NCERT solutions for other chapters are also available on Extramarks in addition to those for Class 6 Math Chapter 8.4.
The use of NCERTpublished textbooks is mandated by the CBSE. The most recent Class 6 syllabus from the CBSE must be followed when studying. Students should also format their answers in accordance with the CBSE grading rules if they want to receive the highest possible score. The NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4, have been written by teachers with considerable expertise in CBSE exams. They produce the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4, in accordance with the most recent CBSE recommendations. According to the most recent recommendations, the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4, are frequently revised and updated. Therefore, the latest curriculum revisions implemented by the CBSE are not something that students need to be concerned about. The NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4, are developed while taking into consideration the mathematical knowledge of Class 6 students. To make it easier to write answers to the questions in this lesson, the problems have been divided into smaller, more manageable chunks. Students are routinely advised by teachers to write thorough, stepbystep answers in exams to receive maximum marks. For the best outcomes, students should carefully follow the directions in the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4. Students are unable to use many of the methods given in the NCERT textbook to solve the exercises’ problems since they are difficult for them to comprehend and recall. However, it will be simpler for students to recall if they use the stepbystep solutions in the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.4.
Q.1 Express as rupees using decimals.
(a) 5 paise (b) 75 paise (c) 20 paise
(d) 50 rupees 90 paise (e) 725 paise
Ans.
$\begin{array}{l}\left(\mathbf{a}\right)\text{}\mathbf{5}\text{}\mathbf{paise}\\ \text{We know that 1}00\text{paise}=\text{1}\\ \Rightarrow \text{1 paise}=\xe2\u201a\xb9\frac{1}{100}\text{}\\ \Rightarrow 5\text{}\mathrm{paise}=\xe2\u201a\xb9\frac{5}{100}\text{\hspace{0.17em}}\\ =\text{\xe2\u20ac\u2039}\xe2\u201a\xb9\text{}0.05\text{}\\ \end{array}$
$\begin{array}{l}\left(\mathbf{b}\right)\text{}\mathbf{75}\text{}\mathbf{paise}\\ \text{We know that 1}00\text{paise}=\xe2\u201a\xb9\text{1}\\ \Rightarrow \text{1 paise}=\xe2\u201a\xb9\frac{1}{100}\text{}\\ \Rightarrow 75\text{}\mathrm{paise}=\xe2\u201a\xb9\frac{75}{100}\text{\hspace{0.17em}}\\ =\text{\xe2\u20ac\u2039}\xe2\u201a\xb9\text{}0.75\text{}\\ \\ \left(\mathbf{c}\right)\text{}\mathbf{20}\text{}\mathbf{paise}\\ \text{We know that 1}00\text{paise}=\xe2\u201a\xb9\text{1}\\ \Rightarrow \text{1 paise}=\xe2\u201a\xb9\frac{1}{100}\text{}\\ \Rightarrow 20\text{}\mathrm{paise}=\xe2\u201a\xb9\frac{20}{100}\text{\hspace{0.17em}}\\ =\text{\xe2\u20ac\u2039}\xe2\u201a\xb9\text{}0.20\\ \text{}\\ \left(\mathbf{d}\right)\text{}\mathbf{50}\text{}\xe2\u201a\xb9\text{}\mathbf{90}\text{}\mathbf{paise}\\ \text{We know that 1}00\text{paise}=\xe2\u201a\xb9\text{1}\\ \Rightarrow \text{1 paise}=\xe2\u201a\xb9\frac{1}{100}\text{}\\ \Rightarrow 90\text{}\mathrm{paise}=\xe2\u201a\xb9\frac{90}{100}\text{\hspace{0.17em}}\\ =\text{\xe2\u20ac\u2039}\xe2\u201a\xb9\text{}0.90\\ \\ \text{}\mathrm{}\therefore 50\xe2\u201a\xb990\mathrm{paise}=50\xe2\u201a\xb9+\text{}\xe2\u201a\xb9\text{}0.90\\ =\text{\hspace{0.17em}}\xe2\u201a\xb9\text{}50.90\end{array}$
$\begin{array}{l}\left(\mathbf{e}\right)\text{}\mathbf{725}\text{}\mathbf{paise}\\ \text{We know that 1}00\text{paise}=\xe2\u201a\xb9\text{1}\\ \Rightarrow \text{1 paise}=\xe2\u201a\xb9\frac{1}{100}\text{}\\ \Rightarrow 725\text{}\mathrm{paise}=\xe2\u201a\xb9\frac{725}{100}\text{\hspace{0.17em}}\\ =\text{\xe2\u20ac\u2039}\xe2\u201a\xb9\text{}7.25\\ \end{array}$
Q.2 Express as metres using decimals.
(a) 15 cm
(b) 6 cm
(c) 2 m 45 cm
(d) 9 m 7 cm
(e) 419 cm
Ans.
$\begin{array}{l}\left(\mathrm{a}\right)\text{}15\text{}\mathrm{cm}\\ \text{We know that 1}00\text{cm}=\text{1}\mathrm{m}\\ \Rightarrow \text{1 cm}=\frac{1}{100}\text{}\mathrm{m}\\ \Rightarrow 15\text{\hspace{0.17em}cm}=\frac{15}{100}\text{\hspace{0.17em}}\mathrm{m}\\ =\text{\xe2\u20ac\u2039}0.15\text{m}\\ \\ \left(\mathrm{b}\right)\text{}6\text{}\mathrm{cm}\text{}\\ \text{We know that 1}00\text{cm}=\text{1}\mathrm{m}\\ \Rightarrow \text{1 cm}=\frac{1}{100}\text{}\mathrm{m}\\ \Rightarrow 6\text{\hspace{0.17em}cm}=\frac{6}{100}\text{\hspace{0.17em}}\mathrm{m}\\ =\text{\xe2\u20ac\u2039}0.06\text{m}\\ \\ \left(\mathrm{c}\right)\text{}2\text{}\mathrm{m}\text{}45\text{}\mathrm{cm}\\ \text{We know that 1}00\text{cm}=\text{1}\mathrm{m}\\ \Rightarrow \text{1 cm}=\frac{1}{100}\text{}\mathrm{m}\\ \Rightarrow 45\text{\hspace{0.17em}cm}=\frac{45}{100}\text{\hspace{0.17em}}\mathrm{m}\\ =\text{\xe2\u20ac\u2039}0.45\text{m}\\ \\ \text{Now,}2\text{}\mathrm{m}\text{}45\text{}\mathrm{cm}=2\text{\hspace{0.17em}}\mathrm{m}+0.45\text{m}\\ =2.45\text{\hspace{0.17em}}\mathrm{m}\\ \text{}\\ \left(\mathrm{d}\right)\text{}9\text{}\mathrm{m}\text{}7\text{}\mathrm{cm}\\ \text{We know that 1}00\text{cm}=\text{1}\mathrm{m}\\ \Rightarrow \text{1 cm}=\frac{1}{100}\text{}\mathrm{m}\\ \Rightarrow 7\text{\hspace{0.17em}cm}=\frac{7}{100}\text{\hspace{0.17em}}\mathrm{m}\\ =\text{\xe2\u20ac\u2039}0.07\text{m}\\ \\ \text{Now,}9\text{}\mathrm{m}\text{}7\text{}\mathrm{cm}=9\text{\hspace{0.17em}}\mathrm{m}+0.07\text{m}\\ =9.07\text{\hspace{0.17em}}\mathrm{m}\text{}\\ \\ \left(\mathrm{e}\right)\text{}419\text{}\mathrm{cm}\\ \text{We know that 1}00\text{cm}=\text{1}\mathrm{m}\\ \Rightarrow \text{1 cm}=\frac{1}{100}\text{}\mathrm{m}\\ \Rightarrow 419\text{\hspace{0.17em}cm}=\frac{419}{100}\text{\hspace{0.17em}}\mathrm{m}\\ =\text{\xe2\u20ac\u2039}4.19\text{m}\end{array}$
Q.3 Express as cm using decimals.
(a) 5 mm
(b) 60 mm
(c) 164 mm
(d) 9 cm 8 mm
(e) 93 mm
Ans.
$\begin{array}{l}\left(\mathrm{a}\right)\text{}5\text{m}\mathrm{m}\\ \text{We know that 1}0\text{mm}=\text{1}\mathrm{cm}\\ \Rightarrow \text{1 mm}=\frac{1}{10}\text{c}\mathrm{m}\\ \Rightarrow 5\text{mm}=\frac{5}{10}\text{\hspace{0.17em}}\mathrm{cm}\\ =\text{\xe2\u20ac\u2039}0.5\text{cm}\\ \\ \left(\text{b}\right)\text{60 mm}\\ \text{We know that 1}0\text{mm}=\text{1}\mathrm{cm}\\ \Rightarrow \text{1 mm}=\frac{1}{10}\text{c}\mathrm{m}\\ \Rightarrow 60\text{mm}=\frac{60}{10}\text{\hspace{0.17em}}\mathrm{cm}\\ =\text{\xe2\u20ac\u2039}6\text{cm or 6.0 cm}\\ \\ \left(\text{c}\right)\text{164 mm}\\ \text{We know that 1}0\text{mm}=\text{1}\mathrm{cm}\\ \Rightarrow \text{1 mm}=\frac{1}{10}\text{c}\mathrm{m}\\ \Rightarrow 164\text{mm}=\frac{164}{10}\text{\hspace{0.17em}}\mathrm{cm}\\ =\text{\xe2\u20ac\u2039}16.4\text{cm}\\ \\ \left(\text{d}\right)\text{9 cm 8 mm}\\ \text{We know that 1}0\text{mm}=\text{1}\mathrm{cm}\\ \Rightarrow \text{1 mm}=\frac{1}{10}\text{c}\mathrm{m}\\ \Rightarrow 8\text{mm}=\frac{8}{10}\text{\hspace{0.17em}}\mathrm{cm}\\ =\text{\xe2\u20ac\u2039}0.8\text{cm}\\ \mathrm{Now},\text{9 cm 8 mm =}\left(\text{9 + 0.8}\right)\text{cm}\\ \text{= 9.8 cm}\\ \\ \left(\text{e}\right)\text{93 mm}\\ \text{We know that 1}0\text{mm}=\text{1}\mathrm{cm}\\ \Rightarrow \text{1 mm}=\frac{1}{10}\text{c}\mathrm{m}\\ \Rightarrow 93\text{mm}=\frac{93}{10}\text{\hspace{0.17em}}\mathrm{cm}\\ =\text{\xe2\u20ac\u2039}9.3\text{cm}\\ \text{}\end{array}$
Q.4 Express as km using decimals.
(a) 8 m
(b) 88 m
(c) 8888 m
(d) 70 km 5 m
Ans.
$\begin{array}{l}\left(\text{a}\right)\text{8 m}\\ \text{We know that 1}000\text{m}=\text{1}\mathrm{km}\\ \Rightarrow \text{1 m}=\frac{1}{1000}\text{k}\mathrm{m}\\ \Rightarrow 8\text{m}=\frac{8}{1000}\text{\hspace{0.17em}}\mathrm{km}\\ =\text{\xe2\u20ac\u2039}0.008\text{km}\\ \\ \left(\text{b}\right)\text{88 m}\\ \text{We know that 1}000\text{m}=\text{1}\mathrm{km}\\ \Rightarrow \text{1 m}=\frac{1}{1000}\text{k}\mathrm{m}\\ \Rightarrow 88\text{m}=\frac{88}{1000}\text{\hspace{0.17em}}\mathrm{km}\\ =\text{\xe2\u20ac\u2039}0.088\text{km}\\ \text{}\\ \left(\text{c}\right)\text{8888 m}\\ \text{We know that 1}000\text{m}=\text{1}\mathrm{km}\\ \Rightarrow \text{1 m}=\frac{1}{1000}\text{k}\mathrm{m}\\ \Rightarrow 8888\text{m}=\frac{8888}{1000}\mathrm{km}\\ =\text{\xe2\u20ac\u2039 8.8}88\text{km}\\ \\ \left(\text{d}\right)\text{70 km 5 m}\\ \text{We know that 1}000\text{m}=\text{1}\mathrm{km}\\ \Rightarrow \text{1 m}=\frac{1}{1000}\text{k}\mathrm{m}\\ \Rightarrow 5\text{m}=\frac{5}{1000}\text{\hspace{0.17em}}\mathrm{km}\\ =\text{\xe2\u20ac\u2039}0.005\text{km}\\ \text{Now, 70 km 5 m=}\left(\text{70 + 0.005}\right)\mathrm{km}\\ =70.005\mathrm{km}\end{array}$
Q.5 Express as kg using decimals.
(a) 2 g
(b) 100 g
(c) 3750 g
(d) 5 kg 8 g
(e) 26 kg 50 g
Ans.
\begin{array}{l}\left(\text{a}\right)\text{2 g}\\ \\ \text{We know that 1}000\text{g}=\text{1}kg\\ \Rightarrow \text{1 g}=\frac{1}{1000}\text{k}g\\ \Rightarrow 2\text{g}=\frac{2}{1000}\text{\hspace{0.17em}}kg\\ =\text{\xe2\u20ac\u2039}\text{}0.002\text{kg}\\ \\ \left(\text{b}\right)\text{100 g}\\ \text{We know that 1}000\text{g}=\text{1}kg\\ \Rightarrow \text{1 g}=\frac{1}{1000}\text{k}g\\ \Rightarrow 100\text{g}=\frac{100}{1000}\text{\hspace{0.17em}}kg\\ =\text{\xe2\u20ac\u2039}\text{}0.1\text{kg}\\ \text{}\\ \left(\text{c}\right)\text{3750 g}\\ \text{We know that 1}000\text{g}=\text{1}kg\\ \Rightarrow \text{1 g}=\frac{1}{1000}\text{k}g\\ \Rightarrow 3750\text{g}=\frac{3750}{1000}\text{\hspace{0.17em}}kg\\ =\text{\xe2\u20ac\u2039}\text{3}\text{.750 kg}\\ \\ \left(\text{d}\right)\text{5 kg 8 g}\\ \text{We know that 1}000\text{g}=\text{1}kg\\ \Rightarrow \text{1 g}=\frac{1}{1000}\text{k}g\\ \Rightarrow 8\text{g}=\frac{8}{1000}\text{\hspace{0.17em}}kg\\ =\text{\xe2\u20ac\u2039}\text{0}\text{.008 kg}\\ \text{Now, 5 kg 8 g=}\left(\text{5 + 0}\text{.008}\right)kg\\ =5.008\text{}kg\\ \\ \left(\text{e}\right)\text{26 kg 50 g}\\ \text{We know that 1}000\text{g}=\text{1}kg\\ \Rightarrow \text{1 g}=\frac{1}{1000}\text{k}g\\ \Rightarrow 50\text{g}=\frac{50}{1000}\text{\hspace{0.17em}}kg\\ =\text{\xe2\u20ac\u2039}\text{}0.05\text{kg}\\ \text{Now, 26 kg 50 g =}\left(\text{26 + 0}\text{.05}\right)kg\\ =26.05\text{}kg\end{array}
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FAQs (Frequently Asked Questions)
1. Where can Class 6 students obtain NCERT Solutions Class 6 Maths Chapter 8 Exercise 8.4?
The Extramarks website and mobile application both provide access to the NCERT Solutions Class 6 Maths Chapter 8 Exercise 8.4. Students can access the solutions online and download them in PDF format. The PDF file is available on the Extramarks website to assist students in referring to the solutions whenever and wherever they wish without having to connect to the internet.
2. How should students use the NCERT Solutions Class 6 Maths Chapter 8 Exercise 8.4 when studying for exams?
Before beginning to solve Exercise 8.4, students should read the theory before the exercise from start to finish. They should then practice the NCERT examples after that. They will be able to learn several strategies for resolving the problems in this exercise. After completing the examples, they should attempt each of the exercise questions. They must attempt to solve the problems without utilising the NCERT Solutions Class 6 Maths Chapter 8 Exercise 8.4. As soon as they are finished, they can check their answers by referring to the solutions provided by Extramarks.
3. If students use the NCERT Solutions Class 6 Maths Chapter 8 Exercise 8.4, will they be able to complete the question paper in the allotted time in exams?
Students should continuously practice the NCERT textbook questions in order to complete the Maths question paper in the allotted time. Students’ writing speeds up as they repeatedly practice the questions from the NCERT book. Questions from the NCERT textbook are also included in the examinations. In order to finish the test question paper as fast as possible, students should refer to the NCERT Solutions Class 6 Maths Chapter 8 Exercise 8.4 and understand the various approaches to solving various questions.