# Important Questions for CBSE Class 8 Maths Chapter 5 – Data Handling

## Data Handling Class 8 Extra Questions

Maths, in general, is defined as a subject that deals with numbers. If you are good at maths, you can calculate very fast. Chapter 5 of Class 8 Maths is called ‘Data Handling’. Data handling denotes collecting a set of data and presenting it in a different form. Data is a collation of numerical figures that constitutes a particular kind of information. The collection of all observations which are gathered initially is called the raw data of the given content. Data can be in any form. It may be represented in words, numbers, measurements, descriptions or observations. Data handling is the process of obtaining the research data collected, archived or disposed of in a protected and safe way during and after fulfilling the analysis process.

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## Get Access to CBSE Class 8 Maths Important Questions 2022-23 with Chapter-Wise Solutions

You can also find CBSE Class 8 Maths Chapter-by-Chapter Important Questions here:

### CBSE Class 8 Maths Important Questions

Sr No. Chapters Chapters Name
1 Chapter 1 Rational Numbers
2 Chapter 2 Linear Equations in One Variable
3 Chapter 3 Understanding Quadrilaterals
4 Chapter 4 Practical Geometry
5 Chapter 5 Data Handling
6 Chapter 6 Squares and Square Roots
7 Chapter 7 Cubes and Cube Roots
8 Chapter 8 Comparing Quantities
9 Chapter 9 Algebraic Expressions and Identities
10 Chapter 10 Visualising Solid Shapes
11 Chapter 11 Mensuration
12 Chapter 12 Exponents and Powers
13 Chapter 13 Direct and Inverse Proportions
14 Chapter 14 Factorisation
15 Chapter 15 Introduction to Graphs
16 Chapter 16 Playing with Numbers

## Data Handling Class 8 Important Questions with Answers

Mentioned below are some of the questions and their answers from our Chapter 5 Class 8 Maths important questions.

### Question 1: A survey was conducted to research the type of music that a certain group of young people enjoyed in a city. The adjoining pie chart exhibits the findings of this survey. From the given pie chart, answer the following questions below:

(i) If 20 people enjoyed classical music, how many young people were surveyed?

(ii) Which is the type of music liked by the maximum number of young people?

(iii) If a cassette company were to make 1000 CDs, how many of each type would they make?

Answer 1: (i) 10% represents 20 people.

100% represents = (100 x 20)/10

= 200

Therefore, 200 young people were surveyed.

(ii) Since 40% of the total young people surveyed enjoyed listening to light music and no other form of music was liked more than that, we can conclude that the maximum number of young people liked light music.

(iii) CD’s of classical music = (10 x 1000)/100 = 100

CD’s of semi-classical music = (20 x 1000)/100 = 200

CD’s of light music = (40 x 1000)/100 = 400

CD’s of folk music = (30 x 1000)/100 = 300

### Question 2: When a die is thrown, list the number of outcomes of an event of getting

(i) (a) a prime number (b) not a prime number.

(ii) (a) a number greater than 5 (b) a number not greater than 5.

Answer 2: (i) (a) The outcomes of the event of getting a prime number are 2, 3 and 5.

(b) The outcomes of the event of not getting any prime numbers are 1, 4 and 6.

(ii) (a) The outcome of the event of getting a number greater than 5 is 6.

(b) The outcomes of the event of not getting a number greater than 5 are 1, 2, 3, 4 and 5.

### Question 3: The monthly salary of an average person is Rs. 15,000. The central angle of the given sector representing his expenses on food and house rent on a pie chart is 60°. The amount he spends on his food and house rent is

(a) Rs. 5000 (b) Rs. 2500 (c) Rs. 6000 (d) Rs. 9000

Answer 3: (b) Rs. 2500

From the question,

The part of the monthly salary spent on food and house rent = 60°/360°

The amount he spends on his food and house rent is = (60°/360°) × 15000

= Rs. 2500

### Question 4: The pie chart given below shows the distribution of constituents

in the human body. The central angle of the given sector showing the

distribution of protein and other constituents is

(a) 108° (b) 54° (c) 30° (d) 216°

The pie chart given above shows us the distribution of constituents

in the human body = 16% + 14% = 30%

= (30/100) × 360v

= 108°

### Question 5: The numbers from 1 to 10 are written on ten separate slips (one number on each slip) and are kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of:

(i) getting the number 6?

(ii) getting a number less than 6?

(iii) getting a number greater than 6?

(iv) getting a 1-digit number?

Answer 5: (i) The outcome of getting exactly the number 6 from ten separate slips is one.

Therefore, the probability of getting exactly the number 6 = 1/10

(ii) The numbers that are less than 6 are as follows 1, 2, 3, 4 and 5. So the total number of numbers is five. Thus, we get 5 outcomes.

Therefore, the probability of getting any number less than 6 = 5/10

= 1/2

(iii) The number that is greater than 6 out of ten are as follows  7, 8, 9, 10. So, we obtain 4 possible outcomes.

Therefore, the probability of getting any number greater than 6 = 4/10

= 2/5

(iv) The one-digit numbers out of 1 to 10 are as follows  1, 2, 3, 4, 5, 6, 7, 8, 9.

Therefore, the probability of getting any  1-digit number = 9/10.

### Question 6: (a) Find out the probability at which the pointer stops on D.

(b) Find the probability of getting any ace from a well-shuffled deck of 52 playing cards.

(c) Find the probability of getting any red apple. (See figure below)

Answer 6: (a) In a given spinning wheel, there are five pointers A, A, B, C, D. So, we obtain five outcomes. The pointer stops at D, which is also one of the outcomes.

So the probability of the pointer to stop on D = 1/5

(b) There are 4 aces in a given deck of 52 playing cards. So there are four events for obtaining any ace.

So, the probability of getting any ace = 4/52 = 1/13

(c) Total number of apples = 7

Number of red apples = 4

The probability of getting any red apple from the given figure = 4/7

### Question 7: The pie chart represents the distribution of  proteins in human body parts. What is the ratio of  the distribution of proteins in the muscles to that of proteins  in the bones?

(a) 3: 1 (b) 1: 2 (c) 1: 3 (d) 2: 1

Answer 7: (d) 2: 1

From the chart,

The distribution of protein in the muscles = 1/3

The distribution of protein in the bones = 1/6

Then,

The ratio of the distribution of the amount of proteins in the muscles to that of proteins in the bones,

= 1/3: 1/6

= (1/3) × (6/1)

= (1/1) × (2/1)

= 2/1

= 2: 1

### Question 8: What is the central angle of the given sector (in the above pie chart) representing skin and bones together?

(a) 36° (b) 60° (c) 90° (d) 96°

Answer 8: (d) 96°

Distribution of protein in the skin = 1/10

Distribution of protein in the bones = 1/6

The central angle of the sector represents skin and bones,

= 1/10 + 1/6

= (3 + 5)/30

= 8/30 × 360°

= 96°

### Question 9: If you own a spinning wheel with 3 green sectors, 1 blue sector and 1 red sector, what is the probability of a green sector being present? What is the probability of getting a single non-blue sector?

Answer 9: A total of sectors present are five. Out of the five present sectors, three sectors are green.

Therefore, the probability green of a sector being present = 3/5.

Out of the five present sectors, one of those sectors is blue.

Hence, the number of amount on-blue sectors = 5 – 1

= 4 sectors.

Therefore, the probability of getting a single non-blue sector present will be equal to 4/5.

### Question 10: The number of hours the students of a particular class have watched television during holidays is shown in the graph given below. Answer the following questions:

(i) How many hours did the maximum number of students watch T.V.?

(ii) How many students have watched T.V. for less than 4 hours?

(iii) How many students have spent more than 5 hours watching T.V.?

Answer 10: (i) 32 students have watched T.V. for 4-5 hours.

Therefore, the maximum number of students who have watched T.V. for 4 – 5 hours.

(ii) The number of students who have watched T.V. for less than 4 hours = 22 + 8 + 4 = 34

(iii) The number of students who have spent more than 5 hours watching T.V. = 8 + 6 = 14

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• The questions covered in our set of important questions Class 8 Maths Chapter 5 are based on various topics covered in Data handling. It is recommended that students revise and clear all their doubts before solving these important questions.
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Q.1 Draw a histogram for the following data:

 Class Interval 10-15 15-20 20-25 25-30 30-35 35-40 40-45 45-50 50-55 55-60 Frequency 30 20 10 90 50 10 30 10 10 40

Marks:3
Ans

Steps to draw the histogram:

1. Taking a scale of 1 cm = 10 units.

2. Represent each interval with height corresponding to the given frequency.

Q.2

On spinning the wheel,
(i) what will be the probability of getting a green (G) sector?
(ii) what will be the probability of not getting a green (G) sector?

Marks:2
Ans

Total outcomes of the event is 8.
(i) Probability of getting a green sector = 4/8 = 1/2
(ii) Probability of not getting a green sector, i.e. probability of getting a red (R) sector = 4/8 = 1

Q.3 Draw a pie chart for the following data:

 Flavours Percentage of students preferring the flavours Chocolate 25% Strawberry 25% Vanilla 50%

Marks:1
Ans

centre angle for Chocolate =

$\frac{25}{100}—360°$

= 90°
centre angle for Strawberry =

$\frac{25}{100}—360°$

= 90°
centre angle for Vanilla =

$\frac{50}{100}—360°$

=180°

Q.4 The number of hours for which a particular age-group of women watched television is shown through the given histogram. Which age-group of women spends minimum hours watching TV?

A. 20-25

B. 30-35

C. 35-40

D. 45-50

Marks:1

Q.5 When a die is thrown, the probability of getting a number greater than 5 is ____.

A. 1/6

B. 1/5

C. 1/4

D. 2/3

## FAQs (Frequently Asked Questions)

### 1. What are the two types of data handling?

The two types of data handling are qualitative data and quantitative data.

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