NCERT Solutions for Class 6 Maths Chapter 8 Decimals (Ex 8.5) Exercise 8.5
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NCERT Solutions for Class 6 Maths Chapter 8 Decimals (Ex 8.5) Exercise 8.5
NCERT textbooks, which serve as the majority of the required reading for CBSE students, might aid in preparing students for future situations. As they broaden students’ foundational knowledge in a variety of ways, these books are a useful resource. The use of NCERT textbooks allows for the thorough development of fundamental knowledge in every subject. Reading the NCERT books carefully would help students comprehend the subjects in depth. This is advantageous in the long run because students who possess the required conceptual clarity may work through issues quickly and effectively. It will not be necessary to learn something if a student can understand it. For students’ fundamental knowledge, NCERT books are the primary source.
India’s largest educational body, in terms of overall enrollment, is the Central Board of Secondary Education (CBSE). It is a nationallevel body that has several public and private schools as members. The Government of India created the CBSE before independence to offer secondary education to kids all over the nation. The board underwent reorganisation in 1962 to help students who had to move from one state to another with their educational requirements. Thousands of schools all around the country are affiliated with the CBSE. In addition, the board has affiliations with a number of schools abroad. Regional offices are spread out over the nation, and the main office is in New Delhi.
A few specific questions and phrases are tweaked to evaluate the student’s comprehension. They can use the NCERT Solutions for Class 6 Maths Chapter 8 Exercise 8.5 if they need assistance. Students preparing for competitive exams can access the Hindi translation of the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5. Students in Class 6 should start preparing for Class 11 if they intend to take the Science stream. As a result, they are taught to maintain a laserlike focus on all they are learning and remembering. It is essential for students to fully understand the study material if they want to perform well in their examinations.
Despite the fact that Maths may appear to be a challenging academic subject, students should be aware that, throughout the course of centuries, eminent Mathematicians from all over the world have made significant contributions to it. The NCERT series of books is prepared and organised according to the academic chronological years and with a grasp of what children’s minds can comprehend at various ages. These NCERT textbooks are designed to support students’ intellectual growth. To assist students in their academic endeavours while considering the structure of NCERT books, the Extramarks online learning platform has developed NCERT Solutions. In addition to other disciplines, Maths has been applied in Physics, Chemistry, Economics, and Engineering. Many of these fields have mathematical principles that must be understood. Students can also refer to NCERT Solutions Class 6 Maths Chapter 8 Exercise 8.1 for access to the Exercise 8.1 solutions.
Although it is sometimes taught in integrated courses in some other curricula, Maths is also taught as an “instrumental subject” to help students learn other academic disciplines. The NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5, are crucial for the kids’ overall growth.
For individuals who desire to participate in competitions after graduating from Class 10 or Class 12, the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5 is crucial. NCERT textbooks provide students with detailed displays of their understanding, so they may react to any questions on either their board examination or annual exams. To ensure that students have no difficulties answering questions, Extramarks focuses on the NCERT books while also offering answers to a variety of other publications. The NCERT books meet all requirements for the CBSE. NCERT is another name for the National Council of Educational Research and Training. When using Extramarks as a learning tool, students should make an effort to answer all of the questions in the NCERT textbooks and more.
Access Other Exercises of Class 6 Maths Chapter 8
Chapter 8 – Decimals Exercises  
Exercise 8.1 
10 Questions & Solutions

Exercise 8.2 
7 Questions & Solutions

Exercise 8.3 
2 Questions & Solutions

Exercise 8.4 
5 Questions & Solutions

Exercise 8.6 
7 Questions & Solutions

NCERT Solutions for Class 6 Maths, Chapter 8: Decimals (Ex 8.5) Exercise 8.5
For CBSE Class 6 students to access and study the solutions even when they are not connected to the internet, the Extramarks website or mobile app makes it possible to download the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5. They must finish NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5, in order to comprehend the problems better.
As the NCERT books’ content is so extensive and indepth on its own, CBSE rarely adds questions beyond them. These disciplines aim to enhance classroom education in addition to being necessary for exams. The book’s advice on the best coping strategies for tough situations and selfevaluation tasks may be helpful to students. NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5 might help students understand the procedure better.
The fundamental aim of Extramarks is to assist students in creating better futures. It has always helped students discover solutions by bringing forward issues. Students should review NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5 multiple times to make sure they fully comprehend the exercise so they can react to issues of the same kind in their yearly exams. Questions from the NCERT textbook are frequently included in exams. NCERT texts fully abide by all CBSE criteria. The leading management and research organisation in the country is NCERT. It is crucial to inform CBSE Board students that by simply studying the NCERT books, they can attain excellent results in their CBSE examinations.
When answering any inquiry, students must pay attention. They are instructed to establish and follow a schedule. They require a schedule so they can devote enough time to each session and attempt to comprehend the fundamental concepts of each issue. The NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5, have been released by Extramarks in an approachable and clear manner. Students will comprehend the questions with ease owing to the simplified writing style used in the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5. Students must have access to Extramarks so they can use the program to quickly find any chapter’s solution.
Access NCERT Solutions for Class 6 Maths, Chapter 8 Decimals
Students can get the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5,. They can use this programme to take competitive exams like the Joint Entrance Exam (JEE) with relative ease if they so desire. This can be used by students who want to get a basic understanding before applying to the Indian Institutes of Technology (IITs) and National Institutes of Technology (NITs). The Central Universities Entrance Tests (CUET) and other competitive exams allow students to seek careers outside of Engineering. They would better understand the content if they studied NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5, because MCQs may be included in such examinations.
Due to a learning portal called Extramarks, students may readily locate NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5, PDF format, making them useful even when they are offline. The finest resource for teaching students is the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5. The majority of students find Class 6 difficult because the curriculum gets harder after that grade. However, as they advance from a basic to an intermediate level, some students occasionally struggle with making decisions to resolve such problems. Finding it on the Extramarks website and mobile application is simple because it is listed as NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5.
Using the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5 will help students understand the questions and learn how to apply the principles in them. Students cannot apply fundamental concepts to complex issues unless they have fully mastered and understood them. The exceedingly straightforward solutions in the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5, allow every learner to understand the topics. Students will benefit from having a comprehensive and clear understanding of a concept due to NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5.
Students should be aware of their career prospects after earning a Science degree. They can master the practice by consistently studying NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5, and will not be scared by the issues when they appear in their yearly exams. Those planning to do their Majors in Science should understand how their major will help them in the future. Students have regularly benefited from Extramarks’ assistance in avoiding problems, and the organisation is available to help them. Students may thoroughly understand the practise and get over their fear of the questions by repeatedly studying through NCERT Class 6 Maths Chapter 8 Exercise 8.5. When students appear for their yearly exams, this will be helpful.
NCERT Solutions for Class 6 Maths, Chapter 8: Decimals, Exercise 8.5
Important concepts like the addition of numbers with decimals are included in NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5, Decimals. By comprehending the students’ grasping abilities, subject matter specialists are able to find solutions to issues. Students can boost their examination confidence by practising problems from the required textbook using the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5.
Students will learn how to add two or more decimals with the aid of the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5 Decimals. Like whole numbers, decimals are added in the same way. Using the examples in the chapter, students will be able to envision adding decimals. Experts match the tenth and hundredth places of two numbers when adding decimals. A thorough explanation that is included with the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5, will help students review the earlier ideas before tackling the tasks.
In the NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5, the addition of decimals is demonstrated stepbystep in decimals. The same method used to add two whole numbers also applies to adding two decimal numbers. In this instance, though, students start by combining the two integers while accounting for the decimal point.
The goal of NCERT Solutions for Class 6 Maths, Chapter 8, Exercise 8.5 is to increase students’ selfassurance and spark their curiosity, which will improve their performance. Students can be encouraged to engage in numerous tasks involving the addition of decimals while working through this exercise.
Q.1 Find the sum in each of the following:
(a) 0.007 + 8.5 + 30.08
(b) 15 + 0.632 + 13.8
(c) 27.076 + 0.55 + 0.004
(d) 25.65 + 9.005 + 3.7
(e) 0.75 + 10.425 + 2
(f) 280.69 + 25.2 + 38
Ans.
\begin{array}{l}\left(\text{a}\right)\text{0}\text{.007 + 8}\text{.5 + 30}\text{.08}\\ \text{}\\ \text{0}\text{.007}\\ \text{8}\text{.500}\\ \text{}\underset{\xaf}{+\text{30}\text{.080}}\\ \text{\hspace{0.17em}}\text{}\underset{\xaf}{\text{}38.587\text{}}\\ \\ \left(\text{b}\right)\text{15 + 0}\text{.632 + 13}\text{.8}\\ \text{}\\ \text{15}\text{.000}\\ \text{0}\text{.632}\\ \text{}\underset{\xaf}{+\text{13}\text{.800}}\\ \text{\hspace{0.17em}}\text{}\underset{\xaf}{\text{}29.432\text{}}\\ \\ \left(\text{c}\right)\text{27}\text{.076 + 0}\text{.55 + 0}\text{.004}\\ \text{}\\ \text{27}\text{.076}\\ \text{0}\text{.550}\\ \text{}\underset{\xaf}{+\text{0}\text{.004}}\\ \text{\hspace{0.17em}}\text{}\underset{\xaf}{\text{}27.630\text{}}\\ \\ \left(\text{d}\right)\text{25}\text{.65 + 9}\text{.005 + 3}\text{.7}\\ \text{}\\ \text{25}\text{.650}\\ \text{9}\text{.005}\\ \text{}\underset{\xaf}{+\text{3}\text{.700}}\\ \text{\hspace{0.17em}}\text{}\underset{\xaf}{\text{38}\text{.355}}\\ \\ \left(\text{e}\right)\text{0}\text{.75 + 10}\text{.425 + 2}\\ \text{}\\ \text{0}\text{.750}\\ \text{10}\text{.425}\\ \text{}\underset{\xaf}{+\text{2}\text{.000}}\\ \text{\hspace{0.17em}}\text{}\underset{\xaf}{\text{13}\text{.175}}\\ \\ \left(\text{f}\right)\text{280}\text{.69 + 25}\text{.2 + 38}\\ \text{}\\ \text{280}\text{.69}\\ \text{25}\text{.20}\\ \text{}\underset{\xaf}{+\text{38}\text{.00}}\\ \text{\hspace{0.17em}}\text{}\underset{\xaf}{\text{343}\text{.89}}\end{array}
Q.2 Rashid spent â‚¹ 35.75 for Maths book and â‚¹ 32.60 for Science book. Find the total amount spent by Rashid.
Ans.
$\begin{array}{l}\text{Amount spent for Maths book}=\text{}\xe2\u201a\xb9\text{35}.\text{75}\\ \text{Amount spent for Science book}=\text{}\xe2\u201a\xb9\text{32}.\text{6}0\\ \\ \text{Total amount spent by Rashid is:}\\ \text{}\\ \text{35}\text{.75}\\ \text{}\underset{\xaf}{\text{+ 32}\text{.60}}\\ \text{\hspace{0.17em}}\underset{\xaf}{\text{68}\text{.35}}\\ \\ \text{Therefore},\text{the amount spent by Rashid is \xe2\u201a\xb9 68}.\text{35}.\end{array}$
Q.3 Radhika’s mother gave her â‚¹ 10.50 and her father gave her â‚¹ 15.80, find the total amount given to Radhika by the parents.
Ans.
$\begin{array}{l}\text{Amount given by mother}=\text{\xe2\u201a\xb9 1}0.\text{5}0\\ \text{Amount given by father}=\text{\xe2\u201a\xb9 15}.\text{8}0\end{array}$
$\begin{array}{l}\text{Total amount given by parents is:}\\ \text{}\\ \text{10}\text{.50}\\ \text{}\underset{\xaf}{\text{+ 15}\text{.80}}\\ \text{\hspace{0.17em}}\underset{\xaf}{\text{26}\text{.30}}\\ \\ \text{Therefore},\text{the amount given by her parents is \xe2\u201a\xb9 26}.\text{3}0.\end{array}$
Q.4 Nasreen bought 3 m 20 cm cloth for her shirt and 2 m cm cloth for her trouser. Find the total length of cloth bught by her.
Ans.
$\begin{array}{l}\text{Material bought by Nasreen for shirt}\mathrm{}=\text{3 m 2}0\text{cm}\\ =\text{3 m}+\frac{20}{100}\mathrm{}\mathrm{m}=3\text{}\mathrm{m}+\mathrm{}0.2\text{}\mathrm{m}=3.2\text{}\mathrm{m}\mathrm{}\\ \mathrm{}\text{Material bought by Nasreen for trouser}=\text{2 m 5 cm}\\ =\text{2 m}+\frac{5}{100}\mathrm{}\mathrm{m}=2\text{}\mathrm{m}+\mathrm{}0.05\text{}\mathrm{m}=2.05\text{}\mathrm{m}\\ \text{Total length of cloth bought by Nasreen}:\text{}\\ \text{}\\ \text{3.20}\\ \text{}\underset{\xaf}{\text{+ 2.05}}\\ \text{\hspace{0.17em}}\underset{\xaf}{\text{5.25}}\\ \text{Hence,the total length of cloth bought by Nasreen is 5.25 m.}\end{array}$
Q.5 Naresh walked 2 km 35 m in the morning and 1 km 7 in the evening. How much distance did he walk in all?
Ans.
$\begin{array}{l}\text{Distance covered by Naresh in the morning}\mathrm{}=\text{2 km 35 m}\\ =\text{2 km}+\frac{35}{1000}\mathrm{}\text{\hspace{0.17em}}\mathrm{km}=2\text{}\mathrm{km}+\text{}\mathrm{}0.035\text{k}\mathrm{m}=2.035\text{km}\\ \text{Distance covered by Naresh in the evening}\mathrm{}=\text{1 km 7 m}\\ =\text{1 km}+\frac{7}{1000}\mathrm{}\text{\hspace{0.17em}}\mathrm{km}=1\text{k}\mathrm{m}+\mathrm{}0.007\text{k}\mathrm{m}=1.007\text{k}\mathrm{m}\\ \text{Total distance walked by Naresh}:\text{}\\ \text{}\\ \text{2.035}\\ \text{}\underset{\xaf}{\text{+ 1.007}}\\ \text{\hspace{0.17em}}\underset{\xaf}{\text{3.042}}\\ \text{Hence,the total distance walked by Naresh is 3.042 km.}\end{array}$
Q.6 Sunita travelled 15 km 268 m by bus, 7 km 7 m by car and 500 m on foot in order to reach her school. How far is her school from her residence?
Ans.
$\begin{array}{l}\mathrm{Distance}\text{}\mathrm{travelled}\text{}\mathrm{by}\text{}\mathrm{Sunita}\text{}\mathrm{in}\text{}\mathrm{bus}\text{}\mathrm{}=15\text{}\mathrm{km}\text{}268\text{}\mathrm{m}\\ =\text{15 km}+\frac{268}{1000}\mathrm{}\text{\hspace{0.17em}}\mathrm{km}=15\text{}\mathrm{km}+\text{}\mathrm{}0.268\text{k}\mathrm{m}=15.268\text{km}\\ \mathrm{Distance}\text{}\mathrm{travelled}\text{}\mathrm{by}\text{}\mathrm{Sunita}\text{}\mathrm{in}\text{}\mathrm{car}\text{}\mathrm{}=7\text{}\mathrm{km}\text{}7\text{}\mathrm{m}\\ =\text{7 km}+\frac{7}{1000}\mathrm{}\text{\hspace{0.17em}}\mathrm{km}=7\text{k}\mathrm{m}+\mathrm{}0.007\text{k}\mathrm{m}=7.007\text{k}\mathrm{m}\\ \mathrm{Distance}\mathrm{}\mathrm{travelled}\mathrm{}\mathrm{by}\mathrm{}\mathrm{Sunita}\mathrm{on}\hspace{0.17em}\mathrm{foot}=500\text{}\mathrm{m}\\ =\frac{500}{1000}\text{}\mathrm{km}=0.5\mathrm{km}\\ \text{Total distance travelled by Sunita:}\\ \text{}\\ \text{15.268}\\ \text{7.007}\\ \text{\hspace{0.17em}+}\underset{\xaf}{\text{0.500}}\\ \text{}\underset{\xaf}{\text{22.775}}\\ \text{Hence,the total distance travelled by Sunita is 22.775 km.}\end{array}$
Q.7 Ravi purchased 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850g flour. Find the total weight of his purchases.
Ans.
$\begin{array}{l}\mathrm{Quantity}\text{}\mathrm{of}\text{}\mathrm{rice}\text{}\mathrm{purchased}\text{}\mathrm{by}\text{}\mathrm{Ravi}\text{}\mathrm{}=5\text{}\mathrm{kg}\text{}400\mathrm{g}\\ =5\text{}\mathrm{kg}+\frac{400}{1000}\mathrm{}\text{\hspace{0.17em}}\mathrm{kg}=5\text{}\mathrm{kg}+\text{}\mathrm{}0.4\text{}\mathrm{kg}=5.4\text{}\mathrm{kg}\\ \\ \mathrm{Quantity}\text{}\mathrm{of}\text{}\mathrm{sugar}\text{}\mathrm{purchased}\text{}\mathrm{by}\text{}\mathrm{Ravi}\text{}\mathrm{}=2\text{}\mathrm{kg}\text{}20\mathrm{g}\\ =2\text{}\mathrm{kg}+\frac{20}{1000}\mathrm{}\text{\hspace{0.17em}}\mathrm{kg}=2\text{}\mathrm{kg}+\text{}\mathrm{}0.02\text{}\mathrm{kg}=2.02\text{}\mathrm{kg}\\ \\ \mathrm{Quantity}\text{}\mathrm{of}\text{}\mathrm{flour}\text{}\mathrm{purchased}\text{}\mathrm{by}\text{}\mathrm{Ravi}\text{}\mathrm{}=10\text{}\mathrm{kg}\text{}850\mathrm{g}\\ 10\text{}\mathrm{kg}+\frac{850}{1000}\mathrm{}\text{\hspace{0.17em}}\mathrm{kg}=10\text{}\mathrm{kg}+\text{}\mathrm{}0.85\text{}\mathrm{kg}=10.85\text{}\mathrm{kg}\\ \text{Total quantity purchased by Ravi:}\\ \text{}\\ \text{5.40}\\ \text{2.02}\\ \text{\hspace{0.17em}+}\underset{\xaf}{\text{10.85}}\\ \text{}\underset{\xaf}{\text{18.27}}\\ \\ \text{Hence,the total quantity purchased by Ravi is 18.27 kg.}\end{array}$
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FAQs (Frequently Asked Questions)
1. Does the NCERT Solutions Class 6 Maths Chapter 8 Exercise 8.5 provide the same concepts as the NCERT Maths Textbook?
Following the NCERT Maths book, the NCERT Solutions Class 6 Maths Chapter 8 Exercise 8.5 has been provided, topic by topic. After reading NCERT Solutions Class 6 Maths Chapter 8 Exercise 8.5, the professionals continuously make sure that NCERT books remain at the centre of their study material.
2. Describe the decimal number concept that is discussed in NCERT Solutions Class 6 Maths Chapter 8 Exercise 8.5.
Decimal numbers are those used to represent numbers lower than unit 1. A decimal number depends heavily on the decimal point or period. A decimal number’s fractional and whole number components are separated by this period. The value of a digit according to its location in a number is known as the place value of a digit. Terms that are crucial for the tests are defined in this chapter’s introduction. Students can use the NCERT Solutions Class 6 Maths Chapter 8 Exercise 8.5, which is available in PDF format, to study and stay current on the most recent CBSE board syllabus.