Important Questions Class 8 Maths Chapter 4: Quadrilaterals with Answers

Important Questions Class 8 Maths Chapter 4 focus on quadrilaterals, closed four-sided figures with four angles and four sides. Students use angle sum, diagonal properties, and side relations to solve rectangle, square, parallelogram, rhombus, kite, and trapezium questions.

Quadrilaterals form a major geometry area in Class 8 Maths because they connect angles, sides, diagonals, and proofs. Important Questions Class 8 Maths Chapter 4 help students practise NCERT-style reasoning for rectangles, squares, parallelograms, rhombuses, kites, and trapeziums. The CBSE 2026 pattern can test direct definitions, angle calculations, construction logic, and property-based proofs from this chapter.

Key Takeaways

  • Angle Sum: Every quadrilateral has four angles whose sum equals 360°.
  • Rectangle Rule: A rectangle has four right angles and equal diagonals that bisect each other.
  • Square Rule: A square has equal sides, right angles, and diagonals that meet at 90°.
  • Parallelogram Rule: A parallelogram has opposite sides parallel and diagonals that bisect each other.

Important Questions Class 8 Maths Chapter 4 Structure 2026

Concept Formula or Rule Key Variables
Angles in a Quadrilateral Sum of four angles = 360° ∠A, ∠B, ∠C, ∠D
Parallelogram Adjacent angles add to 180° ∠A + ∠B = 180°
Rhombus Diagonals bisect at 90° AC ⟂ BD

Important Questions Class 8 Maths Chapter 4 with Answers

Quadrilaterals questions need exact property recall and clear geometric reasoning. These class 8 maths chapter 4 important questions follow the NCERT pattern for Chapter 4.

1. Why does a quadrilateral with three right angles have the fourth angle equal to 90°?

A quadrilateral with three right angles has the fourth angle equal to 90°. The sum of all angles in any quadrilateral is 360°.

  1. Given Data: Three angles are 90°, 90°, and 90°.
  2. Formula Used: Sum of angles in a quadrilateral = 360°.
  3. Calculation:
    Fourth angle = 360° − (90° + 90° + 90°)
    Fourth angle = 360° − 270°
    Fourth angle = 90°.
  4. Final Result: The fourth angle is 90°.

2. How do you find the fourth angle when three angles of a quadrilateral are known?

The fourth angle equals 360° minus the sum of the other three angles. This rule applies to every quadrilateral.

  1. Given Data: Three angles are 80°, 95°, and 110°.
  2. Formula Used: Fourth angle = 360° − sum of three given angles.
  3. Calculation:
    Fourth angle = 360° − (80° + 95° + 110°)
    Fourth angle = 360° − 285°
    Fourth angle = 75°.
  4. Final Result: The fourth angle is 75°.

3. Why is the sum of angles in a quadrilateral equal to 360°?

The sum of angles in a quadrilateral is 360°. A diagonal divides a quadrilateral into two triangles.

  1. Given Data: A quadrilateral ABCD has diagonal AC.
  2. Formula Used: Sum of angles in one triangle = 180°.
  3. Calculation:
    Triangle ABC has angle sum 180°.
    Triangle ADC has angle sum 180°.
    Total angle sum = 180° + 180° = 360°.
  4. Final Result: The angle sum of a quadrilateral is 360°.

Class 8 Maths Chapter 4 Quadrilaterals Extra Questions

Students often confuse quadrilateral families because many shapes share properties. These class 8 maths chapter 4 extra questions separate each shape by its exact NCERT rule.

4. How do you prove that the diagonals of a rectangle are equal?

The diagonals of a rectangle are equal in length. The proof uses congruence between two triangles formed inside the rectangle.

  1. Given Data: ABCD is a rectangle.
  2. Formula Used: SAS congruence rule.
  3. Proof:
    AB = CD because opposite sides of a rectangle are equal.
    ∠BAD = ∠CDA = 90°.
    AD is common to both triangles.
  4. Conclusion: ∆ADC ≅ ∆DAB by SAS.
  5. Final Result: AC = BD.

5. Why do the diagonals of a rectangle bisect each other?

The diagonals of a rectangle bisect each other. Their point of intersection divides both diagonals into two equal parts.

  1. Given Data: Diagonals AC and BD meet at O in rectangle ABCD.
  2. Formula Used: AAS congruence rule.
  3. Proof:
    Vertically opposite angles at O are equal.
    Corresponding right-angle-based parts form congruent triangles.
    ∆AOB ≅ ∆COD by AAS.
  4. Final Result: OA = OC and OB = OD.

6. Can a quadrilateral with all angles equal to 90° be anything other than a rectangle?

No, a quadrilateral with all angles equal to 90° is a rectangle. Opposite sides become equal through triangle congruence.

  1. Given Data: ABCD has four right angles.
  2. Formula Used: AAS congruence rule.
  3. Proof:
    Draw diagonal BD.
    ∆BAD and ∆DCB share side BD.
    Angle relations make the two triangles congruent.
  4. Final Result: ABCD is a rectangle.

7. Why is every square also a rectangle?

Every square is a rectangle because it has four angles of 90°. A square adds one extra condition of four equal sides.

  1. Given Data: A square has four right angles and four equal sides.
  2. Rectangle Rule: A rectangle has four right angles.
  3. Comparison:
    A square satisfies the rectangle angle rule.
    A rectangle may not have four equal sides.
  4. Final Result: Every square is a rectangle.

8. How do you construct a square when its diagonal is 6 cm?

A square with diagonal 6 cm can be constructed using a perpendicular bisector. The diagonals of a square are equal and meet at 90°.

  1. Draw AC = 6 cm.
  2. Draw the perpendicular bisector of AC.
  3. Mark O as the midpoint of AC.
  4. Mark B and D on the perpendicular bisector.
  5. Keep OB = OD = 3 cm.
  6. Join AB, BC, CD, and DA.
  7. Final Result: ABCD is a square with diagonal 6 cm.

Class 8 Maths Quadrilaterals Questions with Answers on Parallelograms

Parallelograms use parallel sides, equal opposite angles, and diagonal bisection. These class 8 maths quadrilaterals questions with answers focus on Chapter 4 proof patterns.

9. How do you find all angles of a parallelogram when one angle is 30°?

The opposite angle is 30°, and each adjacent angle is 150°. Adjacent angles in a parallelogram add to 180°.

  1. Given Data: ∠A = 30° in parallelogram ABCD.
  2. Formula Used: Adjacent angles = 180°.
  3. Calculation:
    ∠B = 180° − 30° = 150°.
    ∠C = ∠A = 30°.
    ∠D = ∠B = 150°.
  4. Final Result: Angles are 30°, 150°, 30°, and 150°.

10. How do you prove that opposite sides of a parallelogram are equal?

Opposite sides of a parallelogram are equal. The proof uses congruent triangles formed by a diagonal.

  1. Given Data: ABCD is a parallelogram.
  2. Formula Used: AAS congruence rule.
  3. Proof:
    Draw diagonal BD.
    Alternate angles are equal because opposite sides are parallel.
    BD is common to both triangles.
  4. Conclusion: ∆ABD ≅ ∆CDB by AAS.
  5. Final Result: AB = CD and AD = BC.

11. How do you prove that diagonals of a parallelogram bisect each other?

The diagonals of a parallelogram bisect each other. Each diagonal gets divided into two equal parts at their intersection point.

  1. Given Data: Diagonals of parallelogram EASY meet at O.
  2. Formula Used: ASA congruence rule.
  3. Proof:
    AE = YS because opposite sides are equal.
    Alternate angles are equal due to parallel sides.
    ∆AOE ≅ ∆YOS by ASA.
  4. Final Result: OA = OY and OE = OS.

12. Are the diagonals of a parallelogram always equal?

The diagonals of a parallelogram are not always equal. They are equal only in special cases like rectangles and squares.

  1. Given Data: ABCD is a parallelogram.
  2. Property Used: Diagonals of a parallelogram bisect each other.
  3. Fact:
    A slant parallelogram can have unequal diagonals.
    A rectangle has equal diagonals.
    A square has equal diagonals.
  4. Final Result: A parallelogram’s diagonals need not be equal.

NCERT Class 8 Maths Chapter 4 Questions on Rhombus, Kite, and Trapezium

A rhombus, kite, and trapezium need careful side and diagonal checks. These NCERT class 8 maths chapter 4 questions follow the exact chapter sequence.

13. How do you find the angles of a rhombus when one angle is 50°?

The opposite angle is 50°, and each adjacent angle is 130°. A rhombus is also a parallelogram.

  1. Given Data: One angle of rhombus ABCD is 50°.
  2. Formula Used: Adjacent angles in a parallelogram = 180°.
  3. Calculation:
    Adjacent angle = 180° − 50° = 130°.
    Opposite angles are equal.
  4. Final Result: The angles are 50°, 130°, 50°, and 130°.

14. Why do the diagonals of a rhombus meet at 90°?

The diagonals of a rhombus meet at 90°. Congruent triangles around the intersection point prove this property.

  1. Given Data: GAME is a rhombus, and diagonals meet at O.
  2. Formula Used: Rhombus diagonal property.
  3. Proof:
    ∆GEO ≅ ∆MEO.
    ∠GOE = ∠MOE as corresponding angles.
    These two angles form a straight angle of 180°.
  4. Calculation:
    ∠GOE = ∠MOE = 180° ÷ 2 = 90°.
  5. Final Result: The diagonals meet at 90°.

15. Why do the diagonals of a rhombus bisect its angles?

The diagonals of a rhombus bisect its angles. Each diagonal divides opposite angles into two equal parts.

  1. Given Data: ABCD is a rhombus.
  2. Formula Used: Congruence in equal-sided triangles.
  3. Proof:
    All sides of a rhombus are equal.
    A diagonal creates two congruent triangles.
    Corresponding angles become equal.
  4. Final Result: Each diagonal bisects a pair of opposite angles.

16. What are the main diagonal properties of a kite?

A kite has one diagonal that bisects the other diagonal at 90°. That same diagonal also bisects two opposite angles.

  1. Given Data: In kite ABCD, AB = BC and CD = DA.
  2. Property Used: Kite diagonal property.
  3. Fact:
    BD bisects ∠ABC and ∠ADC.
    BD bisects AC at O.
    BD is perpendicular to AC.
  4. Final Result: BD is the symmetry diagonal of the kite.

17. How do you find the missing angles in a trapezium?

Missing angles in a trapezium use the 180° rule along each non-parallel side. A trapezium has at least one pair of parallel opposite sides.

  1. Given Data: PQRS is a trapezium with PQ ∥ SR.
  2. Formula Used: Interior angles on the same side of a transversal = 180°.
  3. Calculation:
    ∠P + ∠S = 180°.
    ∠Q + ∠R = 180°.
  4. Final Result: Each missing angle equals 180° minus its adjacent known angle.

18. Why are base angles equal in an isosceles trapezium?

Base angles in an isosceles trapezium are equal. The equal non-parallel sides create congruent right triangles.

  1. Given Data: UV ∥ XW and UX = VW.
  2. Formula Used: Congruent triangle property.
  3. Proof:
    Draw perpendiculars XY and WZ to UV.
    XWZY forms a rectangle.
    ∆UXY ≅ ∆VWZ.
  4. Final Result: ∠U = ∠V.

Class 8 Maths Chapter 4 Solutions for Mixed Practice

Mixed questions train students to identify the quadrilateral before applying any rule. These class 8 maths chapter 4 solutions cover proof, construction, and property-based reasoning.

19. What figure forms when equal perpendicular diameters of a circle are joined?

A square forms when endpoints of equal perpendicular diameters are joined. The diameters act as equal diagonals that bisect each other at 90°.

  1. Given Data: PL and AM are perpendicular diameters of a circle with centre O.
  2. Formula Used: Square diagonal property.
  3. Reason:
    PL = AM because both are diameters of the same circle.
    They bisect each other at O.
    They meet at 90°.
  4. Final Result: APML is a square.

20. Can opposite sides parallel and equal define a rectangle?

No, opposite sides parallel and equal define a parallelogram. A rectangle must also have four right angles.

  1. Given Data: A quadrilateral has opposite sides parallel and equal.
  2. Formula Used: Definition of parallelogram.
  3. Reason:
    A parallelogram can have angles of 60° and 120°.
    A rectangle must have four angles of 90°.
  4. Final Result: The quadrilateral is a parallelogram, not always a rectangle.

21. If a quadrilateral has four equal sides and one angle of 90°, is it a square?

Yes, the quadrilateral is a square. Four equal sides make it a rhombus, and one right angle makes all angles right angles.

  1. Given Data: Four sides are equal, and one angle is 90°.
  2. Formula Used: Adjacent angles in a rhombus add to 180°.
  3. Calculation:
    Adjacent angle = 180° − 90° = 90°.
    Opposite angles are equal.
  4. Final Result: The quadrilateral is a square.

22. What quadrilateral has both pairs of opposite sides equal?

A quadrilateral with both pairs of opposite sides equal is a parallelogram. This result follows from triangle congruence.

  1. Given Data: In ABCD, AB = CD and AD = BC.
  2. Formula Used: SSS congruence rule.
  3. Proof:
    Draw diagonal AC.
    ∆ABC and ∆CDA have three equal side pairs.
    ∆ABC ≅ ∆CDA by SSS.
  4. Final Result: ABCD is a parallelogram.

23. Is a quadrilateral with equal diagonals that bisect each other always a square?

No, it is always a rectangle, but not always a square. A square also needs four equal sides or perpendicular diagonals.

  1. Given Data: Diagonals are equal and bisect each other.
  2. Property Used: Rectangle diagonal property.
  3. Fact:
    A rectangle has equal diagonals that bisect each other.
    A square has equal diagonals that meet at 90°.
  4. Final Result: The quadrilateral is a rectangle, not necessarily a square.

24. Is a quadrilateral with perpendicular diagonals always a rhombus?

No, perpendicular diagonals alone do not always form a rhombus. A kite can also have perpendicular diagonals.

  1. Given Data: Diagonals of a quadrilateral meet at 90°.
  2. Property Used: Rhombus and kite diagonal comparison.
  3. Fact:
    A rhombus has perpendicular bisecting diagonals.
    A kite has one diagonal perpendicular to the other.
  4. Final Result: Perpendicular diagonals alone do not prove a rhombus.

25. What type of quadrilateral is formed by joining two equilateral triangles of side 4 cm?

A rhombus forms when two equilateral triangles of side 4 cm are joined along one side. All outer sides measure 4 cm.

  1. Given Data: Two equilateral triangles have side 4 cm.
  2. Property Used: Definition of rhombus.
  3. Reason:
    Each outer side equals 4 cm.
    The joined side stays inside the figure.
    The outer quadrilateral has four equal sides.
  4. Final Result: The quadrilateral is a rhombus.

Class 8 Maths Important Questions Quadrilaterals for Short Answers

Short-answer questions often test one exact rule in one or two marks. These class 8 maths important questions quadrilaterals cover definitions and property matches.

26. What is the difference between a rectangle and a square?

A square has all rectangle properties and four equal sides. A rectangle needs four right angles but does not need four equal sides.

  1. Rectangle: Four angles equal 90°.
  2. Square: Four angles equal 90° and all sides are equal.
  3. Example: A 6 cm by 4 cm shape is a rectangle.
  4. Final Result: Every square is a rectangle, but every rectangle is not a square.

27. What is the difference between a rhombus and a square?

A square is a rhombus with four right angles. A rhombus only needs all four sides equal.

  1. Rhombus: All sides are equal.
  2. Square: All sides are equal and all angles are 90°.
  3. Example: A rhombus can have angles 60° and 120°.
  4. Final Result: Every square is a rhombus, but every rhombus is not a square.

28. What is the difference between a parallelogram and a trapezium?

A parallelogram has two pairs of parallel opposite sides. A trapezium has at least one pair of parallel opposite sides.

  1. Parallelogram: Both pairs of opposite sides are parallel.
  2. Trapezium: At least one pair of opposite sides is parallel.
  3. Example: A rectangle is a parallelogram.
  4. Final Result: Every parallelogram fits the trapezium condition used in Chapter 4.

29. What is the difference between a kite and a rhombus?

A kite has two pairs of equal adjacent sides. A rhombus has all four sides equal.

  1. Kite: AB = BC and CD = DA.
  2. Rhombus: AB = BC = CD = DA.
  3. Example: A rhombus can be treated as a special kite only when side conditions match.
  4. Final Result: Every kite is not a rhombus.

30. How are rectangle, square, rhombus, and parallelogram related?

A square belongs to both the rectangle and rhombus groups. Rectangles and rhombuses both belong to the parallelogram group.

  1. Rectangle: A parallelogram with four right angles.
  2. Rhombus: A parallelogram with four equal sides.
  3. Square: A rectangle and a rhombus.
  4. Final Result: A square is both a rectangle and a rhombus.

Class 8 Maths Important Questions Chapter-Wise

Chapter No. Chapter Name
Part 1 Chapter 1 A Square and A Cube
Part 1 Chapter 2 Power Play
Part 1 Chapter 3 A Story of Numbers
Part 1 Chapter 4 Quadrilaterals
Part 1 Chapter 5 Number Play
Part 1 Chapter 6 We Distribute, Yet Things Multiply
Part 1 Chapter 7 Proportional Reasoning-1
Part 2 Chapter 1 Fractions in Disguise
Part 2 Chapter 2 The Baudhayana-Pythagoras Theorem
Part 2 Chapter 3 Proportional Reasoning-2
Part 2 Chapter 4 Exploring Some Geometric Themes
Part 2 Chapter 5 Tales by Dots and Lines
Part 2 Chapter 6 Algebra Play
Part 2 Chapter 7 Area

Q.1 Construct a quadrilateral ABCD where AB = 3 cm, BC = 5 cm, CD = 4 cm, DA = 7 cm, and AC = 12 cm.

Marks:3
Ans

To construct a quadrilateral ABCD, given that AB = 3 cm, BC = 5 cm, CD = 4 cm, DA = 7 cm, and AC = 12 cm.
Steps to be followed:
Step1: Draw a line AC =12 cm
Step2: Draw an arc of length 3 cm from A and an arc of length 5 cm from C to intersect at a point B.
Step 3: Draw an arc of length 4 cm from C and an arc of length 7 cm from A on the opposite side of AC to intersect at a point D.
Step4: Join AB, BC, CD, and DA.

Q.2 Construct a rectangle with adjacent sides of lengths 5 cm and 7 cm.

Marks:3
Ans

Steps to construct:
1. Draw AB = 7 cm
2. At A, draw AY ? AB
3. With A as a centre and radius 5 cm, describe an arc cutting AY at D.
4. With D as centre and radius equal to 7 cm, and B as centre and radius 5 cm, draw arcs intersecting at C.
5. Join BC and DC. ABCD is the required rectangle.

Q.3 Construct a square of side 3 cm.

Marks:3
Ans

Steps to construct:

  • Draw AB = 3 cm
  • At A, draw AY ? AB
  • With A as a centre and radius 3 cm, describe an arc cutting AY at D.
  • With B and D as centres and radii equal to 3 cm, draw arcs intersecting at C.
  • Join BC and DC. ABCD is the required square.

Q.4 Construct a rhombus ABCD where AC = 5.2 cm and BD = 6.4 cm.

Marks:4
Ans

In a rhombus, diagonals bisect each other at 90º. Therefore, the given rhombus ABCD can be drawn as follows:

(1) Draw a line segment AC of 5.2 cm and draw its perpendicular bisector. Let it intersect the line segment AC at point O.

(2) Draw arcs of 3.2 cm on both sides of this perpendicular bisector. Let the arcs intersect the perpendicular bisector at points B and D.

(3) Join points B and D with points A and C.

ABCD is the required rhombus.

Q.5 Construct the parallelogram ABCD with AB = 3.5 cm, BC = 4 cm and AC = 6.5 cm.

Marks:3
Ans

The parallelogram can be drawn as follows:

Step1: Draw line segment AC of 6.5 cm.

Step 2: With A as centre and AB (= 3.5 cm) as radius, draw an arc.

Step 3: With C as centre and BC (= 4 cm) as radius, draw another arc to intersect the arc of step 2 at B. Join AB and BC.

Step 4: With A as centre and AD (= 4 cm) as radius, draw an arc on the opposite side of AC.

Step 5: With C as centre and CD (= 3.5 cm) radius, draw another arc to intersect the arc drawn in step 4 at D. Join AD and CD.

ABCD is the required parallelogram.

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FAQs (Frequently Asked Questions)

Important questions in Class 8 Maths Chapter 4 Quadrilaterals include angle sums, rectangle diagonals, square construction, parallelogram angles, rhombus diagonals, and trapezium angle problems. These topics match the NCERT 2026 Chapter 4 question style.

The sum of angles of a quadrilateral is 360°. A diagonal divides a quadrilateral into two triangles, and each triangle has an angle sum of 180°.

Diagonals of a rectangle are equal in Class 8 Maths. They also bisect each other, which means each diagonal gets divided into two equal parts.

A rhombus has all four sides equal. A parallelogram only needs opposite sides to be equal and parallel.

A trapezium has at least one pair of parallel opposite sides. The interior angles on the same side of each non-parallel side add to 180°.