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Speed of Sound Formula
Any medium can transmit the vibration or disturbance known as sound. When it reaches a person’s ear, it is audible and moves by transferring energy from one particle to another. For instance, when an object vibrates, energy is transferred to the nearby particles, which causes them to vibrate as well. The lack of particles that could serve as a medium prevents sound from travelling through the vacuum. Only a medium like water, air, or a solid can transmit sound. This article will talk about sound waves and the Speed of Sound Formula.
Speed of Sound Formula
A longitudinal wave, sound travels through air and liquids but travels both longitudinally and transversely through solids. The properties of the medium in which a sound wave is propagating determine how quickly it moves through that medium. Its speed is independent of the wave’s properties or the force that created it. Its propagation through a medium can be used to examine some of that medium’s characteristics.
The distance a sound wave travels in one unit of time while propagating through an elastic medium is known as the speed of sound. The density and elasticity of a given medium affect the speed of sound in that medium. Physics states that as the sound wave speed increases, elasticity increases, density decreases, and vice versa. As a result, solids have the highest and lowest sound speeds.
The Speed of Sound Formula is a crucial part of the syllabus for students, and they need to be thorough with the concept. The concept of Speed of Sound Formula can be tricky for students to comprehend. The concept can be understood with the help of the textbooks, but they might not seem enough for some students. They can require more resources to have a good understanding of the Speed of Sound Formula.
What is a sound wave?
The speed of sound can be computed as,
speed of sound = the square root of (the coefficient ratio of specific heats × the pressure of the gas / the density of the medium).
Mathematically,
c =(√γ×Pρ)
Where,
c Speed of sound
P Pressure
ρ Density
γ Specific heat ratio
Here γ is representing the adiabatic index and also known as the isentropic expansion factor. It is computed as the ratio of specific heats of a gas at a constant pressure to a gas at a constant volume.
Students can learn more about the sound wave and the Speed of Sound Formula with the help of the learning materials available on the Extramarks platform. The platform and its contents are curated by expert teachers who are experience in the academic field. They design the curriculum on the website and the app in an easy-to-understand language that helps students understand better and faster. Students can also prepare for the exams with the help of the multiple papers like the sample papers, and the practise question papers on the Extramarks platform. Students can learn from anywhere at any time with the help of the offline access. Students do not rely entirely on the textbooks, and they can support their learning with the help of the study guides on the Extramarks platform for concepts like Speed of Sound Formula.
Another important feature of the Extramarks platform is the availability of the audiovisual modules that allow the students to learn in an interactive manner. Learning is made fun with the Extramarks platform. Students can also refer to the platform for doubt clearing sessions before the examinations. Learning about the different formulas like the Speed of Sound Formula can be extremely fun for students, but having a thorough understanding is also essential.
Solved Examples
Q.1: The sound waves travel in the air with a density of 0.034 kg/m³ and pressure of 2k Pa with a temperature of 2°C. Calculate the speed of the sound.
Solution:
As given here:
Temperature, T = 2° C
Density, ρ=0.034kg/m³
and, pressure P = 2k Pa
i.e. P = 2000 Pa
as we know that specific heat ratio in air is,
γ=1.4
Now the speed of sound formula is given by
c =(√γ×Pρ)
c =(√1.4×20000.034)
c= (√82352.94)
c = 286.97
Therefore, speed of sound = 286.97 m/s.
Q. 2: Find out the pressure if sound travels through a medium having a density 0.05 KPa and speed of sound is 400 m/s.
Solution:
As given in the problem,
Density, ρ = 0.05 KPa,
Speed of sound, c = 400 m/s
Also, γ = 1.4 at room temperature for gases.
Now the speed of sound formula is:
c =(√γ×Pρ)
rearranging the formula,
P = c2×ργ
P = 4002×0.051.4
P= 1600×0.051.4
P= 5714.28 Pa
Therefore, Pressure will be 5714.28 Pa.