NCERT Solutions Class 12 Physics Chapter – 2
NCERT Solutions Class 12 Physics Chapter – 2 Electrostatic Potential and Capacitance
NCERT Solutions Class 12 Physics Chapter 2 Electrostatic Potential and Capacitance on Extramarks is the perfect guide for students to prepare for examinations. Physics is an essential part of various competitive examinations like NEET, JEE or even school exams. And hence, to help students with their exam preparations, our subject matter experts at Extramarks have prepared easy and self-explanatory Class 12 Physics Chapter 2 NCERT Solutions. Students can study Physics Chapter 12 by referring to these study materials available for free.
Key Topics Covered In NCERT Solutions Class 12 Physics Chapter 2
The key topics covered under NCERT Solutions Class 12 Physics Chapter 2 are as follows.
|3.3||Potential Due to a Point Charge|
|3.4||Potential Due to an Electric Dipole|
|3.5||Potential Due to a System of Charges|
|3.6.1||Relation between field and potential|
|3.7||Potential Energy of a System of Charges|
|3.8||Potential Energy in an External Field|
|3.8.1||Potential energy of a single charge|
|3.8.2||Potential energy of a system of two charges in an external field|
|3.8.3||Potential energy of a dipole in an external field|
|3.9||Electrostatics of Conductors|
|3.10||Dielectrics and Polarisation|
|3.11||Capacitors and Capacitance|
|3.12||The Parallel Plate Capacitor|
|3.13||Effect of Dielectric on Capacitance|
|3.14||Combination of Capacitors|
|3.14.1||Capacitors in series|
|3.14.2||Capacitors in parallel|
|3.15||Energy Stored in a Capacitor|
|3.16||Van De Graaff Generator|
Students may click on the respective topics to access the NCERT Solutions Class 12 Physics Chapter 2 offered by Extramarks. Here’s a detailed explanation of all subtopics under NCERT Solutions Class 12 Physics Chapter 2.
The electric potential (also called electrostatic potential, electric field potential, potential drop) is the amount of work energy needed to move a unit of electric charge from a reference point to the specific point in an electric field.
SI unit: volt
In SI base units: V = kg⋅m2⋅s−3⋅A−1
Common symbols: V, φ
3.2 Electrostatic Potential
The electrostatic potential is the pressure that is outside, however conservative. It is the paintings executed via outside force in bringing a price s from a factor r to a degree p. The distinction withinside the capacity strength of prices among preliminary and last points is distinguished.
3.3 Potential Due To A Point Charge
This section of NCERT Solutions Class 12 Physics Chapter 2 describes the charge point. The electric potential of a factor price is V=kQ/r V = k Q / r. Electric potential is a scalar, and the electric subject is a vector. The addition of voltages as numbers offers the voltage because of a mixture of factor charges, while the addition of individual fields as vectors offers the overall electric subject.
3.4 Potential Due To An Electric Dipole
The potential because of a dipole relies upon r (distance among the factor wherein capacity is calculated and the mid-factor of the dipole) and perspective among role vector r and dipole second p. Dipole potential is inversely proportional to the square of r.
3.5 Potential Due To A System Of Charges
Under this section of NCERT Solutions Class 12 Physics Chapter 2, students will learn about the system of charges. For a system of point charges, the overall potential at a point is given through the algebraic sum of the potential for individual fees.
3.6 Equipotential Surfaces
The floor that’s the locus of all points on identical ability is called the equipotential floor. No work is needed to transport a charge from one factor to another on the equipotential floor.
3.6.1 Relation Between Field And Potential
This section of NCERT Solutions Class 12 Physics Chapter 2 describes the relationship between potential and area (E) as differential: the electric powered area is the potential (V) gradient in the x-direction. This may be represented as: Ex=−DV dx E x = − dV dx . Because the test charge is moved in the x-direction, the rate of its potential change is the electrical area’s value.
3.7 Potential Energy Of A System Of Charges
The electric potential energy of a system of factor charges is described as the work required to assemble this system of charges via bringing them near together, as withinside the system from a countless distance. To know more, students may refer to NCERT Solutions Class 12 Physics Chapter 2.
3.8 Potential Energy In An External Field
The electric potential energy of a system of point charges is described as the work required to collect this device of charges with the aid of bringing them together within the system from an infinite distance. The potential energy of the charge q withinside the field is identical to the work achieved in bringing the charge from infinity to the point. Here we word that the outside electric field E and the corresponding potential energy of the system range from point to point withinside the subject.
3.8.1 Potential Energy Of A Single Charge
The potential energy of the charge q in the field is equal to the work done in bringing the charge from infinity to the point. To know more, students may refer to Extramarks NCERT Solutions Class 12 Physics Chapter 2.
3.8.2 Potential Energy Of A System Of Two Charges In An External Field
The potential energy of the charge q withinside the area is the same as the work achieved in bringing the charge from infinity to the point. Here we notice that the outside electric field E and the corresponding potential energy of the system range from point to point withinside the area.
3.8.3 Potential Energy Of A Dipole In An External Field
τ = p × E. This work is stored because of the system’s potential energy. The potential energy U(θ) can then be related to the dipole’s inclination θ. To know more, students may refer to Extramarks NCERT Solutions Class 12 Physics Chapter 2.
3.9 Electrostatics Of Conductors
Conductors comprise mobile charge carriers. Inside a conductor, the electrostatic field is 0. The free charges have allotted themselves in the static situation that the electrical field is 0 anywhere inside. The electrostatic field is 0 inside a conductor.
3.10 Dielectrics And Polarization
The molecule acquires a dipole moment when a dielectric slab is positioned in an electric field. In such circumstances, the dielectric is stated to be polarized. The Electric Polarization of a dielectric substance is the dipole moment per unit volume. P is the symbol for polarization.
3.11 Capacitors And Capacitance
Capacitance is the electric property of a capacitor. It is the degree of a capacitor’s ability to save an electrical charge onto its plates. The unit of capacitance is the Farad (abbreviated to F), named after the British physicist Michael Faraday.
3.12 The Parallel Plate Capacitor
This section of NCERT Solutions Class 12 Physics Chapter 2 describes The Parallel Plate Capacitor. A parallel plate capacitor can store a finite quantity of energy earlier than dielectric breakdown. When parallel plates are connected throughout a battery, the plates are charged, and an electric field is mounted among them; this setup is called the parallel plate capacitor.
3.13 Effect Of Dielectric On Capacitance
The energy of the electrical field is decreased because of the presence of dielectric. If the total charge at the plates is stored constant, then the potential difference is reduced throughout the capacitor plates. In this way, the dielectric will increase the capacitance of the capacitor.
3.14 Combination Of Capacitors
In series combinations of capacitors, all capacitors could have identical charges. i.e., the resultant capacitance of series combination C=Q/V is the ratio of charge to total ability difference throughout the two capacitors connected in series.
3.14.1 Capacitors In Series
The overall voltage difference from end to end is apportioned to every capacitor in step with the inverse of its capacitance. The whole series acts as a capacitor smaller than any of its components. To know more, students may refer to NCERT Solutions Class 12 Physics Chapter 2.14.1.
3.14.2 Capacitors In Parallel
When capacitors are linked in parallel, the total capacitance is the sum of the individual capacitors’ capacitances. If or greater capacitors are connected in parallel, the general impact is that of a single equal capacitor having the sum general of the plate areas of the individual capacitors.
3.15 Energy Stored In A Capacitor
The electricity you see saved in a capacitor is electrostatic potential energy associated with the charge Q and voltage V among the plates of capacitor A charged capacitor stores energy withinside the electric field among its plates. As the capacitor gets charged, the electric field builds up.
3.16 Van De Graaff Generator
An electrostatic generator or Van de Graaff generator uses a transferring belt to build up electric charge on a hollow metallic globe at the top of an insulated column, developing excessive electric potentials. It produces excessive voltage direct current (DC) electricity at low current levels.
Students may refer to NCERT Solutions Class 12 Physics Chapter 2 provided by Extramarks to get detailed study material on Electrostatic Potential and Capacitance.
NCERT Solutions Class 12 Physics Chapter 2: Article link for Electrostatic Potential and Capacitance NCERT solutions
Click on the below links to view NCERT Solutions Class 12 Physics Chapter 2:
- Class 12 Physics Chapter 2: Exercise 3.1
- Class 12 Physics Chapter 2: Exercise 3.2
- Class 12 Physics Chapter 2: Exercise 3.3
- Class 12 Physics Chapter 2: Exercise 3.4
- Class 12 Physics Chapter 2: Exercise 3.5
- Class 12 Physics Chapter 2: Exercise 3.6
- Class 12 Physics Chapter 2: Exercise 3.7
- Class 12 Physics Chapter 2: Exercise 3.8
- Class 12 Physics Chapter 2: Exercise 3.9
- Class 12 Physics Chapter 2: Exercise 3.10
- Class 12 Physics Chapter 2: Exercise 3.11
- Class 12 Physics Chapter 2: Exercise 3.12
- Class 12 Physics Chapter 2: Exercise 3.13
- Class 12 Physics Chapter 2: Exercise 3.14
- Class 12 Physics Chapter 2: Exercise 3.15
- Class 12 Physics Chapter 2: Exercise 3.16
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Key Features of NCERT Solutions Class 12 Physics Chapter 2
NCERT Solutions Class 12 Physics Chapter 2 gives you detailed information about electrostatic potential and capacitance. Students will learn the basic concepts about capacitors, insulators, and how the potential energy works. Going through NCERT Solutions Class 12 Physics Chapter 2 will help students understand the topic in a better way.
The key features of NCERT Solutions Class 12 Physics Chapter 2 provided by Extramarks are
- The Solutions are compiled by some of the highly qualified subject matter experts
- Every minute detail of the chapter is included to ensure that students understand the chapter.
- NCERT Solutions Class 12 Physics Chapter 2 by Extramarks can be used as revision notes during the examination.
- They also contain important questions, sample questions, past years’ question papers for the students to refer to.
Q.1 Two charges 5 × 10−8 C and −3 × 10−8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
Q.2 A regular hexagon of side 10 cm has a charge 5 μC at each of its vertices. Calculate the potential at the centre of the hexagon.
Q.3 Two charges 2 μC and −2 μC are placed at points A and B 6 cm apart.
(a) Identify an equipotential surface of the system.
(b) What is the direction of the electric field at every point on this surface?
(a) The plane normal to AB and passing through its middle point has zero potential everywhere and it represents an equipotential surface of the given system.
(b) The direction of the electric field at every point on this surface is along normal to the plane in the direction of AB.
Q.4 A spherical conductor of radius 12 cm has a charge of 1.6 × 10−7 C distributed uniformly on its surface. What is the electric field
(a) Inside the sphere
(b) Just outside the sphere
(c) At a point 18 cm from the centre of the sphere?
Q.5 A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1pF = 10−12 F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6?
Q.6 Three capacitors each of capacitance 9 pF are connected in series.
(a) What is the total capacitance of the combination?
(b) What is the potential difference across each capacitor if the combination is connected to a 120 V supply?
Q.7 Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel.
(a) What is the total capacitance of the combination?
(b) Determine the charge on each capacitor if the combination is connected to a 100 V supply.
Q.8 In a parallel plate capacitor with air between the plates, each plate has an area of 6 ×10−3 m2 and the distance between the plates is 3 mm. Calculate the capacitance of the capacitor. If this capacitor is connected to a 100 V supply, what is the charge on each plate of the capacitor?
Q.9 Explain what would happen if in the capacitor given in Exercise 2.8, a 3 mm thick mica sheet (of dielectric constant = 6) were inserted between the plates,
(a) While the voltage supply remained connected.
(b) After the supply was disconnected.
Q.10 A 12 pF capacitor is connected to a 50V battery. How much electrostatic energy is stored in the capacitor?
Q.11 A 600 pF capacitor is charged by a 200 V supply. It is then disconnected from the supply and is connected to another uncharged 600 pF capacitor. How much electrostatic energy is lost in the process?
Q.12 A charge of 8 mC is located at the origin. Calculate the work done in taking a small charge of −2 × 10−9 C from a point P (0, 0, 3 cm) to a point Q (0, 4 cm, 0), via a point R (0, 6 cm, 9 cm).
Q.13 A cube of side b has a charge q at each of its vertices. Determine the potential and electric field due to this charge array at the centre of the cube.
Q.14 Two tiny spheres carrying charges 1.5 μC and 2.5 μC are located 30 cm apart. Find the potential and electric field:
(a) at the mid-point of the line joining the two charges, and
(b) at a point 10 cm from this midpoint in a plane normal to the line and passing through the mid-point.
Q.15 A spherical conducting shell of inner radius r1 and outer radius r2 has a charge Q.
(a) A charge q is placed at the centre of the shell. What is the surface charge density on the inner and outer surfaces of the shell?
(b) Is the electric field inside a cavity (with no charge) zero, even if the shell is not spherical, but has any irregular shape? Explain.
(a) The magnitude of charge placed at the centre of the shell is +q. Therefore, a charge −q will be induced to the inner surface of the shell.
(b) Yes, the electric field intensity inside a cavity with no charge is zero, even if the shell is not spherical and has any irregular shape. When a closed loop is taken such that a part of it is inside the cavity along a field line and the rest is inside the conductor; the net work done by the electric field in carrying a test charge over a closed loop is zero because the field inside the conductor is zero. Hence, electric field inside a cavity with no charge is zero, whatever is the shape.
Q.16 A long charged cylinder of linear charged density λ is surrounded by a hollow co-axial conducting cylinder. What is the electric field in the space between the two cylinders?
Q.17 In a hydrogen atom, the electron and proton are bound at a distance of about 0.53 Å:
(a) Estimate the potential energy of the system in eV, taking the zero of the potential energy at infinite separation of the electron from proton.
(b) What is the minimum work required to free the electron, given that its kinetic energy in the orbit is half the magnitude of potential energy obtained in (a)?
(c) What are the answers to (a) and (b) above if the zero of potential energy is taken at 1.06 Å separation?
Q.18 Two charged conducting spheres of radii a and b are connected to each other by a wire.
What is the ratio of electric fields at the surfaces of the two spheres? Use the result obtained to explain why charge density on the sharp and pointed ends of a conductor is higher than on its flatter portions.
Q.19 Two charges −q and +q are located at points (0, 0, − a) and (0, 0, a), respectively.
(a) What is the electrostatic potential at the points?
(b) Obtain the dependence of potential on the distance r of a point from the origin when r/a >> 1.
(c) How much work is done in moving a small test charge from the point (5, 0, 0) to (−7, 0, 0) along the x-axis? Does the answer change if the path of the test charge between the same points is not along the x-axis?
Q.20 Figure 2.34 shows a charge array known as an electric quadrupole. For a point on the axis of the quadrupole, obtain the dependence of potential on r for r/a >> 1, and contrast your results with that due to an electric dipole, and an electric monopole (i.e., a single charge).
Q.21 An electrical technician requires a capacitance of 2 μF in a circuit across a potential difference of 1 kV. A large number of 1 μF capacitors are available to him each of which can withstand a potential difference of not more than 400 V. Suggest a possible arrangement that requires the minimum number of capacitors.
Q.22 What is the area of the plates of a 2 F parallel plate capacitor, given that the separation between the plates is 0.5 cm? [You will realize from your answer why ordinary capacitors are in the range of 5F or less. However, electrolytic capacitors do have a much larger capacitance (0.1 F) because of very minute separation between the conductors.]
Q.24 A spherical capacitor consists of two concentric spherical conductors, held in position by suitable insulating supports (Fig. 2.36). Show that the capacitance of a spherical capacitor is given by
Q.25 A spherical conductor of radius 12 cm has a charge of 1.6 × 10−7 C distributed uniformly on its surface. What is the electric field
(a) Inside the sphere
(b) Just outside the sphere
(c) At a point 18 cm from the centre of the sphere?
Q.26 Answer carefully:
(a) Two large conducting spheres carrying charges Q1 and Q2 are brought close to each other. Is the magnitude of electrostatic force between them exactly given by Q1Q2/4πr 2, where r is the distance between their centres?
(b) If Coulomb’s law involved 1/r3 dependence (instead of 1/r2), would Gauss’s law be still true?
(c) A small test charge is released at rest at a point in an electrostatic field configuration. Will it travel along the field line passing through that point?
(d) What is the work done by the field of a nucleus in a complete circular orbit of the electron? What if the orbit is elliptical?
(e) We know that electric field is discontinuous across the surface of a charged conductor. Is electric potential also discontinuous there?
(f) What meaning would you give to the capacitance of a single conductor
(g) Guess a possible reason why water has a much greater dielectric constant (= 80) than say, mica (= 6).
(a) When two charged spheres are brought close to each other, the charge distribution on them does not remain uniform. Therefore, the force between two conducting spheres is not exactly given by the given expression.
(b) Gauss’s law will not be true, if Coulomb’s law involved 1/r3 dependence, instead of 1/r2 dependence.
(c) Yes, if a small test charge is released at rest at a point in an electrostatic field configuration, then it will move along the line of force passing through that point, only if the field lines are straight. If the field lines are not straight, the charge will not go along the line. This is because the field lines give the direction of acceleration.
(d)The direction of force due to field is towards the nucleus, and the electron does not move along the direction of this force. Therefore, whenever the electron completes an orbit, either circular or elliptical, the work done by the field of a nucleus is zero.
(e) No, electric potential is continuous across the surface of a charged conductor.
(f) The capacitance of a single conductor implies a parallel plate capacitor with one of its two plates at infinity.
(g) A water molecule has an unsymmetrical shape as compared to that of mica. Therefore, it has a permanent dipole moment. That is why; it has a greater dielectric constant than mica.
Q.27 A parallel plate capacitor is to be designed with a voltage rating 1 kV, using a material of dielectric constant 3 and dielectric strength about 107 Vm−1. (Dielectric strength is the maximum electric field a material can tolerate without breakdown, i.e., without starting to conduct electricity through partial ionisation.) For safety, we should like the field never to exceed, say 10% of the dielectric strength. What minimum area of the plates is required to have a capacitance of 50 pF?
Q.28 Describe schematically the equipotential surfaces corresponding to
(a) a constant electric field in the z-direction,
(b) a field that uniformly increases in magnitude but remains in a constant (say, z) direction,
(c) a single positive charge at the origin, and
(d) a uniform grid consisting of long equally spaced parallel charged wires in a plane.
(a) The equipotential surfaces are the equidistant planes parallel to the x-y plane.
(b) The equipotential surfaces are the planes parallel to the x-y plane. When the field increases uniformly, planes get closer (differing by fixed potential).
(c) The equipotential surfaces are the concentric spheres centered at the origin.
(d) The equipotential surfaces have the periodically varying shape. The shape of equipotential surfaces becomes parallel to the grid at a far off distance.
As the charge lies always on the outer surface of the shell, therefore, when the sphere and the shell are connected by a wire, charge will flow from the sphere to the shell, whatever be the magnitude and sign of charge q2.
Q.29 Answer the following:
(a) The top of the atmosphere is at about 400 kV with respect to the surface of the earth, corresponding to an electric field that decreases with altitude. Near the surface of the earth, the field is about 100 Vm−1. Why then do we not get an electric shock as we step out of our house into the open? (Assume the house to be a steel cage so there is no field inside!)
(b) A man fixes outside his house one evening a two metre high insulating slab carrying on its top a large aluminium sheet of area 1m2. Will he get an electric shock if he touches the metal sheet next morning?
(c) The discharging current in the atmosphere due to the small conductivity of air is known to be 1800 A on an average over the globe. Why then does the atmosphere not discharge itself completely in due course and become electrically neutral? In other words, what keeps the atmosphere charged?
(d) What are the forms of energy into which the electrical energy of the atmosphere is dissipated during a lightning? (Hint: The earth has an electric field of about 100 Vm−1 at its surface in the downward direction, corresponding to a surface charge density = −10−9 Cm−2. Due to the slight conductivity of the atmosphere up to about 50 km (beyond which it is good conductor), about + 1800 C is pumped every second into the earth as a whole. The earth, however, does not get discharged since thunderstorms and lightning occurring continually all over the globe pump an equal amount of negative charge on the earth.)
(a) As we step out of our house, we do not get an electric shock. This is because the original equipotential surfaces of open air change keeps our body and the ground at the same potential.
(b) Yes, the man will get an electric shock because the steady discharging current in the atmosphere charges up the aluminium sheet and raises its voltage gradually. The rise in its voltage depends on the capacitance of the capacitor formed by the aluminium sheet and the ground.
(c) The atmosphere is charged continuously by occurrence of thunderstorms and lightning. Therefore, even with the presence of discharging current of 1800 A in the atmosphere, the atmosphere is not discharged completely. The two opposing currents are, on an average, in equilibrium and the atmosphere remains electrically charged.
(d) During a lightning, the electrical energy of the atmosphere is dissipated in the form of light energy, heat energy, and sound energy.
FAQs (Frequently Asked Questions)
1. How many topics are there in Chapter 2 Physics Class 12 NCERT Solutions?
There are 15 topics NCERT Solutions Class 12 Physics Chapter 2. All the syllabus has been well designed and prescribed as per CBSE guidelines.
2. Is Class 12th Physics easy?
The syllabus taught in Physics for Class 10 and 12 is easier than that for competitive examinations. For school level examinations, theoretical and proof-based problems cover most question papers. While in competitive exams, conceptual questions are included.