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Mathematics Chapter 7 of Class 8 is about Cubes and Cube Roots. The cube of any number is that number raised to the power of 3. When a number is multiplied three times by itself, we can say that the number has been cubed, and the product is called a cube of that number. If a is a number, then the cube of a is a ³ = a × a × a.
Extramarks is one of the best study platforms for students and assists them with their extensive online studies, which have solutions from Class 1 to Class 12. Our team of experienced Mathematics faculty has compiled NCERT solutions which helps students in their studies and their exam preparation. Students can refer to all our question banks of Important Questions Class 8 Mathematics Chapter 7 to practise examoriented questions. We have assembled questions from various sources such as NCERT textbooks and exemplars, CBSE sample papers, CBSE past year question papers, etc. Students can always prepare well for their exams and tests by simply solving a variety of exercise questions from our Important Questions Class 8 Mathematics Chapter 7.To get good grades in exams students must refer to Extramarks multiple study resources, practice a lot of questions and stick to a study schedule and follow it religiously to come out with flying colours.
Extramarks believes in incorporating joyful learning experiences through its own repository of resources. To get a maximum advantage during exam preparations, students can register on our platform Extramarks website and get full access to Important Questions Class 8 Mathematics Chapter 7 and other study materials, including NCERT solutions, CBSE revision notes, etc.
Get Access to CBSE Class 8 Maths Important Questions 202223 with ChapterWise Solutions
You can also find CBSE Class 8 Maths ChapterbyChapter Important Questions here:
CBSE Class 8 Maths Important Questions 

Sr No.  Chapters  Chapters Name 
1  Chapter 1  Rational Numbers 
2  Chapter 2  Linear Equations in One Variable 
3  Chapter 3  Understanding Quadrilaterals 
4  Chapter 4  Practical Geometry 
5  Chapter 5  Data Handling 
6  Chapter 6  Squares and Square Roots 
7  Chapter 7  Cubes and Cube Roots 
8  Chapter 8  Comparing Quantities 
9  Chapter 9  Algebraic Expressions and Identities 
10  Chapter 10  Visualising Solid Shapes 
11  Chapter 11  Mensuration 
12  Chapter 12  Exponents and Powers 
13  Chapter 13  Direct and Inverse Proportions 
14  Chapter 14  Factorisation 
15  Chapter 15  Introduction to Graphs 
16  Chapter 16  Playing with Numbers 
Important Questions Class 8 Mathematics Chapter 7 – With Solutions
Our inhouse Mathematics faculty has collated an entire list of Important Questions Class 8 Mathematics Chapter 7 by referring to various sources. For each and every question, the team has developed a stepbystep explanation that will help students understand the concepts used in each question. Also, the questions are chosen in a way that would cover the complete chapter with intext and chapter end exercises. . So by practising from our question bank, students will be able to revise the chapter and boost their understanding of strong and weak points. And enhance their preparation by further focusing on weak areas which need more attention instead of trying to maximise their potential by cramming. Scoring a high percentage of marks is not difficult. You just require the right strategy and correct understanding of the concepts.
Given below are a few of the questions and answers from our question bank of Class 8 Mathematics Chapter 7 Important Questions:
Question 1: A cuboid of plasticine made by Parikshit with sides 5 cm, 2 cm, and 5 cm. How many such cuboids will be needed to form a cube?
Answer 1: The given side of the cube is 5 cm, 2 cm and 5 cm.
Therefore, volume of cube = 5×2×5 = 50
The prime factorisation of 50 = 2×5×5
Here, 2, 5 and 5 cannot be grouped into triples of equal factors.
Therefore, we will multiply 50 by 2×2×5 = 20 to get the perfect square.
Hence, 20 cuboids are needed to form a cube.
Question 2: State true or false.
(i) The cube of any odd number is even
(ii) A perfect cube never ends with two zeros.
(iii) If the square of a number ends with 5, then its cube ends with 25.
(iv) There is no perfect cube which ends with 8.
(v) The cube of a twodigit number may be a threedigit number.
(vi) The cube of a twodigit number may have seven or more digits.
(vii) The cube of a singledigit number may be a singledigit number.
Answer 2:
(i) This statement is false.
Taking a cube of any required odd numbers
3³= 3 x 3 x 3 = 27
7³=7 x 7 x 7= 343
5³=5 x 5 x 5=125
All the required cubes of any given odd number will always be odd.
(ii) This statement is true.
10³= 10 x 10 x 10= 1000
20³ = 20 x 20 x 20 = 2000
150³ =150 x150 x150 = 3375000
Hence a perfect cube will never end with two zeros.
(iii) This statement is false.
15²= 15 x15= 225
15³= 15 x 15 x 15= 3375
Thus, the square of any given number ends with 5; then the cube ends with the number 25 is an incorrect statement.
(iv) This statement is false.
2³= 2x2x2= 8
12³ = 12 x 12 x 12= 1728
Accordingly, There are perfect cubes ending with the number 8
(v) This statement is false.
The minimum two digits number is 10
And
10³=1000→4 Digit number.
The maximum two digits number is 99
And
99³=970299→6 Digit number
Accordingly, the cube of twodigit numbers can never be a threedigit number.
(vi) This statement is false
10³=1000→4 Digit number.
The maximum two digits number is 99
And
99³=970299→6 Digit number
Accordingly, the cube of twodigit numbers can never have seven or more digits.
(vii) This statement is true
1³ = 1 x 1 x 1= 1
2³ = 2 x 2 x 2= 8
According to the cube, a singledigit can be a singledigit number.
Question 3: Find the cube root of 91125 by the prime factorisation method.
Answer 3: 91125 = 3×3×3×3×3×3×3×5×5×5
By grouping the factors in triplets of equal factors, 91125 = (3×3×3)×(3×3×3)×(5×5×5)
Here, 91125 can be grouped into triplets of equal factors,
∴ 91125 = (3×3×5) = 45
Thus , 45 is the cube root of 91125.
Question 4: Find the cube of 3.5.
Answer 4: 3.53 = 3.5 x 3.5 x 3.5
= 12.25 x 3.5
= 42.875
Question 5: (1.2) ³ = _________.
Answer 5: (1.2) ³ = 12/10
= (12/10) × (12/10) × (12/10)
= 1728/1000
= 1.728
Question 6: There are _________ perfect cubes between 1 and 1000.
Answer 6:
There are 8 perfect cubes between 1 and 1000.
2 × 2 × 2 = 8
3 × 3 × 3 = 27
4 × 4 × 4 = 64
5 × 5 × 5 = 125
6 × 6 × 6 = 216
7 × 7 × 7 = 343
8 × 8 × 8 = 512
9 × 9 × 9 = 729
Question 7: The cube of 100 will have _________ zeroes.
Answer 7: The cube of 100 will have six zeroes.
= 1003
= 100 × 100 × 100
= 1000000
Question 8: Is 392 a perfect cube? If not, find the smallest natural number by which 392 should be multiplied so that the product is a perfect cube.
Answer 8: The prime factorisation of 392 gives:
392 = 2 x 2 x 2 x 7 x 7
As we can see, number 7 cannot be paired in a group of three. Therefore, 392 is not a perfect cube.
We must multiply the 7 by the original number to make it a perfect cube.
Thus,
2 x 2 x 2 x 7 x 7 x 7 = 2744, which is a perfect cube, such as 23 x 73 or 143.
Hence, the smallest natural number, which should be multiplied by 392 to make a perfect cube, is 7.
Question 9: Find the cube root of 10648 by the prime factorisation method.
Answer 9:10648 = 2×2×2×11×11×11
Grouping the factors in triplets of number equal factors,
10648 = (2×2×2)×(11×11×11)
Here, 10648 can be grouped into triplets of number equal factors,
∴ 10648 = 2 ×11 = 22
Therefore, the cube root of 10648 is 22.
Question 10: Which of the following numbers are in perfect cubes? In the case of a perfect cube, find the number whose cube is the given number 256
Answer 10: A perfect cube can be expressed as a product of three numbers of equal factors
Resolving the given number into prime factors, we obtain
256 = 2 × 2 × 2 × 2 × 2× 2 × 2 × 2
Since the number 256 has more than three factors
∴ 256 is not a perfect cube.
Question 11: (13/10) ³
Answer 11: The cube of a rational number is the result of multiplying a number by itself three times.
To evaluate the cube of (13/10) ³
Firstly we need to convert into proper fractions, i.e.(13/10) ³
We need to multiply the given number three times, i.e. (13/10) × (13/10) × (13/10) =
(2197/1000)
∴ the cube of (1 3/10) is (2197/1000)
Question 12: Find the smallest number by which 128 must be divided to get a perfect cube.
Answer 12: The prime factorisation of 128 is given by:
128 = 2×2×2×2×2×2×2
By grouping the factors in triplets of equal factors,
128 = (2×2×2)×(2×2×2)×2
Here, 2 cannot be grouped into triples of equal factors.
Therefore, to obtain a perfect cube, we will divide 128 by 2.
Question 13: Find out the cube root of 13824 by the prime factorisation method.
Answer 13: First, let us prime factorise 13824:
13824 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3
= 2 ³ × 2 ³ × 2 ³ × 3 ³
3√13824 = 2 × 2 × 2 × 3 = 24
Benefits Of Solving Important Questions Class 8 Mathematics Chapter 7
The subject of Mathematics requires a lot of practice. A major requirement for clearing the entrance exams is a strong understanding of fundamentals and mental aptitude. Such an understanding requires building your concepts from lower classes. . We recommend our students access our platform Extramarks in order to obtain Important Questions Class 8 Mathematics Chapter 7. By solving questions and going through all the required solutions, students will eventually gain a lot of confidence to solve any question from the given chapter Cubes and Cube Roots.
Following are some of the benefits of frequently solving Important questions Class 8 Mathematics Chapter 7:
 Our experienced Mathematics subject teachers have meticulously put together the most Important Questions Class 8 Mathematics Chapter 7, by scrutinising many past years’ question papers.
 The questions and solutions provided are entirely based on the latest CBSE syllabus and as per CBSE guidelines. So the students can completely count on it.
 The questions covered in our set of Important Questions Class 8 Mathematics Chapter 7 are based on various topics covered in cubes and cube roots. It is endorsed that all students should revise and clarify their doubts before solving these important questions.
 By solving our Chapter 7 Class 8 Mathematics Important questions, students will get an idea about the paper. . Going through questions similar to the exam questions would help the students to be confident and get 100% scores in their exams, and set their own benchmark.
Extramarks provides students with a joyful learning experience and constantly strives to upgrade its products year after year to meet the changing demands of the curriculum and present its millennial generation with very simple and easy solutions for each and every student irrespective of their level.
Extramarks provides full and extensive learning solutions for students from Class 1 to Class 12. We have other study resources on our website, along with important questions and solutions. Students can also click on the belowmentioned links and access some of these resources:
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Q.1 Show that 189 is not a perfect cube.
Marks:1
Ans
Prime factors of 189 = 3 — 3 — 3 — 7
Making triplets, one triplet is formed 3 — 3 — 3, leaving one more factor 7.
So, 189 cannot be expressed as a product of triplets.
Hence, 189 is not a perfect cube.
Q.2 Find the cube root of the following by prime factorisation method.
(i) 8000
(ii) 13824
Marks:2
Ans
$\begin{array}{l}\left(\mathrm{i}\right)\text{}\mathrm{Prime}\text{factorisation of 8000}\\ \\ 2\overline{)8000}\\ 2\overline{)4000}\\ 2\overline{)2000}\\ 2\overline{)1000}\\ 2\overline{)500}\\ 2\overline{)250}\\ 5\overline{)125}\\ 5\overline{)25}\\ \text{}5\\ \text{8000 =}\underset{\xaf}{\text{2}\u2014\text{2}\u2014\text{2}}\u2014\underset{\xaf}{\text{2}\u2014\text{2}\u2014\text{2}}\u2014\underset{\xaf}{5\u20145\u20145}\\ \\ \sqrt[3]{8000}=\sqrt[3]{\underset{\xaf}{\text{2}\u2014\text{2}\u2014\text{2}}\u2014\underset{\xaf}{\text{2}\u2014\text{2}\u2014\text{2}}\u2014\underset{\xaf}{5\u20145\u20145}}\\ \text{= 2}\u2014\text{2}\u2014\text{5}\\ \text{= 20}\\ \text{Thus, the cube root of 8000 is 20.}\\ \\ \left(\mathrm{ii}\right)\text{}\mathrm{Prime}\text{factorisation of 13824}\\ \\ 2\overline{)13824}\\ 2\overline{)6912}\\ 2\overline{)3456}\\ 2\overline{)1728}\\ 2\overline{)864}\\ 2\overline{)432}\\ 2\overline{)216}\\ 2\overline{)108}\\ 2\overline{)54}\\ 3\overline{)27}\\ 3\overline{)9}\\ \text{}3\\ \text{}\\ \text{13824 =}\underset{\xaf}{\text{2}\u2014\text{2}\u2014\text{2}}\u2014\underset{\xaf}{\text{2}\u2014\text{2}\u2014\text{2}}\u2014\underset{\xaf}{2\u20142\u20142}\u2014\underset{\xaf}{3\u20143\u20143}\\ \\ \sqrt[3]{13824}=\sqrt[3]{\underset{\xaf}{\text{2}\u2014\text{2}\u2014\text{2}}\u2014\underset{\xaf}{\text{2}\u2014\text{2}\u2014\text{2}}\u2014\underset{\xaf}{2\u20142\u20142}\u2014\underset{\xaf}{3\u20143\u20143}}\\ \text{= 2}\u2014\text{2}\u20142\u20143\\ \text{= 24}\\ \text{Thus, the cube root of 13824 is 24.}\end{array}$
Q.3 Find the cube root of 32768 through estimation.
Marks:1
Ans
The given number is 32768.
Form groups of three starting from the rightmost digit of 32768.
In this case it is 768 and 32 has only 2 digits.
Taking 768, 8 in unit digit, the required cube root is 2.
The other group i.e. 32, as cube of 3 is 27 and cube of 4 is 64, 32 lies between 27 and 64.
The smallest among 3 and 4 is 3.
The ones place of 3 is itself.
Take 3 as tens place of the cube root of 32768.
Thus, cube root of 32768 is 32.
Q.4 Find the smallest number by which 704 must be divided to obtain a perfect cube.
Marks:2
Ans
$\begin{array}{l}704=\underset{\xaf}{2\u20142\u20142}\u2014\underset{\xaf}{2\u20142\u20142}\u201411\\ \mathrm{The}\text{}\mathrm{prime}\text{}\mathrm{factor}\text{}11\text{}\mathrm{does}\mathrm{not}\text{}\mathrm{appear}\text{}\mathrm{in}\text{}\mathrm{a}\text{}\mathrm{group}\text{}\mathrm{of}\text{}\mathrm{three}.\\ \mathrm{So},704\text{}\mathrm{is}\text{}\mathrm{not}\text{}\mathrm{a}\text{}\mathrm{perfect}\text{}\mathrm{cube}.\\ \mathrm{To}\text{}\mathrm{make}\text{}\mathrm{it}\text{}\mathrm{a}\text{}\mathrm{perfect}\text{\u20ac\u2030}\mathrm{cube},\text{}\mathrm{divide}\text{}\mathrm{it}\text{}\mathrm{by}\text{}11.\\ \mathrm{Thus},704\xb711=\underset{\xaf}{2\u20142\u20142}\u2014\underset{\xaf}{2\u20142\u20142}\\ \text{}=64,\text{}\mathrm{which}\text{}\mathrm{is}\text{}\mathrm{a}\text{}\mathrm{perfect}\text{}\mathrm{cube}.\\ \mathrm{Hence},\mathrm{the}\mathrm{required}\mathrm{smallest}\mathrm{number}\mathrm{is}11.\end{array}$